Error in retrieving the lenght of a string [closed] - java

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What's wrong with my code?
import java.util.Scanner;
class Pali
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.println("\nInserisci una stringa: ");
String p = in.next();
int n = p.lenght();
}
}
I get a "cannot find symbol" error in p variable. Why? Many thanks (sorry,if I did something wrong, it's my first post).

It's a typo:
int n = p.lenght();
Should be p.length();

It is a typo.
int n = p.lenght();
Correction: int n = p.length();
It happens to the best of us.

Use: int n = p.length(); instead of p.lenght();

Related

ArrayIndexOutOfBoundsException in INTELIJ [closed]

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Closed 3 years ago.
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I just started learning java, and I created a support code (called HELP) to help me track some variables in another code im writing. But when I try to run HELP I get this exception in return, can someone help me?
Im using INTELIJ
public static void main(String [] args){
int a = Integer.parseInt(args[0]);
int b = Integer.parseInt(args[1]);
int T = Integer.parseInt(args[2]);
for (int i = 0; i < T; i++) {
//bob vĂȘ a carta
int see;
int unseen;
if (Math.random() > .5) {
see = a;
} else see = b;
System.out.println(see);
}
}
the output is:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 0 out of bounds for length 0
at HELP.main(HELP.java:4)
You aren't specifying any arguments when you run the program so args[0], args[1], args[2] isn't a valid index.
In one old post founded this
// to use 10 when there aren't args...
int trials = (args.length > 0) ? Integer.parseInt(args[0]) : 10;

Why integer value gets 0 when the limit is exceeded? [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
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Why an int becomes zero when it exceed the int limit in java?
Eg:
import java.util.Scanner
public class MyClass{
public static void main(Stings [] args){
Scanner sc = new Scanner(System.in);
int x = sc.nextInt(); // enter 50 or higher.
int answer = 1;
while(x>0){
answer = answer*x;
x--;
}
System.out.println(answer);
}
}
At some point answer becomes 0 (integer overflow) and stays 0.

For statement solution [closed]

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Closed 6 years ago.
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I'm just really confused on why there's an error at the for statement line. This is literally code from a tutorial that I can't run because there's an error at line 3
class RoundOne{
public static void main(String[] args){
for(int i =0,i<10,i++){
System.out.println("The number is: "+i);
}
}
}
for(int i =0;i<10;i++){
System.out.println("The number is: "+i);
}
You wrote , instead of ;
In your for loop instead of
for(int i =0,i<10,i++)
write
for(int i =0;i<10;i++)
For loops use ; between the parts, not ,
class RoundOne {
public static void main(String[] args) {
for (int i = 0; i < 10; i++) {
System.out.println("The number is: " + i);
}
}
}

Wierd String error, please be gracious, new to java [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
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So my problem is that it keeps saying I already defined String spaces up top but if I take the definition that's outside of the loop away and try to define spaces only in the loop, it tells me it hasn't been instantiated...
public class NestedLoop {
public static void main (String [] args) {
int userNum = 0;
int i = 0;
int j = 1;
String spaces = "";
Scanner scnr = new Scanner(System.in);
System.out.print("Enter userNum:");
userNum = scnr.nextInt();
for (i = 0; i <= userNum; i++) {
while (j == i){
spaces = spaces.concat(" ");
System.out.print(spaces);
j++;}
System.out.println(i);}
Error: main.java:244: spaces is already defined in main(java.lang.String[])
I just ran this code in my IDE and got no errors, compile time or run time. Not sure I can replicate the errors you're reporting. Only possibility I could think of is an error with your JDK, but at the same time I dunno how or why that would occur.

Variable not found in Java [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 9 years ago.
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I've just started working with some programming in java. I'm experimenting with loops and I have a problem with a for-loop where I'm having a hard time finding the mistake. Its saying that "i" is not a variable, even though i made it one in just above. Hope you guys can help!
import java.util.Scanner;
public class Loops {
public static void main(String [] args)
{
Scanner sc = new Scanner(System.in);
System.out.println("Skriv et tal");
int a = sc.nextInt();
for(int i = 0; i <= 9; i++);
{
System.out.println(a + i);
}
}
}
for(int i=0; i<=9;i++);
// ^ get rid of this
should be
for(int i=0; i<=9;i++)
Because of that the for statement ends there and the new block had been started there.
Beware of the ; behind your loop definition. It is an empty statement.

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