Develop Reference

How to replace a given substring with "" from a given string?

I went through a couple of examples to replace a given sub-string from a given string with "" but could not achieve the result. The String is too long to post and it contains a sub-string which is as follows:-
/image/journal/article?img_id=24810&t=1475128689597
I want to replace this sub-string with "".Here the value of img_id and t can vary, so I would have to use regular expression. I tried with the following code:-
String regex="^/image/journal/article?img_id=([0-9])*&t=([0-9])*$";
content=content.replace(regex,"");
Here content is the original given string. But this code is actually not replacing anything from the content. So please help..any help would be appreciated .thanx in advance.

Use replaceAll works in nice way with regex
content=content.replaceAll("[0-9]*","");
Code
String content="/image/journal/article?img_id=24810&t=1475128689597";
content=content.replaceAll("[0-9]*","");
System.out.println(content);
Output :
/image/journal/article?img_id=&t=
Update : simple, might be little less cozy but easy one
String content="sas/image/journal/article?img_id=24810&t=1475128689597";
content=content.replaceAll("\\/image.*","");
System.out.println(content);
Output:
sas
If there is something more after t=1475128689597/?tag=343sdds and you want to retain ?tag=343sdds then use below
String content="sas/image/journal/article?img_id=24810&t=1475128689597/?tag=343sdds";
content=content.replaceAll("(\\/image.*[0-9]+[\\/])","");
System.out.println(content);
}
Output:
sas?tag=343sdds

If you're trying to replace the substring of the URL with two quotations like so:
/image/journal/article?img_id=""&t=""
Then you need to add escaped quotes \"\" inside your content assignment, edit your regex to only look for the numbers, and change it to replaceAll:
content=content.replaceAll(regex,"\"\"");

You can use Java regex Utility to replace your String with "" or (any desired String literal), based on given pattern (regex) as following:
String content = "ALPHA_/image/journal/article?img_id=24810&t=1475128689597_BRAVO";
String regex = "\\/image\\/journal\\/article\\?img_id=\\d+&t=\\d+";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(content);
if (matcher.find()) {
String replacement = matcher.replaceAll("PK");
System.out.println(replacement); // Will print ALPHA_PK_BRAVO
}

Extracting String's from a String JAVA

Hello I want to extract "Hello, World!" "and" and the Paragraph "This is a minimal....." from the given string in JAVA. I am having problems in extracting, so can anyone help me with it?
So I always get different Strings and want to extract the string between 2 square brackets []......[].
String s1="[sh1] Hello, World! [/s11] and [pp]This is a minimal "hello world" HTML document. It demonstrates the basic structure of an HTML file and anchors. [/xy]"
Thanks

Use the Pattern & Matcher to match square brackets:
Pattern pattern = Pattern.compile("\\[[^\\]]*\\]([^\\]]*)\\[[^\\]]*\\]");
Matcher matcher = pattern.matcher(s1);
while (matcher.find()) {
System.out.println( "Found value: " + matcher.group(1).trim() );
}
Demo: https://ideone.com/kNKBgg

Please don't use RegEx-es to do this (it's what Pattern and Matcher do) - see here for reason why you shouldn't. While you could use this for the particular bracket example, if you expect full-blown HTML don't do it.
If you want to extract content from HTML use a parser, for example SAXParser or DOMParser - see Oracle documentation for examples.

How to get (split) filenames from string in java?

I have a string that contains file names like:
"file1.txt file2.jpg tricky file name.txt other tricky filenames containing áéíőéáóó.gif"
How can I get the file names, one by one?
I am looking for the most safe most through method, preferably something java standard. There has got to be some regular expression already out there, I am counting on your experience.
Edit: expected results:
"file1.txt", "file2.jpg", "tricky file name.txt", "other tricky filenames containing áéíőéáóó.gif"
Thanks for the help,
Sziro

Regular expresion that enrico.bacis suggested (\S.?.\S+)* will not work if there are filenames without characters before "." like .project.
Correct pattern would be:
(([^ .]+ +)*\S*\.\S+)
You can try it here.
Java program that could extract filenames will look like:
String patternStr = "([^ .]+ +)*\\S*\\.\\S+";
String input = "file1.txt .project file2.jpg tricky file name.txt other tricky filenames containing áéíoéáóó.gif";
Pattern pattern = Pattern.compile(patternStr, Pattern.MULTILINE);
Matcher matcher = pattern.matcher(input);
while (matcher.find()) {
System.out.println(matcher.group());
}

