injecting mock beans into spring context for testing - java

I know similar questions have been asked, e.g. here, but having done a search, I've come upon a solution I'm much happier with here
My only problem however, is that I'm not sure how to implement this solution.
What I want to be able to do is via the HotswappableTargetSource override the bean definitions of select beans in my application context with my test versions and then run the test.
Then for each test case I'd like to specify which beans I want to be hot swappable and then each test must be able to create its own mock versions and swap those in, and be able to swap back again.
I am able to get the Application Context the test is running with but what I don't know is how to configure a bean to be hot swappable. I know how to do it when configuring beans with xml but I don't want to go back to using xml to configure beans.

UPDATE: There's a library that does it!
https://bitbucket.org/kubek2k/springockito/wiki/springockito-annotations
The solution is as follows:
You will need to change the spring context of your application to proxy the bean you want to swap:
<bean id="beanSwappable" class="org.springframework.aop.framework.ProxyFactoryBean">
<property name="targetSource" ref="beanSwap" />
</bean>
<bean id="beanSwap" class="org.springframework.aop.target.HotSwappableTargetSource">
<constructor-arg ref="beanToSwap" />
</bean>
beanSwap is the proxy onto this beanSwap.
beanSwappable is the bean which you reference when you want to swap the bean
beanToSwap is the default implementation of the bean
Thus a change to the system under test is necessary.
And in your test the code will look like:
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(locations = { "test.xml", "spring.xml" })
public class Test {
#Resource(name="beanSwappable")
Bean b;
#Resource(name = "beanSwap")
HotSwappableTargetSource beanSwap;
public void swap() {
Bean b = << create mock version >>
beanSwap.swap(b);
// run test code which
}
}

Related

Spring without getBean(..)

I'm trying to get a better understanding of the #Autowired annotations component scanning, but all the examples I found so far use context.getBean(..) at some point to get at least one Bean to start with.
I also read that doing that is considered bad practice , but I can't seem to find any information on how to do it without context.getBean(..)
Could somebody please enlighten me with an example and information on how to do this ?
Define your bean in xml and use
<context:component-scan base-package="com" />
<mvc:annotation-driven />
Bean def
<bean id="processEngine" class="com.processEngine">
<property name="processEngineConfiguration" ref="processEngineConfiguration" />
</bean>
now you can get bean as following
#Autowired
private ProcessEngine processEngine;
how it works
spring scans the bean's recipes either from xml or java configuration. then spring creates a beanDefinitions which are 'loaded' into BeanFactory. BeanFactory triggers a set of BeanPostProcessors (BPP) which are scanning classes for particular annotations like Autowired/Resource/PostProcessor and etc. and do appropriate actions. in case when your class contains #Autowired annotation, AutowiredAnnotationBeanPostProcessor would auto wire required field (dependencies), and when creation of an object is done and all BPP worked out, object is ready to be used by the app, from this point your code can get 'ready' objects from container.
there are some cases when you would need to access this beans from the code which is out of spring's control and not managed by container. in order to do so, you would need to get the ApplicationContext (container) and call #getBean specifying either name or type. using applicationContext directly is not a good practice because there are some problems that you can come to, f.ex. id of a bean might be changed and if you refer to bean by id then NPE would be thrown.
configuration
there are several approaches to configure spring to scan the classes for finding bean recipes. one would be defining component-scan, in this case classes which are located in the path that you've set and having any of valid spring annotations like #Component, #Service, #Repository, #Controller (for web container) would be considered. another way would be specifying each bean separately using <bean> or #Bean.
examples.
if you want to create a web app then you should see DispatcherServlet with ContextLoaderListener classes. this classes would boot your app and load everything according to configuration. f.ex. here,
but if you want to create a desktop app, then you would end up with something like this
From time to time (usually when not using Spring Boot), I use something along the lines of the following code:
public static <T> T autowire(ApplicationContext ctx, T bean) {
ctx.getAutowireCapableBeanFactory().autowireBean(bean);
return bean;
}
In my main, I create an instance of the main application class that contains a few #Autowired annotations for the main services / entry points to my Spring application.

