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spring mvc 4 + thymeleaf

thymeleaf are new and trying to integrate it in spring mvc 4.
By following this tutorial I ran into this problem:
org.springframework.beans.factory.CannotLoadBeanClassException: Cannot find class [org.thymeleaf.templateresolver.ServletContextTemplateResolver]for bean with name 'templateResolver' defined in ServletContext resource [/WEB-INF/spring-mvc-config.xml];
Now I'm sure you have all the necessary jars, could depend on what?
attached the configuration file.
spring-mvc-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="it.shakesoft.common.controller" />
<bean id="templateResolver"
class="org.thymeleaf.templateresolver.ServletContextTemplateResolver">
<property name="prefix" value="/WEB-INF/view/" />
<property name="suffix" value=".html" />
<property name="templateMode" value="HTML5" />
</bean>
<bean id="templateEngine"
class="org.thymeleaf.spring4.SpringTemplateEngine">
<property name="templateResolver" ref="templateResolver" />
</bean>
<bean class="org.thymeleaf.spring4.view.ThymeleafViewResolver">
<property name="templateEngine" ref="templateEngine" />
</bean>
</beans>

the problem was the lack of jar of thymeleaf, I had loaded only to spring mvc 4.

Spring encrypt and decrypt API key in properties file

Original Question
I have a properties file located in Tomcat and a properties file for testing located in src/test/resources.
At the moment I have the following setup. My properties files are loaded in my XML files
config.xml
<?xml version="1.0" encoding="UTF-8"?>
<!-- Repository and Service layers -->
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:cache="http://www.springframework.org/schema/cache"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/cache http://www.springframework.org/schema/cache/spring-cache.xsd">
<!-- ========================= RESOURCE DEFINITIONS ========================= -->
<context:component-scan base-package="be.omniatravel.service" />
<context:property-placeholder
location="file:${catalina.base}/conf/omniatravel.properties"
ignore-unresolvable="true" />
<tx:annotation-driven />
</beans>
test-config.xml
<?xml version="1.0" encoding="UTF-8"?>
<!-- Repository and Service layers -->
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:cache="http://www.springframework.org/schema/cache"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/cache http://www.springframework.org/schema/cache/spring-cache.xsd">
<!-- ========================= RESOURCE DEFINITIONS ========================= -->
<context:component-scan base-package="be.omniatravel.service" />
<context:property-placeholder
location="classpath:omniatravel_test.properties"
ignore-unresolvable="true" />
<tx:annotation-driven />
</beans>
And I am able to access these values by doing placing this in my Java files
public class SunnycarsClient extends WebServiceGatewaySupport {
#Value("${sunnycars.serviceUri}")
private String uri; // provided by the webservice
#Value("${sunnycars.operatingKey}")
private String key; // provide by the webservice
#Value("${sunnycars.passphrase}")
private String passphrase; // provided by the webservice
}
At the moment the operatingKey and passphrase are stored in these properties as plane text. I want to store them as an encrypted value to minimize the risk and still be able to access in the way I do now.
Update 1
So what i did now is replace the content of config.xml to
<?xml version="1.0" encoding="UTF-8"?>
<!-- Repository and Service layers -->
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:cache="http://www.springframework.org/schema/cache"
xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/cache http://www.springframework.org/schema/cache/spring-cache.xsd">
<!-- ========================= RESOURCE DEFINITIONS ========================= -->
<context:component-scan base-package="be.omniatravel.service" />
<!-- bean definitions -->
<bean
class="org.jasypt.spring.properties.EncryptablePropertyPlaceholderConfigurer">
<constructor-arg>
<bean class="org.jasypt.encryption.pbe.StandardPBEStringEncryptor">
<property name="config">
<bean class="org.jasypt.encryption.pbe.config.EnvironmentStringPBEConfig">
<property name="algorithm" value="PBEWithMD5AndDES" />
<property name="passwordEnvName" value="APP_ENCRYPTION_PASSWORD" />
</bean>
</property>
</bean>
</constructor-arg>
<property name="locations">
<list>
<value>file:${catalina.base}/conf/omniatravel.properties</value>
</list>
</property>
</bean>
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close">
<property name="sunnycarsMarshallerUri">
<value>${sunnycars.marshallerUri}</value>
</property>
<property name="sunnycarsServiceUri">
<value>${sunnycars.serviceUri}</value>
</property>
<property name="sunnycarsContextPath">
<value>${sunnycars.contextPath}</value>
</property>
<property name="sunnycarsOperatingKey">
<value>${sunnycars.operatingKey}</value>
</property>
<property name="sunnycarsPassphrase">
<value>${sunnycars.passphrase}</value>
</property>
</bean>
<tx:annotation-driven />
</beans>
But it's still not clear to me how I should access these from my Java code.
Also in the propeties files I should replace sunnycars.operatingKey = THE_KEY with sunnycars.operatingKey = enc(ENCRYPTED_KEY), but how do you get the ENCRYPTED_KEY value?

