Develop Reference

Error java.lang.IllegalArgumentException: NamedQuery of name: Employee.findAll not found

guys please help me for solve this error, it's been 4 days, this problem hasn't been solved.
this is my Entity Class code :
package mybengkel;
import java.io.Serializable;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;
import javax.persistence.Table;
/**
*
* #author rhmtsaepuloh
*/
#Entity
#Table(name = "employee")
#NamedQueries({
#NamedQuery(name = "Employee.findAll", query = "SELECT e FROM Employee e"),
#NamedQuery(name = "Employee.findById", query = "SELECT e FROM Employee e WHERE e.id = :id"),
#NamedQuery(name = "Employee.findByUsername", query = "SELECT e FROM Employee e WHERE e.username = :username"),
#NamedQuery(name = "Employee.findByPassword", query = "SELECT e FROM Employee e WHERE e.password = :password")})
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "id")
private Integer id;
#Basic(optional = false)
#Column(name = "username")
private String username;
#Basic(optional = false)
#Column(name = "password")
private String password;
public Employee() {
}
public Employee(Integer id) {
this.id = id;
}
public Employee(Integer id, String username, String password) {
this.id = id;
this.username = username;
this.password = password;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
#Override
public int hashCode() {
int hash = 0;
hash += (id != null ? id.hashCode() : 0);
return hash;
}
#Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Employee)) {
return false;
}
Employee other = (Employee) object;
if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) {
return false;
}
return true;
}
#Override
public String toString() {
return "mybengkel.Employee[ id=" + id + " ]";
}
}
Persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="MyBengkelPU" transaction-type="RESOURCE_LOCAL">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<jar-file>/Users/rhmtsaepuloh/Downloads/mysql-connector-java-8.0.18/mysql-connector-java-8.0.18.jar</jar-file>
<class>mybengkel.Employee</class>
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/oop?serverTimezone=UTC"/>
<property name="javax.persistence.jdbc.user" value="root"/>
<property name="javax.persistence.jdbc.driver" value="com.mysql.cj.jdbc.Driver"/>
<property name="javax.persistence.jdbc.password" value=""/>
<property name="javax.persistence.schema-generation.database.action" value="create"/>
</properties>
</persistence-unit>
</persistence>
and Main class java :
package mybengkel;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
/**
*
* #author rhmtsaepuloh
*/
public class MyBengkel {
public static void main(String[] args) {
EntityManager em;
EntityManagerFactory emf;
emf = Persistence.createEntityManagerFactory("MyBengkelPU");
em = emf.createEntityManager();
em.getTransaction().begin();
Employee e = new Employee();
e.setUsername("haha");
e.setPassword("hehe");
em.persist(e);
em.getTransaction().commit();
}
}
the problem is when I run the program found error code :
[EL Info]: 2019-11-28 16:07:45.916--ServerSession(347978868)--EclipseLink, version: Eclipse Persistence Services - 2.5.2.v20140319-9ad6abd
[EL Info]: connection: 2019-11-28 16:07:46.813--ServerSession(347978868)--file:/Volumes/Data/Perkuliahan/OOP/NetBeans/MyBengkel/build/classes/_MyBengkelPU login successful
[EL Warning]: metamodel: 2019-11-28 16:07:46.859--The collection of metamodel types is empty. Model classes may not have been found during entity search for Java SE and some Java EE container managed persistence units. Please verify that your entity classes are referenced in persistence.xml using either <class> elements or a global <exclude-unlisted-classes>false</exclude-unlisted-classes> element
Exception in thread "main" java.lang.IllegalArgumentException: Object: mybengkel.Employee[ id=null ] is not a known entity type.
at org.eclipse.persistence.internal.sessions.UnitOfWorkImpl.registerNewObjectForPersist(UnitOfWorkImpl.java:4228)
at org.eclipse.persistence.internal.jpa.EntityManagerImpl.persist(EntityManagerImpl.java:496)
at mybengkel.MyBengkel.main(MyBengkel.java:29)
/Users/rhmtsaepuloh/Library/Caches/NetBeans/11.1/executor-snippets/run.xml:111: The following error occurred while executing this line:
/Users/rhmtsaepuloh/Library/Caches/NetBeans/11.1/executor-snippets/run.xml:68: Java returned: 1
BUILD FAILED (total time: 3 seconds)
I try this on netbeans 11.1 and mysql connector java 8.0.18 Please help me to fix it guys... Thanks before

