let's say I have a file located in:
http://example.com/123.app
now I get the file name using the following (u is an entire url string):
String fileName = u.substring( u.lastIndexOf('/')+1, u.length() );
but I want to put on the same file name also parameters, so it'll look like, this:
http://example.com/123.app?id=87983
And I want to have a String fileName which will contain '123.app', and also String id which will contain '87983' and possibly more parameters.
How would I go about achieving this?
Firstly, take a look at this post, which uses the URL class to make working with the different parts of the URL string a lot easier.
Could you share a link to an URL parsing implementation?
Secondly, you would need to take the Query part of the URL and the Path part of the URL and substring the returned values to get the information that you desire. It should be pretty straight forward.
Use the API of URI! That's what it's for. Forget all this substring/regex/spit stuff.
you need to use the split method on string. So for example on your fileName string
String[] mystrings = fileName.split("?");
then mystrings[0] is your filename and mystrings[1] is your parameter
A simple way is : just repeat substring :
int qidx = filename.indexOf("?");
String realFilename = filename.substring(0, qidx);
String parameters = filename.substring(qidx+1);
and so on for parsing parameters.
If you are writing a servlet try :
String fileName = request.getServletPath();
and for the parameters somthing like
String id = request.getParameter("id");
Try this regex:
String s = "http://example.com/123.app?id=87983";
String[] split = s.split(".*/|\\?id=");
String filename = split[1];
String id = (split.length == 3) ? split[2] : null;
Related
I have string such as
String url = "www.test.com/blabla/?p1=v1?p2=v2?p3=v3"
I would like to replace the "substrings" "v1","v2" and "v3" with other values. How can I achieve this?
Does something like this work for your case?
String url = "www.test.com/blabla/?p1=v1?p2=v2?p3=v3";
String result = String.format(url.replaceAll("v[0-9]", "%s"), "arg1", "arg2", "arg3");
System.out.println(result); //www.test.com/blabla/?p1=arg1?p2=arg2?p3=arg3
Edit:
Just a brief explanation of what this does, it replaces all the v1,v2,v3,v4,v5,v6,v7,v8,v9,v0 in the original url for %s and then uses this in the format method so you can attribute what you want it to be.
I tried searching for something similar, and couldn't find anything. I'm having difficulty trying to replace a few characters after a specific part in a URL.
Here is the URL: https://scontent-b.xx.fbcdn.net/hphotos-xpf1/v/t1.0-9/s130x130/10390064_10152552351881633_355852593677844144_n.jpg?oh=479fa99a88adea07f6660e1c23724e42&oe=5519DE4B
I want to remove the /v/ part, leave the t1.0-9, and also remove the /s130x130/.I cannot just replace s130x130, because those may be different variables. How do I go about doing that?
I have a previous URL where I am using this code:
if (pictureUri.indexOf("&url=") != -1)
{
String replacement = "";
String url = pictureUri.replaceAll("&", "/");
String result = url.replaceAll("().*?(/url=)",
"$1" + replacement + "$2");
String pictureUrl = null;
if (result.startsWith("/url="))
{
pictureUrl = result.replace("/url=", "");
}
}
Can I do something similar with the above URL?
With the regex
/v/|/s\d+x\d+/
replaced with
/
It turns the string from
https://scontent-b.xx.fbcdn.net/hphotos-xpf1/v/t1.0-9/s130x130/10390064_10152552351881633_355852593677844144_n.jpg?oh=479fa99a88adea07f6660e1c23724e42&oe=5519DE4B
to
https://scontent-b.xx.fbcdn.net/hphotos-xpf1/t1.0-9/10390064_10152552351881633_355852593677844144_n.jpg?oh=479fa99a88adea07f6660e1c23724e42&oe=5519DE4B
as seen here. Is this what you're trying to do?