If you want to use regular expressions you can find all the occurrences of:
(\S.*?\.\S+)
(you can test it here)

If there are spaces in the file names, it makes it trickier.
If you can assume there are no dots (.) in the file names, you can use the dot to find each individual records as has been suggested.
If you can't assume there are no dots in file names, e.g. my file.new something.txt
In this situation, I'd suggest you create a list of acceptable extentions, e.g. .doc, .jpg, .pdf etc.
I know the list may be long, so it's not ideal. Once you have done this you can look for these extensions and assume what's before it is a valid filename.

String txt = "file1.txt file2.jpg tricky file name.txt other tricky filenames containing áéíőéáóó.gif";
Pattern pattern = Pattern.compile("\\S.*?\\.\\S+"); // Get regex from enrico.bacis
Matcher matcher = pattern.matcher(txt);
while (matcher.find()) {
System.out.println(matcher.group().trim());
}

conditional replaceAll java

I have html code with img src tags pointing to urls. Some have mysite.com/myimage.png as src others have mysite.com/1234/12/12/myimage.png. I want to replace these urls with a cache file path. Im looking for something like this.
String website = "mysite.com"
String text = webContent.replaceAll(website+ "\\d{4}\\/\\d{2}\\/\\d{2}", String.valueOf(cacheDir));
This code however does not work when the url does not have the extra date stamp at the end. Does anyone know how i might achieve this? Thanks!

Try this one
mysite\.com/(\d{4}/\d{2}/\d{2}/)?
here ? means zero or more occurance
Note: use escape character \. for dot match because .(dot) is already used in regex
Sample code :
String[] webContents = new String[] { "mysite.com/myimage.png",
"mysite.com/1234/12/12/myimage.png" };
for (String webContent : webContents) {
String text = webContent.replaceAll("mysite\\.com/(\\d{4}/\\d{2}/\\d{2}/)?",
String.valueOf("mysite.com/abc/"));
System.out.println(text);
}
output:
mysite.com/abc/myimage.png
mysite.com/abc/myimage.png

You are missing a forward slash between the website.com and the first 4 digits.
String text = webContent.replaceAll(Pattern.quote(website) + "/\\d{4}\\/\\d{2}\\/\\d{2}", String.valueOf(cacheDir));
I'd also recommend using a literal for your website.com value (the Pattern.quote part).
Finally you are also missing the last forward slash after the last two digits so it won't be replaced, but that may be on purpose...

Try:
String text = webContent.replaceAll("(?<="+website+")(.*)(?=\\/)",
String.valueOf(cacheDir));

Java Regex: Extracting a Version Number

I have a program that stores the version number in a text file on the file system. I import the file within java and I am wanting to extract the version number. I'm not very good with regex so I am hoping someone can help.
The text file looks like such:
0=2.2.5 BUILD (tons of other junk here)
I am wanting to extract 2.2.5. Nothing else. Can someone help me with the regex for this?

If you know the structure, you don't need a regex:
String line = "0=2.2.5 BUILD (tons of other junk here)";
String versionNumber = line.split(" ", 2)[0].substring(2);

This regular expression should do the trick:
(?<==)\d+\.\d+\.\d+(?=\s*BUILD)
Trying it out:
String s = "0=2.2.5 BUILD (tons of other junk here)";
Pattern p = Pattern.compile("(?<==)\\d+\\.\\d+\\.\\d+(?=\\s*BUILD)");
Matcher m = p.matcher(s);
while (m.find())
System.out.println(m.group());
2.2.5

Also if you are really looking for a regex, though there are definitely many ways to do this.
String line = "0=2.2.5 BUILD (tons of other junk here)";
Matcher matcher = Pattern.compile("^\\d+=((\\d|\\.)+)").matcher(line);
if (matcher.find())
System.out.println(matcher.group(1));
Output:
2.2.5

There are many ways to do this. Here is one of them
String data = "0=2.2.5 BUILD (tons of other junk here)";
Matcher m = Pattern.compile("\\d+=(\\d+([.]\\d+)+) BUILD").matcher(data);
if (m.find())
System.out.println(m.group(1));
If you are sure that data contains version number then you can also
System.out.println(data.substring(data.indexOf('=')+1,data.indexOf(' ')));