I am working with a java generated dynamic webpage, and I'm printing links from a query to a JDO. But I don't understand how can I get and use the parameter from the url.
My html objects are printed like this
print = print + "Nome:<a href='displayFotos?album="+results.get(i).nome+ "'>"+
results.get(i).nome+ "</a></br>";
The results in having for example:
Nome:<a href='displayFotos?album=album1'>album1</a>
So, in my head when clicked it should be calling the address of the dynamic webpage album like this and should get the parameter. In this case it would be the album1.
else if (address.indexOf("/dinamicas/album") != -1) {
String album = param1;
System.out.println("did it work? "+album);
}
And I have in the beginning of the class a general parameter that I use to get text from html forms.
String param1 = req.getParameter("param1");
I understand this might be an easy question but I'm not getting there by myself.
Nome:<a href='displayFotos?album=album1'>album1</a>
Here, you're using a parameter name of album.
However, you're attempting to get it by a parameter name of param1. This does obviously not match.
String param1 = req.getParameter("param1");
You need to use the same parameter name as is been definied in the request.
String album = req.getParameter("album");
// ...
Related
I have a URL and I want to print in my graphical user interface the ID value after the hashtag.
For example, we have www.site.com/index.php#hello and I want to print hello value on a label in my GUI.
How can I do this using Java in Netbeans?
Simple solution is getRef() in URL class:
URL url = new URL("http://www.anyhost.com/index.php#hello");
jLabel.setText(url.getRef());
EDIT: According to #Henry comment:
I would recommend to use the java.net.URI as it also deals with encoding. The Javadocs say: "Note, the URI class does perform escaping of its component fields in certain circumstances. The recommended way to manage the encoding and decoding of URLs is to use URI, and to convert between these two classes using toURI() and URI.toURL()."
and this comment:
Why not just doing uri.getFragment()
URI uri = new URI("http://www.anyhost.com/index.php#hello");
jLabel.setText(uri.getFragment());
Use the String.split() Method.
public static String getId(string url) {
return url.split("#")[1];
}
String.split() returns an array of Strings that are delimited, or "Split," by the value you pass to it, or in this case #.
Because you want only the string after the #, you can just use the second item in the array that it returns by adding [1] to the end of it.
For more on String.split() go to Tutorials Point.
By the way, the part of the URL you are referencing is the Element ID. It is used to jump to an Element on a webpage.
I want to know if there is a way to get the CQL string that was used to create a Filter object can be recovered or reconstructed, such that it could be used to create the same filter again.
i.e.
Filter filter = ECQL.toFilter("name = 'bob'");
String ecqlString = /* Some code that gets the "name = 'bob'" string back with quotations preserved*/
Filter filter2 = ECQL.toFilter(ecqlString);
The toString() method removes all quoations and I cant find a way to identify weather expressions were originally Strings or numbers useing a visitor. Is there a way to do this?
You are looking for the function ECQL.toCQL(Filter).
Note that there can be a few string representations of a GeoTools Filter object.
I'm trying to send an email using a javascript code in a Java project. Database connection works fine, I already tested it. I got the error:
javax.script.ScriptException: sun.org.mozilla.javascript.internal.EvaluatorException: missing ) after formal parameters (#1) in at line number 1
The only information of relevance is not readily reported: the final JavaScript string executed. Make sure to look at relevant data when debugging. After inspecting the final string it will be apparent why it is incorrect and trivial to "fix".
Hint: it will look something like function sendMail(userblah, foo#bar.qux) { .., which is indeed invalid JavaScript.
The problem and solution should be self-evident from that - use fixed parameters (variable names) in the function declaration and supply arguments (values) via the invokeFunction call.
Solution:
// The following parameter names are JAVASCRIPT variable names.
String script = "function sendMail(username, email, body) { ..";
// And pass correct arguments (values), in order. The variables used
// here are JAVA variables, and align by-position with the JS parameters.
inv.invokeFunction("sendMail", username, email, "EMAIL SENT!!!!");
In addition, the getElementById (invalid ID) is wrong, the body parameter is never used, and encodeURIComponent should be used (instead of escape).
Not sure if this is a typo or not:
result = request.executeQuery("SELECT user.login, user.email "
+ "FROM user " + );
It looks like you are missing the end of your statement.
Hmmmm, your function definition:
function sendMail("username","email") {...}
doesn't look like valid JavaScript to me, apart of that, you never call the function.
Pseudocode, how to do it:
function sendMail(username, email) {
var link = "jadajada" + email; // .... etc
}
sendMail("+username+","+email+");
I need to pass a parameter to my page and I can't find a way to pass parameters that might be null.
