I'm trying to change the saturation of a particular image, in Java. I already know how to edit the hue and brightness of a pixel, but I'm stumped how to do saturation. Here's the loop I use to cycle through each of the pixels, if you need to know it. I know it isn't good for performance, but it's temporary.
Loop:
for(int y = 0; y < height; y++) {
for(int x = 0; x < width; x++) {
int pixel = image.getRGB(x, y);
int r = (pixel >> 16) & 0xFF;
int g = (pixel >> 8) & 0xFF;
int b = (pixel) & 0xFF;
//Adjust saturation:
//?????????????????????
}
}
In short, I'm not sure how to change the saturation of a pixel, but I want to know how. The loop I'm using above is working perfectly, so no problems there. Thanks! :D
You can use:
int red = ...;
int green = ...;
int blue = ...;
float[] hsb = Color.RGBtoHSB(red, green, blue, null);
float hue = hsb[0];
float saturation = hsb[1];
float brightness = hsb[2];
/* then change the saturation... */
int rgb = Color.HSBtoRGB(hue, saturation, brightness);
red = (rgb>>16)&0xFF;
green = (rgb>>8)&0xFF;
blue = rgb&0xFF;
Related
I want to convert a buffered image from RGBA format to CYMK format without using auto conversion tools or libraries,so i tried to extract the RGBA values from individual pixels that i got using BufferedImage.getRGB() and here what I've done so far :
BufferedImage img = new BufferedImage("image path")
int R,G,B,pixel,A;
float Rc,Gc,Bc,K,C,M,Y;
int height = img.getHeight();
int width = img.getWidth();
for(int y = 0 ; y < height ; y++){
for(int x = 0 ; x < width ; x++){
pixel = img.getRGB(x, y);
//I shifted the int bytes to get RGBA values
A = (pixel>>24)&0xff;
R = (pixel>>16)&0xff;
G = (pixel>>8)&0xff;
B = (pixel)&0xff;
Rc = (float) ((float)R/255.0);
Gc = (float) ((float)G/255.0);
Bc = (float) ((float)B/255.0);
// Equations i found on the internet to get CYMK values
K = 1 - Math.max(Bc, Math.max(Rc, Gc));
C = (1- Rc - K)/(1-K);
Y = (1- Bc - K)/(1-K);
M = (1- Gc - K)/(1-K);
}
}
Now after I've extracted it ,i want to draw or construct an image using theses values ,can you tell me of a method or a way to do this because i don't thinkBufferedImage.setRGB() would work ,and also when i printed the values of C,Y,M some of them hadNaN value can someone tell me what that means and how to deal with it ?
While it is possible, converting RGB to CMYK without a proper color profile will not produce the best results. For better performance and higher color fidelity, I really recommend using an ICC color profile (see ICC_Profile and ICC_ColorSpace classes) and ColorConvertOp. :-)
Anyway, here's how to do it using your own conversion. The important part is creating a CMYK color space, and a ColorModel and BufferedImage using that color space (you could also load a CMYK color space from an ICC profile as mentioned above, but the colors would probably look more off, as it uses different calculations than you do).
