I'm looking for something simple (no external lib preferably) to write and load a byte[] from a file. More or less something like [Python's pickle][1].
byte[] bytes = new byte[10];
ByteBuffer bbuf = new ByteBuffer.allocate(bytes.length);
bbuf.wrap(bytes); // edited due to Jon Skeet's answer
CharBuffer cbuf = bbuf.asCharBuffer();
cbuf.put("t");
FileOutputStream test = new FileOutputStream("somebytes");
test.write(bytes);
test.close();
The problem seems to be that I cannot read the Object structure from a file like that. In a hex-editor furthermore the file "somebytes" contains just a couple or 0s. So it doesn't seem the FileOutputStream puts any of the content ("t" or the byte-equivalent) into it.
[1] http://wiki.python.org/moin/UsingPickle
You've allocated a byte buffer with the size of bytes, but that doesn't mean the byte buffer is associated with the byte array. You can wrap a byte array using ByteBuffer.wrap.
Here's a minimal change to your code which does write the t into the file:
byte[] bytes = new byte[10];
ByteBuffer bbuf = ByteBuffer.wrap(bytes);
CharBuffer cbuf = bbuf.asCharBuffer();
cbuf.put("t");
FileOutputStream test = new FileOutputStream("somebytes");
test.write(bytes);
test.close();
Note that for real code you should use a try/finally block to make sure the file is always closed regardless of exceptions.
However, this is a long way from serialization. Java does have its own binary serialization - see ObjectOutputStream and ObjectInputStream. Personally I usually avoid this sort of serialization however, as it can be very brittle in the face of changes to classes. There are various other approaches to serialization, such as using Thrift or Protocol Buffers for binary serialization, or serializing to XML, JSON or some other human-readable format.
You can
seek(position)
b = read(length)
Then b will be an array of bytes of your length.
Sorry - on rereading you're looking for writing, not reading.
A simpler version of the same thing is.
byte[] bytes = new byte[10];
bytes[1] = 't';
FileOutputStream test = new FileOutputStream("somebytes");
test.write(bytes);
test.close();
There are plenty of examples on how to read/write byte[] from files on the web. try google.
Related
I am reading dds textures, but since once built the jar I can't access those textures through url and file and have to use InputStream instead.
So I would need to know how I can obtain a java.nio.ByteBuffer from an java.io.InputStream.
Ps: no matter through 3rd part libraries, I just need it working
For me the best in this case is Apache commons-io to handle this and similar tasks.
The IOUtils type has a static method to read an InputStream and return a byte[].
InputStream is;
byte[] bytes = IOUtils.toByteArray(is);
Internally this creates a ByteArrayOutputStream and copies the bytes to the output, then calls toByteArray().
UPDATE: as long as you have the byte array, as #Peter pointed, you have to convert to ByteBuffer
ByteBuffer.wrap(bytes)
JAVA 9 UPDATE: as stated by #saka1029 if you're using java 9+ you can use the default InputStream API which now includes InputStream::readAllBytes function, so no external libraries needed
InputStream is;
byte[] bytes = is.readAllBytes()
What is about:
ReadableByteChannel channel = Channels.newChannel(inputStream);
ByteBuffer buffer = ByteBuffer.allocate(bufferSize);
while (channel.read(buffer) != -1) {
//write buffer
};
A neat solution with no 3rd party library needed is
ByteBuffer byteBuffer = ByteBuffer.allocate(inputStream.available());
Channels.newChannel(inputStream).read(byteBuffer);
See ReadableByteChannel#read(ByteBuffer)
Below is the code that I have written. I want to do the simple thing, storing binary file data into byteBuffer.
File file = new File(fileName);
try {
ReadableByteChannel channel = new FileInputStream(fileName).getChannel();
ByteBuffer buf = ByteBuffer.allocateDirect(file.length());
// How can use buf.read to get all the contents?
} catch (Exception e){
}
I was wondering
how can I use read to get all data from channel and store it in ByteBuffer
if there is more elegant way to allocate ByteBuffer, other than using File object to get the length of the file
I prefer to use memory mapping.
FileChannel channel = new FileInputStream(fileName).getChannel();
ByteBuffer buf = channel.map(MapMode.READ_ONLY,0,channel.size());
If the file is greater than 2 GB, you have to have more than one mapping. On the plus side this takes around 10 ms regardless of size and doesn't use much heap or direct memory regardless of the size of the file.
