Get total hours and minutes from 10 values - java

I have list of decimal values like...
1.30
1.00
1.50
2.50
2.10
I want to calculate total hours and minutes from this list.
can you please help me how to do it ?
I want this in java.

May be this can help you :
public class TimeCalculator {
public static void main(String[] args) {
long sumOfMilliSeconds = 0;
double array[] = new double[] {
1.30, 1.00, 1.50, 2.50, 2.10
};
for (double d : array) {
sumOfMilliSeconds = sumOfMilliSeconds + convertToMilliSecounds(d);
}
convertDateformat(sumOfMilliSeconds);
}
public static void convertDateformat(long milliSeconds) {
Date date = new Date(milliSeconds);
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss");
sdf.setTimeZone(TimeZone.getTimeZone("GMT"));
System.out.println(sdf.format(date));
}
public static long convertToMilliSecounds(double taktTime) {
long timeInMilliSeconds = (long) (taktTime * 60 * 1000);
return timeInMilliSeconds;
}
}

Related

Implement Java method for test data [duplicate]

I'm trying to generate a random date of birth for people in my database using a Java program. How would I do this?
import java.util.GregorianCalendar;
public class RandomDateOfBirth {
public static void main(String[] args) {
GregorianCalendar gc = new GregorianCalendar();
int year = randBetween(1900, 2010);
gc.set(gc.YEAR, year);
int dayOfYear = randBetween(1, gc.getActualMaximum(gc.DAY_OF_YEAR));
gc.set(gc.DAY_OF_YEAR, dayOfYear);
System.out.println(gc.get(gc.YEAR) + "-" + (gc.get(gc.MONTH) + 1) + "-" + gc.get(gc.DAY_OF_MONTH));
}
public static int randBetween(int start, int end) {
return start + (int)Math.round(Math.random() * (end - start));
}
}
java.util.Date has a constructor that accepts milliseconds since The Epoch, and java.util.Random has a method that can give you a random number of milliseconds. You'll want to set a range for the random value depending on the range of DOBs that you want, but those should do it.
Very roughly:
Random rnd;
Date dt;
long ms;
// Get a new random instance, seeded from the clock
rnd = new Random();
// Get an Epoch value roughly between 1940 and 2010
// -946771200000L = January 1, 1940
// Add up to 70 years to it (using modulus on the next long)
ms = -946771200000L + (Math.abs(rnd.nextLong()) % (70L * 365 * 24 * 60 * 60 * 1000));
// Construct a date
dt = new Date(ms);
Snippet for a Java 8 based solution:
Random random = new Random();
int minDay = (int) LocalDate.of(1900, 1, 1).toEpochDay();
int maxDay = (int) LocalDate.of(2015, 1, 1).toEpochDay();
long randomDay = minDay + random.nextInt(maxDay - minDay);
LocalDate randomBirthDate = LocalDate.ofEpochDay(randomDay);
System.out.println(randomBirthDate);
Note: This generates a random date between 1Jan1900 (inclusive) and 1Jan2015 (exclusive).
Note: It is based on epoch days, i.e. days relative to 1Jan1970 (EPOCH) - positive meaning after EPOCH, negative meaning before EPOCH
You can also create a small utility class:
public class RandomDate {
private final LocalDate minDate;
private final LocalDate maxDate;
private final Random random;
public RandomDate(LocalDate minDate, LocalDate maxDate) {
this.minDate = minDate;
this.maxDate = maxDate;
this.random = new Random();
}
public LocalDate nextDate() {
int minDay = (int) minDate.toEpochDay();
int maxDay = (int) maxDate.toEpochDay();
long randomDay = minDay + random.nextInt(maxDay - minDay);
return LocalDate.ofEpochDay(randomDay);
}
#Override
public String toString() {
return "RandomDate{" +
"maxDate=" + maxDate +
", minDate=" + minDate +
'}';
}
}
and use it like this:
RandomDate rd = new RandomDate(LocalDate.of(1900, 1, 1), LocalDate.of(2010, 1, 1));
System.out.println(rd.nextDate());
System.out.println(rd.nextDate()); // birthdays ad infinitum
You need to define a random date, right?