How to properly set up hibernate persistence with a java model

I am attempting to write a rest API to interface with a MariaDB. I feel like I am most of the way there however I am recieving the following error:
java.lang.IllegalArgumentException: Unknown entity: Models.User
at org.hibernate.internal.SessionImpl.firePersist(SessionImpl.java:808)
at org.hibernate.internal.SessionImpl.persist(SessionImpl.java:789)
at test.Application.addUser(Application.java:40)
at test.Application.main(Application.java:18)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.base/java.lang.reflect.Method.invoke(Method.java:566)
at org.springframework.boot.maven.AbstractRunMojo$LaunchRunner.run(AbstractRunMojo.java:542)
at java.base/java.lang.Thread.run(Thread.java:834)
I imagine that this is because I have incorrectly configured the user class in the persistence.xml file in resources/META-INF. Below are the relavent inter relating files:
persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="potholeAPI" transaction-
type="RESOURCE_LOCAL">
<provider>org.hibernate.jpa.HibernatePersistenceProvider</provider>
<class>Models.User</class>
<properties>
<property name="javax.persistence.jdbc.driver"
value="com.mysql.jdbc.Driver"/>
<property name="javax.persistence.jdbc.url"
value="jdbc:mysql://localhost:3306/PotholeDB?
useUnicode=true&useJDBCCompliantTimezoneShift
=true&useLegacyDate
timeCode=false&serverTimezone=UTC"/>
<property name="javax.persistence.jdbc.user" value="admin"/>
<property name="javax.persistence.jdbc.password" value="admin"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect"/>
</properties>
</persistence-unit>
User.java
package Models;
import org.hibernate.annotations.Entity;
import org.hibernate.annotations.Table;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
#Entity
#Table(appliesTo = "Users")
public class User implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#Column(name = "id", unique = true)
private int id;
#Column(name = "name", unique = true)
private String name;
#Column(name = "created_date")
private int created_date;
getters and setters....
and the main and driver for my testing
Application.java
package test;
import Models.User;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import javax.persistence.*;
import java.util.Date;
import java.util.List;
#SpringBootApplication
public class Application {
private static EntityManagerFactory ENTITY_MANAGER_FACTORY =
Persistence.createEntityManagerFactory("potholeAPI");
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
addUser(1, "jim");
addUser(2, "bob");
getUser(1);
getUsers();
ENTITY_MANAGER_FACTORY.close();
}
public static void addUser(int id, String name) {
EntityManager em = ENTITY_MANAGER_FACTORY.createEntityManager();
EntityTransaction et = null;
Date date = new Date();
try {
et = em.getTransaction();
et.begin();
User user = new User();
user.setId(id);
user.setName(name);
user.setCreated_date(date.getDate());
em.persist(user);
} catch (Exception ex) {
if (et != null) {
et.rollback();
}
ex.printStackTrace();
} finally {
em.close();
}
}
public static void getUser(int id) {
EntityManager em = ENTITY_MANAGER_FACTORY.createEntityManager();
String query = "SELECT u FROM User u WHERE u.id = :userID";
TypedQuery<User> tq = em.createQuery(query, User.class);
tq.setParameter("userID", id);
User user = null;
try {
user = tq.getSingleResult();
System.out.println(user.getName() + " ");
} catch (NoResultException e) {
System.out.println("ex");
e.printStackTrace();
} finally {
em.close();
}
}
public static void getUsers() {
EntityManager em = ENTITY_MANAGER_FACTORY.createEntityManager();
String query = "SELECT u FROM User u WHERE u.id IS NOT NULL";
TypedQuery<User> tq = em.createQuery(query, User.class);
List<User> users;
try {
users = tq.getResultList();
users.forEach(user-> System.out.println(user.getName()+ " "));
} catch (NoResultException e) {
System.out.println("ex");
e.printStackTrace();
} finally {
em.close();
}
}
}
My suspicion is that I screwed up the xml file however I am new to spinning up an API like this so I am not fully confident.