public static void main(String[] args) throws IOException {
BufferedImage img = ImageIO.read(new File(args[0]));
int height = img.getHeight();
int width = img.getWidth();
// Create a color model and image in CMYK color space (see custom class below)
ComponentColorModel cmykModel = new ComponentColorModel(CMYKColorSpace.INSTANCE, false, false, Transparency.TRANSLUCENT, DataBuffer.TYPE_BYTE);
BufferedImage cmykImg = new BufferedImage(cmykModel, cmykModel.createCompatibleWritableRaster(width, height), cmykModel.isAlphaPremultiplied(), null);
WritableRaster cmykRaster = cmykImg.getRaster();
int R,G,B,pixel;
float Rc,Gc,Bc,K,C,M,Y;
for (int y = 0; y < height; y++) {
for (int x = 0; x < width; x++) {
pixel = img.getRGB(x, y);
// Now, as cmykImg already is in CMYK color space, you could actually just invoke
//cmykImg.setRGB(x, y, pixel);
// and the method would perform automatic conversion to the dest color space (CMYK)
// But, here you go... (I just cleaned up your code a little bit):
R = (pixel >> 16) & 0xff;
G = (pixel >> 8) & 0xff;
B = (pixel) & 0xff;
Rc = R / 255f;
Gc = G / 255f;
Bc = B / 255f;
// Equations I found on the internet to get CMYK values
K = 1 - Math.max(Bc, Math.max(Rc, Gc));
if (K == 1f) {
// All black (this is where you would get NaN values I think)
C = M = Y = 0;
}
else {
C = (1- Rc - K)/(1-K);
M = (1- Gc - K)/(1-K);
Y = (1- Bc - K)/(1-K);
}
// ...and store the CMYK values (as bytes in 0..255 range) in the raster
cmykRaster.setDataElements(x, y, new byte[] {(byte) (C * 255), (byte) (M * 255), (byte) (Y * 255), (byte) (K * 255)});
}
}
// You should now have a CMYK buffered image
System.out.println("cmykImg: " + cmykImg);
}
// A simple and not very accurate CMYK color space
// Full source at https://github.com/haraldk/TwelveMonkeys/blob/master/imageio/imageio-core/src/main/java/com/twelvemonkeys/imageio/color/CMYKColorSpace.java
final static class CMYKColorSpace extends ColorSpace {
static final ColorSpace INSTANCE = new CMYKColorSpace();
final ColorSpace sRGB = getInstance(CS_sRGB);
private CMYKColorSpace() {
super(ColorSpace.TYPE_CMYK, 4);
}
public static ColorSpace getInstance() {
return INSTANCE;
}
public float[] toRGB(float[] colorvalue) {
return new float[]{
(1 - colorvalue[0]) * (1 - colorvalue[3]),
(1 - colorvalue[1]) * (1 - colorvalue[3]),
(1 - colorvalue[2]) * (1 - colorvalue[3])
};
}
public float[] fromRGB(float[] rgbvalue) {
// NOTE: This is essentially the same equation you use, except
// this is slightly optimized, and values are already in range [0..1]
// Compute CMY
float c = 1 - rgbvalue[0];
float m = 1 - rgbvalue[1];
float y = 1 - rgbvalue[2];
// Find K
float k = Math.min(c, Math.min(m, y));
// Convert to CMYK values
return new float[]{(c - k), (m - k), (y - k), k};
}
public float[] toCIEXYZ(float[] colorvalue) {
return sRGB.toCIEXYZ(toRGB(colorvalue));
}
public float[] fromCIEXYZ(float[] colorvalue) {
return sRGB.fromCIEXYZ(fromRGB(colorvalue));
}
}
PS: Your question talks about RGBA and CMYK, but your code just ignores the alpha value, so I did the same. If you really wanted to, you could just keep the alpha value as-is and have a CMYK+A image, to allow alpha-compositing in CMYK color space. I'll leave that as an exercise. ;-)
Given an image file, say of PNG format, how to I get an array of int [r,g,b,a] representing the pixel located at row i, column j?
So far I am starting here:
private static int[][][] getPixels(BufferedImage image) {
final byte[] pixels = ((DataBufferByte) image.getRaster().getDataBuffer()).getData();
final int width = image.getWidth();
final int height = image.getHeight();
int[][][] result = new int[height][width][4];
// SOLUTION GOES HERE....
}
Thanks in advance!
You need to get the packed pixel value as an int, you can then use Color(int, boolean) to build a color object from which you can extract the RGBA values, for example...
private static int[][][] getPixels(BufferedImage image) {
int[][][] result = new int[height][width][4];
for (int x = 0; x < image.getWidth(); x++) {
for (int y = 0; y < image.getHeight(); y++) {
Color c = new Color(image.getRGB(i, j), true);
result[y][x][0] = c.getRed();
result[y][x][1] = c.getGreen();
result[y][x][2] = c.getBlue();
result[y][x][3] = c.getAlpha();
}
}
}
It's not the most efficient method, but it is one of the simplest
BufferedImages have a method called getRGB(int x, int y) which returns an int where each byte is the components of the pixel (alpha, red, green and blue). If you dont want to do the bitwise operators yourself you can use Colors.getRed/Green/Blue methods by creating a new instance of Java.awt.Color with the int from getRGB.
