I would like to have multiple Hibernate SessionFactories in a spring application, all of them with identical configurations except for the DataSource. Ideally, I would acquire a particular SessionFactory by name. I need to be able to do this based on runtime state, and it isn't possible to determine which session factories I will need at application startup time. Basically, I need a SessionFactoryTemplate or something like it.
Is this possible? How do I go about doing it?
You might define an abstract bean and use bean inheritance. This means you'll have a bean definition that works as a template and you may have multiple beans just copying the attributes set by the parent bean.
Here's an example:
<bean id="abstractSessionFactory" abstract="true"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="mappingResources">
<list>
<value>product.hbm.xml</value>
</list>
</property>
<property name="hibernateProperties">
<value>
hibernate.dialect=org.hibernate.dialect.HSQLDialect
</value>
</property>
</bean>
<bean id="mySessionFactory" parent="abstractSessionFactory">
<property name="dataSource" ref="myDataSource"/>
...
</bean>
<bean id="mySessionFactory2" parent="abstractSessionFactory">
<property name="dataSource" ref="myDataSource2"/>
...
</bean>
Using the attribute 'abstract' you ensure that bean won't be instantiated and it will be used just as a template.
More info here: link text
Are you sure you need multiple SessionFactories? If all the mappings/configurations are the same and you just have multiple identical databases (e.g. in a multi-tenant app?), then how about having a single SessionFactory that connects to a DataSource which dynamically supplies the appropriate database connection?
See this question for more details:
And this blog post on Dynamic DataSource Routing in Spring.
I have no idea what your current bean definition looks like now, but wouldn't you just ... define a second SessionFactory?
<bean id="mySessionFactory1"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource" ref="myDataSource1"/>
<property name="mappingResources">
<list>
<value>product.hbm.xml</value>
</list>
</property>
<property name="hibernateProperties">
<value>
hibernate.dialect=org.hibernate.dialect.HSQLDialect
</value>
</property>
</bean>
<bean id="mySessionFactory2"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource" ref="myDataSource2"/>
...
</bean>
You could then simply just wire your DAOs up with one sessionFactory vs the other:
<bean id="myProductDao" class="product.ProductDaoImpl">
<property name="sessionFactory" ref="mySessionFactory1"/>
</bean>
<bean id="myCompanyDao" class="product.ProductDaoImpl">
<property name="sessionFactory" ref="mySessionFactory2"/>
</bean>
I don't know of an easy solution for your problem using Spring.
However, you could be able to use Hibernate Interceptors, provided that your particular databases/data-sources can be reached through one master/admin database connection. This blog post explains how in detail, but the gist of it is to dynamically replace table names in SQL statements that Hibernate generates, with qualified names identifying different databases. This is relatively easy to understand and maintain, and works well in my company's multi-tenant set-up.
Apart from that, you can try writing your own TransactionManager, using the HibernateTransactionManager as a starting point, adding support for working with multiple session factories. However, this would mean you having to really dive into Spring ORM support internals, and that is something I tried, but then scrapped in favor of the first approach. I'm sure it can be done with moderate effort, but the previous solution was already doing the job for us.
Related
I have an existing Project working fine, but now I have to implement a Backup System that is executed exery day and dumps the Database to a File. I want to solve this using a ScheduledTask, but this means that there is another Thread using Hibernate.
My Question: How exactly can I make Hibernate Thread safe?
I have the following code-(snippets):
In applicationContext.xml
<bean id="myEmf"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dbDataSource" />
<property name="packagesToScan" value="redb.main.core.model" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.hbm2ddl.auto">validate</prop>
<prop key="hibernate.dialect">org.hibernate.dialect.SQLServer2008Dialect</prop>
<!-- <prop key="hibernate.enable_lazy_load_no_trans">true</prop> -->
</props>
</property>
</bean>
<!-- Transaction Management -->
<tx:annotation-driven transaction-manager="txManager" />
<bean id="txManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="myEmf" />
</bean>
<bean id="persistenceExceptionTranslationPostProcessor"
class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" />
So I can get the EntityManager by
#PersistenceContext
protected EntityManager entityManager;
But if i understood it correctly, every Thread needs its own EntityManager from the EntityManagerFactory.
How can I create a new EntityManager in an other class?
I have no persistence.xml. Do I have to create it?
He-he. Welcome in the hell.
The main problem, that spring tries to do that with an aspect-based solution. Although this is buggy (or undebuggable), in trivial cases it can work.
The general answer to your question is that the EntityManagerFactory can be a global, static object in your software, although I were stoned if I simply used that.
By default, the spring aop "weaves" your application on deployment, finds all of the database entity classes by their annotations, and wraps their methods to provide always an existing entitymanager. This is the theory. But it is not the practice.
The practice is that you have very little control over what exactly will happen.
What I did: there is a servlet filter named org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter, which can open an entitymanager for every request, and flush/close that on need. Yes, its name is about "views", but soon its name is its first bug: practically we had to call it as "requesttransactionfilter" or such. It hasn't anything with the MVC views to do, it is working on the http request entities coming from your servlet container.
