I have to create a method for getting webService response as xml. I know how to create with Java class but problem is getting response as xml from webService.
These webServices are soap based.
Thanks in advance.
I have just solve my problem. HttpURLConnection helps me.
The following code block show how I make poster for getting xml response in java like Mozilla Poster.
public static void main(String[] args) {
try {
String uri = "http://test.com/IntegratedServices/IntegratedServices.asmx?op=GetUserInfo";
String postData = new XmlTest().xmlRequest("QWERTY10");
URL url = new URL(uri);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true); // This is important. If you not set doOutput it is default value is false and throws java.net.ProtocolException: cannot write to a URLConnection exception
connection.setRequestMethod("POST"); // This is method type. If you are using GET method you can pass by url. If method post you must write
connection.setRequestProperty("Content-Type", "text/xml;charset=UTF-8"); // it is important if you post utf-8 characters
DataOutputStream wr = new DataOutputStream(connection.getOutputStream()); // This three lines is importy for POST method. I wrote preceding comment.
wr.write(postData.getBytes());
wr.close();
InputStream xml = connection.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(xml));
String line = "";
String xmlResponse = "";
while ((line = reader.readLine()) != null) {
xmlResponse += line;
}
File file = new File("D://test.xml"); // If you want to write as file to local.
FileWriter fileWriter = new FileWriter(file);
fileWriter.write(xmlResponse);
fileWriter.close();
} catch (Exception e) {
e.printStackTrace();
}
}
public String xmlRequest(String pin) {
return "<?xml version=\"1.0\" encoding=\"utf-8\"?>\n"
+ "<soap:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\">\n"
+ " <soap:Body>\n"
+ " <GetUserInfo xmlns=\"http://tempuri.org/\">\n"
+ " <pin>" + pin + "</pin>\n"
+ " </GetUserInfo>\n"
+ " </soap:Body>\n"
+ "</soap:Envelope>";
}
I hope this helps who want to get xml as response. Also I wrote detailed comment to my code.
For soap type webservice :
Parsing SOAP Response in Java
For rest look at this link:
http://duckranger.com/2011/06/jaxb-without-a-schema/
Related
I have code a java script to consume API response. But I am getting a bad request whenever I am trying to run it.
Kindly help me how to consume API through java.
Here I am trying to generate JWT token....
Please find the code below..
public static void main(String[] args) throws Exception {
URL url = new URL("URL");
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
connection.connect();
try {
String jsonData1 = "{\"grant_type\":\"aksa\"}";
String jsonData2 = "{\"username\":\"dkssdsk\"}";
String jsonData3 = "{\"password\":\"xE2w04kC1a7S\"}";
String jsonData4 = "{\"scope\":\"mksssl,/\"}";
DataOutputStream output = new DataOutputStream(connection.getOutputStream());
output.write(jsonData1.getBytes());
output.write(jsonData2.getBytes());
output.write(jsonData3.getBytes());
output.write(jsonData4.getBytes());``
output.flush();
System.out.println(output);
// Read the response:
BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));`enter code here`
String line;
while ((line = reader.readLine()) != null) {
System.out.println(line);
}
reader.close();
} catch (Exception e) {
System.out.println(e.getMessage());
}
System.out.println("Response code:" + connection.getResponseCode());
System.out.println("Response message:" + connection.getResponseMessage());
}
}
Your code writes:
{"grant_type":"aksa"}
{"username":"dkssdsk"}
{"password":"xE2w04kC1a7S"}
{"scope":"mksssl,/"}
This is not valid JSON. There are many JSON validators (including web pages you can copy/paste into) you could use to show this.
Test your service using a tool such as Postman. Once you have it working, ensure that your program writes the same content as the body configured in Postman.
