I'm using Java AWT to draw lines on a panel (Line2D and Graphics2D.drawLine()) and I'm wondering how I can draw a line with tick marks, similar to:
|----|----|----|----|----|
I know the positions I'd like to draw the ticks at in advance.
The lines could be in any position, so the ticks must be drawn at an angle releative to the line itself.
My basic geometry & ability to apply it in Java is failing me. :)
I suggest you
implement a ruler-drawing-method that draws a simple horizontal ruler from left to right
Figure out the desired angle using Math.atan2.
Apply an AffineTransform with translation and rotation before invoking the ruler-drawing-method.
Here is a complete test-program. (The Graphics.create method is used to create a copy of the original graphics object, so we don't mess up the original transform.)
import java.awt.*;
public class RulerExample {
public static void main(String args[]) {
JFrame f = new JFrame();
f.add(new JComponent() {
private final double TICK_DIST = 20;
void drawRuler(Graphics g1, int x1, int y1, int x2, int y2) {
Graphics2D g = (Graphics2D) g1.create();
double dx = x2 - x1, dy = y2 - y1;
double len = Math.sqrt(dx*dx + dy*dy);
AffineTransform at = AffineTransform.getTranslateInstance(x1, y1);
at.concatenate(AffineTransform.getRotateInstance(Math.atan2(dy, dx)));
g.transform(at);
// Draw horizontal ruler starting in (0, 0)
g.drawLine(0, 0, (int) len, 0);
for (double i = 0; i < len; i += TICK_DIST)
g.drawLine((int) i, -3, (int) i, 3);
}
public void paintComponent(Graphics g) {
drawRuler(g, 10, 30, 300, 150);
drawRuler(g, 300, 150, 100, 100);
drawRuler(g, 100, 100, 120, 350);
drawRuler(g, 50, 350, 350, 50);
}
});
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.setSize(400, 400);
f.setVisible(true);
}
}
Note, that you could just as easily draw numbers above the ticks. The drawString-calls would go through the same transformation and get nicely "tilted" along the line.
Things that need noting:
A perpendicular line has a slope of -1/oldslope.
In order to support lines in any direction, you need to do it parametrically
Thus, you have dy and dx across the original line, which means that newdx=dy; newdy=-1*dx.
If you have it such that <dx, dy> is a unit vector (sqrt(dx*dx+dy+dy)==1, or dx==cos(theta); dy=sin(theta) for some theta), you then just need to know how far apart you want the tick marks.
sx, sy are your start x and y
length is the length of the line
seglength is the length of the dashes
dx, dy is the slopes of the original line
newdx, newdy are the (calculated above) slopes of the cross lines
Thus,
Draw a line from <sx,sy> (start x,y) to <sx+dx*length,sy+dy*length>
Draw a set of lines (for(i=0;i<=length;i+=interval) from <sx+dx*i-newdx*seglength/2,sy+dy*i-newdy*seglength/2> to <sx+dx*i+newdx*seglength/2,sy+dy*i+newdy*seglength/2>
I hope you know matrix multiplication. In order to rotate a line you need to multiple it by rotation matrix. (I coudln't draw a proper matrix but assume both line are not separated)
|x'| = |cos(an) -sin(an)| |x|
|y`| = |sin(an) cos(an)| |y|
The old points are x,y and the new is x',y'. Let us illustrate by an example, lets say you have a vertical line from (0,0) to (0,1), now you want to rotate it by 90 degrees. (0,0) will remain zero so lets just see what happens to (0,1)
|x'| = |cos(90) -sin(90)| |0|
|y`| = |sin(90) cos(90)| |1|
==
|1 0| |0|
|0 1| |1|
==
| 1*0 + 0*1|
| 0*0 + 1*1|
== |0|
|1|
you get to horizontal line (0,0),(0,1) like you would expect.
Hope it helps,
Roni
Related
I like to have maximum control over the screen, so I have to control every pixel, and that has some pros and cons. one con is that I don't really have the help from any built-in functions. so I have no idea how to draw a line.
