Dynamic array declaration in java - java

can anyone tell me the error in this java declaration String[][] t=new String[15][15]; this works fine and if i use String[][] t=new String[][]; because i need to declare the variable t as dynamic as i am not sure how much values i am going to store in t.

Use ArrayList (or other array object who can handle any number of objects). A java array always has a fixed length since some memory will be reserved for the array.
ArrayList creates such array as well to store the objects. Of you add more abjects as the current reserved size of the array than ArrayList will create a new bigger array (+50% if i'm correct). There are some other implementations that act a bit different (for example they create a new array 100% of the original one when the array is full. If performance is really important for you than you can look into this.
ArrayList<ArrayList<String> t = new ArrayList<ArrayList<String>();
void fill() {
ArrayList<String> t2 = new ArrayList<String>();
t2.add("somestring");
String s = "someotherstring";
t2.add(s);
t.add(t2);
}

If you don't know how big it needs to be just declare it as
String[][] t;
and once you know how big it needs to be you can do (before trying to use the array)
t = new String[15][15];
If you're never sure how big the array need to be, you'll need to use something like a List of Lists.
List<List<String>> t = new ArrayList<List<String>>;
public void add(String str, int row, int col) {
while (row >= t.size())
t.add(new ArrayList<String>());
List<String> row_list = t.get(row);
while (col >= row_list.size())
row_list.add("");
row_list.set(col, str);
}

In Java array objects are always of fixed length. Once you have allocated them you cannot change their size. An array variable can be made to point to different array objects of different size. So you can allocate:
String[][] t;
which doesn't point to an object and allocate an object later once you know the size:
int n1,n2;
// calculate n1,n2
t = new String[n1][n2];
If you need a structure where the size can change you are much better off using ArrayList, which can be dynamically resized.

Declare it as String [][]t = null;
And Reinitialize it with actual length once you get it.
t=new String[x][y];

As bemace said, just because you are declaring the variable doesn't mean you have to initialize it immediately.
As Mark said, arrays have a fixed size. Once an array is initialized(not declared, initialized) it has a fixed size.
So, there are two possibilities:
Either you will know how big the array needs to be before you need to start using it, in which case you can simply delay your initialization as suggested by bemace.
Or you won't know how big it needs to be before you start using it, in which case you need to use a dynamically sized data structure(s). Check out the Java Collections API:
tutorial
api reference

There are several good answers already, but it has now been revealed in a comment to Mark Baijens' answer that the purpose of this question is that raju need a key to multi-value mapping.
Mark followed up that comment by suggesting raju use a HashMap<String, String> hashMap = new HashMap<String, String>(); — however that only works for a single key-value pair.
What raju needs is a
Map<String, Collection<String>> t
= new HashMap<String, List<String>>();
Adding the first value for a key requires initialization of a List for that bucket, while adding additional values requires fetching the existing list and adding the new value.
Note I used Collection<String> in the declaration, so it could be a List if the order of values is important, or it could be a Set to prevent duplicate values under the same key.
This would probably be best implemented as a Class itself, perhaps
public class MultiValueMap<K, V> extends Map<K, V>
{
...
}
so the initialization of the List on the first put(key, value) and the subsequent .add(value) to the list could be hidden in the implementation.

Related

Is This The Best Way To "Increase" The Size of An ArrayList?

ArrayList<T> tempArray = new ArrayList<>(size);
I was building a tempArray for my merge sort that will either sort integers or Strings depending on the context. Hence the type T ArrayList.
Then all the sudden I kept running into IndexOutOfBounds errors whenever this was called:
tempArray.set(index, values.get(leftFirst));
After some research I discovered capacity and size don't mean the same thing. So in order to "increase" the size I just added a for loop that runs for size times that adds a null each time:
for (int i = 0; i < size; i++)
tempArray.add(null);
Is this the best solution?
You are trying to use ArrayList as a map, so just switch to Map and hold your keys as integers:
Map<Integer, Object> map = new HashMap<>(size);
map.put(index, values.get(leftFirst));
and then get the index by map.get method:
map.get(index)
Notice if your index start with a million, you will have ~million null values that won't be used. it seems very unnecessary and wrongly implemented.
EDIT
from comments/question, declare your map using T:
Map<Integer, T> map = new HashMap<>(size);
In my opinion the best way is first to create an array of generic type, and after that to create the wrapper with ArrayList.
1.You can see how to create array from generic types here
2.You can see how to create ArrayList from an array here

How to initiate multidimensional arraylist with different objects?

