For statement solution [closed] - java

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I'm just really confused on why there's an error at the for statement line. This is literally code from a tutorial that I can't run because there's an error at line 3
class RoundOne{
public static void main(String[] args){
for(int i =0,i<10,i++){
System.out.println("The number is: "+i);
}
}
}

for(int i =0;i<10;i++){
System.out.println("The number is: "+i);
}
You wrote , instead of ;

In your for loop instead of
for(int i =0,i<10,i++)
write
for(int i =0;i<10;i++)

For loops use ; between the parts, not ,
class RoundOne {
public static void main(String[] args) {
for (int i = 0; i < 10; i++) {
System.out.println("The number is: " + i);
}
}
}

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It is not going inside the first loop and only printing I am outside loop only [closed]

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Closed 2 years ago.
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The below code is not giving any error. After debugging i found it is not going inside the first loop.
package string_pattern;
public class Naive {
public static void main(String[] args)
{
String pattern="This is a text book";
String text="text";
child obj=new child();
obj.search(pattern, text);
}
}
class child{
public void search(String pat,String text)
{
int m,n;
m=pat.length();
n=text.length();
System.out.println("i am outside loop");
for(int i=0; i<= (n-m); i++)
{
int j;
System.out.println("i am inside first loop");
for(j=0;j<m;j++)
{
if(text.charAt(i+j) != pat.charAt(j))
{
System.out.println("OVER HERE");
break;
}
if(j==m)
System.out.println("pattern found at pos" + i);
}
}
}
}
You do the following:
m=pat.length();
n=text.length();
The problem is that text has a length of 4, while pat is longer. So when you do the loop like this -> for(int i=0; i<= (n-m); i++), you end up with a negative number. Since 0 is greater than any negative number you never enter the loop.

Why am I getting an Array out of bounds error? [closed]

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Closed 4 years ago.
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I can not figure out why my code won't let me remove a value from my list. I am suppose to make the list have 10 values in it, and then when I want to take a value out and replace it I use remove() and then add(). My error says this:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 9
at MyList.remove(MyList.java:36)
at MyListDriver.main(MyListDriver.java:17)
Here is my code for those sections:
public class MyListDriver{
public static void main(String[] args){
MyList alpha = new MyList(9);
alpha.add("22");
alpha.add("2");
alpha.add("1");
alpha.add("22");
alpha.add("13");
alpha.add("6");
alpha.add("7");
alpha.add("32");
alpha.add("172");
alpha.add("2");
alpha.remove("12");
alpha.add("23");
alpha.print();
}
}
And the section from the MyList that is the remove(), which is where I am getting an error.
public void remove(String data){
int index = 0;
for(int r = 0; r <=arr.length; r++)
{
if(arr[r].equals(data)){
index=r;
break;
}
}
remove(index);
}
public void remove(int index){
if(index>=0 && index<loc){
for(int i=index; i<loc-1; i++){
arr[index]=arr[index+1];
}
loc--;
}
}
I am suppose to have an overloaded remove method. I dont know why I am getting an Array out of bounds error.
Thank you for any help in advance.
I know U got The Answer
for(int r = 0; r <=arr.length; r++)
{
if(arr[r].equals(data)){
index=r;
break;
}
}
why u getting ArrayIndexOutOfBoundsException
because of when r=arr.lenght for Ex. array lenght is 3 means 0 1 2
when r=3 the condition retunrn true because 3<=3 so change it
for(int r = 0; r < arr.length; r++)
{
if(arr[r].equals(data)){
index=r;
break;
}
}

Wierd String error, please be gracious, new to java [closed]

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Closed 7 years ago.
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So my problem is that it keeps saying I already defined String spaces up top but if I take the definition that's outside of the loop away and try to define spaces only in the loop, it tells me it hasn't been instantiated...
public class NestedLoop {
public static void main (String [] args) {
int userNum = 0;
int i = 0;
int j = 1;
String spaces = "";
Scanner scnr = new Scanner(System.in);
System.out.print("Enter userNum:");
userNum = scnr.nextInt();
for (i = 0; i <= userNum; i++) {
while (j == i){
spaces = spaces.concat(" ");
System.out.print(spaces);
j++;}
System.out.println(i);}
Error: main.java:244: spaces is already defined in main(java.lang.String[])
I just ran this code in my IDE and got no errors, compile time or run time. Not sure I can replicate the errors you're reporting. Only possibility I could think of is an error with your JDK, but at the same time I dunno how or why that would occur.

Problems with displaying multi array [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
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I want to display multi arrays.
public class apples {
public static void main(String[] args){
int Tabela_Nr1[][] = {{8,9,10,11}, {12,13,14,15}};
int Tabela_Nr2[][] = {{30,31,32,33}, {43},{4,5,6,}};
System.out.println("To jest pierwsza tabela: ");
wyswietl(Tabela_Nr1);
System.out.println("To jest druga tabela: ");
wyswietl(Tabela_Nr2);
}
public static void wyswietl(int x [][]){
for (int row = 0; row < x.length; row++){
for(int counter = 0; counter < x[row].length; counter++);
System.out.print(x[row][counter] + "\t");
}
System.out.println();
}
}
Debugger tells me that variable counter is not declare, but it is in "for" loop...
What is the cuz of the problem ?
Console:
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
counter cannot be resolved to a variable
at apples.wyswietl(apples.java:15)
at apples.main(apples.java:8)
The problem is the extra semi colon :
for (int row=0;row<x.length;row++){
for(int counter=0;counter<x[row].length;counter++); //<-- here
System.out.print(x[row][counter]+"\t");
This semi colon end the inner loop, which means the print statement is outside the loop, where counter is unknown.
I think that your System.out.println(); is also wrongly placed. You probably want to place it after each row :
public static void wyswietl(int x[][]){
for (int row=0;row<x.length;row++) {
for(int counter=0;counter<x[row].length;counter++) {
System.out.print(x[row][counter]+"\t");
}
System.out.println();
}
}
for(int counter=0;counter<x[row].length;counter++); --> remove the ; and it will work just fine :)
BTW you might also want to look into --> Arrays.deepToString() which displays multi-dimensional arrays.

Variable not found in Java [closed]

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Closed 9 years ago.
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I've just started working with some programming in java. I'm experimenting with loops and I have a problem with a for-loop where I'm having a hard time finding the mistake. Its saying that "i" is not a variable, even though i made it one in just above. Hope you guys can help!
import java.util.Scanner;
public class Loops {
public static void main(String [] args)
{
Scanner sc = new Scanner(System.in);
System.out.println("Skriv et tal");
int a = sc.nextInt();
for(int i = 0; i <= 9; i++);
{
System.out.println(a + i);
}
}
}
for(int i=0; i<=9;i++);
// ^ get rid of this
should be
for(int i=0; i<=9;i++)
Because of that the for statement ends there and the new block had been started there.
Beware of the ; behind your loop definition. It is an empty statement.

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