I've tried to make a function to handle line drawing but I just can't get it to work!
here's the code I used to draw the line
int startX;
int startY;
int deltaX = x1/x2;
int deltaY = y1/y2;
float deltaPixl = deltaX/deltaY;
for(int i=0;i<deltaY;i=i+1){
if(x1>x2){ startX = x2;}else{ startX=x1;}
if(y1>y2){ startY = y2;}else{ startY=y1;}
pixl(startX+i,round(startY+(deltaPixl*i)),0);
}
it uses a function called pixl so that it easily draw a pixel to the pixel array,
just to clarify why there's a function called pixl in the code.
and when I try to use this code, it doesn't crash, like processing usually does when it has an error!
it just doesn't work, instead just doing nothing!
I'd like some help on this subject, please.
You could get away with simply using PGraphics.
The idea is once you have a PGraphics instance you use dot notation to access the drawing functions used to (as long as they're called between .beginDraw() and .endDraw()).
Using noSmooth() you can get it looking pixel perfect.
Here's a basic sketch to illustrate the idea:
// disable anti-aliasing
noSmooth();
// create a PGraphics layer
PGraphics layer = createGraphics(25, 25);
// render a line
layer.beginDraw();
layer.line(0, 24, 24, 0);
layer.endDraw();
// render the line at 100%
image(layer, 0, 0);
// render the line scaled up
image(layer, 0, 0, width, height);
This should do for most cases. (It's only trickier cases with very small values and transparency that might give you headaches)
If for some reason you need a lot more control, you can you always implement your own method of rasterising. Once place you can probably start with is Bresenham's line algorithm
Regarding your code there are a few things that could go wrong:
float deltaPixl = deltaX/deltaY;: if deltaY is zero you'll run into an exception
you're doing integer division for deltaX and deltaY (potentially making it likely to get 0 for either of the values)
you should try a println() statement before the for loop with the start/end values to get a feel if that loop will actually execute or not. Additionally, within the for loop you can println(i) to see if you get the value you expect.
Overall I recommend checking Kevin Workman's How to Debug guide.
Additionally you could use lerp() to calculate linearly interpolated position between the line's start and end points. Pass each coordinate and a normalized (between 0.0, 1.0) value, where 0.0 = at the start point, 1.0 = at the end point and anything in between is on the line (e.g. 0.5 = 50% along the line).
Here's a basic example:
void drawLinePoints(int x1, int y1, int x2, int y2, int numberOfPoints){
// for each point
for(int i = 0; i < numberOfPoints; i++){
// map the counter to a normalized (0.0 to 1.0) value for lerp
// 0.0 = 0 % along the line, 0.5 = 50% along the line, 1.0 = 100% along the line
float t = map(i, 0, numberOfPoints, 0.0, 1.0);
// linearly interpolate between the start / end points (and snap to whole pixels (casting to integer type))
int x = (int)lerp(x1, x2, t);
int y = (int)lerp(y1, y2, t);
// render the point
point(x, y);
}
}
void setup(){
// render points are large squares
strokeWeight(6);
strokeCap(PROJECT);
}
void draw(){
// clear frame
background(255);
// calculate distance
float distance = dist(10, 10, mouseX, mouseY);
// map distance the number of points to illustrate interpolation (more points = continuous line)
int numPoints = (int)distance / 8;
// render points along the line
drawLinePoints(10, 10, mouseX, mouseY, numPoints);
}
For the sake of completeness here's the above snippet using the pixels[] instead:
void drawLinePoints(int x1, int y1, int x2, int y2, int numberOfPoints){
// for each point
for(int i = 0; i < numberOfPoints; i++){
// map the counter to a normalized (0.0 to 1.0) value for lerp
// 0.0 = 0 % along the line, 0.5 = 50% along the line, 1.0 = 100% along the line
float t = map(i, 0, numberOfPoints, 0.0, 1.0);
// linearly interpolate between the start / end points (and snap to whole pixels (casting to integer type))
int x = (int)lerp(x1, x2, t);
int y = (int)lerp(y1, y2, t);
// convert the x, y coordinate to pixels array index and render the point in black
pixels[x + (y * width)] = color(0);
}
}
void setup(){
noSmooth();
}
void draw(){
// clear frame
loadPixels();
java.util.Arrays.fill(pixels, color(255));
// calculate distance
float distance = dist(10, 10, mouseX, mouseY);
// map distance the number of points to illustrate interpolation (more points = continuous line)
int numPoints = (int)distance;
// render points along the line
drawLinePoints(10, 10, mouseX, mouseY, numPoints);
// update pixels
updatePixels();
}
I'm a bit late but I found a very simple method for line drawing to a pixel array on this website.
