Modulation of adding new Strings -> Method calls - java

If I have a program that does the following:
if(input=='abc'){do x}
if(input=='def'){do y}
In the future, I may want to add another piece of code like so:
if(input=='ghy'){do x}
As you can see, I am adding a new 'if' statement for a different conditional BUT using the SAME function X.
The code in future has potential to have lots of different IF statements (or switches) all of which are comparing a string vs a string and then performing a function. Considering the future expansion, I was wondering if there is a possible 'neater', 'modular' way of achieving the same results.
It's a shame I can't combine the String with a Method call in a hashtable (String, method) in Java. That way I could just store any new procedures inside a hashtable and grab the relevant method for that String.
Any ideas?
Thank you
EDIT: Thank you for everyone's solutions. I was surprised by the quantity and quality of replies I received in such a small amount of time.

Maybe you can use enum. Example:
public enum InputType
{
abc, def
{
#Override
public void x()
{
System.out.println("Another method");
}
},
ghy;
public void x()
{
System.out.println("One method");
}
}
And further:
InputType.valueOf("abc").x();
Cheers!

I guess you could always use a Map<String, Runnable> and map to anonymous Runnable implementations:
myMap.put("abc", new Runnable() { public void run() { do x } });
...
myMap.get(input).run();

You should take a look at the command pattern. There are several ways of implementing it, and frameworks such as Spring can help you do with in a clean way.
But in a simple manner here's what you could do:
1-Create a Command interface with a method that your program will have to call to do the task, say doTask()
2-Create classes for command X and Y, implementing the Command interface.
3-Create a Map<String, Command> that will map your commands (X and Y) to logical names
4-Create a configuration file of your choice, say a .properties file that will map your input to your command names: abc=X, def=Y, ghi=X
5-Your program then does lookups on the config file to know which command to run according to the input.

A lot of ifs always tell us that we could do this better. In your case better option is to use design pattern e.g. Chain of responsibility. You will have good implementation which you can dynamic change and your code will be easier to maintenance than ifs implementation.
Take a look at this adaptation chain of responsibility to your case:
Main:
public static void main(String[] args) {
ClassA classA = new ClassA(Arrays.asList("abc", "ghi"));
ClassB classB = new ClassB(Arrays.asList("def"));
classA.setNextInChain(classB); // you can always write Builder to do this
String input = "def";
classA.execute(input);
}
BaseClass:
public abstract class BaseClass {
private Collection<String> patterns = Collections.EMPTY_LIST;
protected BaseClass nextInChain;
protected abstract void doMethod(); // your doA, doB methods
public void execute(String input) {
// this replace many ifs in your previous implementation
if (patterns.contains(input)) {
doMethod();
} else {
nextInChain.execute(input);
}
}
public void setPatterns(Collection<String> patterns) {
this.patterns = patterns;
}
public void setNextInChain(BaseClass nextInChain) {
this.nextInChain = nextInChain;
}
}
Class in chain:
public class ClassA extends BaseClass {
ClassA(Collection<String> patterns) {
setPatterns(patterns);
}
#Override
protected void doMethod() {
// do A
}
}
public class ClassB extends BaseClass {...}

