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Query not giving solution in DAO class

when i run my query in database visualizer its working perfectly, but i think there are some issues in syntax when i convert it in my DAO class method.
I want to get whole data against the name provided
In Visualizer:
SELECT first_name,last_name,nic,phone,email FROM x_hr_user where (first_name = 'Irum');
Now in Dao
public List<XHrUser> findXHrUserByNameInTable()
{
String name ="Irum";
Query query = em.createQuery("SELECT xHrNewUserObj.firstName,xHrNewUserObj.lastName, xHrNewUserObj.nic, xHrNewUserObj.phone, xHrNewUserObj.emil FROM XHrUser xHrNewUserObj where (xHrNewUserObj.firstName) = (name)");
List<XHrUser> list = query.getResultList();
return list;
}
Instead of showing single row, it displays whole data Table
Thank you

Your current query is not valid JPQL. It appears that you intended to insert the raw name string into your query, which could be done via a native query, but certainly is not desirable. Instead, use a named parameter in your JPQL query and then bind name to it.
String name = "Irum";
Query query = em.createQuery("SELECT x FROM XHrUser WHERE x.firstName = :name")
.setParameter("name", name);
List<XhrUser> list = query.getResultList();

You have to write query as below. where : is used for variable
Query query = em.createQuery("SELECT xHrNewUserObj.firstName,xHrNewUserObj.lastName, xHrNewUserObj.nic, xHrNewUserObj.phone, xHrNewUserObj.emil FROM XHrUser xHrNewUserObj where (xHrNewUserObj.firstName) = :name");

Hibernate Subqueries

I have a situation where I need to convert a query like :-
select hostname, avg(cpu_utilization_percentage) from cpu_utilization where timestamp In (select distinct(timestamp) from report.cpu_utilization order by timestamp desc limit 6) group by hostname
Now, this data I want to fetch using hibernate so I have used Subqueries:-
// For inner Query
DetachedCriteria subquery = DetachedCriteria.forClass(CpuUtilizationDTO.class);
subquery.setProjection(Projections.distinct(Projections.property("timeStamp"))).addOrder(Order.desc("timeStamp"));
subquery.getExecutableCriteria(session).setMaxResults(6);
// For Outer Query
Criteria query = session.createCriteria(CpuUtilizationDTO.class);
ProjectionList list = Projections.projectionList();
list.add(Projections.groupProperty("hostName"));
list.add(Projections.avg("cpuUtilizationpercentage"));
query.setProjection(list);
List<Object[]> obj= (List<Object[]>)hibernateTemplate.findByCriteria(query);ction(list);
//Now to add subquery into main query I am using
query.add(Subqueries.propertyIn("timeStamp", subquery));
But everytime I am getting the average of entire data. Can anyone please help that where did I miss?

Java native query - com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException

I get following error: "com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'Card.findPrefix'"
for:
#NamedNativeQueries({
#NamedNativeQuery(name = "Card.findPrefix",
query = "SELECT DISTINCT(FLOOR(c
.number/10000)) FROM Card c")
})
public List<Integer> findPrefix(){
Query q = em.createNativeQuery("Card.findPrefix");
try{
return q.getResultList();
}catch(Exception ex){
ex.printStackTrace();
return null;
}
}
I can not understand where is my mistake, because when I type this query directly to Mysql it works perfectly.

Use should use createNamedQuery, instead of createNativeQuery.
From EntityManager JavaDoc
createNativeQuery(String sqlString)
Create an instance of Query for executing a native SQL statement, e.g., for update or delete.
createNamedQuery(String name)
Create an instance of Query for executing a named query (in the Java Persistence query language or in native SQL).
So in your code you are executing query name 'Find....' as SQL query.
The right one:
Query q = em.createNamedQuery("Card.findPrefix");

Final code is:
public List<Integer> findPrefix(){
Query q = em.createNamedQuery("Card.findPrefix");
List<Integer> res = new ArrayList<Integer>();
for(Object row : (List<Object>) q.getResultList()){
res.add(((BigInteger)row).intValue());
}
return res;
}
#NamedNativeQueries({
#NamedNativeQuery(name = "Card.findPrefix",
query = "SELECT DISTINCT(FLOOR(c.number/10000)) FROM Card c")
})

Use Criteria to select a particular field from DB?

I have a method like below
public List<String> getSimilarResourceNames(String resourceName){
String searchString = "%"+resourceName+"%";
Session session = getSession();
Criteria criteria = session.createCriteria(Resource.class);
criteria.add(Restrictions.like("name", searchString));
return criteria.list()
}
This will return me the entire resource from the DB, but what i need is just the name of the resource. How can I accomplish that ?

Use Projection, you can find examples in Hibernate documentation.
Criteria criteria = session.createCriteria(Resource.class);
criteria.setProjection(Property.forName("name"))
criteria.add(Restrictions.like("name", searchString));

By using Projection you will get other fields (Which you did not got by Projection) in your Pojo setted to default values. In HQL you can get specified column values as follow:
Query query = session.createQuery("select u.fullname from Users u");
List<Object[]> rows = query.list();
List<String> fullnames = new ArrayList<String>();
for (Object[] row: rows) {
fullnames.add(row[0]);
}
I hope this will help you.

HIbernate query

I want to execute a query using hibernate where the requirment is like
select * from user where regionname=''
that is select all the users from user where region name is some data
How to write this in hibernate
The below code is giving result appropraitely
Criteria crit= HibernateUtil.getSession().createCriteria(User.class);
crit.add(Restrictions.eq("regionName", regionName));

Well as you alaready said you can either use the Criteria API or create a HQL query:
// Criteria
List<User> users = HibernateUtil.getSession().createCriteria(User.class);
crit.add(Restrictions.eq("regionName", regionName)).list();
// HQL
String query = "SELECT FROM User WHERE regionName = :region";
List<User> users = HibernateUtil.getSession().createQuery(query).setString("region", regionName).list();

String hql = "SELECT u FROM User u WHERE regionName=:regionName";
Query q = session.createQuery(hql);
q.setParameter("regionName", regionName);
List result = q.list();