Develop Reference

flac audio file to text file java program

I have code that can convert .wav to text file. But I want to convert .flac to text also. it seems like AudioInputStream doesn't support .flac type . What modification should I do in mycode so that it can convert .flac files to text? Here is the full code. I'm adding this line because stack overflow is asking me to do so.
import java.io.File;
import javax.sound.sampled.*;
public class AudioFileConvert01 {
public static void main(String[] args) {
if (args.length != 2) {
System.out.println("Usage: java AudioFileConvert01 " + "inputFile outputFile");
System.exit(0);
}
System.out.println("Input file: " + args[0]);
System.out.println("Output file: " + args[1]);
// Output file type depends on outputfile name extension.
String outputTypeStr = args[1].substring(args[1].lastIndexOf(".") + 1);
System.out.println("Output type: " + outputTypeStr);
AudioFileFormat.Type outputType = getTargetType(outputTypeStr);
if (outputType != null) {
System.out.println("Output type is supported");
} else {
System.out.println("Output type not supported.");
getTargetTypesSupported();
System.exit(0);
}
// Note that input file type does not depend on file name or extension.
File inputFileObj = new File(args[0]);
AudioInputStream audioInputStream = null;
try {
audioInputStream = AudioSystem.getAudioInputStream(inputFileObj);
} catch (Exception e) {
e.printStackTrace();
System.exit(0);
} // end catch
System.out.println("Input file format:");
showFileType(inputFileObj);
int bytesWritten = 0;
try {
bytesWritten = AudioSystem.write(audioInputStream, outputType, new File(args[1]));
} catch (Exception e) {
e.printStackTrace();
System.exit(0);
}
System.out.println("Bytes written: " + bytesWritten);
System.out.println("Output file format:");
showFileType(new File(args[1]));
}
private static void getTargetTypesSupported() {
AudioFileFormat.Type[] typesSupported = AudioSystem.getAudioFileTypes();
System.out.print("Supported audio file types:");
for (int i = 0; i < typesSupported.length; i++) {
System.out.print(" " + typesSupported[i].getExtension());
}
// for
// loop
System.out.println();
}
private static AudioFileFormat.Type getTargetType(String extension) {
AudioFileFormat.Type[] typesSupported = AudioSystem.getAudioFileTypes();
for (int i = 0; i < typesSupported.length; i++) {
if (typesSupported[i].getExtension().equals(extension)) {
return typesSupported[i];
}
}
return null;// no match
}
private static void showFileType(File file) {
try {
System.out.println(AudioSystem.getAudioFileFormat(file));
} catch (Exception e) {
e.printStackTrace();
System.exit(0);
}
}
}

Java File.renamTo not working

I have made the code which renames all the jpg files in a directory from 1 to n (number of files)..
if there were let say 50 jpg files that after running the program all the files are renamed to 1.jpg ,2.jpg and so on till 50.jpg
But i am facing the problem if I manually rename the file let say 50.jpg to aaa.jpg then again running the program doesn't rename that file
I have wasted one day to resove that issue
Kindly help me
Code:
public class Renaming {
private static String path; // string for storing the path
public static void main(String[] args) {
FileReader fileReader = null; // filereader for opening the file
BufferedReader bufferedReader = null; // buffered reader for buffering the data of file
try{
fileReader = new FileReader("input.txt"); // making the filereader object and paasing the file name
bufferedReader = new BufferedReader(fileReader); //making the buffered Reader object
path=bufferedReader.readLine();
fileReader.close();
bufferedReader.close();
}
catch (FileNotFoundException e) { // Exception when file is not found
e.printStackTrace();
}
catch (IOException e) { // IOException
e.printStackTrace();
}
finally {
File directory=new File(path);
File[] files= directory.listFiles(); // Storing the all the files in Array
int file_counter=1;
for(int file_no=0;file_no<files.length;file_no++){
String Extension=getFileExtension(files[file_no]); //getting the filw extension
if (files[file_no].isFile() && (Extension .equals("jpg")|| Extension.equals("JPG"))){ // checking that if file is of jpg type then apply renaming // checking thaat if it is file
File new_file = new File(path+"\\"+files[file_no].getName()); //making the new file
new_file.renameTo(new File(path+"\\"+String.valueOf(file_no+1)+".jpg")); //Renaming the file
System.out.println(new_file.toString());
file_counter++; // incrementing the file counter
}
}
}
}
private static String getFileExtension(File file) { //utility function for getting the file extension
String name = file.getName();
try {
return name.substring(name.lastIndexOf(".") + 1); // gettingf the extension name after .
} catch (Exception e) {
return "";
}
}`