Tablename is 'User',so User.java->#Table(appliesTo = "Users") should be #Table(appliesTo = "User")

Java ee, JPA 2.1 retruning null

frist of all sorry for my bad english. I am trying to display database (Postgres) rows from one table, and it allways returning null. I am doing project in Java EE using JPA hibernate.
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence" version="2.0">
<persistence-unit name="mesPU">
<class>pl.mes.model.Users</class>
<properties>
<property name="javax.persistence.jdbc.driver" value="org.postgresql.Driver" />
<property name="javax.persistence.jdbc.url" value="jdbc:postgresql://localhost:5432/test" />
<property name="javax.persistence.jdbc.user" value="postgres" />
<property name="javax.persistence.jdbc.password" value="xxxxxx" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.hbm2ddl.auto" value="update" />
<property name="hibernate.connection.url" value="jdbc:postgresql://localhost:5432/test"/>
<property name="hibernate.connection.driver_class" value="org.postgresql.Driver"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQL9Dialect"/>
</properties>
</persistence-unit>
</persistence>
Users entity
package pl.mes.model;
import javax.persistence.Basic;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
#Entity
public class Users {
private Integer userId;
private String firstname;
private String secondname;
private String email;
#Id
#Column(name = "userId", nullable = false)
public Integer getUserId() {
return userId;
}
public void setUserId(Integer userId) {
this.userId = userId;
}
#Basic
#Column(name = "firstname", nullable = true)
public String getFirstname() {
return firstname;
}
public void setFirstname(String firstname) {
this.firstname = firstname;
}
#Basic
#Column(name = "secondname", nullable = true)
public String getSecondname() {
return secondname;
}
public void setSecondname(String secondname) {
this.secondname = secondname;
}
#Basic
#Column(name = "email", nullable = true)
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
#Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Users users = (Users) o;
if (userId != null ? !userId.equals(users.userId) : users.userId != null) return false;
if (firstname != null ? !firstname.equals(users.firstname) : users.firstname != null) return false;
if (secondname != null ? !secondname.equals(users.secondname) : users.secondname != null) return false;
if (email != null ? !email.equals(users.email) : users.email != null) return false;
return true;
}
#Override
public int hashCode() {
int result = userId != null ? userId.hashCode() : 0;
result = 31 * result + (firstname != null ? firstname.hashCode() : 0);
result = 31 * result + (secondname != null ? secondname.hashCode() : 0);
result = 31 * result + (email != null ? email.hashCode() : 0);
return result;
}
}
When i use this
select u from Users u
in console output looks like that:
output
DbSOURCE
I would be grateful if someone can help me with this :)

You have specified the URL jdbc:postgresql://localhost:5432/test for the property javax.persistence.jdbc.url. But when I look at the second screenshot, I can not see a database schema named test.
I guess, you are connecting to the wrong database. Maybe a second instance listening at a different port?
Please also remove the Hibernate specific properties that are already specified by JPA standard properties (as stated out in the comments by Billy Frost).

How to create annotation-based Hibernate mappings?

I am writing a Java project that uses Hibernate ORM and Spring Framework. Right now, when I add a POJO class, I need to modify my hibernate.cfg.xml file, which looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<mapping class="somepackage.class1"/>
<mapping class="somepackage.class2"/>
<!-- etc. -->
</session-factory>
</hibernate-configuration>
Then, I create an annotation-based class. I heard that I could avoid adding per-class mappings in hibernate.cfg.xml if I used proper Hibernate annotations. How can I modify a class to avoid the mappings in an XML file? Here is my example POJO file, generated by NetBeans:
/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package somepackage.pojo;
import java.io.Serializable;
import java.util.Collection;
import javax.persistence.Basic;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.NamedQueries;
import javax.persistence.NamedQuery;
import javax.persistence.OneToMany;
import javax.persistence.Table;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlTransient;
/**
*
* #author D
*/
#Entity
#Table(name = "ACCOUNT")
#XmlRootElement
#NamedQueries({
#NamedQuery(name = "Account.findAll", query = "SELECT a FROM Account a"),
#NamedQuery(name = "Account.findByLogin", query = "SELECT a FROM Account a WHERE a.login = :login"),
#NamedQuery(name = "Account.findByPassword", query = "SELECT a FROM Account a WHERE a.password = :password")})
public class Account implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Basic(optional = false)
#NotNull
#Size(min = 1, max = 100)
#Column(name = "LOGIN", nullable = false, length = 100)
private String login;
#Size(max = 128)
#Column(name = "PASSWORD", length = 128)
private String password;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "author")
private Collection<Comment> commentCollection;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "author")
private Collection<Article> articleCollection;
public Account() {
}
public Account(String login) {
this.login = login;
}
public String getLogin() {
return login;
}
public void setLogin(String login) {
this.login = login;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
#XmlTransient
public Collection<Comment> getCommentCollection() {
return commentCollection;
}
public void setCommentCollection(Collection<Comment> commentCollection) {
this.commentCollection = commentCollection;
}
#XmlTransient
public Collection<Article> getArticleCollection() {
return articleCollection;
}
public void setArticleCollection(Collection<Article> articleCollection) {
this.articleCollection = articleCollection;
}
#Override
public int hashCode() {
int hash = 0;
hash += (login != null ? login.hashCode() : 0);
return hash;
}
#Override
public boolean equals(Object object) {
// TODO: Warning - this method won't work in the case the id fields are not set
if (!(object instanceof Account)) {
return false;
}
Account other = (Account) object;
if ((this.login == null && other.login != null) || (this.login != null && !this.login.equals(other.login))) {
return false;
}
return true;
}
#Override
public String toString() {
return "somepackage.pojo.Account[ login=" + login + " ]";
}
}