A simple way of doing that is to generate a new Date object, using a long (time in milliseconds since 1st January, 1970) and substract a random long:
new Date(Math.abs(System.currentTimeMillis() - RandomUtils.nextLong()));
(RandomUtils is taken from Apache Commons Lang).
Of course, this is far to be a real random date (for example you will not get date before 1970), but I think it will be enough for your needs.
Otherwise, you can create your own date by using Calendar class:
int year = // generate a year between 1900 and 2010;
int dayOfYear = // generate a number between 1 and 365 (or 366 if you need to handle leap year);
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.YEAR, randomYear);
calendar.set(Calendar.DAY_OF_YEAR, dayOfYear);
Date randomDoB = calendar.getTime();
For Java8 -> Assumming the data of birth must be before current day:
import java.time.LocalDate;
import java.time.LocalTime;
import java.time.Period;
import java.time.temporal.ChronoUnit;
import java.util.Random;
public class RandomDate {
public static LocalDate randomBirthday() {
return LocalDate.now().minus(Period.ofDays((new Random().nextInt(365 * 70))));
}
public static void main(String[] args) {
System.out.println("randomDate: " + randomBirthday());
}
}
If you don't mind adding a new library to your code you can use MockNeat (disclaimer: I am one of the authors).
MockNeat mock = MockNeat.threadLocal();
// Generates a random date between [1970-1-1, NOW)
LocalDate localDate = mock.localDates().val();
System.out.println(localDate);
// Generates a random date in the past
// but beore 1987-1-30
LocalDate min = LocalDate.of(1987, 1, 30);
LocalDate past = mock.localDates().past(min).val();
System.out.println(past);
LocalDate max = LocalDate.of(2020, 1, 1);
LocalDate future = mock.localDates().future(max).val();
System.out.println(future);
// Generates a random date between 1989-1-1 and 1993-1-1
LocalDate start = LocalDate.of(1989, 1, 1);
LocalDate stop = LocalDate.of(1993, 1, 1);
LocalDate between = mock.localDates().between(start, stop).val();
System.out.println(between);
Generating random Date of Births:
import java.util.Calendar;
public class Main {
public static void main(String[] args) {
for (int i = 0; i < 100; i++) {
System.out.println(randomDOB());
}
}
public static String randomDOB() {
int yyyy = random(1900, 2013);
int mm = random(1, 12);
int dd = 0; // will set it later depending on year and month
switch(mm) {
case 2:
if (isLeapYear(yyyy)) {
dd = random(1, 29);
} else {
dd = random(1, 28);
}
break;
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
dd = random(1, 31);
break;
default:
dd = random(1, 30);
break;
}
String year = Integer.toString(yyyy);
String month = Integer.toString(mm);
String day = Integer.toString(dd);
if (mm < 10) {
month = "0" + mm;
}
if (dd < 10) {
day = "0" + dd;
}
return day + '/' + month + '/' + year;
}
public static int random(int lowerBound, int upperBound) {
return (lowerBound + (int) Math.round(Math.random()
* (upperBound - lowerBound)));
}
public static boolean isLeapYear(int year) {
Calendar calendar = Calendar.getInstance();
calendar.set(Calendar.YEAR, year);
int noOfDays = calendar.getActualMaximum(Calendar.DAY_OF_YEAR);
if (noOfDays > 365) {
return true;
}
return false;
}
}
You can checkout randomizer for random data generation.This library helps to create random data from given Model class.Checkout below example code.
public class Person {
#DateValue( from = "01 Jan 1990",to = "31 Dec 2002" , customFormat = "dd MMM yyyy")
String dateOfBirth;
}
//Generate random 100 Person(Model Class) object
Generator<Person> generator = new Generator<>(Person.class);
List<Person> persons = generator.generate(100);
As there are many built in data generator is accessible using annotation,You also can build custom data generator.I suggest you to go through documentation provided on library page.