I keep getting a "null" exception when I run this code. If I manually type the url string into my browser the php script posts "{query_result:SUCCESS}" indicating it worked, but when I try it via this code I just get the Exception e as "null". Can anyone help?
protected String signUp(String username) {
String link = "http://12.34.56.78/JSON_addUser.php";
String data = "";
BufferedReader bufferedReader;
String result = "";
String message;
try {
data += "?username=" + URLEncoder.encode(username, "UTF-8");
link += data;
URL url = new URL(link);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
bufferedReader = new BufferedReader(new InputStreamReader(con.getInputStream()));
result = bufferedReader.readLine();
return result;
} catch (Exception e) {
message = "Exception trying: " + link + " Got: " + e.getMessage() + result;
return message;
}
}
Pretty often servers block requests like this because they are automated without a "User Agent" header. You might want to behave like a "real" browser.
Also i see a content encoding issue here. The constructor from InputStreamReader uses the default encoding and this might not be the encoding from the server--it might crash from converting the bytes into chars.
The code below shows a method, downloadUrl(), that takes a String, "myurl," its parameter. There are only two possible urls that I ever send to it, and the behavior of the method is different for each.
when myurl = URL1, it uses a GET request and everything works fine.
when myurl = URL2, however, it uses a POST request, and the response from the php page indicates that the post parameters sent with the request were empty. You can see the line where I set the POST params, so I don't understand why it's sending no params?!
Thanks for any help!
-Adam.
private String downloadUrl(String myurl) throws IOException {
InputStream is = null;
String response = "";
try {
URL urlObject = new URL(myurl);
HttpURLConnection conn = (HttpURLConnection) urlObject.openConnection();
// find out if there's a way to incorporate these timeouts into the progress bar
// and what they mean for shitty network situations
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setDoInput(true);
// INSERTED QUICK CHECK TO SEE WHICH URL WE ARE LOADING FROM
// it's important because one is GET, and one is POST
if (myurl.equals(url2)){
Log.i(TAG, "dlurl() in async recognizes we are doing pre-call");
conn.setRequestMethod("POST");
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
String postParams = "?phone=" + phone;
writer.write(postParams);
Log.i(TAG, "we're adding " + postParams + "to " + urlObject);
writer.flush();
writer.close();
os.close();
}
else {
conn.setRequestMethod("GET");
conn.connect();
}
// Starts the query
int responseCode = conn.getResponseCode();
Log.i(TAG, "from " + myurl + ", The response code from SERVER is: " + responseCode);
is = conn.getInputStream();
// Convert the InputStream into a string
// i guess we look up how to do this
if (responseCode == HttpsURLConnection.HTTP_OK) {
String line;
BufferedReader br = new BufferedReader(new InputStreamReader(is));
while ((line = br.readLine()) != null) {
response += line;
}
} else {
response = "from downloadUrl, php page response was not OK: " + responseCode;
}
// it's good to close these things?
is.close();
conn.disconnect();
Log.i(TAG, "response is " + response);
return response;
// Makes sure that the InputStream is closed after the app is
// finished using it.
} finally {
if (is != null) {
is.close();
}
}
}
try with following code block to send parameters of the POST request.
Map<String,String> params = new LinkedHashMap<>();
params.put("phone", "phone");
StringBuilder postPraamString = new StringBuilder();
for (Map.Entry<String,Object> param : params.entrySet()) {
if (postPraamString.length() != 0) postPraamString.append('&');
postPraamString.append(URLEncoder.encode(param.getKey(), "UTF-8"));
postPraamString.append('=');
postPraamString.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8"));
}
byte[] postDataBytes = postData.toString().getBytes("UTF-8");
writer.write(postDataBytes);
So I figured out the root of the problem...
In the line:
String postParams = "?phone=" + phone;
The problem was that leading question mark. The question mark should only be used in GET requests.
I am tiring to execute some of my project URLs through JAVA APIs. But some of them contain JSON values. Its not accepting the JSON I am providing.
If I hit same URL through browser it executes. I am not getting what is going wrong. Are the " " specified not accepted ?
