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Can't insert data into database through persistence.xml file

I have created a PostgreSQL script just to insert a row in the customer table. The insert happens when my project is starting to run.
But it doesn't work because I'm getting the following error:
[EL Warning]: 2016-10-23 22:14:40.182--ServerSession(609762439)--?>Exception [EclipseLink-4002] (Eclipse Persistence Services - >2.5.2.v20140319-9ad6abd): org.eclipse.persistence.exceptions.DatabaseException Internal Exception: org.postgresql.util.PSQLException: ERROR: syntax >error at end of input
Position: 82 Error Code: 0 Call: INSERT INTO customer (id, Name, Adres, PostalCode, City, Tel, >Fax, Number) VALUES Query: DataModifyQuery(sql="INSERT INTO customer (id, Name, Adres, >PostalCode, City, Tel, Fax, Number) VALUES") [EL Warning]: 2016-10-23 22:14:40.183--ServerSession(609762439)-->Exception [EclipseLink-4002] (Eclipse Persistence Services - >2.5.2.v20140319-9ad6abd): >org.eclipse.persistence.exceptions.DatabaseException Internal Exception: org.postgresql.util.PSQLException: ERROR: syntax >error at or near "1"
Position: 2 Error Code: 0 Call: (1, 'Kantoor Snel Transport / Distributiecentrum', >'Zeugstraat', '2801JD', 'Gouda', 182512784, NULL, '92'); Query: DataModifyQuery(sql="(1, 'Kantoor Snel Transport / >Distributiecentrum', 'Zeugstraat', '2801JD', 'Gouda', 182512784, NULL, >'92');") [EL Info]: connection: 2016-10-23 22:15:02.917-->ServerSession(609762439)-->file:/C:/Users/yomac_000/workspace/.metadata/.plugins/org.eclipse.wst.ser>ver.core/tmp0/wtpwebapps/snel-transport/WEB-INF/classes/_snel-transport >logout successful
Here is the persistence.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1"
xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="snel-transport" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>nl.cimsolutions.snel_transport.models.Orders</class>
<class>nl.cimsolutions.snel_transport.models.OrderLine</class>
<class>nl.cimsolutions.snel_transport.models.OrderList</class>
<class>nl.cimsolutions.snel_transport.models.Customer</class>
<class>nl.cimsolutions.snel_transport.models.Product</class>
<class>nl.cimsolutions.snel_transport.models.Category</class>
<class>nl.cimsolutions.snel_transport.models.Status</class>
<class>nl.cimsolutions.snel_transport.models.Truck</class>
<!-- <jta-data-source>java:app/snel-transport</jta-data-source> -->
<!-- <exclude-unlisted-classes>false</exclude-unlisted-classes> -->
<properties>
<property
name="javax.persistence.schema-generation.database.action"
value="drop-and-create" />
<property name="eclipselink.canonicalmodel.subpackage"
value="dev" />
<property name="javax.persistence.sql-load-script-source"
value="META-INF/sql/Customer2.sql" />
<property name="javax.persistence.schema-generation-target"
value="database" />
<property name="javax.persistence.jdbc.driver"
value="org.postgresql.Driver" />
<property name="javax.persistence.jdbc.url"
value="jdbc:postgresql://localhost:5432/snel-transport" />
<property name="javax.persistence.jdbc.user" value="transport_user" />
<property name="javax.persistence.jdbc.password"
value="admin" />
<property name="javax.persistence.jdbc.show_sql" value="true" />
</properties>
</persistence-unit>
</persistence>
And here is my PostgreSQL script:
INSERT INTO customer (id, Name, Adres, PostalCode, City, Tel, Fax, Number) VALUES
(1, 'Kantoor Snel Transport / Distributiecentrum', 'Zeugstraat', '2801JD', 'Gouda', 182512784, NULL, '92');
And here is how the Customer model looks like:
#Entity
public class Customer implements Serializable {
private static final long serialVersionUID = 1L;
#TableGenerator(
name = "CustomerGenerator",
allocationSize = 1,
initialValue = 1)
#Id
#GeneratedValue(strategy = GenerationType.TABLE,
generator="CustomerGenerator")
private Long id;
private String name;
private String adres;
#Column(name="Number")
private String streetNumber;
#Column(name="PostalCode")
private String postalCode;
#Column(name="City")
private String city;
#Column(name="Tel")
private String tel;
#Column(name="Fax")
private String fax;
#OneToMany(mappedBy = "customer", targetEntity = Orders.class)
private List<Orders> orders;
public Customer() {
// TODO Auto-generated constructor stub
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getStreetNumber() {
return streetNumber;
}
public void setStreetNumber(String streetNumber) {
this.streetNumber = streetNumber;
}
public String getPostalCode() {
return postalCode;
}
public void setPostalCode(String postalCode) {
this.postalCode = postalCode;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
public String getTel() {
return tel;
}
public void setTel(String tel) {
this.tel = tel;
}
public String getFax() {
return fax;
}
public void setFax(String fax) {
this.fax = fax;
}
#Override
public int hashCode() {
int hash = 0;
hash += (id != null ? id.hashCode() : 0);
return hash;
}
#Override
public String toString() {
return "model.OrderLine[ id=" + id + " ]";
}
public String getName() {
return name;
}
public String getAdres() {
return adres;
}
public void setName(String name) {
this.name = name;
}
public void setAdres(String adres) {
this.adres = adres;
}
}
I have already tried using the PostgreSQL script in pgAdmin. And there the script works, but somehow it doesn't work in JPA.. Anyone got a clue how I can solve this problem?