Look this method:
public static Date dateRandom(int initialYear, int lastYear) {
if (initialYear > lastYear) {
int year = lastYear;
lastYear = initialYear;
initialYear = year;
}
Calendar cInitialYear = Calendar.getInstance();
cInitialYear.set(Calendar.YEAR, 2015);
long offset = cInitialYear.getTimeInMillis();
Calendar cLastYear = Calendar.getInstance();
cLastYear.set(Calendar.YEAR, 2016);
long end = cLastYear.getTimeInMillis();
long diff = end - offset + 1;
Timestamp timestamp = new Timestamp(offset + (long) (Math.random() * diff));
return new Date(timestamp.getTime());
}
I think this will do the trick:
public static void main(String[] args) {
Date now = new Date();
long sixMonthsAgo = (now.getTime() - 15552000000l);
long today = now.getTime();
for(int i=0; i<10; i++) {
long ms = ThreadLocalRandom.current().nextLong(sixMonthsAgo, today);
Date date = new Date(ms);
System.out.println(date.toString());
}
}
If you don't mind a 3rd party library, the Utils library has a RandomDateUtils that generates random java.util.Dates and all the dates, times, instants, and durations from Java 8's date and time API
LocalDate birthDate = RandomDateUtils.randomPastLocalDate();
LocalDate today = LocalDate.now();
LocalDate under18YearsOld = RandomDateUtils.randomLocalDate(today.minus(18, YEARS), today);
LocalDate over18YearsOld = RandomDateUtils.randomLocalDateBefore(today.minus(18, YEARS));
It is in the Maven Central Repository at:
<dependency>
<groupId>com.github.rkumsher</groupId>
<artifactId>utils</artifactId>
<version>1.3</version>
</dependency>
simplest method:
public static LocalDate randomDateOfBirth() {
final int maxAge = 100 * 12 * 31;
return LocalDate.now().minusDays(new Random().nextInt(maxAge));
}
Using the original answer and adapting it to the new java.time.* api and adding ways to generate n random dates -- the function will return a List.
// RandomBirthday.java
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.ThreadLocalRandom;
import java.time.LocalDate;
import java.time.format.DateTimeFormatter;
public class RandomBirthday {
public static List<String> getRandomBirthday(int groupSize, int minYear, int maxYear) {
/** Given a group size, this method will return `n` random birthday
* between 1922-2022 where `n=groupSize`.
*
* #param groupSize the number of random birthday to return
* #param minYear the min year [lower bound]
* #param maxYear the max year [upper bound]
* #return a list of random birthday with format YYYY-MM-DD
*/
ArrayList<String> birthdays = new ArrayList<>();
DateTimeFormatter dateFormat = DateTimeFormatter.ofPattern("yyyy-MM-dd");
for (int i = 0; i < groupSize; i++) {
LocalDate baseDate = LocalDate.now();
LocalDate baseYear = baseDate.withYear(ThreadLocalRandom.current().nextInt(minYear, maxYear));
int dayOfYear = ThreadLocalRandom.current().nextInt(1, baseYear.lengthOfYear());
LocalDate baseRandBirthday = baseYear.withDayOfYear(dayOfYear);
LocalDate randDate = LocalDate.of(
baseRandBirthday.getYear(),
baseRandBirthday.getMonth(),
baseRandBirthday.getDayOfMonth()
);
String formattedDate = dateFormat.format(randDate);
birthdays.add(formattedDate);
}
return birthdays;
}
public static void main(String[] args) {
// main method
List<String> bDay = getRandomBirthday(40, 1960, 2022);
System.out.println(bDay);
}
}
I am studying Scala and ended up Googling Java solutions for choosing a random date between range. I found this post super helpful and this is my final solution. Hope it can help future Scala and Java programmers.