Here is a simple implementation I made in Monogame (btw sorry its not using processing - I have never used it):
public void drawLine(int x1, int y1, int x2, int y2)
{
//this will store the colour data of the canvas pixels
Color[] canvasData = new Color[canvas.Width * canvas.Height];
//store the pixel data of the canvas in canvasData
canvas.GetData<Color>(canvasData);
//drawing line starts here
int dx = x2 - x1;
int dy = y2 - y1;
for (int x = x1; x < x2; x++)
{
int y = y1 + dy * (x - x1) / dx;
//[y*canvas.Width+x] converts the 2d array index to a 1d array index
canvasData[y * canvas.Width + x] = Color.Black;
}
//line drawing ended
//setting the canvas' pixels to the modified pixels with the line
canvas.SetData<Color>(canvasData);
}
I'm drawing two shapes (circles) in a JPanel and I need to connect them with a line. I was doing this by just getting the middle point of the circle and connecting each other, easy.
The problem is that now I need to make single-direction lines, which has an "arrow" at the end, to point out which direction the line goes. So now I can't use the middle point of the circle because I need to connect each other from border to border, so the "arrow' can appear correctly.
On my last try that was the result, nothing good:
PS: In the screenshot I'm not filling the circles just to see the exact position of the line, but normally I would fill it.
I'm having trouble to calculate the exact position of the border I need to start/end my line. Anyone has any idea on how to do this?
EDIT: The circles are movable, they could be in any position, so the line should work in any case.
Okay, so basically, we can break down the problem to basic issues:
Get the angle between the two circles
Draw a line from circumference of one circle to another along this angle
Both these issues aren't hard to solve (and any time spent searching the internet would provide solutions - because that's where I got them from ;))
So, the angle between two points could be calculated using something like...
protected double angleBetween(Point2D from, Point2D to) {
double x = from.getX();
double y = from.getY();
// This is the difference between the anchor point
// and the mouse. Its important that this is done
// within the local coordinate space of the component,
// this means either the MouseMotionListener needs to
// be registered to the component itself (preferably)
// or the mouse coordinates need to be converted into
// local coordinate space
double deltaX = to.getX() - x;
double deltaY = to.getY() - y;
// Calculate the angle...
// This is our "0" or start angle..
double rotation = -Math.atan2(deltaX, deltaY);
rotation = Math.toRadians(Math.toDegrees(rotation) + 180);
return rotation;
}
And the point on a circle can be calculated using something like...
protected Point2D getPointOnCircle(Point2D center, double radians, double radius) {
double x = center.getX();
double y = center.getY();
radians = radians - Math.toRadians(90.0); // 0 becomes the top
// Calculate the outter point of the line
double xPosy = Math.round((float) (x + Math.cos(radians) * radius));
double yPosy = Math.round((float) (y + Math.sin(radians) * radius));
return new Point2D.Double(xPosy, yPosy);
}
Just beware, there's some internal modifications of the results to allow for the difference between the mathematical solution and the way that the Graphics API draws circles
Okay, so big deal you say, how does that help me? Well, I great deal actually.
