Java: Integer obj can't cast to Comparable - java

I'm having problems trying to pass an Integer object from a driver class as an argument for function of a SortedArray Generic class I created. From my driver class, I convert the user's int input into an Integer object to be cast onto Comparable of my SortedArray class.
I continue to receive the error: "Exception in thread "main" java.lang.ClassCastException: java.lang.Integer cannot be cast to Comparable". I took a look at some of my classmates' source codes only to find little difference in setting the arguments/parameters yet they have their code working just fine. I've been looking for hours trying to find what error I've made and I still can't find why my Integer object can't be cast to Comparable.
Here's a bit from my SortedArray Class
public class SortedArray implements Comparable{
public int size;
public int increment;
public int top;
Comparable[] a = new Comparable [size];
public SortedArray(int initialSize, int incrementAmount)
{
top = -1;
size = initialSize;
increment = incrementAmount;
}
public int appropriatePosition(Comparable value)
{
int hold = 0;
if(top == -1)
{
return 0;
}
else
{
for(int i = 0; i <= top; i++)
{
if(a[i].compareTo(value) > 0)
{
hold = i;
break;
}
}
}
return hold;
}
public void insert(Comparable value) //The function that my driver class needs to access
{
//Shifting numbers to the top
if(full() == true)
{
Comparable[] tempArray = new Comparable[top + increment];
for(int i= 0; i< size; i++)
{
tempArray[i]= a[i];
a = tempArray;
}
size = top + increment;
}
if(a[appropriatePosition(value) + 1] != null)
{
for(int i = top; i < appropriatePosition(value); i--)
{
a[i + 1] = a[i];
}
}
a[appropriatePosition(value) + 1]= value;
}
Here's the code for my driver class that passes Integer Object insertObj as an argument for SortedArray's insert function.
public class IntDriver {
public static void main(String[] args)
{
Scanner keyboard = new Scanner(System.in);
//Creating variables
int data;
boolean check = false;
int choice;
int size = 5;
int increment = 3;
SortedArray b = new SortedArray(size, increment);
//Creating Menu
while(check == false)
{
System.out.println("Please choose through options 1-6.");
System.out.println("1. Insert\n2. Delete\n3. Clear\n4. Smallest\n5. Largest\n6. Exit");
choice = keyboard.nextInt();
switch(choice)
{
case 1:
System.out.println("Type the int data to store in array location.");
data = keyboard.nextInt();
Integer insertObj = new Integer(data);
b.insert(insertObj);// Here's where I lay "insertObj" as an argument for the SortedArray function.
System.out.println("The value " + data + " is inserted");
break;

The problem is that Integer extends java.lang.Comparable, then your Comparable is not a java.lang.Comparable. Look at the error message, your Comparable comes from the default package rather than java.lang:
Exception in thread "main" java.lang.ClassCastException: java.lang.Integer cannot be cast to Comparable
That is, you can't cast java.lang.Integer to your own class

As mentioned by axtavt, the problem is that you have your own class Comparable. More specifically, what that means is that:
Integer.valueOf(1) instanceof java.util.Comparable == true
Integer.valueOf(1) instanceof Comparable == false
This means that somewhere in your code you have something like:
Object[] a = new Object[] {Integer.valueOf(1);};
Comparable x = (Comparable) a[0];
// or something equivalent, this is likely being passed through layers
// and not being done next to each other like this.
You need to change that to:
Object[] a = new Object[] {Integer.valueOf(1);};
java.util.Comparable x = (java.util.Comparable) a[0];
Even better, you should rename your Comparator class to something that doesn't collide with the standard classes in Java. In general, even though Java has namespacing, you should try to avoid your classes having the same name as the system classes to avoid exactly this kind of confusion.

I haven't put too much effort into this, but wouldn't it just be easier to use a SortedSet implementation (or its child interface NavigableSet) like TreeSet rather than write your own class? That is, unless you wanted duplicate elements...

