Develop Reference

Java Web Service client error

I was creating a Java web service server, using eclipse IDE. that server is the following.
Note: I am working in UBUNTU
package com.tesis.service;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.RejectedExecutionException;
import com.mathworks.engine.*;
/**
* #author root
*
*/
public class CNNPredict
{
public String cNNPredict(int[] Image, int Height, int Width) throws Exception
{
String FilePath = "/home/user/Documents/MATLAB/Project";
char[] CharFilePath = FilePath.toCharArray();
MatlabEngine eng = MatlabEngine.startMatlab();
eng.feval("cd", CharFilePath);
String result = eng.feval("CNNPredict",Image,Height,Width);
return result;
}
}
As you can see I am using MATLAB engine.
Matlab engine documentation. I checked that cNNPredict method is working properly by copying it into a new Java project and It worked perfectly.
I added the .jar files required to run java engine to the Dynamic web project where the web service is located.
Apparently this web service runs without problems Web Service working in local host
If I click on "CnnPredict" link I get the wsdl direction of the class , this direction is what I use to link the client with the server.
this is the client code:
public static void main(String[] args) throws IOException, CNNPredictExceptionException
{
CNNPredictStub stub = new CNNPredictStub();
CNNPredict cnn = new CNNPredict();
BufferedImage img = null;
System.out.println("Reading image ...");
img = ImageIO.read(new File("/home/riosgamarra/Documents/MATLAB/TesisGamarrarios/101_ObjectCategories/laptop/image_0009.jpg"));
int[] UnrolledImage = convertToGray(img);
cnn.setImage(UnrolledImage);
cnn.setWidth(img.getWidth());
cnn.setHeight(img.getHeight());
System.out.println(stub.cNNPredict(cnn).get_return());
}
It has no errors, but when I run it this error message shows up:
Exception in thread "main" org.apache.axis2.AxisFault: <faultstring>com/mathworks/engine/MatlabEngine</faultstring>
at org.apache.axis2.util.Utils.getInboundFaultFromMessageContext(Utils.java:513)
at org.apache.axis2.description.OutInAxisOperationClient.handleResponse(OutInAxisOperation.java:368)
at org.apache.axis2.description.OutInAxisOperationClient.send(OutInAxisOperation.java:414)
at org.apache.axis2.description.OutInAxisOperationClient.executeImpl(OutInAxisOperation.java:225)
at org.apache.axis2.client.OperationClient.execute(OperationClient.java:150)
at com.tesis.service.CNNPredictStub.cNNPredict(CNNPredictStub.java:197)
at com.tesis.client.CallWS.main(CallWS.java:40)
what I am missing ? do I need to add any special permissions to the server project ? What Am I missing ?
Note: I run the client clicking on the class and selecting Run as > Java application.

at com.tesis.service.CNNPredictStub.cNNPredict(CNNPredictStub.java:197)
is where the exception is but
public class CNNPredict
{
public String cNNPredict(int[] Image, int Height, int Width) throws Exception
{
String FilePath = "/home/user/Documents/MATLAB/Project";
char[] CharFilePath = FilePath.toCharArray();
MatlabEngine eng = MatlabEngine.startMatlab();
eng.feval("cd", CharFilePath);
String result = eng.feval("CNNPredict",Image,Height,Width);
return result;
}
}
is not the stub. First we need to the right code to look at. The matlab api is straight forward. My guess is that the stub is making the wrong call

How to serve static content and resource at same base url with Grizzly

I am using Grizzly to serve my REST service which can have multiple "modules". I'd like to be able to use the same base URL for the service and for static content so I can access all these urls:
http://host:port/index.html
http://host:port/module1/index.html
http://host:port/module1/resource
http://host:port/module2/index.html
http://host:port/module2/resource
The code I'm trying to set this up with looks like this:
private HttpServer createServer(String host, int port, ResourceConfig config)
{
HttpServer server = GrizzlyHttpServerFactory.createHttpServer(URI.create("http://" + host + ":" + port + "/"), config, false);
HttpHandler httpHandler = new CLStaticHttpHandler(HttpServer.class.getClassLoader(), "docs/");
server.getServerConfiguration().addHttpHandler(httpHandler, "/");
return server;
}
With this code, I am only able to see the html pages and I get a "Resource identified by path does not exist" response when I try to get my resources.
When I comment out the code to add the HttpHandler, then I am able to access my resources (but don't have the docs of course).
What do I need to do to access both my resources and my static content?