Related

Java inheritance and method resolution order

I've got the following code example:
class p {
public void druckauftrag() {
// ...
drucke();
}
public void drucke() {
System.out.println("B/W-Printer");
}
}
class cp extends p {
public void drucke() {
System.out.println("Color-Printer");
}
}
Calling the following lines:
cp colorprinter = new cp();
cp.druckauftrag();
There is no problem understanding why "cp.druckauftrag();" results in console output "Color-Printer".
But when I call:
p drucker = (p)colorprinter;
drucker.druckauftrag();
I get the same output - why?
Does the typecast overwrite the object "drucker" 's method "drucke" with "drucke" from colorprinter?
Thanks in advance for every explanation.
colorprinter does not stop being an instance of cp when you use the cast operator on it, so its implementation of public void drucke() does not change
What you are expressing with your (p)colorprinter casting is the kind of contract (interface) you expect the object colorprinter to satisfy, which includes a public method with the signature public void drucke(), but not any specific implementation.
And, by the way, this casting is already performed implicitly when you declare drucker of the type p, so (p) is redundant in p drucker = (p)colorprinter;. p drucker = colorprinter; will suffice.
Here you can learn more about typecasting.
Keep in mind that it's best practice to extend from abstract classes or interfaces and only #Override (implement) abstract methods. A better design of your code would be:
abstract class BasePrinter {
public void druckauftrag() {
// ...
drucke();
}
public void drucke();
}
class p extends BasePrinter {
public void drucke() {
System.out.println("B/W-Printer");
}
}
class cp extends BasePrinter {
public void drucke() {
System.out.println("Color-Printer");
}
}
But of course constraints don't always allow for that kind of redesign. Passing the base requirements as parameters to the constructor (dependency injection) instead of extending a base class can also be a good alternative:
interface Druckable {
void drucke();
}
class Druckauftrager {
Druckable dk;
Druckauftrager(Drukable dk){
this.dk = dk;
}
public void druckauftrag() {
// ...
dk.drucke();
}
}
class p implements Druckable {
public void drucke() {
System.out.println("B/W-Printer");
}
}
class cp implements Druckable {
public void drucke() {
System.out.println("Color-Printer");
}
}
Now, if you want to express that a printer requires or can have multiple printing capabilities (like both color and b/w), you just write the class with as much extra Drukable properties and constructor parameters as you want, for example:
class BlackAndWhiteOrColorPrinter {
p blackAndWhitePrintService;
cp colorPrintService;
Druckable selectedPrintService;
BlackAndWhiteOrColorPrinter (p blackAndWhitePrintService, cp colorPrintService){
this.blackAndWhitePrintService = blackAndWhitePrintService;
this.colorPrintService = colorPrintService;
this.selectedPrintService = blackAndWhitePrintService;
}
public void druckauftrag() {
// ...
selectedPrintService.drucke();
}
}
This way, you can even write a class MultiPrinter with a MultiPrinter(List<Druckable> printServices) constructor and add any number of printing modes to its list of printing services: p, cp, and whatever other implementation of Druckable with its public void drucke() comes in the future. It is also extra practical if you want to introduce unit testing, so you can provide mockup objects that force the particular conditions you want to test, like druke() throwing a PaperJamException, for example.
For more information on how interfaces, overriding and inheritance work, see https://docs.oracle.com/javase/tutorial/java/IandI/usinginterface.html
BTW, acording to the latest revision of the official java code conventions guide and also by de facto standard, classes in Java should use CamelCase naming convention. You can also benefit greatly from using semanting naming on all your definitions, like BlackAndWhitePrinter blackAndWhitePrinter and ColorPrinter colorPrinter.
colorprinter is an instance of cp. Even when you upcast it to p, it's drucke() method will be still the one from cp.
The difference is that after you upcast colorprinter, you will not be able to invoke the methods that cp defines on its own.
When you create an object using new operator, memory is allocated in heap. Methods and fields are actually there depending upon the concrete actual class of the object.
Alter a sub class overrides and modifies a behavior from its super class, invoking the overridden method will always result in the modified behavior. Casting will only mean that the object of sub class is now represented by the super type as the object has a modified behavior for a method will always result in the modified behavior.
Suppose you have below classes
public class Fruit{
public void taste(){
System.out.println("depends upon the actual fruit");
}
}
public class Mango extends Fruit{
#Override
public void taste(){
System.out.println("sweet");
}
public void wayToExposeSuperMethod(){
super.taste();
}
}
In other words its like calling mango as a fruit but still mango remains mango.
For above code
Fruit fruit = new Mango();
fruit.taste(); // <-- this will output : sweet
((Mango)fruit).taste();// <-- this will output : sweet
fruit.wayToExposeSuperMethod(); // <-- this will not compile
((Mango)fruit).wayToExposeSuperMethod(); // <-- this will output : depends upon the actual fruit

