About java Runtime self-written public API compatibility - java

I just encounter a real problem about changed API. And i want to know more about this topic.
Using the following example as a demo.
There are 4 simple classes, Child class extends Parent. PubAPI is the class which provides public method for cient use. Client class invokes PubAPI's public methods.
public class Parent
{
}
public class Child extends Parent
{
}
public class PubAPI
{
public Parent getChild(){
return new Child();
}
}
public class Client
{
public static void main(String[] args)
{
System.out.println(new PubAPI().getChild());
}
}
The first 3 class is provided by an API maker, let's say the above version is version 1.
in Version 2, the PubAPI class is changed to return child type :
public class PubAPI
{
public Child getChild(){
return new Child();
}
}
the 3 API provider class is in versoin 2 now, while if we don't recompile the "Client" class and use its version 1 generated class file. IT will fail in java runtime with error can not find the version 1 method (because the return type changes).
I don't know this before, and i want to know if anyone know more about this topic , for example, if the public API add a throw, or addd a synchronize or the class become final, etc. In these situation, how will it hehave.
IN all, what is the public API/class bytecode level compabability rule for API classes used by others.
thanks.

EDIT: You asked almost the exact same question two weeks back and accepted an answer. I am wondering what prompted you to ask again, you didn't think the rules would have changed in two weeks, did you?
You are on the right track with the keyword bytecode level compatibility. It is called binary compatibility which you can look up on the net. For example, here
The rules are not always easy to understand at first but usually make sense when you get an error and think about them. Best thing is to try the individual cases you have listed and when you get an error confirm in JLS that is an incompatibility and then try and rationalize for yourself why it is so.
This question on so seems to discuss the exact same issue. The document at eclipse it sites is an easier read than JLS.

Related

Java Application return super class when initialized

Nowadays we are on writing some core application that is all other application will be relying on. Without further due let me explain the logic with some codes,
We used to have a single java file that was 1000+ lines long and each application was having it as class inside, so when there was a change, each application had to edit the java file inside of it or simply fix one and copy to all. This is hard to implement as much as it is hard to maintain. Then we end-up with creating this as a separate application that is divided to smaller part, which is easy to maintain and also a core maybe a dependency to other application so we fix in one place and all other code applications are fixed too.
I've been thinking for a some great structure for this for a while want to use a builder patter for this as below
TheCore theCore = new TheCore().Builder()
.setSomething("params")
.setSomethingElse(true)
.build();
The problem arises now. Like so, I initialized the object but now I'm having access to that objects public class only. This application actually will have many small classes that has public functions that I don't want them to be static methods that can be called everytime. Instead I want those methods to be called only if TheCore class is initilized like;
// doSomething() will be from another class
theCore.doSomething()
There are some ideas I produced like
someOtherClass.doSomething(theCore)
which is injecting the main object as a parameter but still someOtherClass needs to be initialized or even a static method which doesn't make me feel comfortable and right way to that.
Actually I do not care if initializing TheCore would bring me a super object that includes all other classes inside initialized and ready to be accessed after I initialized TheCore. All I want in this structure to have a maintainable separate app and methods avaiable if only the main object which is TheCore is this circumstances is initialized.
What is to right way to achive it? I see that Java does not allow extending multiple classes even it if does, I'm not sure it that is right way...
Thanks.
After spending significant amount of time of thought I ended up that
// doSomething() will be from another class
theCore.doSomething()
is not suitable since many java classes could possibly have identical method names. So...
// doSomething() will be from another class
theCore.someOtherClass.doSomething()
would be a better approach.
To make it easier to understand I'll have to follow a complex path to explain it which is starting from the package classes first.
Think that I have a package named Tools and a class inside SomeFancyTool
main
└─java
└─com
└─<domainName>
├─Tools
| └─SomeFancyTool.java
└─TheCore.java
Now this SomeFancyTool.java must have a default access level which is actually package level access, because I don't want this classes to be accessed directly;
SomeFancyTool.java
package com.<domainName>.Tools
class SomeFancyTool{
public String someStringMethod(){
return "Some string!";
}
public int someIntMethod(){
return 123;
}
public boolean someBooleanMethod(){
return true;
}
}
So now we have the SomeFancyTool.java class but TheCore.java cannot access it since it is accesible through its Tools package only. At this point I think of an Initializer class that is gonna be in the same package, initialize these private classes and return them with a function when called. So initiliazer class would look like this;
ToolsInitializer.java
package com.<domainName>.Tools
public class ToolsInitializer{
private SomeFancyTool someFancyTool = new SomeFancyTool();
public SomeFancyTool getSomeFancyTool(){
return someFancyTool;
}
}
Since ToolsInitializer.java can initialize all functional private classes inside in Tools package and also can return them as objects to outside of the package scope, still we are not able to use these methods as we cannot import com.<domainName>.SomeFancyTool from TheCore.java because it is package wide accessible. I think here we can benefit from implementation of the java interface. A class that is not functional alone, so no problem even if it is accessed since it's methods will be nothing but declarations.
At this point I'll rename SomeFancyTool.java to SomeFancyToolImplementation.java which it will be implementing the interface and call SomeFancyTool.java to the interface itself.
SomeFancyTool.java (now as an interface)
package com.<domainName>.Tools
public interface SomeFancyTool{
public String someStringMethod();
public int someIntMethod();
public boolean someBooleanMethod();
}
and lets rename prior SomeFancyTool.java and implement the interface
SomeFancyToolImplementation.java (renamed)
package com.<domainName>.Tools
class SomeFancyToolImplementation implements SomeFancyTool{
#override
public String someStringMethod(){
return "Some string!";
}
#override
public int someIntMethod(){
return 123;
}
#override
public boolean someBooleanMethod(){
return true;
}
}
Now our structure has become like this with the final edits;
main
└─java
└─com
└─<domainName>
├─Tools
| ├─SomeFancyTool.java
| ├─SomeFancyToolImplementation.java
| └─ToolsInitializer.java
└─TheCore.java
Finally we can use our TheCore.java class to call all initializer classes with their methods to receive all these private classes inside as an object. This will allow external apps to call and initialize TheCore first to be able to access other methods.
TheCore.java
public class TheCore{
private SomeFancyToolImplementation someFancyTool;
public static class Builder{
private SomeFancyToolImplementation someFancyTool;
public Builder(){
ToolsInitializer toolsInitializer = new ToolsInitializer();
someFancyTool = toolsInitializer.getSomeFancyTool();
}
public Builder setSomeValues(){
//some values that is needed.
return this;
}
public Builder setSomeMoreValues(){
//some values that is needed.
return this;
}
public TheCore build(){
TheCore theCore = new TheCore();
theCore.someFancyTool = someFancyTool;
return theCore;
}
}
}
All Done and it is ready to use. Now the functional package classes and its methods that it relying on if TheCore is initialized or not, cannot be accessed with out TheCore. And simple usage of this Library from a 3rd Party app would simply be;
3rd Party App
TheCore theCore = new TheCore.Builder()
.setSomeValues("Some Values")
.setMoreSomeValues("Some More Values")
.build();
theCore.someFancyTool.someStringMethod();
Note: Note that a the ToolsInitializer.java is still accessible and could be used the get private method without first calling TheCore but we can always set a checker inside getSomeFancyTool() method to throw error if some prerequisites are not satisfied.
I do not still know if this is a functional structural pattern to use or its just some hard thoughts of mine. And don't know if some pattern is already exist that I just could not see yet but this is the solution I end up with.