I ended up writing a service to handle static resources myself. I decided to serve my files from the file system, but this approach would also work for serving them from a jar - you'd just have to get the file as a resource instead of creating the File directly.
#Path("/")
public class StaticService
{
#GET
#Path("/{docPath:.*}.{ext}")
public Response getHtml(#PathParam("docPath") String docPath, #PathParam("ext") String ext, #HeaderParam("accept") String accept)
{
File file = new File(cleanDocPath(docPath) + "." + ext);
return Response.ok(file).build();
}
#GET
#Path("{docPath:.*}")
public Response getFolder(#PathParam("docPath") String docPath)
{
File file = null;
if ("".equals(docPath) || "/".equals(docPath))
{
file = new File("index.html");
}
else
{
file = new File(cleanDocPath(docPath) + "/index.html");
}
return Response.ok(file).build();
}
private String cleanDocPath(String docPath)
{
if (docPath.startsWith("/"))
{
return docPath.substring(1);
}
else
{
return docPath;
}
}
}

One thing you can do is run Grizzly as a servlet container. That way you can run Jersey as servlet filter, and add a default servlet to handle the static content. For example
public class Main {
public static HttpServer createServer() {
WebappContext context = new WebappContext("GrizzlyContext", "");
createJerseyFilter(context);
createDefaultServlet(context);
HttpServer server = GrizzlyHttpServerFactory
.createHttpServer(URI.create("http://localhost:8080/"));
context.deploy(server);
return server;
}
private static void createJerseyFilter(WebappContext context) {
ResourceConfig rc = new ResourceConfig().packages("com.grizzly.test");
// This causes Jersey to forward 404s to default servlet
// which will catch all the static content requests.
rc.property(ServletProperties.FILTER_FORWARD_ON_404, true);
FilterRegistration reg = context.addFilter("JerseyApp", new ServletContainer(rc));
reg.addMappingForUrlPatterns(EnumSet.allOf(DispatcherType.class), "/*");
}
private static void createDefaultServlet(WebappContext context) {
ArraySet<File> baseDir = new ArraySet<>(File.class);
baseDir.add(new File("."));
ServletRegistration defaultServletReg
= context.addServlet("DefaultServlet", new DefaultServlet(baseDir) {});
defaultServletReg.addMapping("/*");
}
public static void main(String[] args) throws IOException {
HttpServer server = createServer();
System.in.read();
server.stop();
}
}
You will need to add the Jersey Grizzly servlet dependency
<dependency>
<groupId>org.glassfish.jersey.containers</groupId>
<artifactId>jersey-container-grizzly2-servlet</artifactId>
<version>${jersey2.version}</version>
</dependency>
The only problem with this approach is that the default servlet is meant to serve files from the file system, not from the classpath, as you are currently trying to do. You can see in the createDefaultServlet method I just set the base directory to the current working directory. So that's where all your files would need to be. You can change it to "docs" so all your files would be in the docs folder, which would be in the current working directory.
If you want to read files from the classpath, you may need to implement your own servlet. You can look at the source code for DefaultServlet and try to modify it to serve from the classpath. You can also check out Dropwizard's AssetServlet, which already does serve content from the classpath.
Or you can just say forget it, and just serve from the file system :-)

