I want to get data from JSON which is returned from URL
(http://localhost:8042/patients/)
I prepared Model in which I have all the same fields as on returned JSON.
I just wanted to get data and save it on my MongoDB, but firstly it will be okay if I can return the same JSON on my endpoint.
I tried it like below but it doesn't work.
#RestController
#RequestMapping("/test")
public class PatientController {
#GetMapping("/patient")
public #ResponseBody ResponseEntity patient() {
RestTemplate restTemplate = new RestTemplate();
String url = "http://localhost:8042/patients/123SomeId123";
ResponseEntity<Patient> responseEntity = restTemplate.getForEntity(url, Patient.class);
return responseEntity;
}
}
If as you said above your app is running inside a docker it couldn't access to localhost unless you run your docker with --network host.
If the app you are trying to access runs also in another docker container you have to ensure that both of them are on the same network and use the internal ip of docker to access it.
You can view it with the command docker inspect "name_of_container" Inside network object in the field IpAdrress
Related
So I have a simple endpoint in my Spring Boot App, which just redirects to another website:
#Controller
public class FeedbackController {
#GetMapping(path = "/test")
public Mono<ResponseEntity<Void>> method() {
String redirectUrl = "https://www.google.com";
return Mono
.just(ResponseEntity.status(HttpStatus.TEMPORARY_REDIRECT).location(URI.create(redirectUrl)).build());
}
Making a GET request to this endpoint (e.g. in browser or with postman) gives me the page content of google as a response. However for testing purposes I want to make sure that the response is a TEMPORARY_REDIRECT with www.google.com as the Location Header.
How can I make a request to this endpoint so that the response is the 307 TEMPORARY_REDIRECT instead of the 200 with page content from the target website?
First
to test if its working, you could use simple tools like curl :
We add the -L flag to tell curl that we want to know if we are getting redirected
curl -L http://www.....
Go further
Then, you could simply use tools like MockMvc to automate this test
See this SO post
I am using Jhipster(Angular + Springboot) Application for my existing project.
I managed to create a controller(app.resource) manually apart from the ones already generated by jhiptser(using .jh file) for achieving a file download functionality.
So, when we start the server we usually initiate two servers i.e gradlew and npm start. The second runs on port 9000 which eventually supports hot reload functionality.(front-end development)
So the problem is, I am able to access those endpoints from the server running on standard 8000 port. However, from the port which is a proxy(9000), the method is returning 404.
I tried to clean build the application several times.
NOTE: The #RequestMapping value on the new controller is different then those present already.
Does this have to do something with spring security?
Thanks in advance.
Here is the previous controller:
#RestController
#RequestMapping("/api")
public class FGAppDiagramResource {
#GetMapping(value = "/fg-app-diagram-downloadFile")
public void getImage(String fileName,String folderName, HttpServletResponse
response){
// Some Code
}
}
Here is my New controller:
#RestController
#RequestMapping("/fileDownload")
public class DownloadFileController {
private final Logger log =
LoggerFactory.getLogger(DownloadFileController.class);
public DownloadFileController() {
super();
}
#Autowired
private ApplicationProperties applicationProperties;
#GetMapping(value = "/fg-app-diagram-downloadFile/{fileName}/{folderName}")
public void getImage(#PathVariable String fileName,#PathVariable String folderName, HttpServletResponse response) {
// Some Code
}
}
Your new controller does not use /api so you must add your endpoint URL /fileDownload to proxy configuration of webpack dev server in webpack/webpack.dev.js
proxy: [{
context: [
/* jhipster-needle-add-entity-to-webpack - JHipster will add entity api paths here */
'/api',
'/fileDownload',
You may want to use /api/fileDownload to avoid changing proxy configuration and also because /api is useful for many other aspects like security and also using HTML5 URL routing strategy in Angular to get rid of # in client routes (see https://github.com/jhipster/generator-jhipster/pull/9098).
/api and /management are namespaces to avoid route conflicts, so it is usually wise to use them for your new endpoints.
I'm a bit new to microservices and Spring. I have Spring Cloud microservices (ports: 8xxx-8xxx) with a Zuul gateway running on port 9000. There's a method inside a controller on a UI service which should do a login and then return to a index.html page:
#RequestMapping(value="/do-login", method = RequestMethod.POST)
public RedirectView doLogin (#ModelAttribute("authEntity") final AuthEntity authEntity, final Model model) {
model.addAttribute(VERSION, applicationVersion);
model.addAttribute("authEntity", new AuthEntity());
authenticatedStatus = true;
model.addAttribute(AUTHENTICATED, authenticatedStatus);
return new RedirectView("index");
}
The problem is that when above method completes it returns an url of the microservice itself localhost:8888/index but not localhost:9000/services/ui/.
If I use a simpler method:
#RequestMapping(value="/do-login", method = RequestMethod.POST)
public String doLogin (#ModelAttribute("authEntity") final AuthEntity authEntity, final Model model) {
model.addAttribute(VERSION, applicationVersion);
model.addAttribute("authEntity", new AuthEntity());
authenticatedStatus = true;
model.addAttribute(AUTHENTICATED, authenticatedStatus);
return "index";
}
This returns correctly an url of gateway localhost:9000/services/ui/do-login but with a /do-login which I do not need.