import java.sql.Timestamp
def date_rand(ts_start_str:String = "2012-01-01 00:00:00", ts_end_str:String = "2015-01-01 00:00:00"): String = {
val ts_start = Timestamp.valueOf(ts_start_str).getTime()
val ts_end = Timestamp.valueOf(ts_end_str).getTime()
val diff = ts_end - ts_start
println(diff)
val ts_rand = new Timestamp(ts_start + (Random.nextFloat() * diff).toLong)
return ts_rand.toString
} //> date_rand: (ts_start_str: String, ts_end_str: String)String
println(date_rand()) //> 94694400000
//| 2012-10-28 18:21:13.216
println(date_rand("2001-01-01 00:00:00", "2001-01-01 00:00:00"))
//> 0
//| 2001-01-01 00:00:00.0
println(date_rand("2001-01-01 00:00:00", "2010-01-01 00:00:00"))
//> 283996800000
//| 2008-02-16 23:15:48.864 //> 2013-12-21 08:32:16.384
int num = 0;
char[] a={'a','b','c','d','e','f'};
String error = null;
try {
num = Integer.parseInt(request.getParameter("num"));
Random r = new Random();
long currentDate = new Date().getTime();
ArrayList<Student> list = new ArrayList<>();
for (int i = 0; i < num; i++) {
String name = "";
for (int j = 0; j < 6; j++) {
name += a[r.nextInt(5)];
}
list.add(new Student(i + 1, name, r.nextBoolean(), new Date(Math.abs(r.nextLong() % currentDate))));
}
request.setAttribute("list", list);
request.setAttribute("num", num);
request.getRequestDispatcher("student.jsp").forward(request, response);
} catch (NumberFormatException e) {
error = "Please enter interger number";
request.setAttribute("error", error);
request.getRequestDispatcher("student.jsp").forward(request, response);
}

Calculate Rate per hour based on Time

import java.text.SimpleDateFormat;
import java.util.Date;
public class Rate_Per_Hour {
public static void main(String[] args) {
String TimeStart = "09.30.00 am";
String TimeEnd= "10.10.00 am";
SimpleDateFormat format = new SimpleDateFormat("hh.mm.ss a");
int total=0;
Date d1 = null;
Date d2 = null;
try {
d1 = format.parse(TimeStart);
d2 = format.parse(TimeEnd);
long diff = d2.getTime() - d1.getTime();
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffMinutes = diff / (60 * 1000) % 60;
if (diffMinutes <= 30) {
total = 20;
}
else if (diffHours <=1){
total = 35;
}
System.out.println("Rs." +total);
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
I want output like this:
(Fixed rate per hour for this is Rs.35 )
For 30 min = Rs.20
For 40 min = Rs.25 and so on......
For 1 hour = Rs.35
For 1 hour 10 min = Rs.40
Please help me, figure out how I can do this.
Since the rate increases by 5 every 10 minutes, so just use a simple function to return the rate:
public double rate(int minutes)
{
return 20 + 5*((minutes - 30)/10);
}
Calculate the number of minutes and then pass it as an argument in that function to get the rate. Also, try to keep your code as short as possible but at the same time, simple.
if you need something more flexible rather than fixed rate you could implement an enum with predefined stops
you could define any rate you want for a given time.
for example if long running tasks shall gain higher rates (from your question it was not obvious to me if this rate shall be just the calculated value as in Manish Kundu's answer or if other values might get assigned.)
with this code you could assign higher rates for long running jobs (for example in computer games, jobs that are harder to achieve you return a higher rate or you lower the rate because the player took too much time...)
import java.time.LocalTime;
import java.time.format.DateTimeFormatter;
import java.time.temporal.ChronoUnit;
public class TimeMain {
private static final DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("hh.mm.ss[ ]a");
public enum Rate {
STOP0(0, 0, 0), // default
STOP1(0, 30, 20), // 30 mins -> Rs.20
STOP2(0, 40, 25), // 40 mins -> Rs.25
STOP3(1, 0, 35), // 1 hour -> Rs.35
STOP4(1, 10, 40); // 1 hour 10 minutes -> Rs.40
int minutes = 0;
int rate = 0;
/*
* hours is actually not needed as 1h10 = 70mins...
