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Use Java to update XML file within different tag

I need to update xml file with adding 2 to the value but within different tag
eg:
data.xml
<?xml version="1.0"?>
<data>
<tag1>2</tag1>
<tag2>6</tag2>
<tag10>7</tag10>
<string>nochange_string</string>
</data>
to updated_data.xml
<?xml version="1.0"?>
<newdata>
<tag1>4</tag1>
<tag2>8</tag2>
<tag10>9</tag10>
<string>nochange_string</string>
</newdata>
I am aware that I would need to call a method to add 2 to each tag except last 'string' tag but I am stuck to keep the tag# as it was but everything should be in the different tag called 'newdata'. How would I do this? Thanks in advance!

A method by using XSLT makes it simple.
Input XML
<?xml version="1.0"?>
<data>
<tag1>2</tag1>
<tag2>6</tag2>
<tag10>7</tag10>
<string>nochange_string</string>
</data>
XSLT
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="utf-8" indent="yes" omit-xml-declaration="no"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/data">
<newdata>
<xsl:apply-templates select="#*|node()"/>
</newdata>
</xsl:template>
<xsl:template match="*[starts-with(local-name(), 'tag')]">
<xsl:copy>
<xsl:value-of select=". + 2"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Output XML
<?xml version='1.0' encoding='utf-8' ?>
<newdata>
<tag1>4</tag1>
<tag2>8</tag2>
<tag10>9</tag10>
<string>nochange_string</string>
</newdata>

Unable to fetch the specific entire XML tag by using XSLT

I have the below sample XML file
Sample XML:
<?xml version="1.0" encoding="UTF-8"?>
<testng-results skipped="0" failed="0" total="10" passed="10">
<class name="com.transfermoney.Transfer">
<test-method status="PASS" name="setParameter" is-config="true" duration-ms="4"
started-at="2018-08-16T21:43:38Z" finished-at="2018-08-16T21:43:38Z">
<params>
<param index="0">
<value>
<![CDATA[org.testng.TestRunner#31c2affc]]>
</value>
</param>
</params>
<reporter-output>
</reporter-output>
</test-method> <!-- setParameter -->
</class>
<class name="com.transfermoney.Transfer">
<test-method status="FAIL" name="setSettlementFlag" is-config="true" duration-ms="5"
started-at="2018-08-16T21:44:55Z" finished-at="2018-08-16T21:44:55Z">
<reporter-output>
<line>
<![CDATA[runSettlement Value Set :false]]>
</line>
</reporter-output>
</test-method> setSettlementFlag
</class>
</testng-results>
I just want to take the below piece of tags from above XML file based on status PASS (I don't want to take <?XML version, <testng-results> and class tags those are should be ignored).
Expected Output:
<test-method status="PASS" name="setParameter" is-config="true" duration-ms="4"
started-at="2018-08-16T21:43:38Z" finished-at="2018-08-16T21:43:38Z">
<params>
<param index="0">
<value>
<![CDATA[org.testng.TestRunner#31c2affc]]>
</value>
</param>
</params>
<reporter-output>
</reporter-output>
</test-method>
I just used below XSLT to get the above output from sample XML file but It doesn't work It returned all the tags but I just want the above output not other than anything.
XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml"/>"
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="class"/>
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
<xsl:for-each select="test-method[#status='PASS']">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:stylesheet>
Also Using the below java code to run the XSLT and sample XML file
Code:
String XML = fetchDataFrmXML(".//Test//testng-results_2.xml");
Transformer t = TransformerFactory.newInstance().newTransformer(new StreamSource(new StringReader(XSL)));
t.transform(new StreamSource(new StringReader(XML)), new StreamResult(new File(".//Test//Sample1.xml")));
This is the sample payload. But the actual payload had multiple nodes with "PASS" and "Failed" status. I'm just only interested to fetch the PASS node in the above output format.
Any leads....

The result you show could be obtained quite simply by doing just:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/testng-results">
<xsl:copy-of select="class/test-method[#status='PASS']" />
</xsl:template>
</xsl:stylesheet>
However, in case of more than one test-method having a status of "PASS" this will result in an XML fragment with no single root element. So you'd probably be better off doing:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/testng-results">
<root>
<xsl:copy-of select="class/test-method[#status='PASS']" />
</root>
</xsl:template>
</xsl:stylesheet>

Copy of element using java XSLT looses namespace with output html (not for first element)

I have the following XML
<root>
<a>test</a>
<b xmlns="bns">test</b>
<a>test</a>
<b xmlns="bns">test</b>
<a>test</a>
</root>
and this XSL
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" indent="no"/>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If i apply the XSL to the XML using Java the namespace of the second b-tag is removed:
<root>
<a>test</a>
<b xmlns="bns">test</b>
<a>test</a>
<b>test</b>
<a>test</a>
</root>
I noticed that this only happens for output method html. Can anybody tell me why and what i can do about it?

