What is the exit strategy for Executors.newSingleThreadExecutor() - java

I'm new to java concurrency so this may be a question already answered many time over or too obvious that I maybe missing something.
I am running as task like so:
Executors.newSingleThreadExecutor().execute(task)
My question is when its comes to end of executing the run method of task why does it not exit or why is the thread still alive? My understanding was once a threads run() completes the thread is no more and ceases to exist, right?

newSingleThreadExecutor returns an ExecutorService which uses a single thread - it can still execute multiple tasks. It doesn't exit because you may want to supply more tasks.
You can use:
ExecutorService service = Executors.newSingleThreadExecutor();
service.execute(task);
service.shutdown();
to shut it down after the task has executed.

the thread remains alive because its lifecycle is not tied to that of the tasks assigned to the executor; take a look at:
javadoc for Executors.newSingleThreadExecutor
you'll find that internally, the returned ExecutorService uses a single thread to sequentially run as many tasks as you assign to it, potentially instantiating a new thread if one of your tasks kills the original one.

Related

How to have java executor with same thread?

For some proposes, I need to create an Executor which has always one same thread.
Executors.newFixedThreadPool(1);
Executors.newScheduledThreadPool(1);
Above examples create one thread pool but when work is done then the thread will be ended and again created a new one if a new task is passed to the executor.
So I figured out something like this:
new ThreadPoolExecutor(1,1,Long.MAX_VALUE, TimeUnit.DAYS, new LinkedBlockingQueue<>());
it seems that works but I have doubts if it's the right approach. Can someone show a better/correct way?
Executors.newSingleThreadExecutor();
From the documentation (emphasis mine):
Creates an Executor that uses a single worker thread operating off an unbounded queue. (Note however that if this single thread terminates due to a failure during execution prior to shutdown, a new one will take its place if needed to execute subsequent tasks.) Tasks are guaranteed to execute sequentially, and no more than one task will be active at any given time. Unlike the otherwise equivalent newFixedThreadPool(1) the returned executor is guaranteed not to be reconfigurable to use additional threads.

A couple of questions regarding Java ExecutorService newFixedThreadPool

Please note that I usually ask a question after googling for more than 20 times about the issue. But I can't still understand it. So I need your help.
Basically, I don't understand the exact usage of newFixedThreadPool
Does newFixedThreadPool(10) mean having ten different threads? Or does it mean it can have 10 of the same threads? or the both?
I executed with submit() methods more than 20 times and it's working.
Does submit() print a value? Or are you putting threads in the ExecutorService?
Briefly, tasks are small units of code that could be executed in parallel (code sections). The threads (in a thread pool) are what execute them. You can think of the threads like workers and the tasks like jobs. Jobs can be done in parallel, and workers can work in parallel. Workers work on jobs.
So, to answer your questions:
newFixedThreadPool(int nThreads) creates a thread pool of nThread threads that operate on the same input queue. nThreads is the maximum number of threads that can be running at any given time. Each thread can run a different task. With your example, you can be running up to 10 tasks at the same time. (The documentation can be found here with credit to #hovercraft-full-of-eels)
submit() pushes the given task into an event queue that is shared by the threads in the thread pool. Once a thread is available, it will take a task from the front of the queue and execute it. It shouldn't print anything, unless the Runnable you pass it has a print statement in it. However, the print statement may not be printed right when you submit the task! It will print once a thread is executing that particular task. (The documentation can be found here)
Just refer java docs or JAVA API's description rather than googling it.
For your questions I have below comments .
Question 1 ->
ExecutorService executorService = Executors.newFixedThreadPool(10);
First an ExecutorService is created using the Executors newFixedThreadPool() factory method. This creates a thread pool with 10 threads executing tasks.
Executors.newFixedThreadPool API creates, a thread pool that reuses a fixed number of threads and these threads work on a s***hared unbounded queue***.
At any point, at most nThreads threads will be active processing tasks.
If additional tasks are submitted when all threads are active, they will wait in the queue until a thread is available.
If any thread terminates due to a failure during execution prior to shutdown, a new one will take its place if needed to execute subsequent tasks. The threads in the pool will exist until it is explicitly SHUTDOWN.
After submitting even 20 tasks ,it worked with this thread pool.
Internally it calls below line of codes .
public static ExecutorService newFixedThreadPool(int nThreads) {
return new ThreadPoolExecutor(nThreads, nThreads,
0L, TimeUnit.MILLISECONDS,
new LinkedBlockingQueue());
}
Question 2- > Submits a Runnable task for execution in Queue and it can also return an Object of type Future Object representing task. we can use Future's get method to check whether submitted task has successfully completed or not because it will return null upon successful completion.