If you don't like to use servlet filters in a spring application, there is a also a spring interceptor named OpenEntityManagerInViewInterceptor with the very similar functionality, too.
Programmatically, you can generate an EntityManager from an EntityManagerFactory by its createEntityManager() method.
Happy googling! You are on the begin of a long way.
The issue I am having is that I use Spring to manage and load hibernate for my web application. I am currently using OpenSessionInViewFilter. This works as intended when I am viewing the application, but not so well when I am trying to access hibernate from non-view related activities such as a Quartz task or some Runnable thread I create to help with some tasks. This causes the Lazy initialize exception and no session available exceptions to occur.
Here is how I currently use Spring to manage Hibernate
<bean id="mainDataSource"
class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
[..DB config..]
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="mainDataSource"/>
</property>
</bean>
<bean id="txManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory"><ref local="sessionFactory"/></property>
<property name="dataSource"><ref local="mainDataSource"/></property>
</bean>
I then configure DAO objects which extend HibernateDaoSupport and inject them into service classes
<bean id="myDAO"
class="package.myDAO">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
<bean id="mySvcTarget" class="package.myService">
<property name="myDAO"><ref bean="myDAO"/></property>
</bean>
<bean id="myService"
class="org.springframework.transaction.interceptor.TransactionProxyFactoryBean">
<property name="transactionManager">
<ref bean="txManager"/>
</property>
<property name="target">
<ref bean="mySvcTarget"/>
</property>
<property name="transactionAttributes">
<props>
<prop key="*">PROPAGATION_REQUIRED</prop>
</props>
</property>
</bean>
So then in my application, myService is injected into my controller classes so I use that to get access to my DAO's. For my situation though it appears I need to access my DAO's (or service preferably) some other way and manually open and close my hibernate sessions since my service classes only seem to be open during view session. I am not exactly sure the best way to do this. All the hibernate configurations are there already in Spring so I'm assuming its just a matter or calling them somehow.
First of all those additional services that you're using (non-views) should be visible by Spring. The simplest way to do it is to use #Service annotation. And to make it work you can add <context:component-scan base-package="your.package"> in your configuration.
After this, if Spring sees your service as a bean, it should be enough to use #Transactional annotation to have Hibernate session in it.
I'm a newbie with Java and I need to create a console application that is going to connect with 4 databases (access, vfp, mysql and sqlserver).
I started with hibernate.cfg.xml files and managed to configure them, one for each database. Then I realized that jpa was a better solution. So I changed all my hibernate files to a persistence.xml file with 4 persistence-unit.
The databases are working well, but to use them I have to create a lot of code. This is an example:
EntityManagerFactory dbPersistence =
Persistence.createEntityManagerFactory("oneOfMyDatabases");
EntityManager em = dbPersistence.createEntityManager();
Query query = em.createQuery("from ProductEntity").setMaxResults(10);
for (Object o : query.getResultList()) {
ProductEntity c = (ProductEntity) o;
System.out.println("Product " + c.getName());
}
cgPersistence.close();
I need to update one of the databases with data from the other databases.
It's a pain to create all the code like this, so I was thinking about creating repositories but I can't see how to create them with different entityManagers for each database.
I tried to inject the managers with google guice without success, but I couldn't handle how to close or where to close the persistence connection.
Finally, I've found Spring Data and it seems to be what I need, but I don't really understand how to use it.
I need some guide to get it working because I've read tons of tutorials and each of them appear to be different:
· Can I use the same persistence.xml or do I need another configuration file? I've seen that Spring Data has jpa compatibility but I'm not sure how it works.
· Is Spring Context the IOC Container of Spring Framework? Do I need it to work with Spring Data?
· What else do I need?
Thank you in advance
Each database is going to be represented by a different data source. For every data source you need a different session factory/entity manager factory.
If you want to save in more than one data source in a single transaction you then need XA transactions, therefore a Java EE or a stand-alone transaction manager, like Bitronix or Atomikos.
You have 4 different entity manager factories, you also need specific repositories for each of those:
<jpa:repositories base-package="your.company.project.repository.access" entity-manager-factory-ref="accessEntityManagerFactory"/>
<jpa:repositories base-package="your.company.project.repository.sqlserver" entity-manager-factory-ref="sqlserverEntityManagerFactory"/>
Then your application doesn't have to care which repository it uses.
The JpaTransactionManager requires one entityManagerFactory, but since you have 4 you may end up creating for of those, which I think it's undisirable.