URL = http://admin.biin.net:8289/project.do?cmd=AddProject&mode=default&projectFieldValueJSON={"fieldIds":[{"id":1360,"value":"project SS33"},{"id":1362,"value":"12/03/2015"},{"id":1363,"value":"12/31/2015"}],"state":1}&jsessionid=AE5B03C9791D1019DCD7BBF0E34CCFEE
The Code is as follows
String requestString = "http://admin.biin.net:8289 /project.do?cmd=AddProject&mode=default&projectJSON={"fieldIds":[{"id":1360,"value":"project SS33"},{"id":1362,"value":"12/03/2015"},{"id":1363,"value":"12/31/2015"}],"state":1}&jsessionid=AE5B03C9791D1019DCD7BBF0E34CCFEE"
URL url = new URL(requestString);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true);
conn.connect();
InputStream in = conn.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuffer responseString = new StringBuffer();
String line = null;
while ((line = reader.readLine()) != null) {
responseString.append(line);
}
Error :
java.io.IOException: Server returned HTTP response code: 505 for URL: http://admin.biin.net:8289/project.do?cmd=AddProject&mode=default&projectJSON={"fieldIds":[{"id":1360,"value":"project SS33"},{"id":1362,"value":"12/03/2015"},{"id":1363,"value":"12/31/2015"}],"state":1}&jsessionid=AE5B03C9791D1019DCD7BBF0E34CCFEE
If I remove the JSON the URL executes.
Don't pass json in QueryString. Since you are using HTTP POST. You should send the sensitive data in the HTTP body. Like this
String str = "some string goes here";
byte[] outputInBytes = str.getBytes("UTF-8");
OutputStream os = conn.getOutputStream();
os.write( outputInBytes );
os.close();
For your current problem. Encode the json value before passing it in url.
Try this:
try {
String s = "http://admin.biin.net:8289/project.do?cmd=AddProject&mode=default&projectFieldValueJSON="
+ URLEncoder.encode("{\"fieldIds\":[{\"id\":1360,\"value\":\"project SS33\"},{\"id\":1362,\"value\":\"12/03/2015\"},{\"id\":1363,\"value\":\"12/31/2015\"}],\"state\":1}", "UTF-8")
+ "&jsessionid=AE5B03C9791D1019DCD7BBF0E34CCFEE";
System.out.println(s);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
Result: http://admin.biin.net:8289/project.do?cmd=AddProject&mode=default&projectFieldValueJSON=%7B%22fieldIds%22%3A%5B%7B%22id%22%3A1360%2C%22value%22%3A%22project+SS33%22%7D%2C%7B%22id%22%3A1362%2C%22value%22%3A%2212%2F03%2F2015%22%7D%2C%7B%22id%22%3A1363%2C%22value%22%3A%2212%2F31%2F2015%22%7D%5D%2C%22state%22%3A1%7D&jsessionid=AE5B03C9791D1019DCD7BBF0E34CCFEE
I want to send some information from PHP to Java. Why? Because I have a database on my server, and I get information from my database using PHP scripts.
Now I want to send that information to my client in Java. How can I do that?
I send information from Java to PHP by POST, and it works well, but I don't know how can I do the reverse.
Can you help me?
I saw this code, from a GET connection in Java... is it correct?
public String HttpClientTutorial(){
String url = "http://testes.neoscopio.com/myrepo/send.php";
InputStream content = null;
try {
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = httpclient.execute(new HttpGet(url));
content = response.getEntity().getContent();
} catch (Exception e) {
Log.e("[GET REQUEST]", "Network exception", e);
}
String response = content.toString();
return response;
}
P.S: I'm an android developer, not a Java developer...
From exampledepot: Sending POST request (Modified to get the output of your send.php.)
try {
// Construct data
String data = URLEncoder.encode("key1", "UTF-8") + "=" + URLEncoder.encode("value1", "UTF-8");
data += "&" + URLEncoder.encode("key2", "UTF-8") + "=" + URLEncoder.encode("value2", "UTF-8");
// Send data
URL url = new URL("http://testes.neoscopio.com/myrepo/send.php");
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(data);
wr.flush();
// Get the response
BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
// Process line...
}
wr.close();
rd.close();
} catch (Exception e) {
}
P.S. This should work fine on Android. :)
(I usually import static java.net.URLEncoder.encode but that's a matter of taste.)