Shutting down ExecutorService

According to documentation, when shutdown() is invoked, any tasks that were already submitted (I assume via submit() or execute) will be executed. When shutdownNow() is invoked, the executor will halt all tasks waiting to be processed, as well as attempt to stop actively executing tasks.
What I would like to clarify is the exact meaning of "waiting to be processed." For example, say I have an executor, and I call execute() on some number of Runnable objects (assume all of these objects effectively ignore interruptions). I know that if I now call shutdown, all of these objects will finish executing, regardless.
However, if I call shutdownNow at this point, will it have the same effect as calling shutdown? Or are some of the objects not executed? In other words, if I want an executor to exit as fast as possible, is my best option always to call shutdownNow(), even when the Runnables passed to the executor all effectively ignore interruptions?
Let's say you have this fabulous Runnable that is not interruptible for 10 seconds once it's started:
Runnable r = new Runnable() {
#Override
public void run() {
long endAt = System.currentTimeMillis() + 10000;
while (System.currentTimeMillis() < endAt);
}
};
And you have an executor with just 1 thread and you schedule the runnable 10 times:
ExecutorService executor = Executors.newFixedThreadPool(1);
for (int i = 0; i < 10; i++)
executor.execute(r);
And now you decide to call shutdown:
The executor continues for the full 10 x 10 seconds and everything scheduled will be executed. The tasks don't see that you're shutting down their executor. shutdown can be used if you want a "short lived" executor just for a few tasks. You can immediately call shutdown and it will get cleaned up later.
Alternatively shutdownNow():
Takes 10 seconds. The already running task is attempted to be interrupted, but that obviously has no effect so it continues to run. The other 9 tasks that were still waiting in the queue are "cancelled" and returned to you as List so you could do something with them, like schedule them later. Could also take 0 seconds if the first task is not yet started. You'd get all tasks back. The method is used whenever you want to abort an entire executor.
What I would like to clarify is the exact meaning of "waiting to be processed".
It means all tasks whose run() method has not yet been called (by the executor).
If I call shutdownNow at this point, will it have the same effect as calling shutdown?
No.
Or is it possible that some of the objects will not be executed?
That is correct.
In other words, if I want an executor to exit as fast as possible, is my best option always to call shutdownNow(), even when the Runnables passed to the executor all effectively ignore interruptions?
That is correct.
Better still, recode the Runnables to pay attention to interrupts ... or put a timeout on the shutdown ...
The API for shutdownNow method says that :
There are no guarantees beyond best-effort attempts to stop processing
actively executing tasks. For example, typical implementations will
cancel via Thread.interrupt(), so any task that fails to respond to
interrupts may never terminate.
source

Java: ExecutorService with Callables: Reuse the same Pool in a loop? Shutdown necessary?

I got a loop {Loop-1}, where I start Threads. The class which contains the {Loop-1} implements Daemon and Runnable.
In the {Loop-1} the thread, which is started, calls a method coordinate() of a class Coordinate.java where I use the ExecutorService.
When the object of Coordinate.java is created (this happens once BEFORE {Loop-1}), I instantiate a ExecutorService
pool = Executors.newFixedThreadPool(2);
In coordinate() I create two Objects of a class which implements Callable and I start them then and store the result in a List of Future results.
callableResults = pool.invokeAll(threads);
After, I try to get the results in a loop with result = future.get();
Then, I return to {Loop-1} and the whole process starts again (call coordinate(), invokeAll(), future.get()
Now Ive got the following question:
1. Do I need to shutdown the pool of ExecutorService after I got the results in coordinate()?
2. Do I need to recreate the pool everytime my {Loop-1} calls coordinate()?
Thanks for answers! :-)
No you do not. The threads in the fixed thread pool can be used until you call shutdown on it. So, you can simply resubmit new tasks to be executed and fetch their results, exactly as you did in the first go-round.
You need to shutdown the executorService once you're done processing all your tasks.
The submission of tasks can be in multiple cycles.
Once you call executorService.shutDown(), you can wait until all tasks are completed after calling shutDown() using executorService.awaitTermination(10, TimeUnit.SECONDS).
Alternatively, you can do: while (!executorService.isTerminated()) { }

How to wait for all tasks in an ThreadPoolExecutor to finish without shutting down the Executor?