From the ReadableByteChannel Javadocs
read(ByteBuffer dst)
An attempt is made to read up to r bytes from the channel, where r is the number of bytes remaining in the buffer, that is, dst.remaining(), at the moment this method is invoked.
So ... channel.read(buf);
As for your second question, if you want to read the entire contents of the file into memory at once that seems like a reasonable approach.
This is a newbie question, I know. Can you guys help?
I'm talking about big files, of course, above 100MB. I'm imagining some kind of loop, but I don't know what to use. Chunked stream?
One thins is for certain: I don't want something like this (pseudocode):
File file = new File(existing_file_path);
byte[] theWholeFile = new byte[file.length()]; //this allocates the whole thing into memory
File out = new File(new_file_path);
out.write(theWholeFile);
To be more specific, I have to re-write a applet that downloads a base64 encoded file and decodes it to the "normal" file. Because it's made with byte arrays, it holds twice the file size in memory: one base64 encoded and the other one decoded. My question is not about base64. It's about saving memory.
Can you point me in the right direction?
Thanks!
From the question, it appears that you are reading the base64 encoded contents of a file into an array, decoding it into another array before finally saving it.
This is a bit of an overhead when considering memory. Especially given the fact that Base64 encoding is in use. It can be made a bit more efficient by:
Reading the contents of the file using a FileInputStream, preferably decorated with a BufferedInputStream.
Decoding on the fly. Base64 encoded characters can be read in groups of 4 characters, to be decoded on the fly.
Writing the output to the file, using a FileOutputStream, again preferably decorated with a BufferedOutputStream. This write operation can also be done after every single decode operation.
The buffering of read and write operations is done to prevent frequent IO access. You could use a buffer size that is appropriate to your application's load; usually the buffer size is chosen to be some power of two, because such a number does not have an "impedance mismatch" with the physical disk buffer.
Perhaps a FileInputStream on the file, reading off fixed length chunks, doing your transformation and writing them to a FileOutputStream?
Perhaps a BufferedReader? Javadoc: http://download-llnw.oracle.com/javase/1.4.2/docs/api/java/io/BufferedReader.html
Use this base64 encoder/decoder, which will wrap your file input stream and handle the decoding on the fly:
InputStream input = new Base64.InputStream(new FileInputStream("in.txt"));
OutputStream output = new FileOutputStream("out.txt");
try {
byte[] buffer = new byte[1024];
int readOffset = 0;
while(input.available() > 0) {
int bytesRead = input.read(buffer, readOffset, buffer.length);
readOffset += bytesRead;
output.write(buffer, 0, bytesRead);
}
} finally {
input.close();
output.close();
}
You can use org.apache.commons.io.FileUtils. This util class provides other options too beside what you are looking for. For example:
FileUtils.copyFile(final File srcFile, final File destFile)
FileUtils.copyFile(final File input, final OutputStream output)
FileUtils.copyFileToDirectory(final File srcFile, final File destDir)
And so on.. Also you can follow this tut.
I have a blob column in my database table, for which I have to use byte[] in my Java program as a mapping and to use this data I have to convert it to InputStream or OutputStream. But I don't know what happens internally when I do so. Can anyone briefly explain me what's happening when I do this conversion?
You create and use byte array I/O streams as follows:
byte[] source = ...;
ByteArrayInputStream bis = new ByteArrayInputStream(source);
// read bytes from bis ...
ByteArrayOutputStream bos = new ByteArrayOutputStream();
// write bytes to bos ...
byte[] sink = bos.toByteArray();
Assuming that you are using a JDBC driver that implements the standard JDBC Blob interface (not all do), you can also connect a InputStream or OutputStream to a blob using the getBinaryStream and setBinaryStream methods1, and you can also get and set the bytes directly.
(In general, you should take appropriate steps to handle any exceptions, and close streams. However, closing bis and bos in the example above is unnecessary, since they aren't associated with any external resources; e.g. file descriptors, sockets, database connections.)
1 - The setBinaryStream method is really a getter. Go figure.