*/
private Rate(int hours, int minutes, int rate) {
this.minutes = minutes + hours * 60;
this.rate = rate;
}
public static Rate from(String timeStart, String timeEnd) {
LocalTime time1 = LocalTime.parse(timeStart.toUpperCase(), dateTimeFormatter);
LocalTime time2 = LocalTime.parse(timeEnd.toUpperCase(), dateTimeFormatter);
long minutesBetween = ChronoUnit.MINUTES.between(time1, time2);
for (int i = 0; i < Rate.values().length; i++) {
Rate r = Rate.values()[i];
if (r.minutes > minutesBetween) {
return Rate.values()[i-1];
}
}
return STOP0;
}
public String toString() {
return String.format("Rs.%s", rate);
}
}
public static void main(String... args) {
String timeStart = "09.30.00 am";
String timeEnd = "10.10.00 am";
System.out.println(Rate.from(timeStart, timeEnd));
}
}

Calculating time between datetimes

Let's say I have two datetimes, 30-11-2015 10:00 and 02-12-2015 15:00. I also have two times, 07:00 and 22:00. How could I calculate the amount of time passed between the two date/times that was within the second times? Using Calendar object? It seems simple but its boggling my mind.
Since none of the other answers include runnable code, I can't tell if they solve the problem or not.
To calculate the duration of a time range within a date range, you have to:
Split the date range into multiple date ranges, each spanning no more than one day.
Calculate the time range within each day date range
Taking the example date range from the question. 30-11-2015 10:00 and 02-12-2015 15:00, we generate the following split day date ranges:
30-11-2015 10:00 - 30-11-2015 24:00
01-12-2015 00:00 - 01-12-2015 24:00
02-12-2015 00:00 - 02-12-2015 15:00
Now, we can apply the time range of 7:00 - 22:00 to each of the split day date ranges.
30-11-2015 10:00 - 30-11-2015 24:00 -> 12 hours
01-12-2015 00:00 - 01-12-2015 24:00 -> 15 hours
02-12-2015 00:00 - 02-12-2015 15:00 -> 8 hours
For a total of 35 hours. The actual calculation would probably be in minutes instead of hours.
Edited to add: I created a Time and a TimeRange class to hold the time and a day time range, respectively. I used the java.util.Date, although I had to create my own increment a day method.
I put all of the classes together so I could post this easier. The classes should be put in separate files.