I can't use shutdown() and awaitTermination() because it is possible new tasks will be added to the ThreadPoolExecutor while it is waiting.
So I'm looking for a way to wait until the ThreadPoolExecutor has emptied it's queue and finished all of it's tasks without stopping new tasks from being added before that point.
If it makes any difference, this is for Android.
Thanks
Update: Many weeks later after revisiting this, I discovered that a modified CountDownLatch worked better for me in this case. I'll keep the answer marked because it applies more to what I asked.
If you are interested in knowing when a certain task completes, or a certain batch of tasks, you may use ExecutorService.submit(Runnable). Invoking this method returns a Future object which may be placed into a Collection which your main thread will then iterate over calling Future.get() for each one. This will cause your main thread to halt execution until the ExecutorService has processed all of the Runnable tasks.
Collection<Future<?>> futures = new LinkedList<Future<?>>();
futures.add(executorService.submit(myRunnable));
for (Future<?> future:futures) {
future.get();
}
My Scenario is a web crawler to fetch some information from a web site then processing them. A ThreadPoolExecutor is used to speed up the process because many pages can be loaded in the time. So new tasks will be created in the existing task because the crawler will follow hyperlinks in each page. The problem is the same: the main thread do not know when all the tasks are completed and it can start to process the result. I use a simple way to determine this. It is not very elegant but works in my case:
while (executor.getTaskCount()!=executor.getCompletedTaskCount()){
System.err.println("count="+executor.getTaskCount()+","+executor.getCompletedTaskCount());
Thread.sleep(5000);
}
executor.shutdown();
executor.awaitTermination(60, TimeUnit.SECONDS);
Maybe you are looking for a CompletionService to manage batches of task, see also this answer.
(This is an attempt to reproduce Thilo's earlier, deleted answer with my own adjustments.)
I think you may need to clarify your question since there is an implicit infinite condition... at some point you have to decide to shut down your executor, and at that point it won't accept any more tasks. Your question seems to imply that you want to wait until you know that no further tasks will be submitted, which you can only know in your own application code.
The following answer will allow you to smoothly transition to a new TPE (for whatever reason), completing all the currently-submitted tasks, and not rejecting new tasks to the new TPE. It might answer your question. #Thilo's might also.
Assuming you have defined somewhere a visible TPE in use as such:
AtomicReference<ThreadPoolExecutor> publiclyAvailableTPE = ...;
You can then write the TPE swap routine as such. It could also be written using a synchronized method, but I think this is simpler:
void rotateTPE()
{
ThreadPoolExecutor newTPE = createNewTPE();
// atomic swap with publicly-visible TPE
ThreadPoolExecutor oldTPE = publiclyAvailableTPE.getAndSet(newTPE);
oldTPE.shutdown();
// and if you want this method to block awaiting completion of old tasks in
// the previously visible TPE
oldTPE.awaitTermination();
}
Alternatively, if you really no kidding want to kill the thread pool, then your submitter side will need to cope with rejected tasks at some point, and you could use null for the new TPE:
void killTPE()
{
ThreadPoolExecutor oldTPE = publiclyAvailableTPE.getAndSet(null);
oldTPE.shutdown();
// and if you want this method to block awaiting completion of old tasks in
// the previously visible TPE
oldTPE.awaitTermination();
}
Which could cause upstream problems, the caller would need to know what to do with a null.
You could also swap out with a dummy TPE that simply rejected every new execution, but that's equivalent to what happens if you call shutdown() on the TPE.
If you don't want to use shutdown, follow below approaches:
Iterate through all Future tasks from submit on ExecutorService and check the status with blocking call get() on Future object as suggested by Tim Bender
Use one of
Using invokeAll on ExecutorService
Using CountDownLatch
Using ForkJoinPool or newWorkStealingPool of Executors(since java 8)
invokeAll() on executor service also achieves the same purpose of CountDownLatch
Related SE question:
How to wait for a number of threads to complete?
You could call the waitTillDone() on Runner class:
Runner runner = Runner.runner(10);
runner.runIn(2, SECONDS, runnable);
runner.run(runnable); // each of this runnables could submit more tasks
runner.waitTillDone(); // blocks until all tasks are finished (or failed)
// and now reuse it
runner.runIn(500, MILLISECONDS, callable);
runner.waitTillDone();
runner.shutdown();
To use it add this gradle/maven dependency to your project: 'com.github.matejtymes:javafixes:1.0'
For more details look here: https://github.com/MatejTymes/JavaFixes or here: http://matejtymes.blogspot.com/2016/04/executor-that-notifies-you-when-task.html
Try using queue size and active tasks count as shown below
while (executor.getThreadPoolExecutor().getActiveCount() != 0 || !executor.getThreadPoolExecutor().getQueue().isEmpty()){
try {
Thread.sleep(500);
} catch (InterruptedException e) {
}
}

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