I am trying to get the shipment label from amazon merchant fulfillment as per the instructions mentioned on the Amazon pages.
"To obtain the actual PDF document, you must decode the Base64-encoded string, save it as a binary file with a “.zip” extension, and then extract the PDF file from the ZIP file."
Has any one got it to work. I have tried couple of things but every time i get blank pdf.
Here is my code. Can please some body guide me if I am doing it correctly
byte[] decodedBytes = Base64.decodeBase64(contents);
ZipOutputStream zos = new ZipOutputStream(new BufferedOutputStream(new FileOutputStream("c:\\output\\asdwd.zip")));
//now create the entry in zip file
ZipEntry entry = new ZipEntry("asd.pdf");
zos.putNextEntry(entry);
zos.write(decodedBytes);
zos.close();
The instructions say to save the bytes as a binary file with the extension .zip.
What you are actually doing is creating a ZIP file with the contents of the byte array as an entry.
According to my reading of the instructions, your code should do this:
byte[] decodedBytes = Base64.decodeBase64(contents);
FileOutputStream fos = new FileOutputStream("c:\\output\\asdwd.zip");
fos.write(decodedBytes);
fos.close();
Or better still:
byte[] decodedBytes = Base64.decodeBase64(contents);
try (FileOutputStream fos = new FileOutputStream("c:\\output\\asdwd.zip")) {
fos.write(decodedBytes);
}
Then using a ZIP tool or a web browser, open asdwd.zip, find the entry containing the PDF, and extract it or print it.
Here is the code to generate a shipping label in case somebody needs it.
byte[] decoded = Base64.decodeBase64(contents);
try (FileOutputStream fos = new FileOutputStream(zipFilePath + amazonOrderId + zipFileName)) {
fos.write(decoded);
fos.close();
}
file = new File(destDirectory + amazonOrderId + pngFile);
if (file.exists()) {
file.delete();
}
try (OutputStream out = new FileOutputStream(destDirectory + amazonOrderId + pngFile)) {
try (InputStream in = new GZIPInputStream(
new FileInputStream(zipFilePath + amazonOrderId + zipFileName))) {
byte[] buffer = new byte[65536];
int noRead;
while ((noRead = in.read(buffer)) != -1) {
out.write(buffer, 0, noRead);
}
}
}
Related
i am currently creating a zip file and filling it with various json files and images. All this should only run in memory and not on the hard disk. Therefore I have the following construct so far:
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ZipOutputStream zip = null;
String FILE_NAME = "file.zip";
try {
zip = new ZipOutputStream(baos);
//now the critical part where the name of the file should be set
ZipEntry entry = new ZipEntry(FILE_NAME);
zip.putNextEntry(entry);
byte[] data = FILE_NAME.getBytes();
zip.write(data, 0, data.length);
zip.closeEntry();
//end of critical part and filling the rest of the zip
//...
//
}finally{
IOUtils.closeQuietly(zip);
byte[] byteFile = baos.toByteArray();
IOUtils.closeQuietly(baos);}
The problem is that the zip-file is called file.zip, but also contains a file.zip itself.
How can I name my Zip file from the ZipOutputStream without packing into this one file with the same name? Unfortunately I only found this solution here.
public byte[] zipBytesFile(List<byte[]> files) throws IOException {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ZipOutputStream zos = new ZipOutputStream(baos);
int i = 0;
for (byte[] file : files) {
ZipEntry entry = new ZipEntry(++i + ".pdf");
entry.setSize(file.length);
zos.putNextEntry(entry);
zos.write(file);
}
zos.closeEntry();
zos.close();
return baos.toByteArray();
}
I have a BLOB file which I have got from the DB team. I know that its a PDF document (I opened using Notepad++ and I could see the file name) and I need to convert the same using java. I have checked for few examples and I couldn't find any example where the BLOB file itself is taken as an input instead of taking directly from the DB (Resultset). Can anyone please give some pointers as to how I can accomplish this?
Thanks in advance!
I have tried below,
File file = new File("C:/Users/User1/Desktop/0LK54E33K1477e2MCEU25JV0G8MG418S007N45JU.BLOB0");
FileInputStream fis = new FileInputStream(file);
//System.out.println(file.exists() + "!!");
//InputStream in = resource.openStream();
ByteArrayOutputStream bos = new ByteArrayOutputStream();
byte[] buf = new byte[1024];
try {
for (int readNum; (readNum = fis.read(buf)) != -1;) {
bos.write(buf, 0, readNum); //no doubt here is 0
//Writes len bytes from the specified byte array starting at offset off to this byte array output stream.
