I want to execute a simple native query, but it does not work:
#Autowired
private EntityManager em;
Query q = em.createNativeQuery("SELECT count(*) FROM mytable where username = :username");
em.setProperty("username", "test");
(int) q.getSingleResult();
Why am I getting this exception?
org.hibernate.QueryException: Not all named parameters have been set: [username]
Named parameters are not supported by JPA in native queries, only for JPQL. You must use positional parameters.
Named parameters follow the rules for identifiers defined in Section 4.4.1. The use of named parameters applies to the Java Persistence query language, and is not defined for native queries. Only positional parameter binding may be portably used for native queries.
So, use this
Query q = em.createNativeQuery("SELECT count(*) FROM mytable where username = ?1");
q.setParameter(1, "test");
While JPA specification doesn't support named parameters in native queries, some JPA implementations (like Hibernate) may support it
Native SQL queries support positional as well as named parameters
However, this couples your application to specific JPA implementation, and thus makes it unportable.
After many tries I found that you should use createNativeQuery And you can send parameters using # replacement
In my example
String UPDATE_lOGIN_TABLE_QUERY = "UPDATE OMFX.USER_LOGIN SET LOGOUT_TIME = SYSDATE WHERE LOGIN_ID = #loginId AND USER_ID = #userId";
Query query = em.createNativeQuery(logQuery);
query.setParameter("userId", logDataDto.getUserId());
query.setParameter("loginId", logDataDto.getLoginId());
query.executeUpdate();
You are calling setProperty instead of setParameter. Change your code to
Query q = em.createNativeQuery("SELECT count(*) FROM mytable where username = :username");
em.setParameter("username", "test");
(int) q.getSingleResult();
and it should work.
I use EclipseLink. This JPA allows the following way for the native queries:
Query q = em.createNativeQuery("SELECT * FROM mytable where username = ?username");
q.setParameter("username", "test");
q.getResultList();
Use set Parameter from query.
Query q = (Query) em.createNativeQuery("SELECT count(*) FROM mytable where username = ?1");
q.setParameter(1, "test");
This was a bug fixed in version 4.3.11
https://hibernate.atlassian.net/browse/HHH-2851
EDIT:
Best way to execute a native query is still to use NamedParameterJdbcTemplate
It allows you need to retrieve a result that is not a managed entity ; you can use a RowMapper and even a Map of named parameters!
private NamedParameterJdbcTemplate namedParameterJdbcTemplate;
#Autowired
public void setDataSource(DataSource dataSource) {
this.namedParameterJdbcTemplate = new NamedParameterJdbcTemplate(dataSource);
}
final List<Long> resultList = namedParameterJdbcTemplate.query(query,
mapOfNamedParamters,
new RowMapper<Long>() {
#Override
public Long mapRow(ResultSet rs, int rowNum) throws SQLException {
return rs.getLong(1);
}
});
Related
I have situation in which I have to compose a JPQL query in some method, then pass this query to spring data query method to be used as the query in #Query annotation.
#Query(value = ":DyanamicQuery")
List<PrizeInsuranceConfiguration> filterConfigurPrizeInsurance(String DyanamicQuery);
This is not possible. As it throws compile error. Can you give me an alternat way to achieve this?
#Query(value = ":DyanamicQuery")
List<PrizeInsuranceConfiguration> filterConfigurPrizeInsurance(String DyanamicQuery);
expected to get Query that I made will go and sit at value = ":DyanamicQuery" I also tried giving #Query("#{#entityName}").
You can create a JPQL query as a string, but you cannot pass it as a parameter to the value attribute of the #Query annotation.
You can use below example -
String dyanamicQuery= "SELECT * FROM table_name WHERE condition= :condition";
#Query(value = dyanamicQuery)
List<Entity> findByField(#Param("condition") String condition);
Or you can use below example also -
#Query(value = "SELECT * FROM table_name WHERE condition= :condition")
List filterConfigurPrizeInsuranceByField(#Param("condition") String condition);
Am upgrading Hibernate from 5.1.2.Final to 5.4.13. Am facing issue in below code,
#Entity
#NamedNativeQuery(name = "getStudentDetails", resultClass = StudentEntity.class, query = "{call getStudentDetails(?)}")
public class StudentEntity {
private Long id;
private String name;
}
and my DAO class like below,
public List<StudentEntity> getStudentDetails(){
List<StudentEntity> result = null;
try{
Query query = em.createNamedQuery("getStudentDetails");
result = query.getResultList();
}catch(Exception e){
}
return result;
}
create or replace procedure getStudentDetails(p_return_cur OUT SYS_REFCURSOR) is Store procedure with only output parameter.
am not set outparameter in java code. Till Hibernate 5.2.* don't have this issue. When update to 5.3.* it return "ordinal parameter not bound 1".
Positional Parameters are not Supported since 5.3
Support for legacy-style query parameter ('?') declarations in HQL/JPQL queries has been removed. This feature has been deprecated since Hibernate 4.1 and finally removed in 5.3 version.
