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Inner joins using Hibernate Criteria on non-primary key column

I want to write this query using Hibernate Criteria language. I am pretty new to Hibernate and not able to convert this query into Criteria form. I referred lots of answers available on SO but in my case I am using inner join on different columns rather than primary key/ foreign key column. I referred this but still can't make it right.
select TableA.columnA1, TableA.columnA2, TableA.columnA3, TableB.columnB1, TableC.columnC2 from TableA inner join TableB
on
cast(TableA.columnA3 as Integer) = TableB.columnB2
inner join
TableC
on
TableB.columnB3 = TableC.columnC1

To handle the joining logic, you are going to want to use from for each of the tables and include all of your conditions from the on-clauses in the where predicate.
Here is a JPA example that handles a parent-child relationship without having a foreign-key relationship:
EntityManager em = getDb().getEntityManager();
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Child> criteria = cb.createQuery(Child.class);
Root<Parent> p = criteria.from(Parent.class);
Root<Child> c = criteria.from(Child.class);
Predicate condition = cb.and(
cb.equal(c.get(Child_.parentId), p.get(Parent_.id)),
...
);
criteria.where(condition);
criteria.select(c);
criteria.orderBy(cb.asc(c.get(Child_.createDate)));
TypedQuery<Child> q = em.createQuery(criteria).setMaxResults(limit);
A JPA example is provided here, because the Hibernate criteria API is deprecated in favor of the JPA criteria API (see Legacy Hibernate Criteria Queries).

JPA Repository : inner join with null value

I am using JPA repository to access Mysql.
I have this query :
#Query("Select s.productName, s.stock from Sell s");
I am getting an execution error because stock is sometime null.
The generated sql translation of this query is :
select sell0_.productName, sell0_.stock_id from T_SELL sell0_ inner join T_STOCK stock0_ on sell0_.stock_id=stock0_.id
Is there a way to make this JPA query work even if stock_id is null?

Should be able to coalesce
#Query("Select s.productName, coalesce(s.stock,'xxx') from Sell s");
Full man is https://docs.jboss.org/hibernate/orm/4.3/devguide/en-US/html/ch11.html
Hope this helps.

Try to change relation definition, using optional = true:
#OneToOne(optional = true)
private Stock stock;
You can even change how this data should be fetched, using a join, a subselect or with a different select. More info here: JPA eager fetch does not join

JPQL table join query

How do I get JPA & JPQL to pass a complete join query to the RDBMS? For example,
SELECT e
FROM Employee e
WHERE a.runkey = e.runkey
AND e.middle = 'M'
AND a.state = 'MA'
With the following Employee class
#Entity
public class Employee implements Serializable {
blah ... blah
#OneToOne
#JoinColumn(
name = "runkey",
referencedColumnName = "runkey",
insertable=false, updatable=false)
private Address address;
}
and the JPQL,
SELECT e
FROM Employee e
INNER JOIN FETCH e.address AS a
WHERE a.state = :state
AND e.middle = :middle
I am able to get Hibernate JPA to pull the data as expected.
However, eclipselink croaks that it cannot traverse associated field "address".
If so, how then should I design the Employee entity and how should I phrase the JPQL in order to get eclipselink to execute a table join with WHERE filters on both tables?
(Rant: Otherwise Eclipselink JPA is no better than JDO!!!)
~
Further edit: Does this post mean anything to my case ....
https://forums.oracle.com/forums/thread.jspa?threadID=1568659

The problem is that you are trying to alias a join fetch which is not allowed according to the JPQL specs. Hibernate allows this anyway.
You can still obtain the desired behavior with EclipseLink using query hints.
Take a look at the following posts:
jpa fetch join query
EclipseLink JPQL (Glassfish v3): join fetch syntax problem?
The following link can also be useful:
http://wiki.eclipse.org/EclipseLink/Examples/JPA/QueryOptimization

How to write a HQL query for Many To Many Associations?

