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Getting the 307 Redirection Response instead of the target-location page content from an enpoint in Spring Boot

So I have a simple endpoint in my Spring Boot App, which just redirects to another website:
#Controller
public class FeedbackController {
#GetMapping(path = "/test")
public Mono<ResponseEntity<Void>> method() {
String redirectUrl = "https://www.google.com";
return Mono
.just(ResponseEntity.status(HttpStatus.TEMPORARY_REDIRECT).location(URI.create(redirectUrl)).build());
}
Making a GET request to this endpoint (e.g. in browser or with postman) gives me the page content of google as a response. However for testing purposes I want to make sure that the response is a TEMPORARY_REDIRECT with www.google.com as the Location Header.
How can I make a request to this endpoint so that the response is the 307 TEMPORARY_REDIRECT instead of the 200 with page content from the target website?

First
to test if its working, you could use simple tools like curl :
We add the -L flag to tell curl that we want to know if we are getting redirected
curl -L http://www.....
Go further
Then, you could simply use tools like MockMvc to automate this test
See this SO post

Method Not Allowed REST Java when trying to do POST

I just want to create a simple REST service and it uses #GET and #POST.
for the #GET function, everything is ok but for #POST, when I want to create a new user on my server the browser just keeps sating (METHOD NOT ALLOWED).
I read so many articles about how to fix this error but I haven't got anything yet.
My code for #POST :
#Path("/hello")
public class HelloResource(){
#POST
#Produces(MediaType.APPLICATION_JSON)
#Path("/post")
public Response createUser(#PathParam("name") String name,#PathParam("address") String address,#PathParam("birthYear") String birth,#PathParam("ps") String password) throws NotAllowedException,MethodNotFoundException,Exception {
DataStore.getInstance().putPerson(new Person(name, address, Integer.parseInt(birth), password));
String json = "{\n";
json += "\"status\": " + '"'+"CREATED" +'"'+ ",\n";
json+="}";
return Response.status(200).entity(json).build();
}}
I also tried adding #Consumes function with (MediaType.APPLICATION.JSON) and (MediaType.TEXT_PLAIN) but nothing changed.
Also the URL I enter for posting is :
http://localhost:8080/HelloREST/rest/hello/post?name=PouYad&address=mustbejsonlater&birthYear=2005&ps=12345
As you see I also tried so many exception handlers.
Can someone please help?

if you enter your URL in the browser URL address field, it won't work because the browser will send a "GET" request. So you must use a client that will allow you to send a "POST" like PostMan. Or write your own small httpConnection function that sends a "POST"
You also have to change the #PathParam to #FormParam for it to work (#QueryParam will also work, but because it is POST, it is best to use #FormParm).

Access URL directly through browser can only create Get Request, not POST Request
You should
Create HTML Form, set the action to your service url with POST method, and then submit it.
Use Rest Client like postman to access your service with POST method.
Write your own Http Client using java.net.http api or just simply use
one of the handy libraries/frameworks (Like Spring has RestTemplate).

How to run the localhost url for post in Jax rs

I am trying to run the localhost url for POST in jax -rs but every time I am trying to run the localhost I am not getting any results. For GET it is perfectly working.
#Path("playlists")
public class PlaylistResource implements PlaylistApi {
#Override
#POST
#Consumes(MediaType.APPLICATION_JSON)
#Produces(MediaType.APPLICATION_JSON)
public Response createPlaylist(PlaylistRequest request)
}
I tried:
localhost:9999/playlists/

If you want do a post request,you must use Postman or some other tools like that,if you only type into the address into a browser,it will be a get request always.

unable to redirect to an external URI in java

so I have given a task that I should redirect a client to bank portal without using spring MVC. i have found javax.ws.rs.core.Response class that might help me! but the problem is the redirection is totally wrong and I also couldn't find a proper solution for this on google!
this is my service
#Path("/ag/v1")
public class testService {
#GET
#Path("/test")
public Response redirectTest(){
URI uri = UriBuilder.fromUri("www.google.com").build();
return Response.seeOther(uri).build();
}
}
this service redirect a client to localhost:8080/api/www.google.com ! but I want to redirect it to www.google.com!
is there another best way?
how can i fix this ?
can you please guide me?

when you write address without http your code is redirecting the User to a URL inside your project.
you can use two way to correct this:
1: you can write http:// for redirecting out side your project.
2: you can set response status with 302
The HTTP response status code 302 is a common way of performing URL redirection

How to protect restful webservice from unauhtorised access

I have a JAX-RS Restful webservice. This resource/webservice is asset for us. I am exposing this service url to third party client that would call this service resource. I want to protect this service from another authorised client/vendors.
Thus my question is -
How to protect this.
I thought to include an API key and the API key should be matched with a perticuler client API Key. And I also need to match the client url address means from whcih url the request is coming.
How to do this. How to get the URL that is calling the our rest service. I am deploying my rest in Tomcat 7.0.
Thanks
Update --
#Path("report")
#Produces(javax.ws.rs.core.MediaType.APPLICATION_XML)
public class DnaReportResource {
#GET
#Produces(javax.ws.rs.core.MediaType.APPLICATION_XML)
public void getDnaReport(#Context UriInfo uri) {
System.out.println(uri.getRequestUri());
System.out.println(uri.getPath());
System.out.println(uri.getAbsolutePath());
System.out.println(uri.getBaseUri());
//MultivaluedMap<String, String> queryParams = uri.getQueryParameters();
}
}

From your servlet handler you can call
String url = request.getRequestURL().toString();
Getting request URL in a servlet
EDIT
did you try
String url = uri.getRequestUri().toString();
What does it return?

You can make use of Tomcat Realm configuration to achieve authenticate your clients.