There have been a couple of times when I've felt the need to do something like the following:
private <T extends Type> Map<GenericClass1<T>,GenericClass2<T>> map;
...or something to that effect. Essentially, using an identical bound in the two arguments for map. (This isn't an actual example, just shows the idea.)
I know this (unfortunately) isn't possible and that it's only available on class definitions and method signatures. My question however is why isn't it available on fields? Is it purely a design choice or is there some technical reason behind it that I'm missing? I've had a think and can't see why this shouldn't be possible from a technical perspective, as far as I can see everything is there for the compiler to work it out correctly and none of the generic information is required at runtime.
<T> means ONE class, not A class.
When your object is instanced T is bound to this ONE class.
You are trying to put two objects with diffrent interfaces (used diffrently because they take/return diffrent types) in to the same container. This is a error because when you take them out of the container (the map) you dont know what it was you put in.
Hope this is the answer you were looking for.
Edit: That said you can have a container that holds members based on there class, to automatically create a new map for EACH type of T. You would then need to know what T was in order to access it.
In general, if you dont want the type information anymore, throw it away. If you do then putting it in the same container as something of another type will throw it away anyway for all practical reasons.
Let's assume that you want to instantiate your map variable. Theoretically you will have to write something like this:
map = new HashMap<GenericClass1<String>,GenericClass2<String>>();
Ok. But now what does not make sense to me anymore is what arguments the put or get methods will accept/return? T? Uh... what is T? GenericClass1|2<String>? Again makes no sense, does it? After all I see no String in the map declaration. So I guess there is no really correct instantiation and usage of this generic variable.
Cheers!
Oh, how I have longed for something like:
private <T> Map<Class<T>, T> instanceCache;
public <T> T getInstanceOf(Class<T> clazz) {
return instanceCache.get(clazz);
}
But as you mentioned, it's completely impossible in Java. The method declaration above is fine, but there's no way to declare the variable such that there's not a cast in the method. Simply add this to the growing list of things you hate about generics and move on.
You can use ? as following:
private List<? extends List> l = new ArrayList<List>();
I hope this helps.
Related
IMPORTANT:
the code I currently have Is working per my expectations. It does what I want it to do. My Question is about wether the WAY in which I have made it work is wrong. The reason I am asking this is because I've seen plenty of stack overflow results about raw types and how they should basically NEVER be used.
What I'm doing and Why I used raw types
Currently I am dynamically creating a concrete subclass of a generic interface where the interface takes in parameters when the class is constructed. When I make an instance of this class and use its returned object to call various methods, I use raw types because it works for what I'm trying to do. Here is an example in my functioning code where the raw types are used. This code is in top down order i.e. between code blocks there is no code.
Loading properties file
Properties prop = new Properties();
try {
prop.load(ObjectFactory.class.getResourceAsStream("config.properties"));
This is the File parser that implements FileParserImplementation and takes in the data and puts it into an array. This code gets the Class type and then makes an instance of that type dynamically.
Class<? extends FileParserImplementation> parser = null;
parser = Class.forName(prop.getProperty("FileParserImplementation")).asSubclass(FileParserImplementation.class);
FileParserImplementation ParserInstance = (FileParserImplementation) parser.getDeclaredConstructors()[0].newInstance();
These two classes and their instances are the two seperate DataParsers implementing DataParserImplementation. These take in the array of Strings that the FileParser gives and creates objects/manipulates the data into whatever is needed. It puts out a Collection of this data. The Fileparser dependency is passed in through constructor injection. This can be configured through the properties file at runtime.
Class<? extends DataParserImplementation> dataset1 = Class.forName(prop.getProperty("DataParserImplementation_1")).asSubclass(DataParserImplementation.class);
Class<? extends DataParserImplementation> dataset2 = Class.forName(prop.getProperty("DataParserImplementation_2")).asSubclass(DataParserImplementation.class);
DataParserImplementation Dataset1Instance = (DataParserImplementation) dataset1.getDeclaredConstructors()[0].newInstance(ParserInstance);
DataParserImplementation Dataset2Instance = (DataParserImplementation) dataset2.getDeclaredConstructors()[0].newInstance(ParserInstance);
This is the Crossreferencer class that implements CrossReferencerImplementation. It takes in the two datasets and Cross references them In whatever way is desired by the actual concrete reflected class. This also can be configured at runtime. It outputs a Map in this main.