You can do this in a loop to fill the three-dimensional array.
This is my code for this problem:
File f = new File(filePath);//image path with image name like "lena.jpg"
img = ImageIO.read(f);
if (img==null) //if img null return
return;
//3d array [x][y][a,r,g,b]
int [][][]pixel3DArray= new int[img.getWidth()][img.getHeight()][4];
for (int x = 0; x < img.getWidth(); x++) {
for (int y = 0; y < img.getHeight(); y++) {
int px = img.getRGB(x,y); //get pixel on x,y location
//get alpha;
pixel3DArray[x][y][0] =(px >> 24)& 0xff; //shift number and mask
//get red
pixel3DArray[x][y][1] =(px >> 16)& 0xff;
//get green
pixel3DArray[x][y][2] =(px >> 8)& 0xff;
//get blue
pixel3DArray[x][y][3] =(px >> 0)& 0xff;
}
}
Hi guys I have to convert this image:
in this:
in Java.
This is my code:
double Cx =original_img.width()/2;
double Cy =original_img.height()/2;
int rho,theta;
for (int i=0;i<img.getHeight();i++){
for(int j=0;j<img.getWidth();j++){
rho = (int)(Math.sqrt(Math.pow(i-Cx,2) + Math.pow(j-Cy,2)));
theta = (int)(Math.atan2((j-Cy),(i-Cx)));
int color;
try{
color = img.getRGB((int)rho, (int)theta);
}catch(Exception e){
color = 0;
}
int alpha = (color>>24) & 0xff;
int red = (color & 0x00ff0000) >> 16;
int green = (color & 0x0000ff00) >> 8;
int blue = color & 0x000000ff;
int pixel = (alpha << 24) | (red << 16) | (green << 8) | blue;
img2.setRGB(rho, theta, pixel);
System.out.println("point: "+rho+" "+theta);
}
}
What's wrong?
I haven't found a simple and good Log-Polar transform in java.
My steps are:
1) take an original image (original_img)
2) cycling on the rows and cols of image
3) calculate rho and theta (are the new X and Y coordinates for the new pixel, right?)
4) get color pixel at coords (rho,theta)
5) create new pixel and set at the new coords.
What miss or wrong?
Thank you.
Now I get it. You want to apply to pixel coordinates. Sorry.
rho = (int)(Math.sqrt(Math.pow(i-Cx,2) + Math.pow(j-Cy,2)));
theta = (int)(Math.atan2((j-Cy),(i-Cx)));
Why would you want int instead of double on the above code? If not required I would suggest use double. Also the code is wrong, you are subtracting the dimension each time. Do not do this:
rho = Math.sqrt(Math.pow(i,2) + Math.pow(j,2));
theta = Math.atan2((j),(i));
That looks fine to me. But why you want to convert to polar anyway?
P.S. The above code has noting to do with Opencv of course.
Edit: If I am interpreting correctly the algorithm you the Cartesian coordinates should be in the center of the image so use your code:
I cannot tell you about the rotation part though but from your statement get color pixel at coords (rho,theta) I am guessing that you don't have to rotate the image. The effect does not require this.
I am trying to read the pixel values of the image using the below code
int[] pixel;
BufferedImage imageA = ImageIO.read(new File("xyz.bmp"));
for (int y = 0; y < imageA.getHeight(); ++y) {
for (int x = 0; x < imageA.getWidth(); ++x) {
pixel = imageA.getRaster().getPixel(x, y, new int[3]);
}}
values of RGB are stored in pixel[0],pixel[1] and pixel[2] respectively and when i saw the output i saw the values ranging between 0 to 255.
I saw some use the below code to get pixel values
int pixel;
BufferedImage imageA = ImageIO.read(new File("xyz.bmp"));
for (int y = 0; y < imageA.getHeight(); ++y) {
for (int x = 0; x < imageA.getWidth(); ++x) {
pixel = imageA.getRGB(x, y);
}}
When i saw the output for a particular pixel it was -14935264 . What does this value represent and whats the difference between the above two methods.
In the second case, you get an int that contains the RGB-values in the lower 24 bits. The red component is bits 23-16, the green component is bits 15-8 and the blue component is bits 7-0.