If I do:
PageParameters pageParameters = new PageParameters ();
pageParameters.add ("key", null);
This will result in an exception
java.lang.IllegalArgumentException: Argument 'value' may not be null.
at org.apache.wicket.util.lang.Args.notNull(Args.java:41)
If I use Google Guava's Optional, I can't find any way to cast the object even if the the Optional object is not holding a null ie not equals to Optional.absent() :
In my landing page's constructor I do
StringValue sv = parameters.get ("key");
sv.to ( Optional.of (MyEnum.SOME_ENUM_CONSTANT).getClass () );
and when I run it I get this error:
org.apache.wicket.util.string.StringValueConversionException: Cannot
convert 'Optional.of(SOME_ENUM_CONSTANT)'to type class
com.google.common.base.Present.
Am I doing something wrong?
Is there any other way to pass a possibly null object in wicket 6?
I noticed in wicket 1.4 they have PageParameters.NULL which seems to have dissapeared in wicket 6.
Thank you
This might be too simple, but what's wrong with
Object value = ?
if (value != null) {
pageParameters.add ("key", value);
}
and
StringValue sv = pageParameters.get("key");
if (!sv.isNull()) {
// process string value
}
All page parameters in wicket will be treated as Strings eventually. The idea is that a page parameter will be on the URL of the request.
From the javadoc:
Suppose we mounted a page on /user and the following url was accessed /user/profile/bob?action=view&redirect=false. In this example profile and bob are indexed parameters with respective indexes 0 and 1. action and redirect are named parameters.
If you add something like x=y&x, the parameter x will appear twice, once with the String y and another with the empty string.
Depending on what you are trying to accomplish I would suggest to either
Don't pass the parameter at all when there is a null value required and use the isNull or toOptional methods.
Use indexed parameters and test for presence of a certain word
I have a JSON String stored in a database. In one of my JSP pages, I retrieve this string, and I want to be able to pass the String or the JSON object into Javascript function. The function is simply this for test purposes
function test(h){
alert(h);
}
Now I can retrieve the JSON string from the database fine, I have printed it out to the screen to ensure that it is getting it, however when I pass it in like this
<input type="button"
name="setFontButton"
value="Set"
class="form_btn_primary"
onclick="test('<%=theJSON%>'); return false;"/>
Nothing happens. I used firebug to check what was wrong, and it says there is invalid character.
So I then tried passing in the JSON object like so
Widget widg = mapper.readValue(testing.get(0), Widget.class);
Then pass in it
onclick="test('<%=widg%>'); return false;"/>
Now this will pass in without an error, and it alerts the object name, however I am unable to parse it. Object comes in like with the package name of where the widget class is stored like so
com.package.mode.Widget#ba8af9
I tried using Stringify, but that doesn't seem to work on this Jackson JSON object.
After all that failed, I tried a last resort of taking the String from the database, and encoding it in base64. However, this too fails if I do this
String test = Base64.encode(theString);
and pass that in. However if I do that, print it out to the screen, then copy what is printed out, and send that through it works, so don't quite understand why that is.
So could someone please tell me what I am doing wrong. I have tried soo many different solutions and nothing is working.
The JSON String is stored in database like this
{
"id":1,
"splits":[
{
"texts":[
{
"value":"Test",
"locationX":3,
"locationY":-153,
"font":{
"type":"Normal",
"size":"Medium",
"bold":false,
"colour":"5a5a5a",
"italics":false
}
}
]
}
]
}
Would be very grateful if someone could point me in the direct direction!!
Edit:
Incase anyone else has same problem do this to pass the JSON from JSP to the JS function
<%=theJSON.replaceAll("\"", "\\\'")%>
That allows you to pass the JSON in,
then to get it back in JavaScript to normal JSON format
theJSON = theJSON.replace(/'/g,'"');
Should work fine
I think the combination of double quotes wrapping the onclick and the ones in your JSON may be messing you up. Think of it as if you entered the JSON manually -- it would look like this:
onclick="test('{ "id":1, "splits":[ { "texts":[ { "value":"Test", "locationX":3, "locationY":-153, "font":{ "type":"Normal", "size":"Medium", "bold":false, "colour":"5a5a5a", "italics":false } } ] } ] }'); return false;"
and the opening double quote before id would actually be closing the double quote following onclick= (You should be able to verify this by looking at the page source). Try specifying the onclick as:
onclick='test(\'<%=theJSON%>\'); return false;'
You can follow the following steps
Fetch the jon string
Using the jackson or any other JSON jar file , convert the json string to json array and print the string using out.println.
Call this jsp which prints the json string
check in the firebug , you will be able to see your json .
If the Json string does not print , there can be some problems in your json format.
this is a good website for json beautification , http://jsbeautifier.org/ , really makes the string simple to read .
Thanks
Abhi