The map serves as the final collection for the data (I might change that later).
Class<? extends CrossReferenceImplementation> crossreferencer = Class.forName(prop.getProperty("CrossReferenceImplementation")).asSubclass(CrossReferenceImplementation.class);
CrossReferenceImplementation crossReferencerInstance =
(CrossReferenceImplementation) crossreferencer.getDeclaredConstructors()[0].newInstance();
Getting the Map result from calling a method on our reflected instance. Then the contents of this map are printed out. currently it seems the map parameters are gotten as well because the Objects that are inside the map are properly using their toString methods when reflectiveFinalMap.get(key).toString() is called.
This leads me to believe it works as I intend.
Map reflectiveFinalMap = (Map)
crossReferencerInstance.CrossReference(Dataset1Instance.Parse(), Dataset2Instance.Parse());
for (Object key:reflectiveFinalMap.keySet()) {
System.out.println(key + " { " +
reflectiveFinalMap.get(key).toString() + " }");
}
return reflectiveFinalMap;
}
//catch block goes here
Notice that each time I reflectively create an instance of a class that implements one of my interfaces, I use the interface as the raw type. My Hope is that the reflection then sees the parameterized type of this raw type when it creates the concrete subclass, because thats where the parameter types are actually specified. The point is to let any class that implements those interfaces be generic to the point where they can take in just about anything and return just about anything.
Things I tried to not use raw types.
I've tried to actually obtain the parameterized type of CrossReferenceImplementation in the reflected crossreferencer Class that I get right now by calling
Class arrayparametertype = (Class)((ParameterizedType)crossreferencer.getClass().getGenericSuperclass()).getActualTypeArguments()[0];
And then I tried to pass in that arrayparameter when creating an instance of crossreferencer like this:
CrossReferenceImplementation crossReferencer = (CrossReferenceImplementation<<arrayparametertype>>) crossreferencer.getDeclaredConstructors()[0].newInstance();
That didn't work since variable parameter types apparently aren't a thing.
I tried to manually specify the specific parameter of the concrete reflected class(I DON'T want this anyway because it breaks the whole point of reflection here, decoupling the Classes from each other by being able to use anythng that implements the appropriate interface). This caused this warning to appear and the code to not actually run the methods it was supposed to:
//how the parameters were specified. Messy and breaks the reflection.
CrossReferenceImplementation<Map<String, SalesRep>,Map<String, SalesRep>,Map<String, SalesRep>> crossReferencer = (CrossReferenceImplementation) crossreferencer.getDeclaredConstructors()[0].newInstance();
//where the warning occured
Map reflectiveFinalMap = (Map) crossReferencer.CrossReference(Dataset1.Parse(), Dataset2.Parse());
The Warning:
"Dataset1 has raw type so result of Parse is erased".
Note that SalesRep here is the object in which the data is held as fields of that object. This object gets manipulated and put into various collections. It too is accessed via reflection in the many methods of DataParserImplementations
A similar error message and problem occured when specifying the parameter type of the Map (AGAIN I DON'T want this because it makes the reflection pointless I want the map return result to be generic and be specified by the implementing class).
//where the parameterized type was specified
Map reflectiveFinalMap = (Map<String,SalesRep>) crossReferencer.CrossReference(Dataset1.Parse(), Dataset2.Parse());
When specifying the actual parameterized type of the map result the error message was:
"crossReferencer has raw type so result of CrossReference is erased".
Running the code did indeed confirm for me that .CrossReference method's results were erased while everything else ran fine.
What internet searches I tried before asking here
So I used the raw types for both operations As can be seen in the main code and everything worked fine. But I have seen so much "Don't use raw types". And this is why I ask: Is this an appropriate use of raw types? Should I do it a different way that DOESN'T break the reflection? It breaks the reflection because manually specifying the type parameter not only makes my code not run, it also means ONLY that concrete class can be used. I reflected so that I could use anything that implements the generic interface. I don't want to only be able to use specific concrete instances. I've tried searching stack overflow for whats in my title and other similar things. I think this might be related to type erasure but I'm honestly not sure of that. Nothing else really addressed this problem because nothing talked about generics, parameterized types and reflection all at once (the crux of my problem). I have been told generics and reflection don't play well together but this code works anyways and works the way I want it to. It works well. I just want to make sure I'm not doing something TERRIBLY wrong.