It's better to switch to JTA instead:
<!-- 1. You define the Bitronix config ->
<bean id="btmConfig" factory-method="getConfiguration" class="bitronix.tm.TransactionManagerServices">
<property name="serverId" value="spring-btm"/>
<property name="warnAboutZeroResourceTransaction" value="true"/>
<property name="logPart1Filename" value="${btm.config.logpart1filename}"/>
<property name="logPart2Filename" value="${btm.config.logpart2filename}"/>
<property name="journal" value="${btm.config.journal:disk}"/>
</bean>
<!-- 2. You define all your data sources ->
<bean id="dataSource" class="bitronix.tm.resource.jdbc.PoolingDataSource" init-method="init"
destroy-method="close">
<property name="className" value="${jdbc.driverClassName}"/>
<property name="uniqueName" value="dataSource"/>
<property name="minPoolSize" value="0"/>
<property name="maxPoolSize" value="5"/>
<property name="allowLocalTransactions" value="false"/>
<property name="driverProperties">
<props>
<prop key="user">${jdbc.username}</prop>
<prop key="password">${jdbc.password}</prop>
<prop key="url">${jdbc.url}</prop>
</props>
</property>
</bean>
<!-- 3. For each data source you create a new persistenceUnitManager and you give its own specific persistence.xml ->
<bean id="persistenceUnitManager" depends-on="transactionManager"
class="org.springframework.orm.jpa.persistenceunit.DefaultPersistenceUnitManager">
<property name="persistenceXmlLocation" value="classpath*:META-INF/persistence.xml"/>
<property name="defaultDataSource" ref="dataSource"/>
<property name="dataSourceLookup">
<bean class="org.springframework.jdbc.datasource.lookup.BeanFactoryDataSourceLookup"/>
</property>
</bean>
<!-- JpaDialect must be configured for transactionManager to make JPA and JDBC share transactions -->
<bean id="jpaDialect" class="org.springframework.orm.jpa.vendor.HibernateJpaDialect"/>
<!-- 4. For each data source you create a new entityManagerFactory ->
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="persistenceUnit"/>
<property name="persistenceUnitManager" ref="persistenceUnitManager"/>
<property name="jpaDialect" ref="jpaDialect"/>
</bean>
<!-- 5. You have only one JTA transaction manager ->
<bean id="jtaTransactionManager" factory-method="getTransactionManager"
class="bitronix.tm.TransactionManagerServices" depends-on="btmConfig, dataSource"
destroy-method="shutdown"/>
<!-- 6. You have only one Spring transaction manager abstraction layer ->
<bean id="transactionManager" class="org.springframework.transaction.jta.JtaTransactionManager">
<property name="transactionManager" ref="jtaTransactionManager"/>
<property name="userTransaction" ref="jtaTransactionManager"/>
</bean>
If this proves too much work for your current problem, you can give a try to having 4 JPA transaction managers and see how it works.
If your schema is same across all the databases, then the best approach is to use hibernate,because hibernate provides portability between multiple databases. once you create the hbm files and pojo classes, the only thing you need to change is the dialect and your datasource.
The transactionmanager support can be provided by spring.
I need to set the properties on a bean with common fields from different "places" so something along the lines of:
<bean id="parent1" abstract="true">
<property name="commonField" value="parent1_val"></property>
</bean>
<bean id="parent2" abstract="true">
<property name="commonField2" value="parent2_val"></property>
</bean>
<bean id="injectDemo1" class="spring.testClasses.InjectDemo1" parent="parent1" parent="parent2>
<property name="val1" value="val1"/>
</bean>
The above example does not work because only one parent attribute is allowed. But this is what I need to do; is there a mechanism in Spring that will allow me to set properties from multiple sources.
I looked at property files to do the same thing but properties files cannot hold Sets, Lists or Maps which I need or can they?
Something like:
<bean id="injectDemo1" class="spring.testClasses.InjectDemo1">
<property name="val1" value="val1"/>
<property name="commonField1" value="${prop1}"/>
<property name="commonField2" value="${prop2}"/>
</bean>
I hope I've explained it okay?
I dont think Spring beans support multiple inheritance, for the same reason the makers of Java decided to not support muliple inheritance.
Looking for some advice before I start a minor project...
I have a Java EE project which uses Spring 3 and Hibernate 3.6 to access a database, in which I've created quite a few APIs to access the database. There are several other applications that need to use these APIs (backed by the same database), so I'd like to break them out into distributable JARs.
Problem is - I can't figure out a good way to distribute a library that is backed by Hibernate. I use annotations, not config files for Hibernate. Each API has a singleton which, in my application, is setup as a Spring bean and consumes a SessionFactory. The Spring bean (copied below) has a few configuration items.
So, my questions are:
I would like to decouple the library from Spring (so the other applications don't necessarily have to use Spring). Is that realistic?
What is the best way to take a DataSource instance (the common
denominator for each application), turn it into a SessionFactory and
pass it to the singleton?
Is there a way to encapsulate the few hibernateProperties items from the bean below, so they're in the library rather than in a config file?
The singletons use the Spring transaction manager with the #Transactional annotation. Obviously that's coupled with Spring, so I suppose I'd have to remove it if I want to make this Spring-agnostic? Should I switch to programmatic transaction management?
So that's the story - does this sound doable?
Spring config:
<jee:jndi-lookup id="dataSource" jndi-name="oracleDatabase" />
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="annotatedClasses">
<list>
<value>com.company.data.DataManagerSingleton</value>
</list>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.Oracle10gDialect</prop>
<prop key="hibernate.default_schema">schema_name</prop>
<prop key="hibernate.jdbc.batch_size">20</prop>
</props>
</property>
<property name="packagesToScan">
<value>com.company.data</value>
</property>
</bean>
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory" ref="sessionFactory" />
<qualifier value="ec" />
</bean>
Thanks.