I'm assuming you mean that 'use' means read, but what i'll explain for the read case can be basically reversed for the write case.
so you end up with a byte[]. this could represent any kind of data which may need special types of conversions (character, encrypted, etc). let's pretend you want to write this data as is to a file.
firstly you could create a ByteArrayInputStream which is basically a mechanism to supply the bytes to something in sequence.
then you could create a FileOutputStream for the file you want to create. there are many types of InputStreams and OutputStreams for different data sources and destinations.
lastly you would write the InputStream to the OutputStream. in this case, the array of bytes would be sent in sequence to the FileOutputStream for writing. For this i recommend using IOUtils
byte[] bytes = ...;//
ByteArrayInputStream in = new ByteArrayInputStream(bytes);
FileOutputStream out = new FileOutputStream(new File(...));
IOUtils.copy(in, out);
IOUtils.closeQuietly(in);
IOUtils.closeQuietly(out);
and in reverse
FileInputStream in = new FileInputStream(new File(...));
ByteArrayOutputStream out = new ByteArrayOutputStream();
IOUtils.copy(in, out);
IOUtils.closeQuietly(in);
IOUtils.closeQuietly(out);
byte[] bytes = out.toByteArray();
if you use the above code snippets you'll need to handle exceptions and i recommend you do the 'closes' in a finally block.
we can convert byte[] array into input stream by using ByteArrayInputStream
String str = "Welcome to awesome Java World";
byte[] content = str.getBytes();
int size = content.length;
InputStream is = null;
byte[] b = new byte[size];
is = new ByteArrayInputStream(content);
For full example please check here http://www.onlinecodegeek.com/2015/09/how-to-convert-byte-into-inputstream.html
There is no conversion between InputStream/OutputStream and the bytes they are working with. They are made for binary data, and just read (or write) the bytes one by one as is.
A conversion needs to happen when you want to go from byte to char. Then you need to convert using a character set. This happens when you make String or Reader from bytes, which are made for character data.
output = new ByteArrayOutputStream();
...
input = new ByteArrayInputStream( output.toByteArray() )
I do realize that my answer is way late for this question but I think the community would like a newer approach to this issue.
byte[] data = dbEntity.getBlobData();
response.getOutputStream().write();
I think this is better since you already have an existing OutputStream in the response object.
no need to create a new OutputStream.
I'm updating some old code to grab some binary data from a URL instead of from a database (the data is about to be moved out of the database and will be accessible by HTTP instead). The database API seemed to provide the data as a raw byte array directly, and the code in question wrote this array to a file using a BufferedOutputStream.
I'm not at all familiar with Java, but a bit of googling led me to this code:
URL u = new URL("my-url-string");
URLConnection uc = u.openConnection();
uc.connect();
InputStream in = uc.getInputStream();
ByteArrayOutputStream out = new ByteArrayOutputStream();
final int BUF_SIZE = 1 << 8;
byte[] buffer = new byte[BUF_SIZE];
int bytesRead = -1;
while((bytesRead = in.read(buffer)) > -1) {
out.write(buffer, 0, bytesRead);
}
in.close();
fileBytes = out.toByteArray();
That seems to work most of the time, but I have a problem when the data being copied is large - I'm getting an OutOfMemoryError for data items that worked fine with the old code.
I'm guessing that's because this version of the code has multiple copies of the data in memory at the same time, whereas the original code didn't.
Is there a simple way to grab binary data from a URL and save it in a file without incurring the cost of multiple copies in memory?
Instead of writing the data to a byte array and then dumping it to a file, you can directly write it to a file by replacing the following:
ByteArrayOutputStream out = new ByteArrayOutputStream();
With:
FileOutputStream out = new FileOutputStream("filename");
If you do so, there is no need for the call out.toByteArray() at the end. Just make sure you close the FileOutputStream object when done, like this:
out.close();
See the documentation of FileOutputStream for more details.
I don't know what you mean with "large" data, but try using the JVM parameter
java -Xmx 256m ...
which sets the maximum heap size to 256 MByte (or any value you like).
If you need the Content-Length and your web-server is somewhat standard conforming, then it should provide you a "Content-Length" header.
URLConnection#getContentLength() should give you that information upfront so that you are able to create your file. (Be aware that if your HTTP server is misconfigured or under control of an evil entity, that header may not match the number of bytes received. In that case, why dont you stream to a temp-file first and copy that file later?)
In addition to that: A ByteArrayInputStream is a horrible memory allocator. It always doubles the buffer size, so if you read a 32MB + 1 byte file, then you end up with a 64MB buffer. It might be better to implement a own, smarter byte-array-stream, like this one:
http://source.pentaho.org/pentaho-reporting/engines/classic/trunk/core/source/org/pentaho/reporting/engine/classic/core/util/MemoryByteArrayOutputStream.java
subclassing ByteArrayOutputStream gives you access to the buffer and the number of bytes in it.
But of course, if all you want to do is to store de data into a file, you are better off using a FileOutputStream.