The Goal.
To gain an Understanding of my current usage of raw types so I know I'm doing it the right way. By 'Right' I mean the opposite of what I define as the 'Wrong' Way below. An example of what 'Understanding' I seek is:
To understand why puesdo code along the lines of:
ConcreteClass forname(myPropertiesFileObject.get(ConcreteClassname)) as subClass of (MyGenericInterface);
MyRAWGenericInterfaceType ConcreteClassInstance = (MyRAWGenericInterfaceType) ConcreteClass.newInstance( Insert generic Type constructor arguments here);
RAWCollectionType someCollection = RAWCollectionType concreteClassInstance.CallingAMethod(Insert generic Type method arguments here);
Uses Raw types where RAW is contained in the Interface or collection type name. This is as opposed to doing it in some way that doesn't use raw types but doesn't break the point of the reflection, to decouple the interactions between these classes. Specifying the parameters with hard code would 'break the reflection' in this case. Additionally I'd like to understand Why specifying parameters (even if I know thats not what I'm going to do) for these RAW types in the pusedocode above causes the errors listed above in the question, Namely why is the result of CallingAMethod erased when supplying the actual parameters to the RAWCollectionType that the method returns? The root problem is that when I supply type parameters to RAWCollectionType when I declare it, it refuses to be updated by what CallingAMethod returns and I Don't Understand Why. It takes the return value, but if the body of the method CallingAMethod has the returned value passed in as an argument, updated inside the method and then returned, the return that I receive doesn't have the updates. CallingAMethod in this example would be like if I hada list like:
[1,2,3]
and inside the method I had something like:
foreach(thing in list){
thing += 1
}
and then I returned the list, the return I'd get when specifying parameters would be [1,2,3] and when using raw types it would be [2,3,4] like I desire. I'm asking this because I've heard bad things about using raw types.
Additionally I want to make sure that my use of raw types is not horribly wrong and that it works because it's SUPPOSED to work. Maybe I've just gotten good at the whole reflection and generics thing and found a valid use for raw types, or I could be doing something so horrible it warrants my arrest. Thats what i intend to find out. To clarify, by wrong I mean:
bad design (should use a different way to call my methods reflectively and also use reflective classes that use generic interfaces)
inefficient design(time complexity wise, code line wise or maintainability wise)
there is a better way, you shouldn't even be doing this in the first place
If any of those reasons or something I missed popped out when you read this code then TELL ME. Otherwise please explain then why my use of raw types is Valid and isn't a violation of this question:[link]What is a raw type and why shouldn't we use it?
Java have type erasure, so your Map<A,B> in runtime is just a Map, same for CrossReferenceImplementation<Map<String, SalesRep>,Map<String, SalesRep>,Map<String, SalesRep>> is just a CrossReferenceImplementation.
This also means that you can cast any map to Map and just put any objects you want in it, so you can have Map<String, Long> that is actually storing objects of Map<Cookie, Fish> type, and this is why you need to be careful with raw types and reflections.
You can't really use reflection and generics normally - you will always have some unchecked code then, but you can limit it to minimum and make it kind of type-safe anyways.
Like you can create own method to get field: (this is a bit of pseudocode, I will skip all possible exceptions, etc)
public class FieldAccessor<O, T> {
final Field field; // + private constructor
public T get(O object) { return (T) field.get(object); } // unsafe, bu we validated this before constructing this accessor
public static <O, T> FieldAccessor<O, T> create(Class<? super O> definingClass, Class<? super T> fieldClass, String fieldName) {
Field field = definingClass.getDeclaredField(fieldName);
if (field.getType() != fieldClass) {
throw some exception;
}
return new FieldAccessor<>(field);
}
Then you have all the needed validation before you need to use that field, and it will already return valid type. So you can get some value of valid type and add it to normal generic Map instance.