How to add namespace name and its value in XSLT?

I want to convert XML to XML using XSLT in JAVA. How to add namespace name and it's value in XSLT file? I have tried many ways to get the namespace value but didn't get the output what i expect. So Please do the needful.
This is my XML,
<?xml version="1.0" encoding="ISO-8859-1"?>
<root xmlns="namespacename">
<child>A</child>
<child>B</child>
</root>
XSLT file,
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:element name="root" namespace="namespacename">
<xsl:element name="child-one">
<xsl:value-of select="root/child"/>
</xsl:element>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
I need the output XML file like this.
<?xml version="1.0" encoding="ISO-8859-1"?>
<root xmlns="namespacename">
<child-one>A</child-one>
</root>

If you know the namespace, then simply add it as the default namespace and write the result as literal elements.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="namespacename"
xmlns:i="namespacename"
exclude-result-prefixes="i">
<xsl:template match="/">
<root>
<child-one>
<xsl:value-of select="i:root/i:child"/>
</child-one>
</root>
</xsl:template>
</xsl:stylesheet>
Note that the XPath expression root/child normally doesn't respect the default namespace, so you have to declare an additional namespace with a prefix (e.g. i) so the path becomes i:root/i:child. However, this also requires excluding the namespace for the result using exclude-result-prefixes="i".

Transforming XSL with XSL

A question about Martin's answer:
Martin Honnen's answer works great, but not with the root element. Let's say I have "cars" as a root element:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="foo">
<cars>
<car1 />
<car2 />
</cars>
</xsl:template>
</xsl:stylesheet>
And I want to obtain:
<xsl:template match="foo">
<cars>
<car1 />
<car2 />
<TANK />
</cars>
</xsl:template>
For this, I'd use:
<xsl:template match="cars" >
<xsl:copy>
<xsl:apply-templates/>
<TANK />
</xsl:copy>
</xsl:template>
Which outputs the exact input, without changing anything. I can try:
<xsl:template match="/" >
<xsl:copy>
<xsl:apply-templates/>
<TANK />
</xsl:copy>
</xsl:template>
But it will place the TANK node outside the stylesheet, like this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="order">
<cars>
<car1/>
<car2/>
</cars>
</xsl:template>
</xsl:stylesheet><TANK/>
How to get the TANK element inside cars?
Original question:
I have a XSL that I use to transform an XML:
XML_format1 -> XSL1 -> XML_format2
I need to transform this first XSL file (using a second XSL) to obtain a third XSL file, which will output an XML with a third format. In short:
XSL1 -> XSL2 -> XSL3
XML_format1 -> XSL3 -> XML_format3
Using the following stylesheet, I am able to copy the first XSL's contents and also skip certain nodes:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//skipThisNode"/>
</xsl:stylesheet>
My problem: in addition to this, I also need to change some nodes' structure (add something), from this:
<car>
<color>green</color>
<fuel>petrol</fuel>
</car>
To this:
<car>
<color>green</color>
<fuel>petrol</fuel>
<topSpeed>99</topSpeed>
</car>
LE: I could create a template to match the specific nodes that I need to add children to, like so:
<xsl:template match="car">
<color>
<!-- existing value-of -->
</color>
<fuel>
<!-- existing value-of -->
</fuel>
<topSpeed>
<!-- * new value-of * -->
</topSpeed>
</xsl:template>
But this seems like going over the top. Is there a simpler way of achieving what I want?

I would rather use
<xsl:param name="newSpeed" select="99"/>
<xsl:template match="car">
<xsl:copy>
<xsl:apply-templates/>
<topSpeed>
<xsl:value-of select="$newSpeed"/>
</topSpeed>
</xsl:copy>
</xsl:template>
that keeps the processing chain up, allowing you to add templates to transform or delete child and descendants of car elements when needed.
[edit]
I am not sure I understand your latest requirement as the input seems to be a complete stylesheet but then as the wanted output you have only shown a single template. So assuming you have the input as
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="order">
<cars>
<car1 />
<car2 />
</cars>
</xsl:template>
</xsl:stylesheet>
and you want to both transform the xsl:template's match attribute as well as the literal result elements in the template body I would use
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xsl:template[#match = 'order']/#match">
<xsl:attribute name="{name()}">
<xsl:text>foo</xsl:text>
</xsl:attribute>
</xsl:template>
<xsl:template match="xsl:template[#match = 'order']/cars">
<xsl:copy>
<xsl:apply-templates/>
<TANK/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
that way I get (tested with Saxon 6.5.5) the result
<?xml version="1.0" encoding="utf-8"?><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="foo">
<cars>
<car1/>
<car2/>
<TANK/></cars>
</xsl:template>
</xsl:stylesheet>
which is hopefully what you want (lacking proper indentation perhaps).