Related
I am trying to get time (HH:MM) from below code in IST format but it still display UTC date, time.
Please help.
public static void main (String args[]) throws ParseException {
String date = "2021-07-05T14:17:00.000Z";
Calendar now = Calendar.getInstance();
TimeZone timeZone = now.getTimeZone();
String timezoneID = timeZone.getID();
// Convert to System format from UTC
SimpleDateFormat format1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
Date actualDate = format1.parse(date);
format1.setTimeZone(TimeZone.getTimeZone(timezoneID));
String date1 = format1.format(actualDate);
String time = date1.substring(11, 16);
String timezoneValue = TimeZone.getTimeZone(timezoneID).getDisplayName(false, TimeZone.SHORT);
String finalTime = time + " " + timezoneValue;
System.out.print(finalTime);
}
java.time
I strongly recommend that you use java.time, the modern Java date and time API, for your date and time work. Then your task becomes pretty simple. Rather than a formatter for your input format I want to define a formatter for your desired time format:
private static final DateTimeFormatter TIME_FORMATTER
= DateTimeFormatter.ofPattern("HH:mm zzz", Locale.ENGLISH);
Now the operation goes in these few lines:
String date = "2021-07-05T14:17:00.000Z";
String finalTime = Instant.parse(date)
.atZone(ZoneId.systemDefault())
.format(TIME_FORMATTER);
System.out.println(finalTime);
Output when I ran in Europe/Dublin time zone:
15:17 IST
Here IST is for Irish Summer Time. IST has several meanings, and I wasn’t sure which one you intended. Also many of the other popular time zone abbreviations are ambiguous. IST may also mean Israel Standard Time, but not here, since Israel uses Israel Daylight Time or IDT at this time of year. One other interpretation is India Standard Time used in India and Sri Lanka, So let’s try running the code in Asia/Kolkata time zone.
19:47 IST
I am exploiting the fact that your string is in ISO 8601 format, the format that the classes of java.time parse and also print as their default, that is, without any specified formatter.
What went wrong in your code?
Your bug is here:
SimpleDateFormat format1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
You must never hardcode Z as a literal in your format pattern, which is what you are doing when enclosing it in single quotes. The Z is a UTC offset and needs to be parsed as such so that Java knows that your date and time are in UTC (which is what Z means). When you hardcode the Z, SimpleDateFormat understands the date and time to be in the default time zone of the JVM. So when afterward you try to convert into that time zone, the time of day is not changed. You’re converting into the time zone you already had. It’s a no-op.
Links
Oracle tutorial: Date Time explaining how to use java.time.
Wikipedia article: ISO 8601
Time Zone Abbreviations – Worldwide List
You are parsing the date using your default TimeZone, not UTC.
You never called format1.setTimeZone before parsing. A DateFormat uses the default timezone unless you set it to something else.
Let’s look at each line of your code:
Calendar now = Calendar.getInstance();
TimeZone timeZone = now.getTimeZone();
That is getting the default TimeZone. You don’t need a Calendar object for that; just call TimeZone.getDefault().
String timezoneID = timeZone.getID();
There is no reason to call that. You already have a TimeZone object. Converting it to a string ID and back to a TimeZone is a pointless round-trip operation. So, you should remove all uses of timezoneID.
SimpleDateFormat format1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
That is the problem. The DateFormat doesn’t treat the 'Z' as anything special; it’s just a literal character which the DateFormat knows not to parse.
You need to actually tell the DateFormat that it’s parsing a UTC time:
SimpleDateFormat format1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
TimeZone utc = TimeZone.getTimeZone(ZoneOffset.UTC);
format1.setTimeZone(utc);
Date actualDate = format1.parse(date);
Instead of cutting out pieces of a formatted string, make a new DateFormat that does exactly what you want:
DateFormat timeFormat = new SimpleDateFormat("HH:mm z");
String finalTime = timeFormat.format(actualDate);
Since a SimpleDateFormat always uses the default TimeZone when it is created, there is no need to call this format object’s setTimeZone method.