How to load two ResourceBundles and inject them separately

I am using Spring for loading localized resource bundles into my application. Here is what I have done.
<bean id="systemMessages" class="o.s.c.s.ResourceBundleMessageSource">
<property name="basename" value="locale/system">
</bean>
<bean id="clientMessages" class="o.s.c.s.ResourceBundleMessageSource">
<property name="basename" value="locale/client">
</bean>
I want to load messages based on the locale in my controller, and I tried both these ways below
#Autowired
#Qualifier("clientMessages")
ResourceBundleMessageSource clientMessages;
#Resource(name="systemMessages")
ResourceBundleMessageSource systemMessages;
EDIT
The application is a JAXRS application and the injection is being tried in a Global Exception Mapper. From the comments I now understand that this class would have been created by the JAXRS container and not Spring ( Code below). How to let Spring know that this injection must work?
import javax.ws.rs.WebApplicationException;
//other imports
public class GlobalWebApplicationException extends WebApplicationException{
private String systemMessage;
private String clientMessage;
//Autowire the multiple resourcebundles
public GlobalWebApplicationException (String key, Locale locale) {
// this is where I want to use the injected object fetch the property
}
public doSomething(){
// Business Logic
}
}
But the injection is not happening and I am getting an NPE. How do I achieve this?
When using Spring and having it do auto wiring using annotations the fields cannot be null. The dependencies need to be satisfied on startup of the application. If that doesn't happen there can be 1 of 2 things wrong
You haven't enabled annotation processing
You aren't using a spring managed bean but are creating instances yourself
For the first option add <context:annotation-config /> to your application context, or if you want to do component scanning add <context:component-scan /> the latter already implies annotation processing.
For the second option you need to make your bean a spring managed bean and use that instead of creating new instances yourself.

Spring: Xml based Autowiring a list of beans by interface type

With Spring it is possible to inject a list of beans by the interface class like:
#Component
public class Service {
#Autowire
private List<InterfaceType> implementingBeans;
...
}
All defined beans that implement this interface will be present in this List.
The annotation based approach is not possible for me, as the Service class is in a module that must not have spring dependencies.
I need to use this mechanism from outside via xml configuration.
<bean id="service" class="...Service">
<property name="implementingBeans">
??? tell spring to create a list bean that resolves all beans of the interfaceType.
</property>
</bean>
Does anyone know how to solve this?
EDIT: Additionally, there are more than one spring applications that use this service. So the best solution would be to handle this szenario completely via xml configuration. I can then copy the xml parts to all spriong applications that need this.
I want to avoid having a kind of initializer bean that gets the service injected and must then be copied to all spring applications.
Kind regards.
An XML-only solution would simply have you declare a <bean> of the "external" type and provide an autowire value of "byType".
Controls whether bean properties are "autowired". This is an
automagical process in which bean references don't need to be coded
explicitly in the XML bean definition file, but rather the Spring
container works out dependencies.
[...]
"byType" Autowiring if there is exactly one bean of the property type in the container. If there is more than one, a fatal error is
raised, and you cannot use byType autowiring for that bean. If there
is none, nothing special happens.
The explanation is a little confusing in that we expect multiple InterfaceType beans, but the actual field is of type List and Spring will be able to dynamically instantiate one and add all the InterfaceType beans to it, then inject it.
Your XML would simply look like
<bean id="service" class="...Service" autowire="byType">
</bean>
My original suggested solution made use of SpEL.
In the module that does have Spring dependencies, create a DTO
#Component(value = "beanDTO")
public class BeanDTO {
#Autowire
private List<InterfaceType> implementingBeans;
public List<InterfaceType> getImplementingBeans() {
return implementingBeans;
}
}
and then use SpEL to retrieve the value of implementingBeans from the beanDTO bean.
<bean id="service" depends-on="beanDTO" class="...Service">
<property name="implementingBeans" value="{beanDTO.implementingBeans}" />
</bean>
Spring will create the BeanTDO bean, inject all the beans that are of type InterfaceType. It will then create the service bean and set its property from beanDTO's implementingBeans property.
Following comments on question:
In an effort to be more JSR 330 compliant, Spring has introduced support for Java EE's javax.inject package. You can now annotate your injection targets with #javax.inject.Inject instead of #Autowired. Similarly, you can use #Named instead of #Component. The documentation has more details.

How to inject all properties from Spring into a bean?