FieldAccessor<X, A> keyAccessor = FieldAccessor.create(X.class, A.class, "someProperty");
FieldAccessor<Y, B> valueAccessor = FieldAccessor.create(Y.class, B.class, "someOtherProperty");
Map<A, B> myMap = new HashMap<>();
mapMap.put(keyAccessor.get(myXValue), valueAccessor.get(myYValue));
This way you have type safe code that still works on reflections - it might still fail at runtime if you will provide invalid types, but at least you always know where it will fail - as here FieldAccessor is already checking all the types in runtime to ensure that you will not do something stupid like add Integer to Map<String, Long> as this might be hard to debug later. (unless someone will use this accessor as raw type, as .get isn't validated - but you can add that by passing definingClass to constructor and checking object instance in get methods)
You can do similar stuff for methods and fields that use generic types (like field of Map<X, Y> type, this FieldAccessor would only allow you to check if it is some kind of Map) - but it would be much harder as API for generics is still a bit "empty" - there is no build in way to create own instances of generic types or to check if they are assignable. (libraries like gson does that so they can deserialize maps and other generic types, they have own implementation of java generic type representation interfaces, like that ParameterizedType and implemented own method to check if given types are assignable)
Just when you are using reflections you need to always remember and understand that you are the one responsible for validating types, as compiler can't help you here, so that unsafe and raw typed code is fine as long as you have logic that validates if this code will never do something really unsafe (like that passing wrong type to generic method, like Integer to map of Long).
Just don't throw raw types and reflections in the middle of some normal code, add some abstraction to it, so it will be easier to maintain such code and project.
I hope this somewhat answers your question.
If I am creating a java class to be generic, such as:
public class Foo<T>
How can one determine internally to that class, what 'T' ended up being?
public ???? Bar()
{
//if its type 1
// do this
//if its type 2
// do this
//if its type 3
// do this
//if its type 4
// do this
}
I've poked around the Java API and played with the Reflection stuff, instanceof, getClass, .class, etc, but I can't seem to make heads or tails of them. I feel like I'm close and just need to combine a number of calls, but keep coming up short.
To be more specific, I am attempting to determine whether the class was instantiated with one of 3 possible types.
I've used a similar solution to what he explains here for a few projects and found it pretty useful.
http://blog.xebia.com/2009/02/07/acessing-generic-types-at-runtime-in-java/
The jist of it is using the following:
public Class returnedClass() {
ParameterizedType parameterizedType = (ParameterizedType)getClass()
.getGenericSuperclass();
return (Class) parameterizedType.getActualTypeArguments()[0];
}
In contrast to .NET Java generics are implemented by a technique called "type erasure".
What this means is that the compiler will use the type information when generating the class files, but not transfer this information to the byte code. If you look at the compiled classes with javap or similar tools, you will find that a List<String> is a simple List (of Object) in the class file, just as it was in pre-Java-5 code.
Code accessing the generic List will be "rewritten" by the compiler to include the casts you would have to write yourself in earlier versions. In effect the following two code fragments are identical from a byte code perspective once the compiler is done with them:
Java 5:
List<String> stringList = new ArrayList<String>();
stringList.add("Hello World");
String hw = stringList.get(0);
Java 1.4 and before:
List stringList = new ArrayList();
stringList.add("Hello World");
String hw = (String)stringList.get(0);
When reading values from a generic class in Java 5 the necessary cast to the declared type parameter is automatically inserted. When inserting, the compiler will check the value you try to put in and abort with an error if it is not a String.
The whole thing was done to keep old libraries and new generified code interoperable without any need to recompile the existing libs. This is a major advantage over the .NET way where generic classes and non-generic ones live side-by-side but cannot be interchanged freely.
Both approaches have their pros and cons, but that's the way it is in Java.
To get back to your original question: You will not be able to get at the type information at runtime, because it simply is not there anymore, once the compiler has done its job. This is surely limiting in some ways and there are some cranky ways around it which are usually based on storing a class-instance somewhere, but this is not a standard feature.
Because of type erasure, there is no way to do this directly. What you could do, though, is pass a Class<T> into the constructor and hold onto it inside your class. Then you can check it against the three possible Class types that you allow.
However, if there are only three possible types, you might want to consider refactoring into an enum instead.
The Problem is that most of the Generic stuff will disappear during compilation.
One common solution is to save the type during the creation of the Object.
For a short introduction in the Type Erasure behaviour of java read this page
If you know a few specific types that are meaningful, you should create subclasses of your generic type with the implementation.
So
public class Foo<T>
public ???? Bar()
{
//else condition goes here
}
And then
public class DateFoo extends Foo<Date>
public ???? Bar()
{
//Whatever you would have put in if(T == Date) would go here.