Shadowing variable used in a default method of an interface in Java 8

Today I was thinking about a nice way to write less code for a common functionality that is required for different objects.
Inheritance can do the job but then the classes won't be able to inherit from anyone else, so I chose Interfaces.
So I have my interface with the functionality I will need for some objects:
public interface Test {
String message = "Hello from Interface!";
default void printMessage() {
System.out.println(message);
}
}
And then I can use it in any object without having to override/write any code more than just simply calling the method when needed:
public class TestingTest implements Test {
public String message = "Hello from Class!";
public TestingTest() {
printMessage();
}
public static void main(String[] args) {
new TestingTest();
}
}
It works like a charm! But... Then I thought, what if I want some of those objects to specify a different message without being required (optional), well first thing I thought was to shadow the interface variable, but it doesn't work, the default method keeps using the variable from the interface instead of the class variable (which shadowed it).
A solution of course would be to overload the printMessage method in the interface so it recieves the message as a parameter for when the user requires to specify the message, but is there any more elegant way? Something like simply just declaring a new message in the class?
The String message in the interface is static (AFAIK). So that scheme does not work.
You might do something (ugly) as:
default void printMessage(String... messages) {
if (messages.length == 0) {
messages = new String[] { "arrgg" };
}
System.out.println(messages[0]);
}
Fields have no inheritance, so the value can only stem from an overridable method like
public String message() { return "..."; }
What you want is a functionality in n classes that should also be modifiable, if needed.
To be honest, your example is a little bit abstract and thus my answer will be abstract, too.
public interface Test {
void printMessage();
default void printMessage(String message) {
System.out.println(message);
}
}
public class TestingTest {
private final test;
public TestingTest(Test test) {
this.test = test;
}
public void someMethod() {
test.printMessage("Hello from class");
}
}
Additionally, you would have a class that implements the interface and offers the message. This way you could group your objects, change the message, make more complex logging and you would actually see the dependency from outside.
In my opinion, you are misusing the interface. An interface offers public methods to call it from outside, but you want to use them inside like they were private functionalities for the class.
Just use objects instead.

Java Passing in Type as Function Parameter

I come from a Python background and in Python you can pass in the type of an object as a parameter. But in Java you cannot do this, any tips on how to get something like this working?
private void function(Type TypeGoesHere)
Stock s = new TypeGoesHere();
s.analyze();
}
Java does not support Python’s way of referencing functions and classes. To achieve this behaviour, you have to use two advanced techniques: generics and reflection. Explaining these concepts is beyond the scope of a SO answer. You should read a Java guide to learn about them.
Yet here is an example how this would look like, assuming that the given class has a no-argument constructor:
public <T extends Stock> void analyzeNewStock(Class<T> clazz) throws Exception {
Stock s = clazz.newInstance();
s.analyze();
}
Then call this function with analyzeNewStock(MyStock.class).
As this is a rather complicated and error-prone approach, you’d rather define an interface that creates Stock instances:
public interface StockProvider {
Stock createStock(String value);
}
public class MyStockProvider implements StockProvider {
private final String valueTwo;
public MyStockProvider(String valueTwo) {
this.valueTwo = valueTwo;
}
#Override
public Stock createStock(String valueOne) {
return new MyStock(valueOne, valueTwo);
}
}
public class MyOtherClass {
public void analyzeNewStock(StockProvider provider) {
provider.createStock("Hi!").analyze();
}
public static void main(String[] args) {
analyzeNewStock(new MyStockProvider("Hey!"));
}
}
In Java you can pass a Class. You can do it like this:
private void function(Class c)
This is not very common procatice though. You can probably get wha you need by looking into Strategy pattern, or proper use of Object Oriented Programming (polymorphism).
If you are looking for a way to build some objects, look into Factory pattern.
If you want to create a generic class- look into this detailed answer: https://stackoverflow.com/a/1090488/1611957
You could use generics. For example:
private <T> void function(Class<T> clazz) {
try{
T t = clazz.newInstance();
//more code here
}catch(InstantiationException | IllegalAccessException ex){
ex.printStackTrace();
}
}
The Class<T> clazz shows what type to instantiate. The try/catch is just to prevent errors from stopping your code. The same idea is expanded in this SO post. More info here.
However, I'm not really sure why you would want to do this. There should easily be a workaround using a simple interface. Since you already know that you want an object with type Stock, you could pass an implementation of the interface. For example:
//interface to implement
public interface Stock {
public void analyze();
}
//rewrite of function
private void function(Stock s){
s.analyze();
}
And using two ways to call function:
//first way
public class XYZ implements Stock{
public void analyze(){
//some code here
}
}
//calling the function
function(new XYZ());
//second way
function(new Stock(){
public void analyze(){
//your code here
}
});

Is it a good idea to use reflections in a Web application?