You'd calculate the angle between the to circles (both to and from, you might be able to simple inverse one angle, but I have the calculation available so I used it). From that, you can calculate the point on each circle where the line will intersect and then you simply need to draw it, something like...
double from = angleBetween(circle1, circle2);
double to = angleBetween(circle2, circle1);
Point2D pointFrom = getPointOnCircle(circle1, from);
Point2D pointTo = getPointOnCircle(circle2, to);
Line2D line = new Line2D.Double(pointFrom, pointTo);
g2d.draw(line);
Runnable Example
Because I've distilled much of the calculations down to communalised properties, I've provided my test code as a runnable example. All the calculations are based on dynamic values, nothing is really hard coded. For example, you can change the size and positions of the circles and the calculations should continue to work...
import java.awt.Color;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Shape;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Line2D;
import java.awt.geom.Point2D;
import java.awt.geom.Rectangle2D;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
public class Test {
public static void main(String[] args) {
new Test();
}
public Test() {
EventQueue.invokeLater(new Runnable() {
#Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new TestPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public class TestPane extends JPanel {
private Ellipse2D circle1;
private Ellipse2D circle2;
private Point2D drawTo;
public TestPane() {
circle1 = new Ellipse2D.Double(10, 10, 40, 40);
circle2 = new Ellipse2D.Double(100, 150, 40, 40);
//addMouseMotionListener(new MouseAdapter() {
// #Override
// public void mouseMoved(MouseEvent e) {
// drawTo = new Point2D.Double(e.getPoint().x, e.getPoint().y);
// repaint();
// }
//});
}
protected Point2D center(Rectangle2D bounds) {
return new Point2D.Double(bounds.getCenterX(), bounds.getCenterY());
}
protected double angleBetween(Shape from, Shape to) {
return angleBetween(center(from.getBounds2D()), center(to.getBounds2D()));
}
protected double angleBetween(Point2D from, Point2D to) {
double x = from.getX();
double y = from.getY();
// This is the difference between the anchor point
// and the mouse. Its important that this is done
// within the local coordinate space of the component,
// this means either the MouseMotionListener needs to
// be registered to the component itself (preferably)
// or the mouse coordinates need to be converted into
// local coordinate space
double deltaX = to.getX() - x;
double deltaY = to.getY() - y;
// Calculate the angle...
// This is our "0" or start angle..
double rotation = -Math.atan2(deltaX, deltaY);
rotation = Math.toRadians(Math.toDegrees(rotation) + 180);
return rotation;
}
protected Point2D getPointOnCircle(Shape shape, double radians) {
Rectangle2D bounds = shape.getBounds();
// Point2D point = new Point2D.Double(bounds.getX(), bounds.getY());
Point2D point = center(bounds);
return getPointOnCircle(point, radians, Math.max(bounds.getWidth(), bounds.getHeight()) / 2d);
}
protected Point2D getPointOnCircle(Point2D center, double radians, double radius) {
double x = center.getX();
double y = center.getY();
radians = radians - Math.toRadians(90.0); // 0 becomes th?e top
// Calculate the outter point of the line
double xPosy = Math.round((float) (x + Math.cos(radians) * radius));
double yPosy = Math.round((float) (y + Math.sin(radians) * radius));
return new Point2D.Double(xPosy, yPosy);
}
#Override
public Dimension getPreferredSize() {
return new Dimension(200, 200);
}
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
g2d.draw(circle1);
g2d.draw(circle2);
// This was used for testing, it will draw a line from circle1 to the
// drawTo point, which, if enabled, is the last known position of the
// mouse
//if (drawTo != null) {
// Point2D pointFrom = center(circle1.getBounds2D());
// g2d.setColor(Color.RED);
// g2d.draw(new Line2D.Double(drawTo, pointFrom));
//
// double from = angleBetween(pointFrom, drawTo);
// System.out.println(NumberFormat.getNumberInstance().format(Math.toDegrees(from)));
//
// Point2D poc = getPointOnCircle(circle1, from);
// g2d.setColor(Color.BLUE);
// g2d.draw(new Line2D.Double(poc, drawTo));
//}
double from = angleBetween(circle1, circle2);
double to = angleBetween(circle2, circle1);
Point2D pointFrom = getPointOnCircle(circle1, from);
Point2D pointTo = getPointOnCircle(circle2, to);
g2d.setColor(Color.RED);
Line2D line = new Line2D.Double(pointFrom, pointTo);
g2d.draw(line);
g2d.dispose();
}
}
}
Arrow head
The intention is to treat the arrow head as a separate entity. The reason is because it's just simpler that way, you also get a more consistent result regardless of the distance between the objects.
