Simple question, maybe someone knows:
In GWT devmode, my urls look like this: http://myserver/myapp/myservice
When I run 'ant war' and deploy that war on tomcat, they mysteriously change to: http://myserver/myapp/myapp/myservice
Everything still works, but obviously the URLs are uglier. I'd like to just keep the URLs used in devmode. Any info is appreciated, thanks.
-tjw
Deploy the web service as ROOT.war, not as myapp.war, because the first 'myapp' is the web application context path, and 'myapp/myservice' is the path inside the web application.
Change your mappings in your web.xml to all start with / instead of /myapp/ and deploy your application as myapp.war or deploy the war as Root.war
Ok, I've got a solution for this. So many people are having this problem all over the net, I decided to answer my own question. The key is to use #RemoteServiceRelativePath in your RemoteService interface file. For example, to solve my original problem, I would annotate my RemoteService interface like this:
#RemoteServiceRelativePath("../myservice")
This way, whatever path is in front of the service's URL is irrelevant. Now in the web.xml, instead of using /myapp/myservice as the url-pattern, I just use /myservice. Now it works in both GWT's devmode and in Tomcat with no further modification needed.
Related
I have created application in Dropwizard, which is serving REST API to my clients. I used to run this from .jar file on server, everything worked fine.
Now I have requirement to move my application to WildFly, so now I assume that I need to have a WAR instead of JAR, and here comes my problem:
How to write web.xml to my application? What to include in there? Could anyone give me any template or tutorial or some example how it is done in Dropwizard?
I found what I was looking for. It's wizard-in-a-box project that do all the necessary things to build a WAR file.
There is an application, say myApp.war (developed using Spring MVC) that I give the users to deploy in their tomcat webapp folder. When the user starts tomcat, the war is exploded, and then I ask the user to go myApp/WEB-INF/classes/persistence.properties and ask him to edit just one property name (actually an HSQLDB path). Post that I ask the user to stop tomcat, delete the war file and start tomcat server again. And the application is up and running.
Although the users are not complaining, I believe there has to be a better way of doing this. For example when the users deploy wordpress or hudson and the first time they try to access the app. they are redirected to an install page where they do their basic configuration and they are up and running. How can I achieve it here.
I have used JNDI to solve this very problem in the past. Here is a nice example to show you how to do this with Spring:
http://www.journaldev.com/2597/spring-datasource-jndi-with-tomcat-example
Checkout JMX which can allow on the fly configuration, or there is one obix framework
Why not something like this:
Use a relative path with sysprops, like ${user.home}/path-to-hsqldb. If the user runs tomcat as user "jim", it will look in c:\users\jim\path-to-hsqldb (Windows) or /usr/jim/path-to-hsqldb (Linux)
You might need to use Spring's <context:property-placeholder/> to enable this.
I currently have a Jersey webapp without a web.xml. It deploys nicely, but doesn't start up until it receives its first web request.
To get the webapp to load at startup, I could create a web.xml for the webapp and give a load-on-startup tag. However, I'd strongly prefer not to make a web.xml.
Is there a way to get a JAX-RS application to load at startup without web.xml? I'll even accept a solution that is specific to Jersey and/or Tomcat.
EDIT: I would also accept a solution that loads all apps in a Tomcat instance eagerly.
EDIT: Let me give a little more information on how the app is being deployed, per a comment.
The deployment process is not sophisticated.
The App will live on an EC2 instance running Ubuntu 12.04. I'm setting up one instance of the App by hand; once it works, I will make an AMI of the app and create additional copies of it as needed.
To deploy the app on the initial instance, I'm simply copying the WAR file to /var/lib/tomcat7/webapps and restarting Tomcat. No other webapps will be running on this Tomcat instance.
If any additional information would be useful, let me know! I'll happily add it.
EDIT: For clarity's sake, this is how my webapp Application class looks, at a high level:
#ApplicationPath("/")
public class App extends ResourceConfig {
// ...
}
I'm using the Jersey-specific ResourceConfig class instead of the more general JAX-RS Application class because I'm using Jersey's built-in HK-2 to do some dependency injection.