Related

Inputting random integers into a file and sorting them into another file? FileIO

I'm trying to create a FileIO where random numbers are placed into a .txt file and outputted, sorted in another .txt file. I have a bubble sort code that can sort numbers & I have another code that makes a .txt file. I'm just not sure how I'd implement these 2 together.
Here's my fileIO code:
public static void main(String[] args) {
File file = new File("test.txt");
//Writes name and age to the file
try {
PrintWriter output = new PrintWriter(file);
output.println("Rober");
output.println(27);
output.close();
} catch (IOException ex) {
System.out.printf("ERROR: %s\n", ex);
}
//Reads from the file
try {
Scanner input = new Scanner(file);
String name = input.nextLine();
int age = input.nextInt();
System.out.printf("Name: %s Age %d\n", name, age);
} catch (FileNotFoundException ex) {
System.out.printf("ERROR: %s\n", ex);
}
}
And here is my bubble sort code:
public static void main(String[] args) {
Random num = new Random();
//Creating an array for 10 integers
int [] number = new int [10];
System.out.print("Random Numbers:");
/*Display the unsorted numbers in a random order.
These numbers range from 0 to 100
*/
for (int d = 0 ; d<number.length ; d++){
/* We add a "+1" to the nextInt(100) here because then the numbers
will only range from 0 to 99.
*/
int RandomG = num.nextInt(100)+1;
number[d] = RandomG;
System.out.print(" " +RandomG);
}
//Display the sorted numbers
System.out.print("\nSorted Numbers:"+Arrays.toString(BubbleSortAsceMethod(number)));
}
public static int [] BubbleSortAsceMethod(int[] number){
int placeholder;
for(int i = 0 ; i < number.length-1 ; i++){
for ( int x = 1 ; x < number.length-i ; x++){
/*If the first number in the sequence is greater than the second
number, than save the first number of sequence in placeholder
and place the second number in the first numbers position, and
put the placeholder in the second numbers position (SWAP).
*/
/*
Since this is saying that when the first term is bigger than the
2nd term, the sequence will increase. If we flip the relational
operator, the sequence will decrease.
*/
if ( number[x-1] < number[x]){
placeholder = number[x-1];
number[x-1] = number[x];
number[x] = placeholder;
}
}
}
return number;
}
I'm kinda new to all this java stuff so please go a bit easy on me! Any help at all is appreciated :)
As the data contained in the file will consist of a pair of values: The name (String) and the age (int), you will need to retain their relationship. The best way of doing this would be to create a Class to represent the data. Eventually you want to sort the data on age using your BubbleSort method. While practically this would not be your first choice to sort data, I assume that this is a requirement. The BubbleSort method you have sorts an int[] by comparing each entry against it's immediate neighbor. With int being primitive, you can directly compare each element using the < operator.
public class Person implements Comparable<Person> {
private String name;
private int age;
public Person(String name, int age) {
this.age = age;
this.name = name;
}
public String getName() { return name; }
public int getAge() { return age; }
#Override
public String toString() {
return name + System.lineSeperator() + age;
}
#Override
public int compareTo(Person person) {
return this.age - person.age;
}
}
You may want to implement the Comparable interface to compare Objects; in which the interface must be implemented by Overriding the compareTo(Person person) method. You can impose sorting on age by returning the difference in age. This is not the only way you can impose the order you want; you may wish to compare directly using the getAge() of each Object or create a Comparator object.
Using the Comparable interface does allow you to make your BubbleSort class more generic, however (though the array must be of Objects that implement the interface; hence no primitive types).
public class BubbleSort {
public static <T extends Comparable> T[] BubbleSortAsceMethod(T[] array) {
for (int i = 0; i < array.length - 1; i++) {
for (int x = 1; x < array.length - i; x++) {
if (comparator.compare(array[x - 1], array[x]) < 0) {
T placeholder = array[x - 1];
array[x - 1] = array[x];
array[x] = placeholder;
}
}
}
return array;
}
}
You will notice that this sort method has some slight differences from your original, namely the BubbleSortAsceMethod method signature with the introduction of generic type parameters. Once again, this is completely optional, though this does give you the flexibility to use this method in the future for other arrays of Classes that extend the Comparable interface.
If you don't want to use generics or the Comparable interface, you will need to change the method signature and if statement.
You're method signature should instead look like public static Person[] BubbleSortAsceMethod(Person[] array) and the if statement if (array[x-1].getAge() < array[x].getAge())
This can give you an illustration of it working, though this does not consider the file io which should be simple to implement from what you have done already.
static Random random = new Random();
public static void main (String args[]) {
int size = 100;
Person[] peopleArray = new Person[size];
for (int i = 0; i < size; i++) {
String name = generateName(random.nextInt(4) + 4);
int age = random.nextInt(100);
peopleArray[i] = new Person(name, age);
}
peopleArray = BubbleSort.BubbleSortAsceMethod(peopleArray);
}
Note that this conforms, at least as much as possible, to the code you have implemented this far. If the BubbleSort and use of arrays are not critical, data structures that implement the List interface, such as ArrayList, can allow you to implement this much cleaner. This does not use the BubbleSort method at all.
public static void main (String args[]) {
int size = 100;
ArrayList<Person> people = new ArrayList<>();
for (int i = 0; i < size; i++) {
String name = generateName(random.nextInt(4) + 4);
int age = random.nextInt(100);
people.add(new Person(name, age));
}
peopleList.sort(Person::compareTo);
//or, if you don't want to implement comparable
peopleList.sort(Comparator.comparing(Person::getAge));
}
Appendix:
Used for illustrative purposes: Generates a name of a set length (randomly).
static char[] alphabet = "abcdefghijklmnopqrstuvwxyz".toCharArray();
public static String generateName(int length) {
if (length > 0) {
return alphabet[random.nextInt(alphabet.length)] + generateName(length - 1);
}
return "";
}