So, to start with, I define a new Shape...
public class ArrowHead extends Path2D.Double {
public ArrowHead() {
int size = 10;
moveTo(0, size);
lineTo(size / 2, 0);
lineTo(size, size);
}
}
Pretty simple really. It just creates two lines, which point up, meeting in the middle of the available space.
Then in the paintComponent method, we perform some AffineTransform magic using the available information we already have, namely
The point on our target circles circumference
The angle to our target circle
And transform the ArrowHead shape...
g2d.setColor(Color.MAGENTA);
ArrowHead arrowHead = new ArrowHead();
AffineTransform at = AffineTransform.getTranslateInstance(
pointTo.getX() - (arrowHead.getBounds2D().getWidth() / 2d),
pointTo.getY());
at.rotate(from, arrowHead.getBounds2D().getCenterX(), 0);
arrowHead.transform(at);
g2d.draw(arrowHead);
Now, because I'm crazy, I also tested the code by drawing an arrow pointing at our source circle, just to prove that the calculations would work...
// This just proofs that the previous calculations weren't a fluke
// and that the arrow can be painted pointing to the source object as well
g2d.setColor(Color.GREEN);
arrowHead = new ArrowHead();
at = AffineTransform.getTranslateInstance(
pointFrom.getX() - (arrowHead.getBounds2D().getWidth() / 2d),
pointFrom.getY());
at.rotate(to, arrowHead.getBounds2D().getCenterX(), 0);
arrowHead.transform(at);
g2d.draw(arrowHead);
Let the first circle center coordinates are AX, AY, radius AR, and BX, BY, BR for the second circle.
Difference vector
D = (DX, DY) = (BX - AX, BY - AY)
Normalized
d = (dx, dy) = (DX / Length(D), DY / Length(D))
Start point of arrow
S = (sx, sy) = (AX + dx * AR, AY + dy * AR)
End point
E = (ex, ey) = (BX - dx * BR, BY - dy * BR)
Example:
AX = 0 AY = 0 AR = 1
BX = 4 BY = 3 BR = 2
D = (4, 3)
Length(D) = 5
dx = 4/5
dy = 3/5
sx = 0.8 sy = 0.6
ex = 4 - 2 * 4/5 = 12/5 = 2.4
ey = 3 - 2 * 3/5 = 9/5 = 1.8
Looking at the Screenshot, I think you need to find the top right corner of circle A, and then add half of the total distance to the bottom to y. Next, find the top right corner of circle B, and add half of the distance to the top left corner to x. Finally, make a line connecting the two, and render an arrow on the end of it.
Like this:
private int x1, y1, x2, y2 width = 20, height = 20;
private void example(Graphics g) {
// Set x1, x2, y1, and y2 to something
g.drawOval(x1, y1, width, height);
g.drawOval(x2, y2, width, height);
g.drawLine(x1, y1 + (height/2), x2 + (width/2), y2);
g.drawImage(/*Image of an arrow*/, (x2 + width/2)-2, y2);
}
My trick:
Let the two centers be C0 and C1. Using complex numbers, you map these two points to a horizontal segment from the origin by the transformation
P' = (P - C0) (C1 - C0)* / L
where * denotes conjugation and L = |C1 - C0|. (If you don't like the complex number notation, you can express this with matrices as well.)
Now the visible part of the segment goes from (R0, 0) to (L - R1, 0). The two other vertices of the arrow are at (L - R1 - H, W) and (L - R1 - H, -W) for an arrowhead of height H and width 2W.