Entity to DTO conversion in a J2EE application using an enum?

This is one of those topics I don't even know how to search in google (tried already, most of the results were for C#), so here I go:
I'm messing around with our huge application, trying to get to work a brand new DAO/Entity/Service/DTO.. euh...thing. I've been left more or less on my own, and, again, more or less, I'm getting to understand some of the hows and maybe one or two of the whys.
The thing is that I got all, the way "up", from the DB to the Service:
I got a DAO class which executes a query stored on an Entity class. After executing it, it returns the Entity with the values.
The service receives the Entity and, somehow, transforms the Entity to a DTO and returns it to whenever is needed.
My problem is with the "somehow" thing the code goes like this:
DTOClass dto = ClassTransformerFromEntityToDTO.INSTANCE.apply(entityQueryResult);
I went into ClassTransformerFromEntityToDTO and found this:
public enum ClassTransfomerFromEntityToDTO implements Function<EntityClass,DTO Class> ) {
INSTANCE;
#Override
public DTOClass apply(EntityClass entityInstance) {
/*Code to transform the Entity to DTO and the return*/
}
}
The class that this... thing, implements, is this:
package com. google .common . base;
import com. google .common . annotations. GwtCompatible ;
import javax. annotation .Nullable ;
#GwtCompatible
public abstract interface Function <F , T >
{
#Nullable
public abstract T apply (#Nullable F paramF) ;
public abstract boolean equals (#Nullable Object paramObject) ;
}
I'm in the classic "everyone who where at the beginning of the project fled", and no one knows why is this or what is this (The wisest one told me that maybe it had something to do with Spring), so, I have two main questions (which can be more or less answered in the same side):
1) What's this? What's the point of using an enum with a function to make a conversion?
2) What's the point of this? Why can I just make a class with a single function and forget about this wizardry?
not sure there's much to answer here... And I'm adding an answer to illustrate my thoughts with some code I've seen, but that you have is horrible. I've actually seem similar stuff. My guess is that that codes actually precedes Spring. It's used as some sort of Singleton.
I have seen code like this, which is worse:
public interface DTO {
find(Object args)
}
public class ConcreteDTO1 implements DTO {
...
}
public class ConcreteDTO2 implements DTO {
...
}
public enum DTOType {
CONCRETE_DTO1(new ConcreteDTO1(someArgs)),
CONCRETE_DTO2(new ConcreteDTO2(someOtherArgs))
private DTO dto;
public DTOType(DTO dto) {
this.dto = dto;
}
public DTO dto() {
return dto;
}
}
and then the DTOs are basically accessed through the Enum Type:
DTOType.CONCRETE_DTO1.dto().find(args);
So everyone trying to get hold of a DTO accesses it through the enum. With Spring, you don't need any of that. The IoC container is meant to avoid this kind of nonsense, that's why my guess is that it precedes Spring, from some ancient version of the app when Spring was not there. But it could be that someone was wired to do such things regardless of whether Spring was already in the app or not.
For that kind of stuff you're trying to do, you're better of with the Visitor pattern. Here's an example from a different answer: passing different type of objects dynamically on same method
It's me. From the future.
Turns out that this construct is a propossed Singleton Implementation, at least on "Effective Java 2nd edition".
So, yeah, Ulise's guess was well oriented.