package com.ggl.testing;
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Date;
import java.util.List;
public class TimeRangeTest {
private static final SimpleDateFormat inputDateFormat = new SimpleDateFormat(
"dd-MM-yyyy");
public static void main(String[] args) {
TimeRangeTest test = new TimeRangeTest();
int minutes = test.calculateTotalMinutes("30-11-2015 10:00",
"02-12-2015 15:00", "07:00", "22:00");
System.out.println(minutes + " minutes, " + (minutes / 60) + " hours");
}
public int calculateTotalMinutes(String startDateTimeString,
String endDateTimeString, String startTimeString,
String endTimeString) {
try {
List<TimeRange> timeRanges = generateTimeRanges(
startDateTimeString, endDateTimeString);
return calculateTimeRange(timeRanges, startTimeString,
endTimeString);
} catch (ParseException e) {
e.printStackTrace();
return 0;
}
}
private List<TimeRange> generateTimeRanges(String startDateTimeString,
String endDateTimeString) throws ParseException {
Date startDate = inputDateFormat.parse(startDateTimeString.substring(0,
10));
Time startTime = new Time(startDateTimeString.substring(11));
Date endDate = inputDateFormat
.parse(endDateTimeString.substring(0, 10));
Time endTime = new Time(endDateTimeString.substring(11));
List<TimeRange> timeRanges = new ArrayList<>();
Date currentDate = new Date(startDate.getTime());
Time currentTime = new Time(startTime);
Time eodTime = new Time("24:00");
while (currentDate.compareTo(endDate) < 0) {
TimeRange timeRange = new TimeRange(currentDate, currentTime,
eodTime);
timeRanges.add(timeRange);
currentTime = new Time("00:00");
currentDate = new Date(currentDate.getTime() + 24L * 60L * 60L
* 1000L);
}
TimeRange timeRange = new TimeRange(currentDate, currentTime, endTime);
timeRanges.add(timeRange);
return timeRanges;
}
private int calculateTimeRange(List<TimeRange> timeRanges,
String startTimeString, String endTimeString) {
int count = 0;
Time startTime = new Time(startTimeString);
Time endTime = new Time(endTimeString);
for (TimeRange timeRange : timeRanges) {
Time sodTime = new Time(timeRange.getStartTime());
Time eodTime = new Time(timeRange.getEndTime());
Time sTime = startTime.max(sodTime);
Time eTime = endTime.min(eodTime);
count += eTime.difference(sTime);
}
return count;
}
public class TimeRange {
private final SimpleDateFormat inputDateFormat = new SimpleDateFormat(
"dd-MM-yyyy");
private final Date date;
private final Time startTime;
private final Time endTime;
public TimeRange(Date date, Time startTime, Time endTime) {
this.date = date;
this.startTime = startTime;
this.endTime = endTime;
}
public Date getDate() {
return date;
}
public Time getStartTime() {
return startTime;
}
public Time getEndTime() {
return endTime;
}
#Override
public String toString() {
return inputDateFormat.format(getDate()) + " "
+ startTime.toString() + " -> " + endTime.toString();
}
}
public class Time {
private final int minutesPastMidnight;
public Time(String timeString) {
int hours = Integer.valueOf(timeString.substring(0, 2));
int minutes = Integer.valueOf(timeString.substring(3, 5));
this.minutesPastMidnight = hours * 60 + minutes;
}
public Time(Time time) {
this.minutesPastMidnight = time.getMinutesPastMidnight();
}
private int getMinutesPastMidnight() {
return minutesPastMidnight;
}
public int difference(Time time) {
return this.getMinutesPastMidnight()
- time.getMinutesPastMidnight();
}
public Time min(Time time) {
return (difference(time) > 0) ? time : this;
}
public Time max(Time time) {
return (difference(time) > 0) ? this : time;
}
#Override
public String toString() {
int hours = minutesPastMidnight / 60;
int minutes = minutesPastMidnight - (hours * 60);
return String.format("%02d:%02d", hours, minutes);
}
}
}
If you use java8, you can use LocalDateTime. Then your code could looks like this:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm");
LocalDateTime dateTimeStart = LocalDateTime.parse("2015-10-01 10:00", formatter);
LocalDateTime dateTimeEnd = LocalDateTime.parse("2015-10-02 10:00", formatter);
long seconds = Duration.between(dateTimeStart, dateTimeEnd).getSeconds();
Or LocalTime if you have only time. Then it could looks like this:
LocalTime timeStart = LocalTime.parse("07:00");
LocalTime timeEnd = LocalTime.parse("22:00");
long seconds = Duration.between(timeStart, timeEnd).getSeconds();
If you can't use java8, you can get the number of milliseconds since 1970-01-01 00:00:00 to your date using getTime() method and do simple subtraction operation, like this:
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm");
Date dateStart = simpleDateFormat.parse("2015-10-01 10:00");
Date dateEnd = simpleDateFormat.parse("2015-10-02 10:00");
long milliseconds = dateEnd.getTime() - dateStart.getTime();
long seconds = resultInMillisecond / 1000;

Find the number of months and day between date range

I have a start date and end date in database like below.
start date:01/06/2014 end date:30/06/2014
start date:01/07/2014 end date:30/09/2014
start date:01/10/2014 end date:31/03/2015
if i enter the date range
start date 02/06/2014 end date 01/02/2015
the output has to be.