}
The whole point of a generic class is that you dont need to know the type that is being used....
It looks like what you want is in fact not a Generic class, but an interface with a number of different implementations. But maybe it would become clearer if you stated your actual, concrete goal.
I agree with Visage. Generics is for compile-time validation, not runtime dynamic typing. Sounds like what you need is really just the factory pattern. But if your "do this" isn't instantiation, then a simple Enum will probably work just as well. Like what Michael said, if you have a slightly more concrete example, you'll get better answers.
Now and then in my code I find that I can solve a problem by either using a naked generic class or one with wildcards.
I have a design where a class like this:
Class World<T, C> { .... }
definitely in general is making my code cleaner than it would have been without generics.
Yet, sometimes I use
World theWorld;
or sometimes I end up with
World<?, ?> theWorld;
I do this because it seems to be what it takes to make the compiler accept it and my
attempts to avoid them lead me to more casting or inheriting complexity.
It looks ugly and smelly to me and yet I cannot justify the added complexity it looks like I need to introduce to avoid it.
What are some cases (if any) that you believe using a naked or wildcarded generic is acceptable idiomatic Java?
There is a good example (use case) of using <?> in the Wildcards section of the Generics tutorial.
A sort summary: if you want to write a printCollection method which accepts all kinds of Collection you could use Collection<?> as a parameter type. You cannot use Collection<Object> as the parameter type for this purpose because it is not a supertype of all kinds of collections.
Using Collection<?> instead of "pure" Collection in this case is safer because you cannot add items to Collection<?> (except for null) in the printCollection method.
Any time you could use generics but don't need it in that specific situation. <?> tells the compiler roughly: "I know about generics, but I don't need the type now".
Maybe the type is needed in other situation. E.g. if you have a Set that just stores anything, like a cache, and you just don't care for the type of the elements at all. At other times you do, when you process specific elements.
It smells if you use too loosely bound type parameters (like <?> which is quite loose) but try to determine the type afterwards, e.g. with instanceof or some custom type discriminator. Then something was designed poorly.
The Wildcard also proves as very useful, when you want to store multiple objects, that are a subclass of another class.
For example:
Collection<? extends Shape> myShapes
This Collection now could keep all the objects, that are a subclass of Shape.
So you are type-safe when adding any object that is a subclass of Shape. For Example:
myShapes.add(new Rectangle())
myShapes.add(new Triangle())
If I am creating a java class to be generic, such as:
public class Foo<T>
How can one determine internally to that class, what 'T' ended up being?
public ???? Bar()
{
//if its type 1
// do this
//if its type 2
// do this
//if its type 3
// do this
//if its type 4
// do this
}
I've poked around the Java API and played with the Reflection stuff, instanceof, getClass, .class, etc, but I can't seem to make heads or tails of them. I feel like I'm close and just need to combine a number of calls, but keep coming up short.
To be more specific, I am attempting to determine whether the class was instantiated with one of 3 possible types.
I've used a similar solution to what he explains here for a few projects and found it pretty useful.
http://blog.xebia.com/2009/02/07/acessing-generic-types-at-runtime-in-java/
The jist of it is using the following:
public Class returnedClass() {
ParameterizedType parameterizedType = (ParameterizedType)getClass()
.getGenericSuperclass();
return (Class) parameterizedType.getActualTypeArguments()[0];
}
In contrast to .NET Java generics are implemented by a technique called "type erasure".
What this means is that the compiler will use the type information when generating the class files, but not transfer this information to the byte code. If you look at the compiled classes with javap or similar tools, you will find that a List<String> is a simple List (of Object) in the class file, just as it was in pre-Java-5 code.
Code accessing the generic List will be "rewritten" by the compiler to include the casts you would have to write yourself in earlier versions. In effect the following two code fragments are identical from a byte code perspective once the compiler is done with them:
Java 5:
List<String> stringList = new ArrayList<String>();
stringList.add("Hello World");
String hw = stringList.get(0);
Java 1.4 and before:
List stringList = new ArrayList();
stringList.add("Hello World");
String hw = (String)stringList.get(0);
When reading values from a generic class in Java 5 the necessary cast to the declared type parameter is automatically inserted. When inserting, the compiler will check the value you try to put in and abort with an error if it is not a String.