Name Clash, override fail, on a class implementing two interfaces with same erasure

I am creating a class that overrides a method signature whose erasure is identical between 2 implemented interfaces, but with a minor difference in regards of the generic type (one is a method-inferred type, the other an inferred-class type). I am looking for a neat solution. I CAN ONLY edit the inherited class, not the original legacy interfaces.
To show the case, I made up an abstract sample, to understand the problem:
I got a Developer legacy parent class:
public class Developer<C>{
Rate<C> getRate(Taxes<C> tax){ /*...*/ }
}
I also got a Rentable legacy interface, with an almost identical signature
public interface Rentable {
<C> Rate<C> getRate(Taxes<C> taxes);
}
As a developer is not rentable, in my model, I create an special
developer which is both a Developer, and Rentable material.
public class OutsourcableDeveloper<C>
extends Developer<C>
implements Rentable{
#Override
public Rate<C> getRate(Taxes<C> taxes){ /*...*/}
}
and then I got the infamous
Name clash: The method getRate(Developer.Taxes) of type
OutsourcableDeveloper has the same erasure as
getRate(Developer.Taxes) of type Rentable but does not override it
How can I get rid of it, so OutsourcableDeveloper.getRate() hides
both Developer and Rentable. getRate()?
It seems a bit illogical to fail a common override but then disallowing extending both signatures as the erasures are equal.
Does it really matters so much the fact that one of the supertypes infers type from de method and the other from the class specially when I'm not going to call any super in my implementation? Is there perhaps a trick to overcome the issue given this simplification?
EDIT: I opened a more abstract, less solution-oriented to my actual problem, question to discuss the inheritance design problem which I believe is the correlated essence of the actual issue I am having: Why can't I extend an interface "generic method" and narrow its type to my inherited interface "class generic"?
EDIT2: Previous question lead me to the answer posted here
Well they are actually not equal. Because any Rentable-Instance allows any typeparameter T to be given, while the OutsourcableDeveloper restricts it.
Of course you can assume that in your case it is easy to use the
<C> Rate<C> getRate(Taxes<C> taxes);
Version of the interface. But expect how confused a developer could be, if he wants to subclass OutsourceableDeveloper. From the definition of Developer he can assume that the Method getRate is fixed to C but actually it can suddenly take any value. -> allowing this would lead to confusion.
What i can offer you is the following code-example, which may be suitable for your case. Although it definitely will be inconvenient to use it. But as you forward all methods to the OursourcableDeveloperRentable it is possible. The comments should explain how it works.
//This class itself can be added to any Developer-lists
public class OutsourcableDeveloper<C> extends Developer<C> {
public final OutSourcableDeveloperRentable RENTABLE_INSTANCE = new OutSourcableDeveloperRentable();
#Override
public Rate<C> getRate(final Taxes<C> taxes) {
// Simply forward to the more general getRate instance.
return this.RENTABLE_INSTANCE.getRate(taxes);
}
public void exampleBehaviourA() {
//Example for how you can make both objects behave equally.
}
// This class can be added to the lists requiring a Rentable
// And the original value can be retrieved by both classes.
public class OutSourcableDeveloperRentable implements Rentable {
public final OutsourcableDeveloper<C> PARENT_INSTANCE = OutsourcableDeveloper.this;
//This method is the one to implement because it is more general than
//the version of OutsourcableDeveloper.
#Override
public <T> Rate<T> getRate(final Taxes<T> taxes) {
// Do your work.
return null;
}
public void exampleBehaviourA() {
//Just an example - Maybe for you it makes for sence to
//forward the method of Oursoursable-Developer to here.
//Then all Behaviour would be found in this class.
OutsourcableDeveloper.this.exampleBehaviourA();
}
}
}
Ok, I found a way to solve it. It's clumpsy, but it's the easier one if the architecture is not very complex, inspired by my Why can't I extend an interface "generic method" and narrow its type to my inherited interface "class generic"? own answer:
public class OutsourcableDeveloper<C>
extends Developer<C>
implements Rentable{
/* This might not be needed if we don't need to extract C from taxes parameter */
final Class<C> currencyClass;
public OutsourcableDeveloper(Class<C> currencyClass){ this.currencyClass = currencyClass;}
#Override
public Rate<C> getRate(#SuppressWarnings("rawtypes") Taxes taxes){
try{
C taxesCurrency = (C) currencyClass.cast(taxes.getCurrency()); //IF actually needed getting the typed instance
return new Rate<C>(taxesCurrency); //Or whatever processing
} catch (ClassCastException e){
throw new UnsupportedOperationException("OutsourcableDeveloper does not accept taxes in a currency that its not hims");
}
}
}
It is also possible to play with "extends Developer" without the generic type, so it is implictly raw. but we loose typing for the non-conflicting methods as well