The only way I can think of to do that is to switch to setting up the Jersey ServletContainer yourself and set its "load on startup" value to something greater than zero. You might use a ServletContainerInitializer (no relation--the naming is just a coincidence) to do it. If you happen to be using Spring, its WebApplicationInitializer offers the same mechanism with a slightly more convenient interface.
Another, rather hacky, way would be to write a class that extends ServletContainer and give it an appropriate Servlet 3.0 annotation, something like #WebServlet(value="/", loadOnStartup=1)
One solution would be to force a first request to the app by simply adding a call to curl or wget to your deployment script. It has the additional advantage of warming up any caches. And it can be used for testing if the deployment and the app really work. (Just check HTTP status code or some text on the response page...)
I'm trying to deploy my first servlet to my server. There are, of course, many tutorials online. But most of them are very detailed and complicated, and I only need to deploy a few simply servlets to this server.
I found what I think to be the shortest method of deployment: Deployment on Tomcat Startup. I moved my .WAR file (FirstProject.war) into $CATALINA_BASE/webapps folder, but when trying to access it (ServerIP/FirstProject) I get the "The requested resource is not available." error.
Is there anything I forgot in the process of deployment?
I know that deployOnStartup has to be set to true, but I didn't change anything with the server's hosts, so the current host is localhost. I didn't change its settings, so deployOnStartup should be true (It's said that true is the default).
What am I missing?
You are using easiest way but I don't know what you are missing. Here what I would suggest is run your server and access through localhost:8080 then click manage app then enter username and password then you can deploy your war.
If you have any query post command.
Even i used to face this problem while deploying my first web application on Jboss and Apache ..
Even though your code is working properly with all your servlet mappings and paths using in your content files ...some times they kick back in real time environment ..So we have to know the proper deployment folder structure and accordingly we have to change our paths in the code
what i am concluding is check the below lines of code
Examples, assuming root is http://foo.com/site/
Absolute path, no matter where we are on the site
/foo.html
will refer to http://foo.com/site/foo.html
Relative path, assuming the containing link is located in http://foo.com/site/part1/bar.html
../part2/quux.html
will refer to http://foo.com/site/part2/quux.html
or
part2/blue.html
will refer to http://foo.com/site/part1/part2/blue.html
I have installed Tomcat 5.0 in order to execute a web application. How can I show my files which are present in Tomcat to the web browser? I tried http://hostname:8080/myfolder/login.html, but I can't see the files.
One more thing I know about JDBC and other database connectivity and I have developed a HTML page. How can I let a button in the page execute the code written in a Servlet and perform validations?
The simplest thing is to add to the root webapp. That is webapps/ROOT. Any file you put in there will be served unless you change the default configuration.
You should read about the details, of course.
I have installed Tomcat 5.0 in order to execute a web application.
First of all, why are you using the ancient (8 year old) Tomcat 5.0? If you can, rather grab the latest one, Tomcat 6.0.
How can I show my files which are present in Tomcat to the web browser? I tried http://hostname:8080/myfolder/login.html, but I can't see the files.
Is myfolder the context name or just a folder in your webcontent? If it's a context name, then you need to ensure that it's properly deployed. You can find details in the server logs in the /logs folder. If it is a folder in your webcontent and the webapplication is thus supposedly to be the "root" application, then you need to ensure that it's deployed as ROOT.
To learn more about using Tomcat, go through the documentation.
One more thing I know about JDBC and other database connectivity and I have developed a HTML page. How can I let a button in the page execute the code written in a Servlet and perform validations?
To the point, just create a class which extends HttpServlet, implement the doPost() method, define the servlet in web.xml and let the action attribute of the HTML <form> element point to an URL which is covered by the url-pattern of the servlet mapping in the web.xml.
As the question is pretty broad, I have the impression that you haven't learned in any way how to work with Tomcat and JSP/Servlets. I would strongly recommend to go through those tutorials to familarize yourself with JSP/Servlet on Tomcat and Eclipse (an IDE) first: Beginning and Intermediate-Level Servlet, JSP, and JDBC Tutorials
Tomcat is not a web server like, say, Apache. It's a servlet container. You can not just move file in a subfolder which seem to be what you did. You need to pack your web application in a .war and deploy it.
The URL should rather be http://host:8080/webapp/subfolder/login.jsp
Without much information it's hard to help. Please edit your question and describe what you've done so far.