Why is this a static binding instead of dynamic binding?

I'm still a little confused with regards to the difference between static and dynamic. From what I know dynamic uses object while static use type and that dynamic is resolved during runtime while static is during compile time. so shouldn't this.lastName.compareTo(s1.lastName) use dynamic binding instead?
key.compareTo(list[position-1]) use dynamic binding
public static void insertionSort (Comparable[] list)
{
for (int index = 1; index < list.length; index++)
{
Comparable key = list[index];
int position = index;
while (position > 0 && key.compareTo(list[position-1]) < 0) // using dynamic binding
{
list[position] = list[position-1];
position--;
}
list[position] = key;
}
}
Why does (this.lastName.compareTo(s1.lastName)) use static binding?
private String firstName;
private String lastName;
private int totalSales;
#Override
public int compareTo(Object o) {
SalePerson s1 = (SalePerson)o;
if (this.totalSales > s1.getTotalSales())
{
return 1;
}
else if (this.totalSales < s1.getTotalSales())
{
return -1;
}
else //if they are equal
{
return (this.lastName.compareTo(s1.lastName)); //why is this static binding??
}
}
Your question isn't complete and doesn't include all relevant the code. However this is the basic difference between the different bindings
Java has both static and dynamic binding. Binding refers to when variable is bound to a particular data type.
Static/Early binding is done at compile time for: private, final and static methods and variables. And also for overloaded methods
Dynamic/late binding is done at runtime for: methods which can be overriden methods. This is what enables polymorphic behaviour at runtime.
To further demonstrate this point have a look at this code and see if you can determine when it would be early and late binding:
/* What is the output of the following program? */
public class EarlyLateBinding {
public boolean equals(EarlyLateBinding other) {
System.out.println("Inside of overloaded Test.equals");
return false;
}
public static void main(String[] args) {
Object t1 = new EarlyLateBinding(); //1
Object t2 = new EarlyLateBinding(); //2
EarlyLateBinding t3 = new EarlyLateBinding(); //3
Object o1 = new Object();
Thread.currentThread().getStackTrace();
int count = 0;
System.out.println(count++);
t1.equals(t2);//n
System.out.println(count++);
t1.equals(t3);//n
System.out.println(count++);
t3.equals(o1);
System.out.println(count++);
t3.equals(t3);
System.out.println(count++);
t3.equals(t2);
}
}
Answer:
++ is after the count and hence the result returned is the 0 before incrementing it. Hence starts with 0 and proceeds as you expect.
The only scenario where the equals methods of EarlyLateBinding object
is actually invoked is is statement 3.
This is because the equals method is overloaded (Note: the different
method signature as compared to the object class equals)
Hence the type EarlyLateBinding is bound to the variable t3 at
compile time.
.
in this code
public static void insertionSort (Comparable[] list)
{
for (int index = 1; index < list.length; index++)
{
Comparable key = list[index];
int position = index;
while (position > 0 && key.compareTo(list[position-1]) < 0)
{
list[position] = list[position-1];
position--;
}
list[position] = key;
}
}
key can be anything that implements the Comparable interface so in the compile time compiler doesn't know the exact type so type is resolved in the runtime by using the object that key referring to.
But in this code,
#Override
public int compareTo(Object o) {
SalePerson s1 = (SalePerson)o;
if (this.totalSales > s1.getTotalSales())
{
return 1;
}
else if (this.totalSales < s1.getTotalSales())
{
return -1;
}
else //if they are equal
{
return (this.lastName.compareTo(s1.lastName));
}
}
compiler knows the type of the s1 so it use the static binding