I want to inject a map containing all the properties that spring knows of (which are inserted by a library) to a config class that I have through the spring xml. Is that possible?
<bean class="Config">
<constructor-arg name="env">
<map>
//inject all properties?
</map>
</constructor-arg>
</bean>
Why don't you just inject the Spring Context? Through the Context, you can look up any bean via its name.
Edit:
From this answer, you could also use the following:
<bean class="Config">
<constructor-arg name="env">
<util:properties location="${path.to.properties.file}"/>
</constructor-arg>
</bean>
Where your "env" constructor argument is a java.util.Properties object.
For later versions of Spring (including spring-boot) that support the injection of an Environment you can use this to access all properties loaded.
To answer this question inject a AbstractEnvironment so that you are able to call the getPropertySources() method that will allow you to see where the properties have been loaded from (e.g. a file, OS variables, etc)
#Autowired
public Config(AbstractEnvironment environment)
{
MutablePropertySources propertySources = environment.getPropertySources();
// inspect propertySources to see all properties loaded by Spring
}
Can you not extend the library class that you use and instantiate your bean instead of the default library one? Then you would be able to inspect all the values.
Otherwise, if you know the signature of the library, you can always use AOP to weave some code around the library and get access to the properties there. A bit more complicated, but still gets you where you need to go. You can definitely use AspectJ (which requires a little more config) or even Spring AOP, depending how things are being accessed.
If you want/need more insight on this, let me know.

using spring, can I extract some part of a static method to use to set a property on a bean?

I have a static method I have no control over: MyUtils.getServiceURL() which returns a URL. I need to extract just the port from this URL to set a property on a bean:
<bean id="myBean>
<property name="defaultPort" value="?????"/>
</bean>
I can get the string value of the URL as a bean like this:
<bean id="serviceURL" class="MyUtils" factory-method="getServiceURL" />
I'm probably just going to write a method to parse the URL in myBean and extract the port. I was wondering if there was a way to avoid having to do this, and configure this directly in the spring context?
No need for custom classes, or parsers. Remember, a bean is just a class with get/is/set methods. A java.net.URL class qualifies as such.
Solution: Use a java.net.URL as a Spring-configurable bean and call it's getPort method.
Remember, in Spring, you can wire anything as a bean very easily so long as it sports methods using the get/is/set Bean convention. The java.net.URL class does such a thing.
** warning ** I'm just typing this out of my a$$, you'll have to check for any syntax shenanigans that I might be introducing in this Spring-config pseudo-code. One thing that is certain is that the concept will work with Spring 2.5 and that it relies on the util schema.
If you are using an older version of Spring, you'll have to use a PropertyPathFactoryBean. If you are using Spring 3.0, you'll want to use Spring expression language (EL), but I can't comment on the later since I'm not familiar with Spring 3.0.
In java:
int port = (new URL(MyUtils.getServiceURL()).getPort()
In Spring:
<bean id="serviceURL" class="MyUtils" factory-method="getServiceURL" />
<bean id="myURL" class="java.net.URL">
<constructor-arg>
<ref-bean="serviceURL"/>
</constructor-arg>
</bean>
<util:property-path id="defaultPort" path="myURL.port"/>
<bean id="myBean>
<property name="defaultPort" ref="defaultPort"/>
</bean>
There might be a way to consolidate all these four expressions into three or less, don't know if that will improve readability, though. The concept remains the same, though. Treat a java.net.URL instance as a bean, set its URL via its constructor, and get a hold (via Spring) of its getPort() method.
** edit **:
If you are using Spring 2.5 you can create an inline groovy bean that does all that for you. I've seen people doing that as integration glue to get rid of multitude of temp Spring bean place holders. That's the best choice IMO when you need to define a class (when it's simpler than just using Spring tags) and when you know such a class won't be used outside of Spring wiring of things.
Not I can think of. Either way, you probably have to write something to parse the port out. Since you have no control of that static method, perhaps you may want to utilize the adapter pattern to hide that static method. Doing so also makes your code easier to test because you can easily mock that external API out. For example:-
public interface URLServiceAdapter {
int getServiceURLPort();
}
public class URLServiceAdapterImpl implements URLServiceAdapter {
public int getServiceURLPort() {
return MyUtils.getServiceURL().getPort();
}
}
Your beans will then rely on your adapter class instead of MyUtils.getServiceURL() directly:-
<bean id="urlServiceAdapter" class="project.URLServiceAdapterImpl" />
That way, you can do something like this:-
#Autowired
private UrlServiceAdapter urlServiceAdapter;
...
bean.setDefaultPort(urlServiceAdapter.getServiceURLPort());
SpEL is your friend.
<bean id="myBean>
<property name="defaultPort"
value='#{ T(com.foo.MyUtils).getServiceURL().split(":")[2].split("/")[0] }'/>
</bean>
Enjoy,

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