28 days, in 1st slab date range
2 months, 29 days, in 2nd slab date range
4 months in 3rd slab date range
how to achieve this in java.
Thanks in advance.
This question is difficult to answer accurately. I believe this is what you really want,
// get the minimum of any number of dates.
private static Date getMinimum(Date... dates) {
if (dates == null)
return null;
Date min = dates[0];
for (Date d : dates) {
if (d.compareTo(min) < 0) {
min = d;
}
}
return min;
}
// get the maximum of any number of dates.
private static Date getMaximum(Date... dates) {
if (dates == null)
return null;
Date max = dates[0];
for (Date d : dates) {
if (d.compareTo(max) > 0) {
max = d;
}
}
return max;
}
public static String getDateDiff(Date startDate,
Date endDate) {
StringBuilder sb = new StringBuilder();
Calendar start = Calendar.getInstance();
start.setTime(getMinimum(startDate, endDate));
Calendar end = Calendar.getInstance();
end.setTime(getMaximum(startDate, endDate));
if (start.compareTo(end) < 0) {
int monthCount = 0;
int dayCount = 0;
while (start.compareTo(end) < 0) {
start.add(Calendar.MONTH, 1);
if (start.compareTo(end) < 0) {
monthCount++;
}
}
start = Calendar.getInstance();
start.setTime(getMinimum(startDate, endDate));
start.add(Calendar.MONTH, monthCount);
while (start.compareTo(end) < 0) {
start.add(Calendar.DAY_OF_MONTH, 1);
if (start.compareTo(end) < 0) {
dayCount++;
}
}
if (monthCount > 0) {
sb.append(String.format("%d months",
monthCount));
}
if (dayCount > 0) {
if (sb.length() > 0) {
sb.append(", ");
}
sb.append(String.format("%d days", dayCount));
}
} else {
sb.append("0 days");
}
return sb.toString();
}
public static void main(String[] args) {
String[] input = { "01/06/2014-30/06/2014", //
"01/07/2014-30/09/2014", //
"01/10/2014-31/03/2015", //
"02/06/2014-01/02/2015", };
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
for (String str : input) {
String sArr[] = str.split("-");
try {
Date start = df.parse(sArr[0]);
Date end = df.parse(sArr[1]);
System.out.printf("start: %s, end: %s - diff: %s\n", sArr[0],
sArr[1], getDateDiff(start, end));
} catch (ParseException e) {
e.printStackTrace();
}
}
}
The output is
start: 01/06/2014, end: 30/06/2014 - diff: 28 days
start: 01/07/2014, end: 30/09/2014 - diff: 2 months, 28 days
start: 01/10/2014, end: 31/03/2015 - diff: 5 months, 29 days
start: 02/06/2014, end: 01/02/2015 - diff: 7 months, 29 days
Please check whether below code is helpful. I am using this.