Can't create entity with Hibernate. SQLGrammarException

I spent the whole day to solve this problem. An error occurs on line with session.getTransaction().commit();
private SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
#Override
public void initGroup(Group group) throws BotException {
Session session = sessionFactory.openSession();
try {
session.beginTransaction();
session.persist(group);
session.getTransaction().commit();
} catch (PersistenceException e)
{
throw new BotException("You are already registred");
}
finally {
session.close();
sessionFactory.close();
}
Surprisingly, I have the same function for "Station" entity, but it works fine
It's strange so much. I don't know how to solve it.
It's my Group.class
#Entity
#Table(name = "group")
public class Group {
private String name;
private String password;
private String telegramId;
private int experience;
private int money;
private String nowStation;
public Group() {}
public Group(String name, String password, String telegramId) {
this.name = name;
this.password = password;
this.telegramId = telegramId;
}
#Id
#Column(name = "name", nullable = false, length = 45)
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
#Basic
#Column(name = "password", nullable = false, length = 45)
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
#Basic
#Column(name = "telegram_id", nullable = false, length = 45)
public String getTelegramId() {
return telegramId;
}
public void setTelegramId(String telegramId) {
this.telegramId = telegramId;
}
#Basic
#Column(name = "experience", nullable = true)
public int getExperience() {
return experience;
}
public void setExperience(int experience) {
this.experience = experience;
}
#Basic
#Column(name = "money", nullable = true)
public int getMoney() {
return money;
}
public void setMoney(int money) {
this.money = money;
}
#Basic
#Column(name = "now_station", nullable = true, length = 45)
public String getNowStation() {
return nowStation;
}
public void setNowStation(String nowStation) {
this.nowStation = nowStation;
}
and hibernate.cfg.xml
<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="connection.url">jdbc:mysql://localhost:3306/game_data_base</property>
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="dialect">org.hibernate.dialect.MySQLDialect</property>
<property name="connection.username">root</property>
<property name="connection.password">*******</property>
<mapping class="model.Group"/>
<mapping class="model.Station"/>
<mapping class="model.User"/>
<!-- DB schema will be updated if needed -->
<!-- <property name="hbm2ddl.auto">update</property> -->
</session-factory>
</hibernate-configuration>
Errors
сен 25, 2016 7:42:54 PM org.telegram.telegrambots.logging.BotLogger severe
19:42:54.374 [PMPUTestBot Telegram Executor] DEBUG org.hibernate.service.internal.AbstractServiceRegistryImpl - Implicitly destroying ServiceRegistry on de-registration of all child ServiceRegistries
SEVERE: BOTSESSION
19:42:54.374 [PMPUTestBot Telegram Executor] INFO org.hibernate.orm.connections.pooling - HHH10001008: Cleaning up connection pool [jdbc:mysql://localhost:3306/game_data_base]
javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement
19:42:54.374 [PMPUTestBot Telegram Executor] DEBUG org.hibernate.boot.registry.internal.BootstrapServiceRegistryImpl - Implicitly destroying Boot-strap registry on de-registration of all child ServiceRegistries
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:147)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:155)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:162)
at org.hibernate.internal.SessionImpl.doFlush(SessionImpl.java:1411)
at org.hibernate.internal.SessionImpl.managedFlush(SessionImpl.java:475)
at org.hibernate.internal.SessionImpl.flushBeforeTransactionCompletion(SessionImpl.java:3168)
at org.hibernate.internal.SessionImpl.beforeTransactionCompletion(SessionImpl.java:2382)
at org.hibernate.engine.jdbc.internal.JdbcCoordinatorImpl.beforeTransactionCompletion(JdbcCoordinatorImpl.java:467)
at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl.beforeCompletionCallback(JdbcResourceLocalTransactionCoordinatorImpl.java:146)
at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl.access$100(JdbcResourceLocalTransactionCoordinatorImpl.java:38)
at org.hibernate.resource.transaction.backend.jdbc.internal.JdbcResourceLocalTransactionCoordinatorImpl$TransactionDriverControlImpl.commit(JdbcResourceLocalTransactionCoordinatorImpl.java:220)
at org.hibernate.engine.transaction.internal.TransactionImpl.commit(TransactionImpl.java:68)
at dao.GroupDaoImpl.initGroup(GroupDaoImpl.java:32)
Thank you :)