I have a bunch of strings like this:
Some text, bla-bla http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter
And I need to parse this String to two:
Some text, bla-bla
http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter
I need separate them, but, of course, it's enough to parse only URL.
Can you help me, how can I parse url from string like this.
By using split :
String str = "Some text, bla-bla http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter";
String [] ar = str.split("http\\.*");
System.out.println(ar[0]);
System.out.println("http"+ar[1]);
This depends on how robust you want your parser to be. If you can reasonably expect every url to start with http://, then you can use
string.indexOf("http://");
This returns the index of the first character of the string you pass in (and -1 if the string does not appear).
Full code to return a substring with just the URL:
string.substring(string.indexOf("http://"));
Here's the documentation for Java's String class. Let this become your friend in programming! http://docs.oracle.com/javase/7/docs/api/java/lang/String.html
Try something like this:
String string = "sometext http://www.something.com";
String url = string.substring(string.indexOf("http"), string.length());
System.out.println(url);
or use split.
I know in PHP you'd be able to run the explode() (http://www.php.net/manual/en/function.explode.php) function. You'd choose which character you want to explode at. For instance, you could explode at "http://"
So running the code via PHP would look like:
$string = "Some text, bla-bla http://www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter";
$pieces = explode("http://", $string);
echo $pieces[0]; // Would print "Some text, bla-bla"
echo $pieces[1]; // Would print "www.easypolls.net/poll.html?p=51e5a300e4b084575d8568bb#.UeWjBcCzaaA.twitter"
I have a string containing a short-code which looks like the one below:
some text...
[video url="http://www.example.com/path/to/my/video.ext"]
...some more text...
I want to be able to first check if the string contains that short-code and second extract the URL from it in Java (specifically Android).
use this regex for checking and grabbing url:
\[\w+\s+url="(?<urllink>)[^"]*"\s*]
and get gorup named urllink
try as:
String str = "[video url=\"http://www.example.com/path/to/my/video.ext\"]";
if (str.contains("url=\""))
{
int indexoff = str.indexOf("url=\"");
int indexofff = str.indexOf("\"]");
String strurl = str.substring(indexoff, indexofff - indexoff);
strurl = strurl.Replace("url=\"", ""); //get url string here
}
Android provides several function for this purpose. SOme of this are:
http://hc.apache.org/httpcomponents-client-ga/httpclient/apidocs/org/apache/http/client/utils/URLEncodedUtils.html
http://developer.android.com/reference/org/apache/http/client/utils/URLEncodedUtils.html
String url = "whatever"
Boolean myBool = url.contains("ate");
String contains. Not sure what extract url means, but the string class has lots of useful functions.
A powerful and maintainable manner it to Java URL.class, then, you can mix with Regex
I have a string like myweb.com/blabla/blabla/image.jpg How could I get substring that starts at the end and ends when first "/" char? Expected string will be image.jpg.
Use Below Code for that.
String s="myweb.com/blabla/blabla/image.jpg";
int i=s.lastIndexOf("/");
s=s.substring(i+1);
String string = "myweb.com/blabla/blabla/image.jpg";
string.subString(string.lastIndexOf("/"));
Being String.substring clearly the solution for generic case, there is another way of doing your particular task in android:
String url = "myweb.com/blabla/blabla/image.jpg";
Uri uri = Uri.parse(url);
uri.getLastPathSegment();
getLastPathSegment in you case will return image.jpg. Apart from that you can easilly extract other information using uri object.
String name = fullpath.subString(fullpath.lastIndexOf("/")+1);
fullPath being the myweb.com/blabla/blabla/image.jpg
Use lastIndexOf method of String class..
String string = "myweb.com/blabla/blabla/image.jpg ";
String imageName = string.subString(string.lastIndexOf("/")+1);
Take a look at the File class. Has everything you need to get paths, filenames, extensions etc.
http://developer.android.com/reference/java/io/File.html
getName() will help.
http://developer.android.com/reference/java/io/File.html#getName()