first of all, you should use the path separator / . It's work on Windows, Linux and Mac OS.
This is my version of your problem to rename all files into a folder provide. Hope this will help you. I use last JDK version to speed up and reduce the code.
public class App {
private String path = null;
public static int index = 1;
public App(String path){
if (Files.isDirectory(Paths.get( path ))) {
this.path = path;
}
}
public void rename() throws IOException{
if ( this.path != null){
Files.list(Paths.get( this.path ))
.forEach( f ->
{
String fileName = f.getFileName().toString();
String extension = fileName.replaceAll("^.*\\.([^.]+)$", "$1");
try {
Files.move( f ,Paths.get( this.path + "/" + App.index + "." + extension));
App.index++;
} catch (IOException e) {
e.printStackTrace();
}
}
);
}
}
public static void main(String[] args) throws IOException {
App app = new App("c:/Temp/");
app.rename();
}
}

zip4j zipping for files and folders in java

I wish to create a zip program in Java, which zip files and folders let say structure like this -
folder-one/
folder-one/one.txt
folder-one/two.mp3
folder-one/three.jpg
folder-two/
folder-two/four.doc
folder-two/five.rtf
folder-two/folder-three/
folder-two/folder-three/six.txt
I used zip4j open source, I have collected all the files (with absolute path) in one list then given it to zip but it is zipping files only as in my.zip -
one.txt
two.mp3
three.jpg
four.doc
five.rtf
six.txt
How can I preserve same structure on zipping and unzipping as it was on local earlier. Please suggest if any other open source can help me to zip/unzip in same structure files and folders like other windows zip programs.
Code is below --
public class CreateZipWithOutputStreams {
ArrayList filesToAdd = new ArrayList();
public void CreateZipWithOutputStreams(String sAbsolutePath) {
ZipOutputStream outputStream = null;
InputStream inputStream = null;
try {
ArrayList arrLocal = exploredFolder(sAbsolutePath);
outputStream = new ZipOutputStream(new FileOutputStream(new File("c:\\ZipTest\\CreateZipFileWithOutputStreams.zip")));
ZipParameters parameters = new ZipParameters();
parameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
parameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL);
parameters.setEncryptFiles(true);
parameters.setEncryptionMethod(Zip4jConstants.ENC_METHOD_AES);
parameters.setAesKeyStrength(Zip4jConstants.AES_STRENGTH_256);
parameters.setPassword("neelam");
for (int i = 0; i < arrLocal.size(); i++) {
File file = (File) arrLocal.get(i);
outputStream.putNextEntry(file, parameters);
if (file.isDirectory()) {
outputStream.closeEntry();
continue;
}
inputStream = new FileInputStream(file);
byte[] readBuff = new byte[4096];
int readLen = -1;
while ((readLen = inputStream.read(readBuff)) != -1) {
outputStream.write(readBuff, 0, readLen);
}
outputStream.closeEntry();
inputStream.close();
}
outputStream.finish();
} catch (Exception e) {
e.printStackTrace();
} finally {
if (outputStream != null) {
try {
outputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
if (inputStream != null) {
try {
inputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
public ArrayList exploredFolder(String sAbsolutePath) {
File[] sfiles;
File fsSelectedPath = new File(sAbsolutePath);
sfiles = fsSelectedPath.listFiles();
if (sfiles == null) {
return null;
}
for (int j = 0; j < sfiles.length; j++) {
File f = sfiles[j];
if (f.isDirectory() == true) {
exploredFolder(f.getAbsolutePath());
} else {
filesToAdd.add(f);
}
}
return filesToAdd;
}
public static void main(String[] args) {
new CreateZipWithOutputStreams().CreateZipWithOutputStreams("c:\\ZipTest");
}
}
Thanks!