The whole thing was done to keep old libraries and new generified code interoperable without any need to recompile the existing libs. This is a major advantage over the .NET way where generic classes and non-generic ones live side-by-side but cannot be interchanged freely.
Both approaches have their pros and cons, but that's the way it is in Java.
To get back to your original question: You will not be able to get at the type information at runtime, because it simply is not there anymore, once the compiler has done its job. This is surely limiting in some ways and there are some cranky ways around it which are usually based on storing a class-instance somewhere, but this is not a standard feature.
Because of type erasure, there is no way to do this directly. What you could do, though, is pass a Class<T> into the constructor and hold onto it inside your class. Then you can check it against the three possible Class types that you allow.
However, if there are only three possible types, you might want to consider refactoring into an enum instead.
The Problem is that most of the Generic stuff will disappear during compilation.
One common solution is to save the type during the creation of the Object.
For a short introduction in the Type Erasure behaviour of java read this page
If you know a few specific types that are meaningful, you should create subclasses of your generic type with the implementation.
So
public class Foo<T>
public ???? Bar()
{
//else condition goes here
}
And then
public class DateFoo extends Foo<Date>
public ???? Bar()
{
//Whatever you would have put in if(T == Date) would go here.
}
The whole point of a generic class is that you dont need to know the type that is being used....
It looks like what you want is in fact not a Generic class, but an interface with a number of different implementations. But maybe it would become clearer if you stated your actual, concrete goal.
I agree with Visage. Generics is for compile-time validation, not runtime dynamic typing. Sounds like what you need is really just the factory pattern. But if your "do this" isn't instantiation, then a simple Enum will probably work just as well. Like what Michael said, if you have a slightly more concrete example, you'll get better answers.
So, I'm looking through a java library (JScience) after someone here thoughfully pointed me towards it for getting Vectors (mathematical ones, that is) in java.
Unfortunately, I've never seen anything in my life before like:
public static <F extends Field<F>> DenseVector<F> valueOf(F... elements)
as a method you can call in the DenseVector class. What...does that even mean. Is it returning a "<F extends Field<F>>" (and if so, why does Eclipse think it's an input?)
http://jscience.org/api/org/jscience/mathematics/vector/DenseVector.html#valueOf(F...)
It really confuses me. I can't make a new DenseVector() because only the super class has that, and it's protected, and trying to do DenseVector.valueOf() apparently only works if I give it...that...weird thing as an input.
I've seen people having to instantiate methods when trying to instantiate objects (or something like that)...is that like that (or IS it that?)) What is the API trying to get me to do?
I'm kind of confused that I've learned java in school (and used it a bit at work, though we use a lot of differnet stuff besides just java), and never came across anything like this. What's it for? What's it trying to get me to do? Is it new? Old? Obscure?
-Jenny
You should be able to invoke this method to create a vector, like this:
Real r1 = Real.ONE, r2 = Real.valueOf(2D), r3 = Real.ZERO;
DenseVector<Real> v = valueOf(r1, r2, r3);
In this example, the type argument F is Real. Real obeys the constraint "extends Field<F>" because it implements Field<Real>.
For different applications, different fields are likely to be used. For example, security applications might use the ModuloInteger field. It's a little confusing because this is a mathematical field, not a "vector field" like one talks about in physics.
By using type variables, this library helps to make sure you perform all operations within a given field. For example, given v declared as a DenseVector<Real> like above, the compiler will complain if you try to multiply it by a Complex number.
It's a generic return type. See here for a tutorial on Java Generics.
These are called Generic types. They've been added in Java 5 and are similar to C++ templates.
The idea is that you define a collection of items of a particular type rather than something general.
This helps you avoid frequent downcasting. In older Java code, suppose that you knew your vector would contain only X's. Once you retrieved items out of that collection, you would just get Object, and you had to explicitly downcast it.
It is also safer because you can't put Ys into a vector of Xs, and clearer to read for the same reasons.
The story behinds the "extends" in these brackets is that you can define collections of "Xs and all their subtypes" that would still accept subtypes of X but reject Y.
public static <F extends Field<F>> DenseVector<F> valueOf(F... elements)
Lets break this down:
public static
Its a public static method.
<F extends Field<F>>
Its a generic method for any class F where F is an extention of Field
DenseVector<F>
It returns a (generic) DenseVector for F
valueOf(F... elements)
A method named valueOf where parameters are zero or more Fs.