By applying the inverse transform you get the original coordinates,
P = C0 + L P' / (C1 - C0)*.
I'm creating a graphical display to show whether a user is approaching a danger zone. For this i'm using a display similar to that of an archery board. The idea is to start in the center, but as the user gets closer to the danger zone enter the orange zone. And once the user breaks the 'safety threshold' enter the red zone. My idea is to draw a point on the board depending on what value the user gives me.
To draw this board I do the following.
Graphics2D g2d = (Graphics2D) bs.getDrawGraphics();
g2d.setColor(Color.white);
g2d.fillRect(0, 0, 800, 600); //set screen to white
g2d.setColor(Color.red);
g2d.fillOval(250, 250, 175, 175); //draw outerlayer of board as red
g2d.setColor(Color.black);
g2d.drawOval(250, 250, 175, 175);//give this red an outline
g2d.setColor(Color.orange);
g2d.fillOval(275, 275, 125, 125); //draw innerlayer as orange
g2d.setColor(Color.black);
g2d.drawOval(275, 275, 125, 125);//give this orange an outline
g2d.setColor(Color.green);
g2d.fillOval(300, 300, 75, 75); //draw innermost layer as green
g2d.setColor(Color.black);
g2d.drawOval(300, 300, 75, 75); //give the green an outline
First of all I could probably improve this, but that's not the main issue for now.
Instead my issue is finding exactly the pixels covered by each part of the board.
I've been using x+(width/2), y+(height/2) to get the center point
Thus using:
g2d.drawString(String.valueOf("X"), 338, 338);
To draw the center point of my green oval. This doesn't seem overly accurate but anyway.
I thought I would be able to simply give the outer edge as the x,y co-ords and the inner edge as the x+height, y+width co-ords as so:
g2d.drawOval(500, 500, 75, 75);
g2d.drawString(String.valueOf("X"), 537, 537); //centre???
g2d.drawString(String.valueOf("X"), 575, 575); //inneredge?x+width, y+height
g2d.drawString(String.valueOf("X"), 500, 500); //outer edge x+y co-ords
However, I think due to the oval shape this doesn't work.
I would be very grateful if someone could show me how to find the pixel range that each oval covers.
EDIT: Below is the board that i'm using, is it possible to find the pixel range for each color(Red,Orange,Green)?
Understanding a bit more what you wanted, here is the trick (using trigonometry):
int force = ...; // from 0 to 250
int radius = ...; // radius of the target (50 for example)
int centerX = ...; // X-coordinate of the center of the target
int centerY = ...; // Y-coordinate of the center of the target
double direction = Math.toRadians(Math.random() * 360); // a random angle between 0° and 360°
double x = (force * radius / 250.0d) * Math.cos(direction) + centerX; // X-coordinate of the new point
double y = (force * radius / 250.0d) * Math.sin(direction) + centerY; // Y-coordinate of the new point
Point2D point = new Point2D.Double(x,y); // Then you can plot this point on your target
All of your ovals appear to be circles. So, let's create a Circle model class.
You would call the draw method from a JPanel paintComponent method.
You would call the contains method when you want to see if a point is inside or on the edge of a circle.
You would keep track of all of the circles in a List, so you can maintain the order of the circles.
package com.ggl.testing;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.Point;
public class Circle {
private final int radius;
private final Color color;
private final Point location;
public Circle(int x, int y, int radius, Color color) {
this.location = new Point(x, y);
this.radius = radius;
this.color = color;
}
public boolean contains(int x, int y) {
double distance = Point.distance(x, y, location.x, location.y);
double radiusD = radius;
if (radiusD >= distance) {
return true;
} else {
return false;
}
}
public void draw(Graphics g) {
g.setColor(color);
g.fillOval(location.x - radius, location.y - radius, radius + radius,
radius + radius);
}
}
Use a concrete Ellipse2D for each zone. Then you can use g2d.fill() to draw the zone. Since an Ellipse2D is also a Shape, you can use the contains(Point2D p) method to check if a point is in bounds. Since the circles overlap, you'll have to check them in front-to-back order.