I have developed below code with the intention to remove if else conditions so that code cyclomatic complexity should be less.
For this I have used reflection api and wrote method which takes condition as an argument and called respective method on the condition name basis.
This works fine, I want to know is it a good idea to use reflection (This code) in web application, so that I am free from checking conditions.
For example in below code we have different method with prefix state ex: stateSUBMIT, stateWithdraw etc.
we can call stateSUBMIT method by passing only "SUBMIT".
public class Participate {
public String execute(String methodName) {
String st = null;
try {
Method method = this.getClass().getDeclaredMethod(
"state" + methodName);
method.invoke(this);
} catch (Exception e) {
e.printStackTrace();
}
return st;
}
public void stateSUBMIT() {
System.out.println("in SUBMIT");
}
public void stateWithdraw() {
System.out.println("in Withdraw");
}
public void state() {
System.out.println("in state ");
}
public void statenull() {
System.out.println("in null ");
}
public static void main(String[] args) {
Participate p = new Participate();
p.execute("SUBMIT");
}
}
This is valid code, but can be achieved without reflections.
Step One: Define an interface
public interface Command {
public void execute();
}
Step Two: Create Concrete Implementations
public class StateCommand implements Command {
public void execute() {
// Your code.
}
}
Step Three: Add a collection of these to your original class
private Map<String, Command> commands;
Step Four: Populate
public MyClass() {
commands = new HashMap<String, Command>();
commands.put("state", new StateCommand());
}
Get that class and execute
public String callMethod(String name) {
Command command = commands.get(name);
if(command != null) {
command.execute();
}
}
This is just a relatively simple alternative to using reflections, which should be considered as a last resort.
I would avoid it. There are better alternatives. You could pick one of all the numerous web frameworks or you could code something similar without reflection. For example, use a HashMap from the action (SUBMIT, ...) to an object that implements an interface. That way you can call a method with parameters without reflection, which is slow and which provides no compile-time validations. This is not a recommendation (go with a framework!), but it is a better way of doing what you are doing right now.
Your implementation is beneficial in case if you are doing for making this Generic approach for all other other classes in your project.Its good if you are having re usability of this in many other scenarios.
But if its only for specific implementation which is not generalized then there are many simple ways to do this job, because if you will use java reflections than there is some amount of time complexity involved which is comparatively less if you do it without using reflectns.

JAVA: Call class method based on value of variable

I am working on a project in java and am quite new to the language and OOP. My dilema is that I want to carry out a task/function from a specific class based on the value of a variable.
This is kind of what I am trying to achieve.
class mainClass{
String option;
public static void main(String[] args) {
mainClass main = new mainClass();
}
mainClass(){
secondClass sC = new secondClass();
thirdClass tC = new thirdClass();
switch (option){
case "1" :
sC.doSomething();
case "2" :
tC.doSomething();
}
}
}
class secondClass{
void doSomething(){
System.out.println("1");
}
}
class thirdClass{
void doSomething(){
System.out.println("2");
}
}
The reason I don't want to do this, is because if I want to add a fourth, fifth, sixth class etc... I would have to update the switch.
I tried using a hashmap. Where I assigned secondClass the key of "1". But then I would have to cast the object, but this brings me back to the original headache of not knowing what class would need to be called in advance.
So then I tried using a hashmap like this,
HashMap<String, Object> map = new HashMap<String, Object>();
Which I could then do map.get("1") but then now I can't call any of the methods for the class in question.
If I need to use a large switch statement I will, but I am actively seeking a more efficient alternative.
You were right to use a Map but you were also right to balk at casting. However, nowadays with generics you can get around all that:
interface DoesSomething {
// An object implementing this interface does something.
public void doSomething();
}
// Class that does something.
class FirstClass implements DoesSomething {
#Override
public void doSomething() {
// What FirstClass does.
}
}
// Another class that does something.
class SecondClass implements DoesSomething {
#Override
public void doSomething() {
// What SecondClass does.
}
}
// How I know what to do. Map the string to a DoesSomethng.
Map<String, DoesSomething> whatToDo = new HashMap<>();
{
// Populate my map.
whatToDo.put("1", new FirstClass());
whatToDo.put("2", new SecondClass());
}
public void doSomethingDependingOnSomething(String something) {
// Look up the string in the map.
DoesSomething toDo = whatToDo.get(something);
// Was it in there?
if (toDo != null) {
// Yes! Make it do it's thing.
toDo.doSomething();
}
}
If you want to avoid using Reflection (wich is discouraged here), you should consider a simple SAM-Interface:
public interface Doable { public void doSomething(); }
and have all classes implement the interface (no other changes required in these classes) and having a Map<String, Doable> and calling
if (map.containsKey(option)) map.get(option).doSomething();
// Or (may be a little faster)
Doable opt = map.get(option);
if (opt != null) opt.doSomething();
If your implementations have different methods, you'll most likely be bound to use Reflection to get the declared methods and compare by String.

Categories

Resources