I was recently searching for an answer to a different question about load-time-weaving and autowiring and I remember coming across something like this, but I'm not sure how to configure it. Essentially, I have class instances created outside of my control, so I need load-time weaving in order to wire my dependencies automatically as instances are created. I'd like to configure the dependencies in XML, though, as it's not able to autowire a certain List field.
Here's what I'd like to do:
#Configurable
public class RuntimeCreatedBean {
private List<RuntimeDependency> runtimeDependencies;
// setters omitted for brevity
}
XML:
<beans>
<bean class="RuntimeCreatedBean">
<property name="runtimeDependencies">
<list>
<bean class="RuntimeDependencyOne"/>
</list>
</property>
</bean>
</beans>
Is there a way to do this, where the bean definition is used to wire the RuntimeCreatedBean?
I haven't tried exactly like that, but I believe it will work exactly as you posted it. Have you tried it?
Edit: Yes, I just tried it in a sample project, and it works as expected.
I believe the answer you are looking for is in this Spring documentation.
You will need to include the spring-aspects.jar in your classpath. It looks like what you have should work. If not, you may need to specify to the #Configurable annotation the bean name to use.
#Configurable("RuntimeCreatedBean")
Related
I am using spring. I know how to use properties data inside a class but I need to know how to give component name from the properties file.
#Component("componentName") // here I need to give my property instead of "componentName".
public class TestClass {
}
I do search abt it but not able to find sos! Please help me...
I'm afraid that is not possible. All names that is given to #Controller, #Service and so on requires to be final/constant.
If you can use additional XML config, use alias directive as explained in this other question:
<beans>
<alias name="${service.class}" alias="Service"/>
<context:property-placeholder location="example/app.properties"/>
<context:component-scan base-package="example"/>
<beans>
If you need to use java config only, there's an open issue about it here. It is still unresolved, so for strictly java config the same is not currently possible.
If that's a problem, you can also register a bean programmatically as detailed here. So you'd autowire a property and your target bean, implement BeanDefinitionRegistryPostProcessor and register your bean in the registry you get as a parameter using your property.
I'm not sure if I understand correctly, from Spring 3 or up, you can use
#PropertySource annotation to externalize your configuration to a properties file. And then display the values with #Value
If you are talking about distinguishing configuration beans, #Qualifier is the thing you are looking for
With Spring it is possible to inject a list of beans by the interface class like:
#Component
public class Service {
#Autowire
private List<InterfaceType> implementingBeans;
...
}
All defined beans that implement this interface will be present in this List.
The annotation based approach is not possible for me, as the Service class is in a module that must not have spring dependencies.
I need to use this mechanism from outside via xml configuration.
<bean id="service" class="...Service">
<property name="implementingBeans">
??? tell spring to create a list bean that resolves all beans of the interfaceType.
</property>
</bean>
Does anyone know how to solve this?
EDIT: Additionally, there are more than one spring applications that use this service. So the best solution would be to handle this szenario completely via xml configuration. I can then copy the xml parts to all spriong applications that need this.
I want to avoid having a kind of initializer bean that gets the service injected and must then be copied to all spring applications.
Kind regards.
An XML-only solution would simply have you declare a <bean> of the "external" type and provide an autowire value of "byType".
Controls whether bean properties are "autowired". This is an
automagical process in which bean references don't need to be coded
explicitly in the XML bean definition file, but rather the Spring
container works out dependencies.
[...]
"byType" Autowiring if there is exactly one bean of the property type in the container. If there is more than one, a fatal error is
raised, and you cannot use byType autowiring for that bean. If there
is none, nothing special happens.
The explanation is a little confusing in that we expect multiple InterfaceType beans, but the actual field is of type List and Spring will be able to dynamically instantiate one and add all the InterfaceType beans to it, then inject it.
Your XML would simply look like
<bean id="service" class="...Service" autowire="byType">
</bean>
My original suggested solution made use of SpEL.
In the module that does have Spring dependencies, create a DTO
#Component(value = "beanDTO")
public class BeanDTO {
#Autowire
private List<InterfaceType> implementingBeans;
public List<InterfaceType> getImplementingBeans() {
return implementingBeans;
}
}
and then use SpEL to retrieve the value of implementingBeans from the beanDTO bean.
<bean id="service" depends-on="beanDTO" class="...Service">
<property name="implementingBeans" value="{beanDTO.implementingBeans}" />
</bean>
Spring will create the BeanTDO bean, inject all the beans that are of type InterfaceType. It will then create the service bean and set its property from beanDTO's implementingBeans property.
Following comments on question:
In an effort to be more JSR 330 compliant, Spring has introduced support for Java EE's javax.inject package. You can now annotate your injection targets with #javax.inject.Inject instead of #Autowired. Similarly, you can use #Named instead of #Component. The documentation has more details.
I want to inject a map containing all the properties that spring knows of (which are inserted by a library) to a config class that I have through the spring xml. Is that possible?
<bean class="Config">
<constructor-arg name="env">
<map>
//inject all properties?
</map>
</constructor-arg>
</bean>
Why don't you just inject the Spring Context? Through the Context, you can look up any bean via its name.