Using compareTo function in a generic class in Java causes [Ljava.lang.Object; cannot be cast to [Ljava.lang.Comparable

I'm facing an exception: [Ljava.lang.Object; cannot be cast to [Ljava.lang.Comparable; while I try to use the compareTo function in my generic class.
Here is my code and I'm facing this issue in the function of insert():
public class BinaryTreeArray<T extends Comparable<T>>{
T[] array;
int level, count;
final int capacity;
public BinaryTreeArray(int size)
{
capacity=size;
array=(T[]) new Object[capacity];
for(int i=0; i<capacity; i++)
array[i]=null;
}
public BinaryTreeArray(T val, int size) //val is the root in this case
{
capacity=size;
array=(T[]) new Object[capacity];
array[0]=val;
count=0;
for(int i=1; i<capacity; i++)
array[i]=null;
}
public void insert(T x)
{
int currentIndex = 0;
System.out.println("Adding: "+x);
while(true) {
if(array[currentIndex]==null)
{
array[currentIndex]=x;
System.out.println(" Inserted at index: "+currentIndex);
break;
}
else if(array[currentIndex].compareTo(x)<=0)
{
if(array[currentIndex] == x){
System.out.println("ERROR!-- Repeating element" );
break;
}else
System.out.print(" Right ");
currentIndex =(2*currentIndex) + 2;
}
else if(array[currentIndex].compareTo(x)>=0)
{
if(array[currentIndex] == x){
System.out.println( "ERROR!-- Repeating element");
break;
}else
System.out.println(" Left ");
currentIndex=1+(2 * currentIndex);
}
}
}
}
Any help would be appreciated. Thank you.
Since the erasure of T is Comparable, not Object, you can't create an Object[] and cast it to a T[].
Create a Comparable[] instead.
array=(T[]) new Comparable[capacity];
However, you don't really need to constrain your class to naturally comparable types: if you also pass a Comparator<? super T> to the constructor, and store that in a field to use when you compare elements, you can accept any type.
array[currentIndex].compareTo(x)
Would become
comparator.compare(array[currentIndex], x)
That would remove the upper bound extends Comparable<T> from T, and allow your Object[] array creation to work.

Using a data structure to solve this in O(n)