I have 3 tables, Role[roleId, roleName], Token[tokenID, tokenName] & ROLETOKENASSOCIATION[roleId, tokenID]. The 3rd one was created automatically by hibernate. Now if i simply write a Query to get all the objects from Role class means, it gives the all role objects along with the associated tokenID & tokenName.
I just wanted the association as unidirectional. i.e: Roles--->Tokens
So the annotation in the Role class looks like,
#Id
#GeneratedValue(strategy=GenerationType.AUTO)
private int roleId;
private String roleName;
#ManyToMany
#JoinTable(name="ROLE_TOKEN_ASSOCIATION",
joinColumns={#JoinColumn(name="roleId")},
inverseJoinColumns={#JoinColumn(name="tokenID")})
private List<Token> tkns;
//Getters & Setters
Now i want the tokenNames for the specific roleId.
First i made a query like this SELECT tkns.tokenName FROM Role WHERE Role.roleId=:roleId
But, i ended up with some dereference error.
Then i changed the query to SELECT tkns FROM Role r WHERE r.roleId=:roleId
Now i have got what i wanted. But it comes with roleId too.
How shall i get tokenName itself?
Actually my problem is solved, but i would like to know how to do it.
It ll be helpful to me, if anyone explains the Query Construction.
Any suggestions!!

Have you tried
SELECT t.tokenName FROM Role r JOIN r.tkns t WHERE r.roleId = :roleId
EDIT: This query almost directly maps to the corresponding SQL query where Role r JOIN r.tkns t is a shorthand syntax for the SQL join via the link table Role r JOIN ROLETOKENASSOCIATION rt ON r.roleId = rt.roleId JOIN Token ON rt.tokenId = t.tokenId. Affe's answer is another syntax for the same query.
See also:
Chapter 14. HQL: The Hibernate Query Language

You want a scalar list of just the name field? You should be able to get that like this
select t.name from Roles r, IN(r.tkns) t where r.roleId = :id

How do I left join tables in unidirectional many-to-one in Hibernate?

I'm piggy-backing off of How to join tables in unidirectional many-to-one condition?.
If you have two classes:
class A {
#Id
public Long id;
}
class B {
#Id
public Long id;
#ManyToOne
#JoinColumn(name = "parent_id", referencedColumnName = "id")
public A parent;
}
B -> A is a many to one relationship. I understand that I could add a Collection of Bs to A however I do not want that association.
So my actual question is, Is there an HQL or Criteria way of creating the SQL query:
select * from A left join B on (b.parent_id = a.id)
This will retrieve all A records with a Cartesian product of each B record that references A and will include A records that have no B referencing them.
If you use:
from A a, B b where b.a = a
then it is an inner join and you do not receive the A records that do not have a B referencing them.
I have not found a good way of doing this without two queries so anything less than that would be great.
Thanks.

I've made an example with what you posted and I think this may work:
select a,b from B as b left outer join b.parent as a in HQL.
I have to find a "criteria" way of doing that though.

You may do so by specifying the fetch attribute.
(10) fetch (optional) Choose between outer-join fetching and fetching by sequential select.
You find it at: Chapter 6. Collection Mapping, scroll down to: 6.2. Mapping a Collection
EDIT
I read in your question's comment that you wanted a way to perform a raw SQL query? Here a reference that might possibly be of interest:
Chapter 13 - Native SQL Queries
and if you want a way to make it possible through HQL:
Chapter 11. HQL: The Hibernate Query Language
In chapter 11, you want to scroll down to 11.3. Associations and joins.
IQuery q = session.CreateQuery(#"from A as ClassA left join B as ClassB");
I guess however that ClassB needs to be a member of ClassA. Further reasdings shall help.
Another thing that might proove to be useful to you are named queries:
<query name="PeopleByName">
from Person p
where p.Name like :name
</query>
And calling this query from within code like so:
using (var session = sessionFactory.OpenSession())
using (var tx = session.BeginTransaction()) {
session.GetNamedQuery("PeopleByName")
.SetParameter("name", "ayende")
.List();
tx.Commit();
}
Please take a look at the referenced link by Ayende who explains it more in depth.