Group is an SQL keyword. Rename your table to something else
#Table(name = "my_group")

Hibernate/JPA : IllegalArgumentException: Not an entity

I try to run a basic application with hibernate and jpa, but now I'm stuck on this exception when running app...Here's the code and erro below:
java.lang.IllegalArgumentException: Not an entity: class pka.EclipseJPAExample.domain.Employee
at org.hibernate.ejb.metamodel.MetamodelImpl.entity(MetamodelImpl.java:158)
at org.hibernate.ejb.criteria.QueryStructure.from(QueryStructure.java:136)
at org.hibernate.ejb.criteria.CriteriaQueryImpl.from(CriteriaQueryImpl.java:177)
at pka.EclipseJPAExample.jpa.JpaTest.createEmployees(JpaTest.java:47)
at pka.EclipseJPAExample.jpa.JpaTest.main(JpaTest.java:33)
JpaTest.java:
public class JpaTest {
private EntityManager manager;
public JpaTest(EntityManager manager) {
this.manager = manager;
}
/**
* #param args
*/
public static void main(String[] args) {
EntityManagerFactory factory = Persistence.createEntityManagerFactory("persistenceUnit");
EntityManager manager = factory.createEntityManager();
JpaTest test = new JpaTest(manager);
EntityTransaction tx = manager.getTransaction();
tx.begin();
try {
test.createEmployees();
} catch (Exception e) {
e.printStackTrace();
}
tx.commit();
test.listEmployees();
System.out.println(".. done");
}
private void createEmployees() {
CriteriaBuilder builder = manager.getCriteriaBuilder();
CriteriaQuery<Employee> query = builder.createQuery(Employee.class);
query.from(Employee.class);
int numOfEmployees = manager.createQuery(query).getResultList().size();
if (numOfEmployees == 0) {
Department department = new Department("java");
manager.persist(department);
manager.persist(new Employee("Jakab Gipsz",department));
manager.persist(new Employee("Captain Nemo",department));
}
}
private void listEmployees() {
CriteriaBuilder builder = manager.getCriteriaBuilder();
CriteriaQuery<Employee> query = builder.createQuery(Employee.class);
query.from(Employee.class);
List<Employee> resultList = manager.createQuery(query).getResultList();
for (Employee next : resultList) {
System.out.println("next employee: " + next);
}
}
}
and persistence.xml:
....<persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL">
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/testowa" />
<property name="javax.persistence.jdbc.user" value="root" />
<property name="javax.persistence.jdbc.password" value="enchantsql" />
<property name="hbm2ddl.auto" value="create" />
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect" />
</properties>
</persistence-unit>....
Could you point where is the problem?
EDIT:
I forgot to paste Employee class...so here it is below:
#Entity
#Table(name="Employee")
public class Employee {
#Id
#GeneratedValue
private Long id;
private String name;
#ManyToOne
private Department department;
public Employee() {}
public Employee(String name, Department department) {
this.name = name;
this.department = department;
}
public Employee(String name) {
this.name = name;
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Department getDepartment() {
return department;
}
public void setDepartment(Department department) {
this.department = department;
}
#Override
public String toString() {
return "Employee [id=" + id + ", name=" + name + ", department="
+ department.getName() + "]";
}
}
As you can see it is mapped.

