[Quartz]How to display scheduled Job? - java

I use Quartz with JobJDBCStore and it works perfectly. The problem now is that I want to display Job that will fire ,their dates of execution and some info that I put in the associated JobDataMap.
Thanks you for your help

You can do that with:
Scheduler scheduler = SchedulerSingleton.instance();
Trigger trigger = scheduler.getTrigger(job, group);
trigger.getNextFireTime()

Related

Quartz Scheduler next execution time equal current time plus interval of scheduler

I am working with Quartz scheduler and everything work perfect according to the requirement. But there one thing that I want to implement and i.e. I want my next execution of job will trigger on (currentFinishTime + intervalOfScheduler)
Example of job execution with 30 seconds of interval:
Job-1-First-Executed at 10-10-2020 18:30:05
Job-1-Second-Executed at 10-10-2020 18:30:35
Job-1-Third-Executed at 10-10-2020 18:31:05
So, here if the job takes 20 seconds to execute then next trigger will happen on 05+20+30 = 55. Instead of 10-10-2020 18:30:35, it will trigger at 10-10-2020 18:30:55 and same for other execution and so on...
Note: #DisallowConcurrentExecution and MyJobExecutor implements Job {public void execute(JobExecutionContext context){...}} are already implemented.
Please help me to solve my problem.
After a lots of research, I have implemented my own solution which suffice my requirement. The code is mentioned below:
if(isExecutionTimeIncluded) {
final TriggerBuilder triggerBuilder = context.getTrigger().getTriggerBuilder();
final Trigger newTrigger = triggerBuilder
.withSchedule(SimpleScheduleBuilder.simpleSchedule()
.withIntervalInSeconds(cpoPullJobData.getInterval())
.repeatForever())
.startAt(futureDate(interval/*eg.30*/, DateBuilder.IntervalUnit.SECOND);)
.build();
context.getScheduler().rescheduleJob(context.getTrigger().getKey(), newTrigger);
}

quartz job to wait till start and standby after completion

I'm using quartz job my requirement is like I get some data to be persist in DB but before that I need to perform some modification on given data so I started processing the data in background using quartz. But now what is happening some of the time job is getting standby even before starting and due to that some of the data payload didn't get processed.
How can I maintain the job to be wait until the job complete its work.
scheduler.start();
scheduler.scheduleJob(job, trigger);
try {
Thread.sleep(3000);
} catch (InterruptedException e) {
e.printStackTrace();
}
scheduler.standby();
In my code if job starts before 3 second the standby will wait for job to complete the task but some of the time job taking more time to stat.
Instead of making your job wait for data, you can
Start your job every x minutes
Don't spawn new jobs if there's already a working one so they
won't overlap

FireBase Job Dispatcher. job starts after 20-60 sec, even with Triger.Now. How can i fix it?

Job job = dispatcher.newJobBuilder()
.setTag("JOB_TAG")
.setService(MyService.class)
.setTrigger(Trigger.NOW)
.setReplaceCurrent(false)
.setRetryStrategy(RetryStrategy.DEFAULT_EXPONENTIAL)
.setConstraints(Constraint.ON_ANY_NETWORK)
.build();
dispatcher.schedule(job);
my code is here. even when all conditions are here, my job starts with delay. Can i trigger it somehow?
Use Trigger.executionWindow(0, 0) instead of Trigger.NOW .It will normally start your job immediately or within 1 second.

How can I build a cron-like job executor in Java?

I'd like to develop a Java program that executes tasks registered in a database. The tasks have their own cron-like schedule, which is an object of CronExpression of Quartz Scheduler, and saved in the database after being serialized.
Tasks should be executed anytime according to its schedule, so I think the program should be daemonized, and may be able to be restarted or stopped outside the program (like an usual service beneath /etc/init.d/)
I'm studying the examples of Quartz
and saw the program running continuously even if there's no sleep and shutdown method. This seems nice to achieve my purpose, but I'm not sure if this way can generate a daemon process.
// TODO: Retrieve cron format from the database
Trigger trigger = org.quartz.TriggerBuilder.newTrigger()
.withIdentity("trigger1", "group1")
.withSchedule(cronSchedule("* * * ? * MON-FRI"))
.startNow()
.build();
try {
sched.scheduleJob(job, trigger);
sched.start();
// Thread.sleep(90L * 1000L);
// sched.shutdown(true);
} catch (SchedulerException e) {
...
My question is
What is the best way to build a cron job scheduler which runs continuously on a server?
Thank you in advance, and any opinions or questions would be appreciated.

Quartz: Based on configured schedule, the given trigger will never fire

I am getting the "Based on configured schedule, the given trigger will never fire" error when scheduling my job. I have tried adding ".startNow()" to the trigger, but that didn't solve it. I don't understand what I have done wrong.
JobDetail jobDetail = newJob(DeploymentJob.class)
.withIdentity(scheduleName)
.usingJobData("uploadLocation", deployment.getUploadDir())
.build();
// Add the job to the Scheduler
scheduler.addJob(jobDetail, true);
// Create the trigger with cron expression
Trigger trigger = newTrigger()
.withIdentity(scheduleName)
.withSchedule(cronSchedule(cron))
.forJob(jobDetail)
.build();
// Tell quartz to schedule the job using our trigger
scheduler.scheduleJob(jobDetail, trigger); <--- Problem line.
scheduler.start();
Thanks in advance for the answers! Much appreciated!
Your setting time is beyond reach.Spring Quartz never execute the task which time is beyond reach.So change your setting time.

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