Maybe I can get rid of /do-login/ part of url? Or maybe there is a solution for the incorrect redirect?
Thanks in advance!
If you use relative path like in return "index"; the result of the POST request sent to http://localhost:9000/services/ui/do-login will include URLs to http://localhost:9000/... unless coded otherwise in the jsp / freemarker / thymeleaf file.
If you want to get rid of the do-login, you would need to implement what's called a Redirect After Post (or redirect after form submit) approach so that a page refresh doesn't resubmit the form. If you take this approach, which seem what you were doing when using: return new RedirectView("index");, I can think of a couple ways of fixing the URL and set it to the proxy host.
1) http://docs.spring.io/spring-framework/docs/current/javadoc-api/org/springframework/web/servlet/view/RedirectView.html, there are a couple of constructors that takes a host parameter, you would need to inject the proxy host in the controller class and most-likely in every controller class that implements Redirect After Post.
2) http://tuckey.org/urlrewrite/, include UrlRewriteFilter and configure rules to rewrite from webapp host to proxy host when webapp http status code response is 302. With this approach it would only be once rule and no need to inject proxy host to controller classes or change the return new RedirectView("index");`
3) Maybe this rewriting is implemented in Zuul and you don't need include and configure UrlRewriteFilter as suggested in 2).
As a side note, I have configured Nginx's proxy_pass to a Java webapps (where I implemented Redirect After Post) in the past and I don't recall having this issue. Will have to take a look at both UrlRewriteFilter and Nginx config files to expand on this.
I found that this (thanks to answer in here: Spring redirect url issue when behind Zuul proxy) seems to work as required (but is considered a 'workaround'):
#RequestMapping(value="/do-login", method = RequestMethod.POST)
public void doLogin (#ModelAttribute("authEntity") final AuthEntity authEntity,
final Model model,
HttpServletResponse servletResponse) throws IOException {
...
String rUrl = ServletUriComponentsBuilder.fromCurrentContextPath().path("/").build().toUriString();
servletResponse.sendRedirect(rUrl);
}
Pardon for the amateur question, however, I am struggling with testing a java Rest Api Locally.
#Path("/Product") //URL to call
public class ProductSearch {
#Path("/item")
#POST
#Consumes(MediaType.APPLICATION_JSON)
#Produces({MediaType.APPLICATION_JSON})
public List<ProductObject> getProjects(Credentials login) throws ConnectionException{
Assuming credentials has username, password, url, itemname, What should the localhost url look like? I get a 404 when I go to http://localhost:8080/productsearchapi/Product/item
I am able to deploy to heroku and test by sending json string but I need to be able to test and debug locally.
You could use postman to test your POST call to the API without deploying to heroku.
Your request in postman would look similar to the following, and under the body tab you would have to create the valid JSON that your path is consuming.
Postman Call
After hitting send with providing a valid JSON you should get the response json returned to you
Since I want to use the RestTemplate from Spring I want to use the same class as well for Unit-Testing. The idea would be to download a JSON-File and save it locally for the purpose of testing. Therefore I would like to change the URI from a HTTP to a File address. When it as File-address I get an Excpetion
Exception in thread "main" java.lang.IllegalArgumentException: Object of class [sun.net.www.protocol.file.FileURLConnection] must be an instance of class java.net.HttpURLConnection
urlGETList = "http://api.geonames.org/countryInfoJSON?username=volodiaL";
RestTemplate restTemplate = new RestTemplate();
CountryInfoResponse results = restTemplate.getForObject(urlGETList, CountryInfoResponse.class);
Any ideas how I can use the same classes for Unit-Testing?
I think you could look into Wiremock.
Wiremock allows subbing of requests. The advantage is that you really test the complete stack and your tests make real requests against a server responding with mock responses. These mock response bodies can be files (there are other possibilities as well.)
In your unit test you set up wiremock server like this:
#Rule
public WireMockRule wireMockRule = new WireMockRule(port);
Then you can setup a stub with a file response like this:
public void givenResponse(int statusCode, MediaType contentType, String bodyPath) {
String responseBody;
try (InputStream data = new ClassPathResource(bodyPath).getInputStream()) {
responseBody = copyToString(data, UTF_8);
}
stubFor(any(urlPathEqualTo(getWireMockUri().getPath()))
.willReturn(aResponse()
.withStatus(statusCode)
.withHeader("Content-Type", contentType.toString())
.withHeader("Content-Length", String.valueOf(responseBody.length()))
.withBody(responseBody)
));
}
You could also put the complete stub into a stub file like described here
Afterwards you can check if a certain request has been made:
verify(postRequestedFor(urlEqualTo("/form"))
.withHeader("Content-Type", containing(MULTIPART_FORM_DATA_VALUE)));
You can find out more about verification here
You would use the RestTemplate to make requests. You just need to have host and port configurable so you can use localhost and the wiremock port in your tests.