Make sure #Entity annotation in your entity. You also need to configure an entity in persistence.xml
<persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL">
<class>pka.EclipseJPAExample.domain.Employee</class>

If you have numerous ENTITY classes in your application, adding an entry for every entity in "persistence.xml" won't be a good choice.
Instead, create your own data source bean using Custom AutoConfiguration.
Use LocalContainerEntityManagerFactoryBean inside dataSource bean Creation method.
Here, you need to define
LocalContainerEntityManagerFactoryBean entityManagerFactoryBean = new
LocalContainerEntityManagerFactoryBean();
entityManagerFactoryBean.setPackagesToScan("org.springframework.boot.entities");
This package is the location where all entity classes have been saved.
Thus no need to define every single entry for Entity classes at "persistence.xml".
Prefer Spring-based Scanning.

The target entity of the relationship attribute cannot be determined

I can't figure out what the problem is, please help. I've searched a lot, but didn't find any useful advice. Maybe you can help me. Thanks a lot.
There are two classes using eclipselink as jpa provider:
#Entity
#Table(name = "USER")
public class User {
#Id
#GeneratedValue(strategy = GenerationType.TABLE)
private Long id;
private String login;
private Long groupId;
private String email;
#ManyToMany(mappedBy = "users")
private List polls;
#OneToMany(mappedBy = "user")
private List votes;
public List getVotes() {
return votes;
}
public void setVotes(List votes) {
this.votes = votes;
}
public User() {
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getLogin() {
return login;
}
public void setLogin(String login) {
this.login = login;
}
public Long getGroupId() {
return groupId;
}
public void setGroupId(Long groupId) {
this.groupId = groupId;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public List getPolls() {
return polls;
}
public void setPolls(List polls) {
this.polls = polls;
}
}
and
#Entity
#Table(name = "VOTE")
public class Vote {
#Id
#GeneratedValue(strategy = GenerationType.TABLE)
private Long vid;
private String comment;
#ManyToOne
private User user;
#ManyToOne
private Option option;
public Vote() {
}
public Long getVid() {
return vid;
}
public void setVid(Long vid) {
this.vid = vid;
}
#Column(name = "comment")
public String getComment() {
return comment;
}
public void setComment(String comment) {
this.comment = comment;
}
public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
public Option getOption() {
return option;
}
public void setOption(Option option) {
this.option = option;
}
}
When I'm trying to compile this, I receive error:
Exception [EclipseLink-7214] (Eclipse Persistence Services - 2.4.0.v20120608-r11652): org.eclipse.persistence.exceptions.ValidationException
Exception Description: The target entity of the relationship attribute [votes] on the class [class logic.User] cannot be determined. When not using generics, ensure the target entity is defined on the relationship mapping.
Here is my persistence.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="1.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="pollsPU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<class>logic.Option</class>
<class>logic.Poll</class>
<class>logic.User</class>
<class>logic.Vote</class>
<class>logic.Greeting</class>
<properties>
<property name="eclipselink.jdbc.password" value="" />
<property name="eclipselink.jdbc.user" value="" />
<property name="eclipselink.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="eclipselink.jdbc.url"
value="jdbc:mysql://localhost:3306/core_polls" />
<property name="eclipselink.ddl-generation" value="drop-and-create-tables" />
<property name="eclipselink.logging.level" value="INFO" />
<property name="eclipselink.ddl-generation.output-mode"
value="database" />
</properties>
</persistence-unit>
</persistence>

As stated in the Javadoc
If the collection is defined using generics to specify the element
type, the associated target entity type need not be specified;
otherwise the target entity class must be specified.
So, you can do either
#OneToMany(mappedBy = "user")
private List<Vote> votes;
or
#OneToMany(targetEntity=logic.Vote.class, mappedBy = "user")
private List votes;
But I would prefer the first.