public String getDifference(Date date1, Date date2){
long difference = date2.getTime() - date1.getTime();
long diffDays = difference / (24 * 60 * 60 * 1000);
return (diffDays/30)+" months and "+(diffDays%30)+" days";
}
public int monthsBetweenDates(Date startDate, Date endDate){
Calendar start = Calendar.getInstance();
start.setTime(startDate);
Calendar end = Calendar.getInstance();
end.setTime(endDate);
int monthsBetween = 0;
int dateDiff = end.get(Calendar.DAY_OF_MONTH)-start.get(Calendar.DAY_OF_MONTH);
if(dateDiff<0) {
int borrrow = end.getActualMaximum(Calendar.DAY_OF_MONTH);
dateDiff = (end.get(Calendar.DAY_OF_MONTH)+borrrow)-start.get(Calendar.DAY_OF_MONTH);
monthsBetween--;
if(dateDiff>0) {
monthsBetween++;
}
}
else {
monthsBetween++;
}
monthsBetween += end.get(Calendar.MONTH)-start.get(Calendar.MONTH);
monthsBetween += (end.get(Calendar.YEAR)-start.get(Calendar.YEAR))*12;
return monthsBetween;
}

Get time with hour, minute, second, millisecond, microsecond

I have this code:
SimpleDateFormat sDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
I know that this code return hour, minute, second in the time.
How i can get also the millisecond and microsecond??
You won't have microseconds, because a Date stores the number of milliseconds since Jan. 1 1970. For the milliseconds, use S, as documented in the javadoc.
The only way to get micro-seconds is to parse the string yourself. Note: Date should be used to store micro-seconds, but you can use a long. (which you can also use for milli-seconds or nano-seconds)
private static final String YEARS_TO_MINUTES = "yyyy-MM-dd HH:mm";
private static final SimpleDateFormat YEARS_TO_MINUTES_SDF = new SimpleDateFormat(YEARS_TO_MINUTES);
public static long parseMicroSeconds(String text) throws ParseException {
long timeMS;
synchronized (YEARS_TO_MINUTES_SDF) {
timeMS = YEARS_TO_MINUTES_SDF.parse(text.substring(0, YEARS_TO_MINUTES.length())).getTime();
}
long microSecs = 0;
if (text.length() > YEARS_TO_MINUTES.length() + 1) {
double secs = Double.parseDouble(text.substring(YEARS_TO_MINUTES.length() + 1));
microSecs = (long) (secs * 1e6 + 0.5);
}
return timeMS * 1000 + microSecs;
}
public static String formatMicroSeconds(long timeMicroSeconds) {
String dateTime;
synchronized (YEARS_TO_MINUTES_SDF) {
dateTime = YEARS_TO_MINUTES_SDF.format(new Date(timeMicroSeconds / 1000));
}
long secs = timeMicroSeconds % 60000000;
return dateTime + String.format(":%09.6f", secs / 1e6);
}
public static void main(String... args) throws ParseException {
String dateTime = "2011-01-17 19:27:59.999650";
long timeUS = parseMicroSeconds(dateTime);
for (int i = 0; i < 5; i++)
System.out.println(formatMicroSeconds(timeUS += 175));
}
prints
2011-01-17 19:27:59.999825
2011-01-17 19:28:00.000000
2011-01-17 19:28:00.000175
2011-01-17 19:28:00.000350
2011-01-17 19:28:00.000525
You can do similarly if you need nano-timings.
The best you can do is:
SimpleDateFormat sDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
You can only show the millisecond: :SS.
import java.time.ZonedDateTime;
import java.time.format.DateTimeFormatter;
public class MyClass
{
public static void main(String args[]) {
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("HH:mm:ss:SSSSS");
for(int i=0; i<=5;i++) {
System.out.println("Class 1 : " + ZonedDateTime.now().format(formatter));
}
}
}
Example output:
Class 1 : 19:25:19:77336
Class 1 : 19:25:19:77483
Class 1 : 19:25:19:77487
Class 1 : 19:25:19:77490
Class 1 : 19:25:19:77493
Class 1 : 19:25:19:77496
Check the Java-doc of SimpleDateFormat, it tells :
Millisecond : S
Microseconds are not available.
This example gets millisecond. Microseconds isn't available.
Date someDate = sDate.parse(dateString);
Calendar c = Calendar.setTime(someDate);
int millisecond = c.get(Calendar.MILLISECOND);
Generally the milliseconds are given with capital s and in your case it will be yyyy-MM-dd HH:mm:ss:SSS. For more info refer to Customizing formats

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