Develop Reference

Amazon Merchant Fulfilment Create Shipment Label

I am trying to get the shipment label from amazon merchant fulfillment as per the instructions mentioned on the Amazon pages.
"To obtain the actual PDF document, you must decode the Base64-encoded string, save it as a binary file with a “.zip” extension, and then extract the PDF file from the ZIP file."
Has any one got it to work. I have tried couple of things but every time i get blank pdf.
Here is my code. Can please some body guide me if I am doing it correctly
byte[] decodedBytes = Base64.decodeBase64(contents);
ZipOutputStream zos = new ZipOutputStream(new BufferedOutputStream(new FileOutputStream("c:\\output\\asdwd.zip")));
//now create the entry in zip file
ZipEntry entry = new ZipEntry("asd.pdf");
zos.putNextEntry(entry);
zos.write(decodedBytes);
zos.close();

The instructions say to save the bytes as a binary file with the extension .zip.
What you are actually doing is creating a ZIP file with the contents of the byte array as an entry.
According to my reading of the instructions, your code should do this:
byte[] decodedBytes = Base64.decodeBase64(contents);
FileOutputStream fos = new FileOutputStream("c:\\output\\asdwd.zip");
fos.write(decodedBytes);
fos.close();
Or better still:
byte[] decodedBytes = Base64.decodeBase64(contents);
try (FileOutputStream fos = new FileOutputStream("c:\\output\\asdwd.zip")) {
fos.write(decodedBytes);
}
Then using a ZIP tool or a web browser, open asdwd.zip, find the entry containing the PDF, and extract it or print it.

Here is the code to generate a shipping label in case somebody needs it.
byte[] decoded = Base64.decodeBase64(contents);
try (FileOutputStream fos = new FileOutputStream(zipFilePath + amazonOrderId + zipFileName)) {
fos.write(decoded);
fos.close();
}
file = new File(destDirectory + amazonOrderId + pngFile);
if (file.exists()) {
file.delete();
}
try (OutputStream out = new FileOutputStream(destDirectory + amazonOrderId + pngFile)) {
try (InputStream in = new GZIPInputStream(
new FileInputStream(zipFilePath + amazonOrderId + zipFileName))) {
byte[] buffer = new byte[65536];
int noRead;
while ((noRead = in.read(buffer)) != -1) {
out.write(buffer, 0, noRead);
}
}
}

How to convert a byte array to ZIP file and download it using Java?

I need to write a code to convert a byte array to ZIP file and make it download in Spring MVC.
Byte array is coming from a webservice which is a ZIP file originally. ZIP file has a folder and the folder contains 2 files. I have written the below code to convert to byte array to ZipInputStream. But I am not able to convert into ZIP file. Please help me in this.
Here is my code.
ZipInputStream zipStream = new ZipInputStream(new ByteArrayInputStream(bytes));
ZipEntry entry = null;
while ((entry = zipStream.getNextEntry()) != null) {
String entryName = entry.getName();
FileOutputStream out = new FileOutputStream(entryName);
byte[] byteBuff = new byte[4096];
int bytesRead = 0;
while ((bytesRead = zipStream.read(byteBuff)) != -1)
{
out.write(byteBuff, 0, bytesRead);
}
out.close();
zipStream.closeEntry();
}
zipStream.close();

I am presuming here that you want to write a byte array to a ZIP file. As the data sent is also a ZIP file and to be saved is also ZIP file, shouldn't be a problem.
Two steps are needed: save it on disk and return the file.
1) Save on disk part:
File file = new File(/path/to/directory/save.zip);
if (file.exists() && file.isDirectory()) {
try {
OutputStream outputStream = new FileOutputStream(new File(/path/to/directory/save.zip));
outputStream.write(bytes);
outputStream.close();
} catch (IOException ignored) {
}
} else {
// create directory and call same code
}
}
2) Now to get it back and download it, you need a controller :
#RequestMapping(value = "/download/attachment/", method = RequestMethod.GET)
public void getAttachmentFromDatabase(HttpServletResponse response) {
response.setContentType("application/octet-stream");
response.setHeader("Content-Disposition", "attachment; filename=\"" + file.getFileName() + "\"");
response.setContentLength(file.length);
FileCopyUtils.copy(file as byte-array, response.getOutputStream());
response.flushBuffer();
}
I have edited the code I have, so you will have to make some changes before it suits you 100%. Let me know if this is what you were looking for. If not, I will delete my answer. Enjoy.