If you want to get the components out of the int:
int red = (pixel >> 16) & 0xFF;
int green = (pixel >> 8) & 0xFF;
int blue = pixel & 0xFF;
The other way around:
int pixel = (red << 16) | (green << 8) | blue;
I know the java code for grayscale is this( 0.2126 * red + 0.7152 * green + 0.0722 * blue(
I was wondering if anyone knows how I can find more variety of coloring formulas, like if i want to make the picture old fashion way, more orange, make it brighter, or darker ... sharper and so on
int pixel = image.getRGB(j, i);
int red = (pixel) & 0xff;
int green = (pixel >> 8) & 0xff;
int blue = (pixel >> 16) & 0xff;
int newPixel = (int) (0.2126 * red + 0.7152 * green + 0.0722 * blue);
image1.setRGB(j, i, newPixel);
The old fashion way you mention is called "sepia" effect. Take a look at this question particularly this answer which points out to the following code snippet (note that I did not write this code, just helping out in finding answers to your question)
/**
*
* #param img Image to modify
* #param sepiaIntensity From 0-255, 30 produces nice results
* #throws Exception
*/
public static void applySepiaFilter(BufferedImage img, int
sepiaIntensity) throws Exception
{
// Play around with this. 20 works well and was recommended
// by another developer. 0 produces a grey image
int sepiaDepth = 20;
int w = img.getWidth();
int h = img.getHeight();
WritableRaster raster = img.getRaster();
// We need 3 integers (for R,G,B color values) per pixel.
int[] pixels = new int[w*h*3];
raster.getPixels(0, 0, w, h, pixels);
// Process 3 ints at a time for each pixel. Each pixel has 3 RGB
colors in array
for (int i=0;i<pixels.length; i+=3)
{
int r = pixels[i];
int g = pixels[i+1];
int b = pixels[i+2];
int gry = (r + g + b) / 3;
r = g = b = gry;
r = r + (sepiaDepth * 2);
g = g + sepiaDepth;
if (r>255) r=255;
if (g>255) g=255;
if (b>255) b=255;
// Darken blue color to increase sepia effect
b-= sepiaIntensity;
// normalize if out of bounds
if (b<0) b=0;
if (b>255) b=255;
pixels[i] = r;
pixels[i+1]= g;
pixels[i+2] = b;
}
raster.setPixels(0, 0, w, h, pixels);
}
I would just play with the numbers.
more orange,
more red and a little more green (red + green = yellow)
brighter
increase all the factors
darker
decrease all the factors
sharper
This is specific filter which compare surrounding pixels to find edges. It not just a matter of playing with the colours.
BTW: You should add capping of the values. i.e. Math.min(255, Math.max(0, value))
You can manipulate the proportion between the color channels in order to change the scene "atmosphere". The images below were created using the ColorChannel plug-in.
The algorithm source code is presented below. The method getAttribute() gets the parameters (red,gree,blue) passed by the user. The methods getIntComponent0, getIntComponent1 and getIntComponent2 get each color channel (red, gree and blue). The method setIntColor sets back the value of each channel.
#Override
public void process
(
MarvinImage imageIn,
MarvinImage imageOut,
MarvinAttributes attrOut,
MarvinImageMask mask,
boolean preview
) {
int vr = (Integer)getAttribute("red");
int vg = (Integer)getAttribute("green");
int vb = (Integer)getAttribute("blue");
double mr = 1+Math.abs((vr/100.0)*2.5);
double mg = 1+Math.abs((vg/100.0)*2.5);
double mb = 1+Math.abs((vb/100.0)*2.5);
mr = (vr > 0? mr : 1.0/mr);
mg = (vg > 0? mg : 1.0/mg);
mb = (vb > 0? mb : 1.0/mb);
int red,green,blue;
for(int y=0; y<imageIn.getHeight(); y++){
for(int x=0; x<imageIn.getWidth(); x++){
red = imageIn.getIntComponent0(x, y);
green = imageIn.getIntComponent1(x, y);
blue = imageIn.getIntComponent2(x, y);
red = (int)Math.min(red * mr, 255);
green = (int)Math.min(green * mg, 255);
blue = (int)Math.min(blue * mb, 255);
imageOut.setIntColor(x, y, 255, red, green, blue);
}
}
}