I'm having trouble trying to initiate an arraylist in which the first column I want to be a string, and the second column be a custom object.
For example column [0] be String, and column[1] be an Integer. Convention attempts of creating a multidimensional arraylist as in those used by int[][] or String[][] don't seem to work :( I would welcome any help. At this point I don't think it's something java allows. I can make it work for just one type of object but it's not what I want. Thanks!
Do you need an arraylist? You could create a Map<String, Object> or Map<String, Integer> or whatever you need..
Sure it does, but you weaken/eliminate type-checking:
Map myMap<String>, Integer> myData = new HashMap<String, Integer>();
Now your list of strings can be retrieved by myMap.keySet() and values can be retrieved by myMap.values(). Each of these return a Set, which you can easily convert to a List using the following code:
List<String> strings = new ArrayList<String>(myMap.keySet()); // get your strings
List<Integer> numbers = new ArrayList<Integer>(myMap.values(); // get your numbers
Good luck and if you should run into problems, do leave a comment.
Arrays are geared towards one specific type of thing - be they Object or String or int. Despite the fact that you're adding multiple dimensions to them, they still only hold one type of information.
What you would rather have is a mapping between two objects. This allows you to do the following:
Associate any key to a particular value
Eliminate duplicate key entries
Be much easier to access instead of array indexing
Here's an example. Say your custom object is a Cat, and you want to map the name of the owner to a particular Cat. You create a new instance of a Map.
Map<String, Cat> catOwners = new HashMap<>();
You can then put elements into it...
catOwners.put("Jamie", new Cat("Tycho"));
...and retrieve them with relative ease.
Cat currentCat = catOwners.get("Jamie"); // gets Jamie's cat
if you really want to, you can even iterate over them using the Map.Entry object provided with all Maps:
for(Map.Entry<String, Cat> element : catOwners.entrySet()) {
System.out.println(element.getKey()
+ " owns " + element.getValue().getName());
}
What you can do is use the generic Object type, and cast accordingly.

Best and fastest way to return an array from a map based on some condition

I'm trying to figure out the best and most efficient way for this scenario with a map. It needs to be an array. I've made a dummy example to explain this.
Basically if there is a map that consists of some sandwhich id and and sandwhich details and I only want the ones with lettuce to be in an array.
The problem with arrays is that the size must be known, in this case I do not know how many sandwhiches with lettuces there will be. I could use an array list but I would need to convert it to an array - some copy method which would make this inefficient.
Example:
//Assume that this map is given
Map<Integer, Sandwich> sandwiches = //some method gets all sandwiches
Meal[] meal = new Meal[sandwiches.size()];
for(Map.Entry<Integer, Sandwich> e : sandwiches.entrySet())
{
if(e.getValue().hasLettuce())
meal = new Meal(e.getValue);
}
//mandatory: An array must be returned
return meal;
Use an ArrayList. There's no way to avoid making copies if you don't know how many Meals you'll need, the amortized cost of the copies is cheap, and lists are a better conceptual fit for the problem than arrays anyway. You can call list.toArray(new Meal[0]) to get an array if you really want one.