we have sequence of 4 characters (A,B,C and D)that map to numbers form 1 to n.
we define components to be:
Component(k) :
A {cell[k]}
if Color(left_k) = Color(k)
then
A <-- A U Component(left_k)
if Color(right_k) = Color(k)
then
A <-- A U Component(left_k)
return A
there is 3 types of operations(the numbers in list indicate the input):
by giving index it should remove the component in that index(the numbers mapping to characters are fixed)
example : AABBBDA is the string. if index is 3 it should return AADA
by giving index it should rotate the string based on the component on that index(the numbers mapping to characters are fixed)
example : AABBBDA is the string. if index is 3 it should return DABBBAA
it should print the string.
inputs are like:
1 2 --> first operation with index=2
2 3 --> second operation with index=3
3 --> third operation
It's an assignment, happy to get help.
this is what i've tried so far:
public static void main(String[] args)
{
int numberOfOps;
String[] print = new String[30];
List list = new List();
Scanner input = new Scanner(System.in);
int count = input.nextInt();
String colors = new String();
colors = input.next();
for(int i = 0; i < count; i++)
{
list.add(colors.charAt(i));
}
numberOfOps = input.nextInt();
list.printElement();
for (int i = 0; i < numberOfOps; i++)
{
int op = input.nextInt();
if(op == 1)
{
int index = input.nextInt();
char c = list.item[index];
int temp = index;
int prevIndex = index;
int nexIndex = index;
if(index != 0)
{
while (list.item[--index] == c)
{
prevIndex--;
}
while (list.item[++temp] == c)
{
nexIndex++;
}
list.setNext(prevIndex-1, nexIndex+1);
}
else
{
while (list.item[++temp] == c)
{
nexIndex++;
}
list.setNext(prevIndex, nexIndex+1);
}
}
if(op == 2)
{
int index = input.nextInt();
}
if(op == 3)
{
print[i] = list.printElement();
}
}
}
here is my List class:
public class List {
// reference to linked list of items
public static final int MAX_LIST = 20;
public static final int NULL = -1;
public char item[] = new char[MAX_LIST]; // data
public int avail;
public int next[] = new int[MAX_LIST]; // pointer to next item
private int numItems; // number of items in list
public List()
{
int index;
for (index = 0; index < MAX_LIST-1; index++)
next[index] = index + 1;
next[MAX_LIST-1] = NULL;
numItems = 0;
avail = 0;
} // end default constructor
public void add(char e)
{
item[avail] = e;
avail = next[avail];
numItems++;
}
public String printElement()
{
String temp = null;
int index = 0;
while(index<avail)
{
temp += item[index];
System.out.println(item[index]);
index = next[index];
}
return temp;
}
public int size()
{
return numItems;
}
public void setNext(int i, int value)
{
next[i] = value;
}
}
if you test it you'll get, it has lots of problems, such as, I have no idea to do the rotate operation, and it has problem with connecting two components when the middle component has been removed.
This is a difficult question to answer, because the requirements are not properly stated.
For example the first bunch of pseudo-code does not make it clear whether A is a set, a multi-set or a list. The notation (use of curly brackets, and U (union?)) seems to say set ... but the output seems to be a list. Or maybe it is supposed to be a schema for a data structure??
And even the inputs are not clearly described.
But putting that on one side, there is still room for some (hopefully) helpful advice.
Make sure that >>you<< understand the requirements. (I imagine that the real requirements for the assignment are better stated than this, and the details have been "lost in translation".)
I would actually use an array list (or a StringBuilder) rather than a linked list for this. (But a properly implemented linked list ... implementing the List API ... would work.)
But whatever data structure you chose, there is no point in implementing it from scratch ... unless you are specifically required to do that. There are perfectly good list classes in the Java standard libraries. You should reuse them ... rather than attempting to reinvent the wheel (and doing a bad job).
If you are required to implement your own data structure type, then your current attempt is a mess. It looks like a hybrid between an array list and a linked list ... and doesn't succeed in being either. (For example, a decent array list implementation does not need a MAX_LIST, and doesn't have next pointers / indexes. And a linked list does not have any arrays inside it.)

How to find out the lowest value with a generic method?

I am trying to resolve an excercise about finding out the lowest value in array using loop. The excercise is about generics. But i have a hard to find out the solution. For an array of string i will use " if (minimum.compareTo(list[i]) > 0) ". I am stuck in how to do this with an array of integer. Any hint or help is very appreciate.
There is my code:
public class Excercise {
public static void main(String[] args) {
//Create an array
Integer[] intArray = { new Integer(45), new Integer(2), new Integer(6), new Integer(15) };
//print the lowest value
System.out.print(min(intArray));
// min(intArray);
}
public static <E extends Comparable<E>> E min(E[] list) {
E minValue = list[0];
for(int i = 1; i < list.length; i++) {
if(minValue.compareTo(list[i]) { <-- i get an error her
minValue = list[i];
return minValue;
}
}
compareTo doesn't return a boolean, so you can't use it as a condition of your if clause.
See http://docs.oracle.com/javase/7/docs/api/java/lang/Comparable.html#compareTo%28T%29
Instead, it an returns int. If the result is above zero, that means the first term is greater. If it is below, it is lesser.
So use if(minValue.compareTo(list[i])>0)) instead.
There are other bugs in the code (mostly typos). I will leave those to you.
because compareTo() method will return integer value
change
if(minValue.compareTo(list[i]) {
to
if(minValue.compareTo(list[i]) > 0) {
The proper method should be as follows:
public static <E extends Comparable<E>> E min(E[] list) {
E minValue = list[0];
for(int i = 1; i < list.length; i++) {
if( minValue.compareTo(list[i]) > 0) { //compareTo always returns an int
minValue = list[i];
}
}
return minValue; // returs the minimum after checking all the array
}

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