Edit:
From this answer, you could also use the following:
<bean class="Config">
<constructor-arg name="env">
<util:properties location="${path.to.properties.file}"/>
</constructor-arg>
</bean>
Where your "env" constructor argument is a java.util.Properties object.
For later versions of Spring (including spring-boot) that support the injection of an Environment you can use this to access all properties loaded.
To answer this question inject a AbstractEnvironment so that you are able to call the getPropertySources() method that will allow you to see where the properties have been loaded from (e.g. a file, OS variables, etc)
#Autowired
public Config(AbstractEnvironment environment)
{
MutablePropertySources propertySources = environment.getPropertySources();
// inspect propertySources to see all properties loaded by Spring
}
Can you not extend the library class that you use and instantiate your bean instead of the default library one? Then you would be able to inspect all the values.
Otherwise, if you know the signature of the library, you can always use AOP to weave some code around the library and get access to the properties there. A bit more complicated, but still gets you where you need to go. You can definitely use AspectJ (which requires a little more config) or even Spring AOP, depending how things are being accessed.
If you want/need more insight on this, let me know.
If I create a bean as follows:
#Repository("myRepository")
public class MyRepository {
...
}
In XML should I be able to wire it in as follows:
<bean id="xmlBean" class="uk.co.foo.myBean">
<constructor-arg ref="myRepository"/>
</bean>
Or is mixing like this not allowed?
The reason is for some things, generally business logic, it make sense for me to configure and wire various beans in XML as I may have multiple instances of the same interfaces, be likely to swap stuff round and it lets me to see my project configuration clearly from XML. However for repositorys it's very unlikely I am going to need to do or see any of those things and it's much more convenient just to use annotations.
It should work fine dont forget to enable context scanning in your xml configuration for Spring to find the bean it needs to AutoWire. You enable scanning by
<context:component-scan base-package="your package to scan" />
I have a static method I have no control over: MyUtils.getServiceURL() which returns a URL. I need to extract just the port from this URL to set a property on a bean:
<bean id="myBean>
<property name="defaultPort" value="?????"/>
</bean>
I can get the string value of the URL as a bean like this:
<bean id="serviceURL" class="MyUtils" factory-method="getServiceURL" />
I'm probably just going to write a method to parse the URL in myBean and extract the port. I was wondering if there was a way to avoid having to do this, and configure this directly in the spring context?
No need for custom classes, or parsers. Remember, a bean is just a class with get/is/set methods. A java.net.URL class qualifies as such.
Solution: Use a java.net.URL as a Spring-configurable bean and call it's getPort method.
Remember, in Spring, you can wire anything as a bean very easily so long as it sports methods using the get/is/set Bean convention. The java.net.URL class does such a thing.
** warning ** I'm just typing this out of my a$$, you'll have to check for any syntax shenanigans that I might be introducing in this Spring-config pseudo-code. One thing that is certain is that the concept will work with Spring 2.5 and that it relies on the util schema.
If you are using an older version of Spring, you'll have to use a PropertyPathFactoryBean. If you are using Spring 3.0, you'll want to use Spring expression language (EL), but I can't comment on the later since I'm not familiar with Spring 3.0.
In java:
int port = (new URL(MyUtils.getServiceURL()).getPort()
In Spring:
<bean id="serviceURL" class="MyUtils" factory-method="getServiceURL" />
<bean id="myURL" class="java.net.URL">
<constructor-arg>
<ref-bean="serviceURL"/>
</constructor-arg>
</bean>
<util:property-path id="defaultPort" path="myURL.port"/>
<bean id="myBean>
<property name="defaultPort" ref="defaultPort"/>
</bean>
There might be a way to consolidate all these four expressions into three or less, don't know if that will improve readability, though. The concept remains the same, though. Treat a java.net.URL instance as a bean, set its URL via its constructor, and get a hold (via Spring) of its getPort() method.
** edit **:
If you are using Spring 2.5 you can create an inline groovy bean that does all that for you. I've seen people doing that as integration glue to get rid of multitude of temp Spring bean place holders. That's the best choice IMO when you need to define a class (when it's simpler than just using Spring tags) and when you know such a class won't be used outside of Spring wiring of things.
Not I can think of. Either way, you probably have to write something to parse the port out. Since you have no control of that static method, perhaps you may want to utilize the adapter pattern to hide that static method. Doing so also makes your code easier to test because you can easily mock that external API out. For example:-
public interface URLServiceAdapter {
int getServiceURLPort();
}
public class URLServiceAdapterImpl implements URLServiceAdapter {
public int getServiceURLPort() {
return MyUtils.getServiceURL().getPort();
}
}
Your beans will then rely on your adapter class instead of MyUtils.getServiceURL() directly:-
<bean id="urlServiceAdapter" class="project.URLServiceAdapterImpl" />
That way, you can do something like this:-
#Autowired
private UrlServiceAdapter urlServiceAdapter;
...
bean.setDefaultPort(urlServiceAdapter.getServiceURLPort());
SpEL is your friend.
<bean id="myBean>
<property name="defaultPort"
value='#{ T(com.foo.MyUtils).getServiceURL().split(":")[2].split("/")[0] }'/>
</bean>
Enjoy,