I'm trying to draw a circle on my canvas. Pseudocode of my algorithm looks like that
double R = 1.0;
// Draw 11 points, lying on the circle with the radius of 1
// and angle from 0 to 90 degrees
for(int i=0; i<=10; i++)
{
drawPoint( R*cos(PI*i/20), R*sin(PI*i/20) );
}
// Draw a circle with center at the (0; 0) and with the radius of 1
drawCircle(0, 0, R);
That's what I've got:
Looks fine, but there is one problem. When I increase radius only points with angles 0, 45 and 90 lie on a circle.
That's how it looks 72 degrees:
There is no any info about accuracy of the method drawCircle on developer.android.com.
I guess that it draws, based on the values at points with angles 0, 45, 90, ..., and calculate line in other positions very approximately.
I know, that I can draw circle as accurate as I want to, if I'll draw it like a polyline with tiny step, but it will work very slow.
So I want to find out - is there any methods to draw circle accurate in Android?
UPD 1:
How do I draw a points:
int x, y;
x = getPixelX(point.getX());
y = getPixelY(point.getY());
canvas.drawCircle(x, y, point.radius, paint);
Where getPixelX and getPixelY takes a coorditate of the point on plane and returns the same coordinate on the screen, basing on scale and offset.
I thought that I could make some mistake in those methods, but they work perfectly with the lines. I can zoom in lines and there is no error, all the points lies just on the line.
UPD 2:
There are comments, that probably I make a mistake in my calculations. I do not argue, perhaps you're right. So here is my "calculations".
How do I zoom in:
public void mouseWheelMoved(MouseWheelEvent e) {
// zoomQ is 0.9 or 1.1
double zoomQ = (e.getWheelRotation() + 10) / 10.0;
scaleX *= zoomQ;
scaleY *= zoomQ;
}
How do I move the plane:
public void mouseDragged(MouseEvent e) {
centerX -= (e.getX() - lastMouseX)/scaleX;
centerY -= (e.getY() - lastMouseY)/scaleY;
lastMouseX = e.getX();
lastMouseY = e.getY();
}
How do getPixelX/Y works:
public int getPixelX(double planeX) {
return (int)Math.round( scaleX*(planeX - centerX) + ScreenWidth/2 );
}
public int getPixelY(double planeY) {
return (int)Math.round( scaleY*(planeY - centerY) + ScreenHeight/2 );
}
I'm trying to get a bunch of small circles that have varying shades of green to be drawn within a big circle to get a "bush" look, but I can't figure out how to get all the small circles within the shape of a big circle. I can only figure out how to get it within a rectangle.
public void paintComponent(Graphics g)
{
super.paintComponent(g);
for(int i = 0; i < 1000; i++){
int redV = (int) ((Math.random() * 100) + 27);
g.setColor(new Color(red, red + 31, red - 15));
int x = (int) ((Math.random() * 400) + 150);
int y = (int) ((Math.random() * 500) + 200);
g.fillOval(x, y, 50, 50);
}
}
I guess you have to do some geometry here, and verify whether the x and y coordinates generated randomly are within your circle. As you said, within a rectangle is easy (because you just check that x > left, x+50 < right, y > top, y+50 < bottom), however for a circle you have to use the equation of a circle and check that (x,y) and (x+50,y+50) are within it before actually doing the fillOval().
I think you have a simple way out by using the Java 2D Shape.contains(), which is implemented by Ellipse2D. So essentially you create an instance of Ellipse2D.Double or Ellipse2D.Float for the greater circle, and then just call contains() each time you generate the coordinates to check they are within it before drawing them.
I think you can just change the Color slightly, and increment/decrement x, y, width, and height slightly to get them to be within the older circle. The new oval should be painted over the old one.
Choose the point that should be the center of the big circle, and draw the big circle relative to that (e.g. using java.awt.geom.Ellipse2D).
You can then use the center of the big circle and its radius to position the other smaller circles relative to that also, inside the circumference.