Unable to overide the wsdl location in apache cxf 2.4.6

i have placed the wsdl files in
E:/testworkspace/projectname/docroot
WEB-INF
src
com
test
wsdl
if i give the full path say wsdlLocation = "file:E:/testworkspace/projectname/docroot/WEB- INF/src/com/test/wsdl/some.wsdl" , it picks the WSDL file.
but i need to make generic something like directly fetching:
#WebServiceClient(name = "TestInterfaceService",
wsdlLocation = "WEB-INF/wsdl/some.wsdl",
targetNamespace = "http://www.google.com/job")
public class TestInterfaceService extends Service {
public final static URL WSDL_LOCATION;
public final static QName SERVICE = new QName("http://www.google.com/job", "TestInterfaceService");
public final static QName TestInterfaceSoapHttpPort = new QName("http://www.google.com/job", "TestInterfaceSoapHttpPort");
static {
URL url = null;
try {
url = new URL("WEB-INF/wsdl/some.wsdl");
} catch (MalformedURLException e) {
java.util.logging.Logger.getLogger(TestInterfaceService.class.getName())
.log(java.util.logging.Level.INFO,
"Can not initialize the default wsdl from {0}", "WEB-INF/wsdl/some.wsdl");
}
WSDL_LOCATION = url;
}
Can you please suggest how to pick WSDL files independently from that of my local system, currently it throws the error Can not initialize the default wsdl from WEB-INF/wsdl/some.wsdl

You need a valid URL string to be able to create a new URL. If your service does expose the URL, it might be an option to use that.
If your client is a web application, another option is to make the wsdl available via your application and reference it from there using http://localhost/app/some.wsdl
Hope that helps

Not sure what you are trying to achive here, the configuration: wsdlLocation = "WEB-INF/wsdl/some.wsdl" is perfectly fine as long as WSLD file is under WEB-INF/wsdl, if you placed the wsdl in WEB-INF/src/com/test/wsdl and specifying WSDL location like this: wsdlLocation = "WEB-INF/wsdl/some.wsdl - of course it won't work, add your WSDL in WEB-INF/wsdl and all will be fine.

How to change wsdl location file inside service

I have a preliminary MyService generated with the wsimport gradle task with provided wsdl location path file:/D:/someLocationWherePlacedMyWSDl.interface.v2.wsdl
public class MyService
extends Service
{
private final static URL MyService_WSDL_LOCATION;
private final static Logger logger = Logger.getLogger(com.google.services.MyService.class.getName());
static {
URL url = null;
try {
URL baseUrl;
baseUrl = com.google.services.MyService.class.getResource(".");
url = new URL(baseUrl, "file:/D:/someLocationWherePlacedMyWSDl.interface.v2.wsdl");
} catch (MalformedURLException e) {
logger.warning("Failed to create URL for the wsdl Location: 'file:/D:/someLocationWherePlacedMyWSDl.interface.v2.wsdl', retrying as a local file");
logger.warning(e.getMessage());
}
MyService_WSDL_LOCATION = url;
}
}
How can I change it? It happens because the file was generated in one environment and then the artifact (war) was moved to another server.
Any thoughts?
Yes, I get it. Locally everything works perfectly. But this file located inside war file and when Jenkins trying to get this file /var/distributives/myservice/tomcat-base/wsdl/someLocationWherePlacedMyWSDl.interface.v2.wsdl I get exception (No such file or directory). It looks like it could not see files inside war file. Any thoughts how can I handle this?

Use the constructor of your service class, MyService, to pass the wsdlLocation.
String WSDL_LOCATION = "http://server:port/localtionWSDL.interface.v2.wsdl";
try {
final URL url = new URL(WSDL_LOCATION);
final QName serviceName = new QName("http://mynamespace/", "MyService");
final MyService service = new MyService(url, serviceName);
port = service.getMyServicePort();
// Call some operation of WebService
} catch (final Exception e) {
// Handle the exception
}

I solved this problem with relative path. Here is the solution
#Value("classpath:com//google//resources//wsdl//myservice.interface.v2.wsdl")
public void setWsdlLocation(final Resource wsdlLocation)
{
m_wsdlLocation = wsdlLocation;
}

How to call a web service (described by a wsdl) from java

Knowing nothing of web services, I'm just trying to call some "isAlive" service that is described by a wsdl.
This seems to me like something that should take no more than 2-5 lines of code but I can't seem to find anything but huge long examples involving 3rd party packages etc.
Anyone has any ideas? If it is always suppose to be long maybe a good explanation as to why it has to be so complicated will also be appreciated.
I'm using Eclipse and the wsdl is SOAP.