Update a New Java Library Without Affecting Existing Systems

Suppose I have created a library and distribute all over the company and it use in every project.
Library is 1.0 and Suppose I have a interface Componentble.
public interface Componentble {
public String getComponentId();
}
I had done some modification and updated the jar for 1.1 and Componentble interface modified as follows.
public interface Componentble {
public String getComponentId();
public Componentble getParentComponent();
}
When this jar applied to existing project it will gives compile errors.
I want to do this modifications and update the jar. but case is it should not affect to existing projects.
What is the best way to do this.
Create ComponentbleV2 and in new project ask to use ComponentbleV2 not Componentble.
Or Create custom class loader and do what need.
The answer what i want is how we can do api modification and apply to existing project with out any compilation issue for existing projects.
One way to do this is by annotating the method(s) in your old interface with #Deprecated and explaining in the javadocs what to use instead.
For more documentation on that, see Oracle documentation on #Deprecated
For the sake of backwards compatibility, you're going to have to keep both interfaces for now. This might require a bit of customization in the implementation of the interfaces. In a while, after you've been through a couple more versions, you can remove the old interface.
Make sure to properly document your deprecated methods, so that the developers who use it know what to use instead and where to find it.
From Java 8 on you can provide default implementations for interface methods. They were invented exactly for your problem.
public interface Componentble {
public String getComponentId();
public default Componentble getParentComponent() {
return null;
}
}
Two interfaces
There is no need to deprecate the old one.
Create two interfaces where the new one extends the old one.
public interface Componentble {
public String getComponentId();
}
and
public interface ComponentbleWithStructure extends Componentble {
public Componentble getParentComponent();
}
Implementing a interface should imply that the implementer follows the contract of that interface.
This way you know that any class implementing both has been remade to fit the new contract and the ones implementing only the old still follows the old contract.
Example of use:
void doStuff(Componentble component){
if(component instanceof ComponentbleWithStructure){
Componentble parent=((ComponentbleWithStructure)component).getParentComponent();
....
}
....
}
Default implementation
The java8 way is only useful when it is possible to express the new functionality using the old interface. For example if you have a service that can look up parents you could write.
public interface Componentble {
public String getComponentId();
public default Componentble getParentComponent() {
return ParentLookUpService.getParent(getComponentId());
}
}
This way you will know that all instances using the new interface have a correct implementation.

Java - Using two classes with the same name in an Interface

I need to use two classes with the same name but different namespaces (foo.request.Response and bar.request.Response) in an interface. In classes this can be achieved by using the full name with namespace :
public foo.request.Response method1() { [...]
public bar.request.Response method2() { [...]
But this does not seem to work in Interfaces.
What is the correct way of dealing with this problem ?
Edit 1
Error comes from Eclipse :
foo cannot be resolved to a type
Interface code :
public interface ITestController {
String method1(foo.request.Response response);
}
I found the issue, it was not coming from the interface it was a simple mess-up in the dependencies. Thanks for your help ;)
It works in interfaces, but care should be taken so that the implementing classes fully qualify the names in the same way.
Note that you can not choose which of the two classes when implement the interface. It's the interface that specifies which of the two classes is to be used when implementing the interface.
The code you've posted in your answer is messed up. If the two first methods belong to a class implementing ITestController then that class must also include an implementation for
public String method1(foo.request.Response response) { ... }

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