Input stored in Arraylist or String array? (New programmer) Java

It seems to me like ArrayList would be easier to use in nearly every scenario, it being very versatile. Is there an instance where a String[] would be used to store inputted data? If there is such a case, there must be a drawback in ArrayList, what would that be?
Only thing that comes to mind off the top of my head would be the variety of String methods like, substring() and split(), etc.
EDIT: New to StackOverflow as well. I apologize if this was a re-post. And thanks for the formatting.
The short answer is: don't use an array, always use an array list. The only exception to this is if you absolutely need to control the amount of memory used or you have some specific performance constraint that only String[] can support.
In general, though, arrays are terrible to work with in an object oriented language, and almost always for the same reason: they make it very easy to break encapsulation. For example:
public class ExampleArray {
private final String[] strings;
public ExampleArray(String... strings) { this.strings = strings; }
public String[] getStrings() { return strings; }
}
See any problems? Yea, you need to write getStrings() like this:
// ...
public String[] getStrings() { return Arrays.copy(strings); }
// ...
Otherwise, some caller can get a hold of your class' internal data and start modifying it. The only way to prevent this is to copy it every time a caller wants to see it. As opposed to the right way:
public class ExampleList {
private final List<String> strings;
// ...
public List<String> getStrings() { return Collections.unmodifiableList(strings); }
}
Now you're not copying the data, you're just sticking it behind an API that doesn't allow changes. If you use the Guava Immutable* classes, even better.
Of course there are situations where you want to use String[] instead. If you know in advance how long the list will be, for instance, and the list might be large.
The main disadvantage of using ArrayList is that as the list grows, the array has to be reallocated, which isn't a free operation. You can mitigate that by preallocating it to be the size (or larger) you expect using the constructor that accepts an initialCapacity.
ArrayList is dynamic grow-able array in size, Where as string array or any type of array is static in size.
Obviously this dynamic grow features cause some cost, it reallocate the array with new size and copy element to it.
You can initialize Java arrays at compile time, like:
String data[] = { "a", "b", "c" };
In old versions of Java there was also the case for type safety. ArrayList elements had to be casted to the original type whereas Java arrays where type safe.
Java arrays are part of the language and you will not be able to change them. ArrayList is part of the Java API. If you need (I do not recommend it though) you could substitute your own library to implement the ArrayList job.
Check out these questions asked by others in stackoverflow:
Array or List in Java. Which is faster?
Java Performance - ArrayLists versus Arrays for lots of fast reads
The only case that comes to my mind when array is used to hold some values is when there's a method taking variable number of arguments like:
void doSth(int i, String... strings){
if(strings.length>0){
//some stuff
}
Otherwise I hardly ever intentionally create a situation, when array needs to be used.

Java array of Hashtables

I need an array of Hashtables in a program that is storing all words from a given set of documents.
Index 1 of the array holds a hashtable of String -> Double which stores a word, and its count for document 1 (array index 100 = document number 100's hashtable).
I dont need help using this data structure, just in creating it.
I declare the Hashtable Array as follows:
Hashtable<String,Double>[] h1 = new Hashtable<String,Double>[];
... but this does not compile.
(NOTE: The Double is necessary rather than an Integer in the above declaration for later usage.)
QUESTION:
How do you create an array of hashtables which stores String->Double ???
Any suggestions appreciated guys....
... but this does not compile.
That's because the array has no name, new expects a number of elements and you can't just allocate an array of generics. Prefer a List instead:
List<Hashtable<String,Double>> wordCountPerDoc
= new ArrayList<Hashtable<String,Double>>();
just use
#SuppressWarnings("unchecked")
Hashtable<String,Double>[] h = (Hashtable<String,Double>[])new Hashtable<?,?>[10];
h[0] = new Hashtable<String, Double>();
why don't you use a Map<Integer, Map<String, Double> > ?
this way you don't waste space for non-existing documents, and still get O(1) retrieval.
you can create like this.
Hashtable<String,Double>[] arr = new Hashtable[10];
Two things: you can't declare an array with the parameterized types like that; you have to imply declare it a new Hashtable[]. And you need to give the array a length.
Mixing arrays and Collections, although possible, tends to be confusing and lead to problems in my experience; also HashMap is generally preferred to Hashtable. So I would tend to prefer a List<Map<String, Double>> for this application.
The reasons why this is an error are covered in Angelika Langer's Generics FAQ: Can I create an array whose component type is a concrete parameterized type?
Can I create an array whose component type is a concrete parameterized type?
No, because it is not type-safe.
Arrays are covariant, which means that
an array of supertype references is a
supertype of an array of subtype
references. That is, Object[] is a
supertype of String[] and a string
array can be accessed through a
reference variable of type Object[].
Arrays and generics can have odd interactions (largely due to implementation compromises to support compatibility). You may be better off (as larsmans suggested) looking at a suitable collection type such as a List of Maps.
An array seems to be an unusual choice of structure here. Perhaps you should consider storing your hashtables in a List. It will dynamically resize for you if you don't know how many document you will have ahead of time. If you use an ArrayList, you will still have constant-time reads of random indeces (like an array.) I think it's much simpler than using an array, and you still get the generic type checking. If you choose a List, you syntax becomes:
List<Map<String,Double>> documentWordCounts = new ArrayList<Map<String,Double>>();
Or choose a LinkedList depending on what kind of read/write pattern you want.
For fixed size array:
Hashtable<String,Double>[] h1 = new Hashtable[]{new Hashtable< String,Double>(),new Hashtable< String,Double>(),new Hashtable< String,Double>()};

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