JDK 6 comes with jax-ws, everything you need to develop a client for a web service.
I'm unable to find some simple enough examples to post , but start at https://jax-ws.dev.java.net/
Edit: here's a simple example - a client for this web service: http://xmethods.com/ve2/ViewListing.po?key=427565
C:\temp> md generated
C:\temp>"c:\Program Files\Java\jdk1.6.0_17"\bin\wsimport -keep -d generated http://www50.brinkster.com/vbfacileinpt/np.asmx?wsdl
Create PrimeClient.java which look like:
import javax.xml.ws.WebServiceRef;
import com.microsoft.webservices.*;
//the above namespace is from the generated code from the wsdl.
public class PrimeClient {
//Cant get this to work.. #WebServiceRef(wsdlLocation="http://www50.brinkster.com/vbfacileinpt/np.asmx?wsdl")
static PrimeNumbers service;
public static void main(String[] args) {
try {
service = new PrimeNumbers();
PrimeClient client = new PrimeClient();
client.doTest(args);
} catch(Exception e) {
e.printStackTrace();
}
}
public void doTest(String[] args) {
try {
System.out.println("Retrieving the port from the following service: " + service);
PrimeNumbersSoap pm = service.getPrimeNumbersSoap();
System.out.println("Invoking the getPrimeNumbersSoap operation ");
System.out.println(pm.getPrimeNumbers(100));
} catch(Exception e) {
e.printStackTrace();
}
}
}
Compile and run:
C:\temp>"c:\Program Files\Java\jdk1.6.0_17"\bin\javac -cp generated PrimeClient.java
C:\temp>"c:\Program Files\Java\jdk1.6.0_17"\bin\java -cp .;generated PrimeClient
Retrieving the port from the following service: com.microsoft.webservices.PrimeN
umbers#19b5393
Invoking the getPrimeNumbersSoap operation
1,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97

There are plugins for IDE's which generate the needed code to consume a web service for you.
After the plugin generates you the base methods you simply call a web service like that:
TransportServiceSoap service = new TransportServiceLocator().getTransportServiceSoap();
service.getCities();
Have a look at http://urbas.tk/index.php/2009/02/20/eclipse-plug-in-as-a-web-service-client/

There are three ways to write a web service client
Dynamic proxy
Dynamic invocation interface (DII)
Application client
Example for Dynamic Proxy Client
import java.net.URL;
import javax.xml.rpc.Service;
import javax.xml.rpc.JAXRPCException;
import javax.xml.namespace.QName;
import javax.xml.rpc.ServiceFactory;
import dynamicproxy.HelloIF;
public class HelloClient {
public static void main(String[] args) {
try {
String UrlString = "Your WSDL URL"; //
String nameSpaceUri = "urn:Foo";
String serviceName = "MyHelloService";
String portName = "HelloIFPort";
System.out.println("UrlString = " + UrlString);
URL helloWsdlUrl = new URL(UrlString);
ServiceFactory serviceFactory =
ServiceFactory.newInstance();
Service helloService =
serviceFactory.createService(helloWsdlUrl,
new QName(nameSpaceUri, serviceName));
dynamicproxy.HelloIF myProxy =
(dynamicproxy.HelloIF)
helloService.getPort(
new QName(nameSpaceUri, portName),
dynamicproxy.HelloIF.class);
System.out.println(myProxy.sayHello("Buzz"));
} catch (Exception ex) {
ex.printStackTrace();
}
}
}
I hope , this would solve your question.

The easiest I've found so far to use is the Idea IntelliJ wizard which - using Metro libraries - generate a very small code snippet which works fine with Java 6.