SmbFileOutputStream write creating corrupted jpg files

I'm using JCIFS SmbFileOutputStream write to upload jpg (and mp4) files to a share on a local Windows network. While this works well most of the time, I sometimes find that the resulting files are corrupt - e.g. if it's a jpg perhaps only the top part of the photo will be legible/visible.
I have the upload in a try/catch block, but it is not throwing an exception. Is there any way that I can verify that a file has been uploaded correctly?
try {
if (debugging_on) {
logger.info("UploadService.011 UploadFiles: uploading file:" + destFileName);
}
SmbFileOutputStream sfos = new SmbFileOutputStream(sFile);
FileInputStream fileInputStream = new FileInputStream(new File(
sSourceFilePath));
byte[] buf = new byte[16 * 1024 * 1024];
int len;
while ((len = fileInputStream.read(buf)) > 0) {
sfos.write(buf, 0, len);
}
fileInputStream.close();
sfos.close();
// Update the database to include the date/time of this upload
millisStart = Calendar.getInstance().getTimeInMillis();
sql = "UPDATE upload_history SET file_uploaded_date = "
+ millisStart + " WHERE filename = '" + filename + "'";
db.execSQL(sql);
} catch (Exception e) {
mNotifyBuilder.setContentText("Upload error - check folder permissions");
mNotificationManager.notify(1, mNotifyBuilder.build());
return "WriteFailure";

sfos.close();
needs to go before
fileInputStream.close();
Close the output before you close the input,
Adding 'sfos.flush()' couldn't hurt.

How to download a dataset using java

I want to make an app that will download all the paper mentioned in the image by taking the domain as input. i have been able to download a single file from some other website but was unable to download a paper form acm digital library.
what i need to do is download the entire data set.
here is the code that i used to download a single file.
String fileName = "1.txt";
URL link = new URL("http://shayconcepts.com");
InputStream in = new BufferedInputStream(link.openStream());
ByteArrayOutputStream out = new ByteArrayOutputStream();
byte[] buf = new byte[2048];
int n = 0;
while (-1!=(n=in.read(buf)))
{
out.write(buf, 0, n);
}
out.close();
in.close();
byte[] response = out.toByteArray();
FileOutputStream fos = new FileOutputStream(fileName);
fos.write(response);
fos.close();
How can I modify it to download entire data set

is it possible to convert .swf file to base64 format in java

I am trying to load a .swf file in my page, i would like to make this load faster by converting it to Base64, rather providing a src. This is working great with image formats by using the below code
Java code
BufferedImage buffImg = ImageIO.read(new File(imagePath));
ImageIO.write(buffImg, imgExtension, bos);
byte[] imageBytes = bos.toByteArray();
BASE64Encoder encoder = new BASE64Encoder();
imageString = encoder.encode(imageBytes);
but this is not working for swf file. is there any possible way to achieve this.
Html
<object width="10" height="10" data="data:application/x-shockwave-flash;base64, RldTCSEAAABIAZAAZAAADAEARBEIAAAAQwIAAP9AAAAA"></object>
thanks in advance.

Trying to get the file in base64 will not speed up the file transfer, it's just the opposite as it will convert the file which is stored in bytes (base256 if it can be said that way) to base64 (64 printable characters), so the final amount of data you will be transfering is more.
The only "win" is that you might be able to load it as part of the page instead of the browser making another call for the swf file, which should be no issue on http 1.1.
Unless you have some other good reason to do this, I would not suggest this kind of practice.
If you have your swf file(s) in a database as a blob, you could just make a servlet which sets the proper contenttype and write the whole file with the ServletOutputStream, without any tags. In your html code, you would have to reference to the servlet instead of a fixed file.
If you still want to convert the file to base64, you shouldn't use some image API, but get the file in a standard way for binary files, here's a sample that should do the job:
http://www.javapractices.com/topic/TopicAction.do?Id=245
You can still do the encoding as you did it once you have a byte array:
File file = new File(imagePath);
log("File size: " + file.length());
byte[] result = null;
try {
InputStream input = new BufferedInputStream(new FileInputStream(file));
result = readAndClose(input);
}
catch (FileNotFoundException ex){
log(ex);
}
BASE64Encoder encoder = new BASE64Encoder();
imageString = encoder.encode(result);
And the readAndClose method:
byte[] readAndClose(InputStream aInput){
byte[] bucket = new byte[32*1024];
ByteArrayOutputStream result = null;
try {
try {
result = new ByteArrayOutputStream(bucket.length);
int bytesRead = 0;
while(bytesRead != -1){
bytesRead = aInput.read(bucket);
if(bytesRead > 0){
result.write(bucket, 0, bytesRead);
}
}
}
finally {
aInput.close();
}
}
catch (IOException ex){
log(ex);
}
return result.toByteArray();
}
This should do the trick, maybe some fine tunings to adapt the code to your specific situation, optimize it and better error handling...