Okay so first the code that is attached is supposed to work the way it is because the exploredFolder(String absolutePath) method is returning the "files to add" which in turn is being used by the CreateZipWithOutputStreams() method to create a single layered(flat) zip file.
What needs to be done is looping over the individual folders and keep adding them to the ZipOutputStream.
Please go through the link below and you will find the code snippet and detailed explaination.
Let me know if that helps!
http://www.java-forums.org/blogs/java-io/973-how-work-zip-files-java.html

Java: Iterate over HTML files in a directory

I'm taking HTML file and one XSLT file as input and generating HTML output but in my folder there are multiple HTML files and I've to take each of them as input and generate the corresponding output file while XSLT input file remains same every time. Currently in my code I'm repeating the code block every time to take the input HTML file. Instead of this I want to iterate over all the HTML files in the folder and take them as input file one by one to generate the output. In my current code file names are also fixed like part_1.html but it can vary and in that case this code won't work and this will create problem. Can anyone please help out in this matter:
Thanking you!
Current Java code (Sample for two files):
public void tranformation() {
// TODO Auto-generated method stub
transform1();
transform2();
}
public static void transform1(){
String inXML = "C:/SCORM_CP/part_1.html";
String inXSL = "C:/source/xslt/html_new.xsl";
String outTXT = "C:/SCORM_CP/part1_copy_copy.html";
String renamedFile = "C:/SCORM_CP/part_1.html";
File oldfile =new File(outTXT);
File newfile =new File(renamedFile);
HTML_Convert hc = new HTML_Convert();
try {
hc.transform(inXML,inXSL,outTXT);
} catch(TransformerConfigurationException e) {
System.err.println("Invalid factory configuration");
System.err.println(e);
} catch(TransformerException e) {
System.err.println("Error during transformation");
System.err.println(e);
}
try{
File file = new File(inXML);
if(file.delete()){
System.out.println(file.getName() + " is deleted!");
}else{
System.out.println("Delete operation is failed.");
}
}catch(Exception e){
e.printStackTrace();
}
if(oldfile.renameTo(newfile)){
System.out.println("Rename succesful");
}else{
System.out.println("Rename failed");
}
}
public static void transform2(){
String inXML = "C:/SCORM_CP/part_2.html";
String inXSL = "C:/source/xslt/html_new.xsl";
String outTXT = "C:/SCORM_CP/part2_copy_copy.html";
String renamedFile = "C:/SCORM_CP/part_2.html";
File oldfile =new File(outTXT);
File newfile =new File(renamedFile);
HTML_Convert hc = new HTML_Convert();
try {
hc.transform(inXML,inXSL,outTXT);
} catch(TransformerConfigurationException e) {
System.err.println("Invalid factory configuration");
System.err.println(e);
} catch(TransformerException e) {
System.err.println("Error during transformation");
System.err.println(e);
}
try{
File file = new File(inXML);
if(file.delete()){
System.out.println(file.getName() + " is deleted!");
}else{
System.out.println("Delete operation is failed.");
}
}catch(Exception e){
e.printStackTrace();
}
if(oldfile.renameTo(newfile)){
System.out.println("Rename succesful");
}else{
System.out.println("Rename failed");
}
}
public void transform(String inXML,String inXSL,String outTXT)
throws TransformerConfigurationException,
TransformerException {
TransformerFactory factory = TransformerFactory.newInstance();
StreamSource xslStream = new StreamSource(inXSL);
Transformer transformer = factory.newTransformer(xslStream);
transformer.setErrorListener(new MyErrorListener());
StreamSource in = new StreamSource(inXML);
StreamResult out = new StreamResult(outTXT);
transformer.transform(in,out);
System.out.println("The generated XML file is:" + outTXT);
}
}

File dir = new File("/path/to/dir");
File[] htmlFiles = dir.listFiles(new FilenameFilter() {
#Override
public boolean accept(File dir, String name) {
return name.endsWith(".html");
}
});
if (htmlFiles != null) for (File html: htmlFiles) {
...
}