System.out.println("read " + readNum + " bytes,");
}
} catch (IOException ex) {
//Logger.getLogger(genJpeg.class.getName()).log(Level.SEVERE, null, ex);
}
byte[] bytes = bos.toByteArray();
//below is the different part
File someFile = new File("C:/Users/User1/Desktop/Test.pdf");
FileOutputStream fos = new FileOutputStream(someFile);
fos.write(bytes);
fos.flush();
fos.close();
I have a method which takes a file and upload it on given path.
Here is my service
public String fileUpload(MultipartFile file) throws IOException {
log.debug("uploading video");
File fileUpload = new File(file.getOriginalFilename());
if (!file.isEmpty()) {
InputStream inputStream = file.getInputStream();
byte[] buf = new byte[1024];
FileOutputStream fileOutputStream = new FileOutputStream(new File(
fileUploadPath + File.separator
+ file.getOriginalFilename()));
int numRead = 0;
while ((numRead = inputStream.read(buf)) >= 0) {
fileOutputStream.write(buf, 0, numRead);
}
inputStream.close();
fileOutputStream.close();
}
else {
return Constants.EMPTY_FILE;
}
}
After uploading the file i have to save it information in my database.File size could be 1GB or 2GB.My problem is how would i know the file is fully uploaded or not.So that i can save it status uploaded successfully in my db.
Anyone please help me looking into this ?
You can create a MD5 hash before uploading the file. Take a look at this on creating MD5 hash with JavaScript via How to calculate md5 hash of a file using javascript.
And after the file is completely uploaded, you can use MessageDigest to create another MD5 hash to compare it again the one before the upload. (See example: http://javarevisited.blogspot.com/2013/06/how-to-generate-md5-checksum-for-files.html)
I need to write a code to convert a byte array to ZIP file and make it download in Spring MVC.
Byte array is coming from a webservice which is a ZIP file originally. ZIP file has a folder and the folder contains 2 files. I have written the below code to convert to byte array to ZipInputStream. But I am not able to convert into ZIP file. Please help me in this.
Here is my code.
ZipInputStream zipStream = new ZipInputStream(new ByteArrayInputStream(bytes));
ZipEntry entry = null;
while ((entry = zipStream.getNextEntry()) != null) {
String entryName = entry.getName();
FileOutputStream out = new FileOutputStream(entryName);
byte[] byteBuff = new byte[4096];
int bytesRead = 0;
while ((bytesRead = zipStream.read(byteBuff)) != -1)
{
out.write(byteBuff, 0, bytesRead);
}
out.close();
zipStream.closeEntry();
}
zipStream.close();
I am presuming here that you want to write a byte array to a ZIP file. As the data sent is also a ZIP file and to be saved is also ZIP file, shouldn't be a problem.
Two steps are needed: save it on disk and return the file.
1) Save on disk part:
File file = new File(/path/to/directory/save.zip);
if (file.exists() && file.isDirectory()) {
try {
OutputStream outputStream = new FileOutputStream(new File(/path/to/directory/save.zip));
outputStream.write(bytes);
outputStream.close();
} catch (IOException ignored) {
}
} else {
// create directory and call same code
}
}
2) Now to get it back and download it, you need a controller :
#RequestMapping(value = "/download/attachment/", method = RequestMethod.GET)
public void getAttachmentFromDatabase(HttpServletResponse response) {
response.setContentType("application/octet-stream");
response.setHeader("Content-Disposition", "attachment; filename=\"" + file.getFileName() + "\"");
response.setContentLength(file.length);
FileCopyUtils.copy(file as byte-array, response.getOutputStream());
response.flushBuffer();
}
I have edited the code I have, so you will have to make some changes before it suits you 100%. Let me know if this is what you were looking for. If not, I will delete my answer. Enjoy.
I want to make an app that will download all the paper mentioned in the image by taking the domain as input. i have been able to download a single file from some other website but was unable to download a paper form acm digital library.
what i need to do is download the entire data set.
here is the code that i used to download a single file.
String fileName = "1.txt";
URL link = new URL("http://shayconcepts.com");
InputStream in = new BufferedInputStream(link.openStream());
ByteArrayOutputStream out = new ByteArrayOutputStream();
byte[] buf = new byte[2048];
int n = 0;
while (-1!=(n=in.read(buf)))
{
out.write(buf, 0, n);
}
out.close();
in.close();
byte[] response = out.toByteArray();
FileOutputStream fos = new FileOutputStream(fileName);
fos.write(response);
fos.close();
How can I modify it to download entire data set