I'd suggest you export the hibernate configuration to the spring configuration because of the flexibility that spring provides. Your concern is to not declare the class in the configuration every time you create a new entity. Using spring configuration you can do the following. (packagestoscan property)
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="org.baeldung.spring.persistence.model" />
<property name="hibernateProperties">
<props>
<prop key="hibernate.hbm2ddl.auto">${hibernate.hbm2ddl.auto}</prop>
<prop key="hibernate.dialect">${hibernate.dialect}</prop>
</props>
</property>
</bean>
Ref: http://www.javacodegeeks.com/2013/05/hibernate-3-with-spring.html

class listed in the persistence.xml file but not mapped

I have listed my class in persistence.xml but mapped class is not recognized inside.
I tried <exclude-unlisted-classes>false</exclude-unlisted-classes>
But no luck.
My persistence.xml file
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="advertiserAPI" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.advertiser.model.Application</class>
<properties>
<property name="hibernate.connection.url" value="jdbc:mysql://host:port/DB" />
<property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/>
<property name="hibernate.connection.autoReconnect" value="true"/>
<property name="hibernate.connection.username" value="root"/>
<property name="hibernate.connection.password" value="password"/>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>
<property name="hibernate.validator.apply_to_ddl" value="false"/>
<property name="hibernate.hbm2ddl.auto" value="validate"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.format_sql" value="false"/>
<property name="hibernate.use_sql_comments" value="true"/>
<property name="hibernate.default_batch_fetch_size" value="16"/>
<property name="hibernate.current_session_context_class" value="thread"/>
</properties>
</persistence-unit>
</persistence>
Test class file
package com.advertiser.model.test;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
import javax.persistence.Query;
import javax.servlet.ServletException;
import org.junit.Test;
import com.advertiser.model.Application;
public class ApplicationTest {
#Test
public void listAll() throws ServletException {
EntityManagerFactory emf = Persistence.createEntityManagerFactory("advertiserAPI");
try {
EntityManager em = emf.createEntityManager();
Query query = em.createQuery("SELECT id FROM Application");
System.out.println("query " + query);
} catch (Exception ex) {
ex.printStacktrace();
}
}
}
Application class has following
package com.advertiser.model;
import javax.persistence.Column;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;
import org.apache.commons.lang.builder.ToStringBuilder;
import org.hibernate.annotations.Entity;
import static org.apache.commons.lang.builder.ToStringStyle.MULTI_LINE_STYLE;
#Entity
#Table(name = "applications")
public class Application {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id", unique = true, nullable = false, insertable = false, updatable = false)
private Integer id;
#Column(name = "name", length = 255)
private String name;
#Column(name = "host", length = 255, nullable = false)
private String host;
#Column(name = "app_type", columnDefinition = "TINYINT")
private String appType;
#ManyToOne
#JoinColumn(name = "advertiser_id")
private Integer advertiserId;
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getHost() {
return host;
}
public void setHost(String host) {
this.host = host;
}
public String getAppType() {
return appType;
}
public void setAppType(String appType) {
this.appType = appType;
}
public Integer getAdvertiserId() {
return advertiserId;
}
public void setAdvertiserId(Integer advertiserId) {
this.advertiserId = advertiserId;
}
}

You have annotated your class with #org.hibernate.annotations.Entity instead of annotating it with #javax.persistence.Entity.