Trouble working with EntityManagerFactory

I'm trying to figure out how to use #PersistenceUnit as I've read it's a much better solution than #PersistenceContext. The trouble is.... I can't figure out how to get it to work properly...
#Controller
public class Content {
#PersistenceUnit(unitName = "CMTPU")
public EntityManagerFactory emf;
public EntityManager em = emf.createEntityManager();
#RequestMapping(value={"/content/edit*"}, method=RequestMethod.GET)
public ModelAndView edit(Model model) {
ModelAndView mv = new ModelAndView();
mv.setViewName("content/edit");
//get symbols
List<Symbol> symbols = em.createNamedQuery("Symbol.findAll").getResultList();
mv.addObject(symbols);
return mv;
}
}
My app loaded before I added the //get symbols section and the EntityManager stuff. Now I'm seeing the error SEVERE: Exception while loading the app : java.lang.IllegalStateException: ContainerBase.addChild: start: org.apache.catalina.LifecycleException: org.apache.catalina.LifecycleException: java.lang.NullPointerException
I've read that I need to define a unitName, but then I'm looking at this documentation and it doesn't show that being done.
persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="CMTPU" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>CMT_DEV</jta-data-source>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties/>
</persistence-unit>
</persistence>
I'm having trouble determining what I'm doing wrong.
update
My model defines the database and all of that as seen below. Do I even need a persistence.xml?
package com.fettergroup.cmt.models;
import java.io.Serializable;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;
import javax.persistence.Table;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;
#Entity
#Table(name = "symbol", catalog = "DATABASE1", schema = "dbo")
#NamedQueries({
#NamedQuery(name = "Symbol.findAll", query = "SELECT s FROM Symbol s"),
#NamedQuery(name = "Symbol.findById", query = "SELECT s FROM Symbol s WHERE s.id = :id"),
#NamedQuery(name = "Symbol.findBySymbol", query = "SELECT s FROM Symbol s WHERE s.symbol = :symbol"),
#NamedQuery(name = "Symbol.findByHtmlNumber", query = "SELECT s FROM Symbol s WHERE s.htmlNumber = :htmlNumber"),
#NamedQuery(name = "Symbol.findByHtmlName", query = "SELECT s FROM Symbol s WHERE s.htmlName = :htmlName"),
#NamedQuery(name = "Symbol.findByAsciiDec", query = "SELECT s FROM Symbol s WHERE s.asciiDec = :asciiDec"),
#NamedQuery(name = "Symbol.findByAsciiHex", query = "SELECT s FROM Symbol s WHERE s.asciiHex = :asciiHex")})
public class Symbol implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Basic(optional = false)
#NotNull
#Column(name = "id")
private Short id;
#Size(max = 10)
#Column(name = "symbol")
private String symbol;
#Size(max = 10)
#Column(name = "html_number")
private String htmlNumber;
#Size(max = 10)
#Column(name = "html_name")
private String htmlName;
#Size(max = 10)
#Column(name = "ascii_dec")
private String asciiDec;
#Size(max = 10)
#Column(name = "ascii_hex")
private String asciiHex;
public Symbol() {
}
public Symbol(Short id) {
this.id = id;
}
public Short getId() {
return id;
}
public void setId(Short id) {
this.id = id;
}
public String getSymbol() {
return symbol;
}
public void setSymbol(String symbol) {
this.symbol = symbol;
}
public String getHtmlNumber() {
return htmlNumber;
}
public void setHtmlNumber(String htmlNumber) {
this.htmlNumber = htmlNumber;
}
public String getHtmlName() {
return htmlName;
}
public void setHtmlName(String htmlName) {
this.htmlName = htmlName;
}
public String getAsciiDec() {
return asciiDec;
}
public void setAsciiDec(String asciiDec) {
this.asciiDec = asciiDec;
}
public String getAsciiHex() {
return asciiHex;
}
public void setAsciiHex(String asciiHex) {
this.asciiHex = asciiHex;
}
#Override
public int hashCode() {
int hash = 0;
hash += (id != null ? id.hashCode() : 0);
return hash;
}
#Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Symbol)) {
return false;
}
Symbol other = (Symbol) object;
if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
return false;
}
return true;
}
#Override
public String toString() {
return "com.project1.models.Symbol[ id=" + id + " ]";
}
}

use only
#Controller
public class Content {
#PersistenceContext(unitName = "CMTPU")
public EntityManager em;
The entity manager should be controlled by spring.
This ins an example, it uses hiberante as persistence provider, but I think you can adapt it.
<tx:annotation-driven transaction-manager="transactionManager" />
<bean class="org.springframework.orm.jpa.JpaTransactionManager" id="transactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
id="entityManagerFactory">
<property name="persistenceUnitName" value="myPersistenceUnit" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="false" />
</bean>
</property>
</bean>
sample persistance unit, that works with that configuration
<persistence-unit name="myPersistenceUnit" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5InnoDBDialect" />
<property name="hibernate.hbm2ddl.auto" value="validate" />
<property name="hibernate.connection.charSet" value="UTF-8" />
</properties>
</persistence-unit>