You have to implement something like
public class Transformation {
public static void main (String[] args){
transformation(".", ".");
}
public static void transform(String inXML, String inXSL, String outTXT, String renamedFile){
System.out.println(inXML);
System.out.println(inXSL);
System.out.println(outTXT);
System.out.println(renamedFile);
}
public static void transformation(String inFolder, String outFolder){
File infolder = new File(inFolder);
File outfolder = new File(outFolder);
if (infolder.isDirectory() && outfolder.isDirectory()){
System.out.println("In " + infolder.getAbsolutePath());
System.out.println("Out " + outfolder.getAbsolutePath());
File[] listOfFiles = infolder.listFiles();
String outPath = outfolder.getAbsolutePath();
String inPath = infolder.getAbsolutePath();
for (File f: listOfFiles) {
if (f.isFile() ) {
System.out.println("File " + f.getName());
int indDot = f.getName().lastIndexOf(".");
String name = f.getName().substring(0, indDot);
String ext = f.getName().substring(indDot+1);
if (ext != null && ext.equals("html")){
transform(f.getAbsolutePath(), inPath+File.separator+name+".xsl", outPath+File.separator+name+".txt", outPath+File.separator+name+".html");
}
}
}
}
}
}

First you should write a method that take inXML, inXSL, outTXT and renamedFile as arguments.
Then, using the list() method of the File class, that eventually take a FilenameFilter, you may iterate over the files you want to transform.
Here is a sample of FilenameFilter :
FilenameFilter filter = new FilenameFilter() {
public boolean accept(File dir, String name) {
return name.contains("part");
}
};
Regards

use DirectoryScanner which will make your job easier
Example of usage:
String[] includes = {"**\*.html"};
ds.setIncludes(includes);
ds.setBasedir(new File("test"));
ds.setCaseSensitive(true);
ds.scan();
System.out.println("FILES:");
String[] files = ds.getIncludedFiles();
for (int i = 0; i < files.length; i++) {
System.out.println(files[i]);
}
http://plexus.codehaus.org/plexus-utils/apidocs/org/codehaus/plexus/util/DirectoryScanner.html

Combining audio files

I recorded some audio files, stored them in sdcard. I need to combine all the recorded files into a single audiofile. I used the following code. My problem is the combined file contains only the first recorded file. Any suggestions...In readAudioAsStream() method i tried to combine the files.
public void readAudioAsStream() {
getFullAudioPath()
File f;
FileInputStream ins = null;
try
{
String comfile=getCombineFile();
//FileOutputStream fos=new FileOutputStream(comfile);
Log.d("combined file",comfile);
File file=new File(comfile);
RandomAccessFile raf = new RandomAccessFile(file, "rw");
Log.d("path size",Integer.toString(audFullPath.size()));
for (int i=0;i<audFullPath.size();i++)
{
String filepath=audFullPath.get(i);
Log.d("Filepath",filepath);
f=new File(audFullPath.get(i));
fileContent = new byte[(int)f.length()];
ins=new FileInputStream(audFullPath.get(i));
int numofbytes=ins.read(fileContent);
System.out.println("Number Of Bytes Read===========>>>"+numofbytes);
raf.seek(file.length());
raf.write(fileContent);
}
}
catch (FileNotFoundException e1) {
e1.printStackTrace();
}
catch (IOException e) {
e.printStackTrace();
}
}
public ArrayList<String> getFullAudioPath() {
ArrayList<String> fullPath=new ArrayList<String>();
fullPath.clear();
String path=filePath();
File f=new File(path);
if(f.isDirectory())
{
File[] files=f.listFiles();
for(int i=0;i<files.length;i++)
{
String fpath=path+File.separator+files[i].getName().toString().trim();
System.out.println("File Full Path======>>>"+fpath);
fullPath.add(fpath);
}
}
return fullPath;
}
public String filePath() {
String newFolderName="/MyAudio";
String extstoredir=Environment.getExternalStorageDirectory().toString();
String newPath=extstoredir+newFolderName;
return newPath;
}
public String getCombineFile() {
String newFolderName="/MyComAudio";
String extstoredir=Environment.getExternalStorageDirectory().toString();
String path=extstoredir+newFolderName;
File myNewPath=new File(path);
if(!myNewPath.exists()) {
myNewPath.mkdir();
}
String audname="ComAudio";
String ext=".3gp";
File audio=new File(myNewPath,audname+ext);
if(audio.exists()) {
audio.delete();
}
String audpath=path+"/"+audname+ext;
Log.d("Combined audio file",audpath);
return audpath;
}

You can't merge two .3gp files just by writing content of one .3gp file at the end of another .3gp file.