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It is not going inside the first loop and only printing I am outside loop only [closed]

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Closed 2 years ago.
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The below code is not giving any error. After debugging i found it is not going inside the first loop.
package string_pattern;
public class Naive {
public static void main(String[] args)
{
String pattern="This is a text book";
String text="text";
child obj=new child();
obj.search(pattern, text);
}
}
class child{
public void search(String pat,String text)
{
int m,n;
m=pat.length();
n=text.length();
System.out.println("i am outside loop");
for(int i=0; i<= (n-m); i++)
{
int j;
System.out.println("i am inside first loop");
for(j=0;j<m;j++)
{
if(text.charAt(i+j) != pat.charAt(j))
{
System.out.println("OVER HERE");
break;
}
if(j==m)
System.out.println("pattern found at pos" + i);
}
}
}
}

You do the following:
m=pat.length();
n=text.length();
The problem is that text has a length of 4, while pat is longer. So when you do the loop like this -> for(int i=0; i<= (n-m); i++), you end up with a negative number. Since 0 is greater than any negative number you never enter the loop.

ArrayIndexOutOfBoundsException in INTELIJ [closed]

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Closed 3 years ago.
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I just started learning java, and I created a support code (called HELP) to help me track some variables in another code im writing. But when I try to run HELP I get this exception in return, can someone help me?
Im using INTELIJ
public static void main(String [] args){
int a = Integer.parseInt(args[0]);
int b = Integer.parseInt(args[1]);
int T = Integer.parseInt(args[2]);
for (int i = 0; i < T; i++) {
//bob vê a carta
int see;
int unseen;
if (Math.random() > .5) {
see = a;
} else see = b;
System.out.println(see);
}
}
the output is:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: Index 0 out of bounds for length 0
at HELP.main(HELP.java:4)

You aren't specifying any arguments when you run the program so args[0], args[1], args[2] isn't a valid index.
In one old post founded this
// to use 10 when there aren't args...
int trials = (args.length > 0) ? Integer.parseInt(args[0]) : 10;

Bubble sort sorts weirdly [closed]

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Closed 4 years ago.
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I just tried coding my first sorting algorithm aand it does weird things. I dont actually know, where this comes from but i think it has to do something with array length. because the first numbers always equal array length. Here i put the simple code i wrote in hopes, that somebody helps me debug it. Thank you very much in advance!!
public class BubbleSort {
private static void sort(int[] pole) {
for (int i = 0; i < pole.length; i++) {
for (int j = 1; j < pole.length - i; j++) {
if (pole[j-1] > pole[j]) {
int tm = pole[j-1];
pole[j-1] = j;
pole[j] = tm;
}
}
}
}
public static void main(String[] args) {
int[] pole = { 65, 210, 41, 23, 3, 2, 4, 78 };
System.out.println("before: " + Arrays.toString(pole));
sort(pole);
System.out.println("after: " + Arrays.toString(pole));
}
}

You have an error in your if check. You're assigning the index of a value rather than the value itself - pole[j-1] = j;. So, you should correct it to:
...
if(pole[j-1] > pole[j]) {
tm = pole[j-1];
//assign the value here
pole[j-1] = pole[j];
pole[j] = tm;
}
...

For statement solution [closed]

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Closed 6 years ago.
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I'm just really confused on why there's an error at the for statement line. This is literally code from a tutorial that I can't run because there's an error at line 3
class RoundOne{
public static void main(String[] args){
for(int i =0,i<10,i++){
System.out.println("The number is: "+i);
}
}
}

for(int i =0;i<10;i++){
System.out.println("The number is: "+i);
}
You wrote , instead of ;

In your for loop instead of
for(int i =0,i<10,i++)
write
for(int i =0;i<10;i++)

For loops use ; between the parts, not ,
class RoundOne {
public static void main(String[] args) {
for (int i = 0; i < 10; i++) {
System.out.println("The number is: " + i);
}
}
}

Problems with displaying multi array [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
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I want to display multi arrays.
public class apples {
public static void main(String[] args){
int Tabela_Nr1[][] = {{8,9,10,11}, {12,13,14,15}};
int Tabela_Nr2[][] = {{30,31,32,33}, {43},{4,5,6,}};
System.out.println("To jest pierwsza tabela: ");
wyswietl(Tabela_Nr1);
System.out.println("To jest druga tabela: ");
wyswietl(Tabela_Nr2);
}
public static void wyswietl(int x [][]){
for (int row = 0; row < x.length; row++){
for(int counter = 0; counter < x[row].length; counter++);
System.out.print(x[row][counter] + "\t");
}
System.out.println();
}
}
Debugger tells me that variable counter is not declare, but it is in "for" loop...
What is the cuz of the problem ?
Console:
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
counter cannot be resolved to a variable
at apples.wyswietl(apples.java:15)
at apples.main(apples.java:8)

The problem is the extra semi colon :
for (int row=0;row<x.length;row++){
for(int counter=0;counter<x[row].length;counter++); //<-- here
System.out.print(x[row][counter]+"\t");
This semi colon end the inner loop, which means the print statement is outside the loop, where counter is unknown.
I think that your System.out.println(); is also wrongly placed. You probably want to place it after each row :
public static void wyswietl(int x[][]){
for (int row=0;row<x.length;row++) {
for(int counter=0;counter<x[row].length;counter++) {
System.out.print(x[row][counter]+"\t");
}
System.out.println();
}
}

for(int counter=0;counter<x[row].length;counter++); --> remove the ; and it will work just fine :)
BTW you might also want to look into --> Arrays.deepToString() which displays multi-dimensional arrays.