Therefore, the following query declaration is not valid:
Query<Product> query = OBDal.getInstance().getSession()
.createQuery("from Product as p where p.name = ? and p.stocked = ?", Product.class);
query.setParameter(0, "Ale Beer");
query.setParameter(1, true);
To make the previous query work fine it must use named parameters:
Query<Product> query = OBDal.getInstance().getSession()
.createQuery("from Product as p where p.name = :name and p.stocked = :isStocked", Product.class);
query.setParameter("name", "Ale Beer");
query.setParameter("isStocked", true);
Code sample is taken from http://wiki.openbravo.com/wiki/Hibernate_5.3_Migration_Guide
when i run my query in database visualizer its working perfectly, but i think there are some issues in syntax when i convert it in my DAO class method.
I want to get whole data against the name provided
In Visualizer:
SELECT first_name,last_name,nic,phone,email FROM x_hr_user where (first_name = 'Irum');
Now in Dao
public List<XHrUser> findXHrUserByNameInTable()
{
String name ="Irum";
Query query = em.createQuery("SELECT xHrNewUserObj.firstName,xHrNewUserObj.lastName, xHrNewUserObj.nic, xHrNewUserObj.phone, xHrNewUserObj.emil FROM XHrUser xHrNewUserObj where (xHrNewUserObj.firstName) = (name)");
List<XHrUser> list = query.getResultList();
return list;
}
Instead of showing single row, it displays whole data Table
Thank you
Your current query is not valid JPQL. It appears that you intended to insert the raw name string into your query, which could be done via a native query, but certainly is not desirable. Instead, use a named parameter in your JPQL query and then bind name to it.
String name = "Irum";
Query query = em.createQuery("SELECT x FROM XHrUser WHERE x.firstName = :name")
.setParameter("name", name);
List<XhrUser> list = query.getResultList();
You have to write query as below. where : is used for variable
Query query = em.createQuery("SELECT xHrNewUserObj.firstName,xHrNewUserObj.lastName, xHrNewUserObj.nic, xHrNewUserObj.phone, xHrNewUserObj.emil FROM XHrUser xHrNewUserObj where (xHrNewUserObj.firstName) = :name");
Actually I had one SQL query that runs very fine with mySql database. but, my problem is that I want to write that query in hibernatetemplate query.
My SQL QUERY IS
SELECT * FROM task, dependency WHERE DEPENDENCY_From IN(10,11,12,13)
and I want it to executed by the hibernate template.
How do I to convert this to a HibernateTemplate Query?
If you want to use HibernateTemplate query then below is example of hibernate query but in your case, we need mapping files to see how the entities are associated. Hope below query will help you.
public List<Object[]> getCities(Integer stateId) {
List<Object[]> cityList = new ArrayList<Object[]>();
String query = "select city.cityId,city.cityName from City city where city.state.stateId=?";
Object[] queryParam = {stateId};
cityList = getHibernateTemplate().find(query, queryParam);
return cityList;
}
or
String query="from City";
List<City> cityList = getHibernateTemplate().find(query);
HQL query
Object[] params = {cid,cid};
List list=getHibernateTemplate().find("select S.stateName,C.countryName from State S,Country C where C.countryId=? and S.countryId=?", params);
SQL Query
select S.stateName,C.countryName from State S,Country C where S.countryId=C.countryId;
I have the following parametrised JPA, or Hibernate, query:
SELECT entity FROM Entity entity WHERE name IN (?)
I want to pass the parameter as an ArrayList<String>, is this possible? Hibernate current tells me, that
java.lang.ClassCastException: java.util.ArrayList cannot be cast to java.lang.String
Is this possible at all?
ANSWER: Collections as parameters only work with named parameters like ":name", not with JDBC style parameters like "?".
Are you using Hibernate's Query object, or JPA? For JPA, it should work fine:
String jpql = "from A where name in (:names)";
Query q = em.createQuery(jpql);
q.setParameter("names", l);
For Hibernate's, you'll need to use the setParameterList:
String hql = "from A where name in (:names)";
Query q = s.createQuery(hql);
q.setParameterList("names", l);
in HQL you can use query parameter and set Collection with setParameterList method.
Query q = session.createQuery("SELECT entity FROM Entity entity WHERE name IN (:names)");
q.setParameterList("names", names);
Leaving out the parenthesis and simply calling 'setParameter' now works with at least Hibernate.
String jpql = "from A where name in :names";
Query q = em.createQuery(jpql);
q.setParameter("names", l);
Using pure JPA with Hibernate 5.0.2.Final as the actual provider the following seems to work with positional parameters as well:
Entity.java:
#Entity
#NamedQueries({
#NamedQuery(name = "byAttributes", query = "select e from Entity e where e.attribute in (?1)") })
public class Entity {
#Column(name = "attribute")
private String attribute;
}
Dao.java:
public class Dao {
public List<Entity> findByAttributes(Set<String> attributes) {
Query query = em.createNamedQuery("byAttributes");
query.setParameter(1, attributes);
List<Entity> entities = query.getResultList();
return entities;
}
}
query.setParameterList("name", new String[] { "Ron", "Som", "Roxi"}); fixed my issue