First you have to download jasypt1.9* toolkit from http://www.jasypt.org/
and
Try to run encrypt.dat file with following command in cmd like
encrypt.date input=[YOUR PROPERTY FILE VALUE] password=[encryption key value]
it will generate
output of encrypted value which you need to replace at properties file
with
=ENC(output encrypted value)
..
<bean class="org.jasypt.encryption.pbe.config.EnvironmentStringPBEConfig">
<property name="algorithm" value="PBEWithMD5AndDES" />
<property name="password" value="APP_ENCRYPTION_PASSWORD" />
</bean> ..
you can also hardcode password at class file and assign to bean as well
<bean class="org.jasypt.encryption.pbe.config.EnvironmentStringPBEConfig">
<property name="algorithm" value="PBEWithMD5AndDES" />
<property name="password" value="#Key.keyValue}" />
</bean>
where Key.keyValue is Static method of Key class.

Take a look on Jasypt. It supports encrypted properties (http://www.jasypt.org/spring31.html).

How do I configure the date format the server returns using CXF JAX-RS and Jackson 2 in XML?

This took me a lot of effort to figure out so I'm going to answer the question below. This answer doesn't use annotations and does not require creating additional classes.

You put this in your spring xml context configuration:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jaxrs="http://cxf.apache.org/jaxrs" xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://cxf.apache.org/jaxrs
http://cxf.apache.org/schemas/jaxrs.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd">
...
<bean id="jacksonMapper" class="com.fasterxml.jackson.databind.ObjectMapper">
<property name="dateFormat">
<bean class="java.text.SimpleDateFormat">
<constructor-arg type="java.lang.String" value="yyyyMMdd'T'HHmmss.SSSZ"/>
</bean>
</property>
</bean>
<bean id="jsonProvider" class="com.fasterxml.jackson.jaxrs.json.JacksonJsonProvider"
p:mapper-ref="jacksonMapper"/>
...
<jaxrs:providers>
<ref bean="jsonProvider"></ref>
</jaxrs:providers>
</jaxrs:server>

Turn on Autowire in Spring

I check my application without
<context:spring-configured/>
and the #Autowire working properly. I don't know how the container can auto inject without
<context:spring-configured/>
Here is my application-context.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:p="http://www.springframework.org/schema/p" xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-
mvc-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd">
<context:component-scan base-package="com.somepackage" />
<tx:annotation-driven transaction-manager="transactionManager" />
<mvc:annotation-driven conversion-service="conversionService" />
<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" />
<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass">
<value>org.springframework.web.servlet.view.tiles3.TilesView</value>
</property>
</bean>
<bean id="tilesConfigurer" class="org.springframework.web.servlet.view.tiles3.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean id="conversionService" class="org.springframework.context.support.ConversionServiceFactoryBean">
<property name="converters">
<set>
<bean class="com.somepackage.converter.CategoryConverter"/>
</set>
</property>
</bean>
</beans>

Autowiring is working because of
context:component-scan
Check out this javadoc

You need to add context schema into your Configuration XML to use #Autowired annotation, like below :
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-2.5.xsd">
<context:annotation-config/>
For more check the link below :
3.11. Annotation-based configuration
Also, check the difference between context:annotation-config vs context:component-scan , You were getting #Autowiring because of the context:component-scan being used in your context schema.

How to have auto suggest / auto complete for the spring config file?

<?xml version="1.0" encoding="UTF-8"?>
<bean id="reservation" class="com.youtube.Reservation" init-method="init" destroy-method="destroy">
<property name="train" ref="trainobject" />
<property name="bus" ref="busobject" />
</bean>
<bean id="busobject" class="com.youtube.Mode">
<property name="name" value="KPN" />
</bean>
<bean id="trainobject" class="com.youtube.Mode">
<property name="name" value="Shatabdi" />
</bean>
My XML looks like above. I need auto suggest for creating this spring configuration. Can anyone help?

For starters, proper beans tag would be useful.
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
Please refer to Spring documentation regarding this topic.