I should mention that the java.time and java.time.format packages are much better for working with dates and times:
String date = "2021-07-05T14:17:00.000Z";
Instant instant = Instant.parse(date);
ZonedDateTime utcDateTime = instant.atZone(ZoneOffset.UTC);
ZonedDateTime istDateTime =
utcDateTime.withZoneSameInstant(ZoneId.systemDefault());
String finalTime = String.format("%tR %<tZ", istDateTime);
// Or:
// String finalTime = istDateTime.toLocalTime() + " "
// + itsDateTime.getZone().getDisplayName(
// TextStyle.SHORT, Locale.getDefault());
format1.setTimeZone(TimeZone.getTimeZone("Asia/Kolkata"));
is what you need since the 3-letter zone names are really deprecated. Plus:
String timezoneValue = format1.getTimeZone().getDisplayName(false, TimeZone.SHORT);
The method Calendar.getInstance() gets a calendar using the default time zone and locale - UTC±00:00.
Use "IST" instead of timeZone.getID().
Exemple:
String date="2021-07-05T14:17:00.000Z";
Calendar now = Calendar.getInstance();
TimeZone timeZone = now.getTimeZone();
String timezoneID = "IST"; // <<<<<
// Convert to System format from UTC
DateFormat format1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
Date actualDate = format1.parse(date);
format1.setTimeZone(TimeZone.getTimeZone(timezoneID));
String date1 = format1.format(actualDate);
String time = date1.substring(11, 16);
String timezoneValue = TimeZone.getTimeZone(timezoneID).getDisplayName(false, TimeZone.SHORT);
String finalTime = time + " " + timezoneValue;
System.out.print(finalTime);
I have two strings which can be seen as time stamps:
String min="2017-04-15 13:27:31";
String max="2017-04-15 13:40:01";
Assume we want to find out the time passed from first time stamp to the second one. If there was only the time and no date included, I could get it using my following code:
String[] partsMin=min.split(":");
String[] partMax=max.split(":");
int diffZero=Integer.parseInt(partMax[0])-Integer.parseInt(partsMin[0]);
int diffOne=Integer.parseInt(partMax[1])-Integer.parseInt(partsMin[1]);
int diffOTwo=Integer.parseInt(partMax[2])-Integer.parseInt(partsMin[2]);
diffInSec=diffZero*3600+diffOne*60+diffOTwo;
So here is the question. How to get the job done while there is a date within the time stamp?
I would construct LocalDateTime instances from it.
Then i would get the milliseconds from it and substract startTime from EndTime.
What is remaining are the milliseconds passed between the two. A DateTimeFormatter is helpful as well for this purpose.
String strMin = "2017-04-15 13:27:31";
DateTimeFormatter formatterTime = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime dateTimeMin = LocalDateTime.parse(strMin, formatter);
String strMax = "2017-04-15 13:40:01";
LocalDateTime dateTimeMax = LocalDateTime.parse(strMax, formatter);
long minutes = ChronoUnit.MINUTES.between(dateMin, dateMaxto);
long hours = ChronoUnit.HOURS.between(dateMin, dateMax);
If you want to get the milliseconds:
long millisPassed = dateMax.toEpochMilli() - dateMax.toEpochMilli();
Use the java date time libraries (even the old Date class would be fine for this) to parse the string into a proper object.
Depending on the date time library you chose you can then look at the difference between them. The simplest would be something like:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");
Date date1 = sdf.parse(str1);
Date date2 = sdf.parse(str2);
long differenceInSeconds = (date2.getTime()-date1.getTime())/1000;
The new Java 8 time classes would also allow you to do this and would be better to learn going forwards. I can't remember the syntax for that off the top of my head though.
Did you try with replace all the other part of your String like this :
String[] partsMin = min.replaceAll("\\d+-\\d+-\\d+", "").trim().split(":");
String[] partMax = max.replaceAll("\\d+-\\d+-\\d+", "").trim().split(":");
Doing this in your code:
int diffZero=Integer.parseInt(partMax[0])
is the same as doing:
int diffZero=Integer.parseInt("2017-04-15")
that is generating an Exception(NumberFormatException)
you should better try to PARSE those strings min and max into a date
Edit:
you can inspect your code/ variables: and see that splitting to ":" is not giving you back the correct array since the element at index 0 is holding more information than you need...
but as I said before, you are going on the wrong path, dont re invent the wheel and look how practical will get using the APIs that java has for us:
String min = "2017-04-15 13:27:31";
String max = "2017-04-15 13:40:01";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime dateTimeMin = LocalDateTime.parse(min, formatter);
LocalDateTime dateTimeMax = LocalDateTime.parse(max, formatter);
long days = ChronoUnit.DAYS.between(dateTimeMin, dateTimeMax);
long minutes = ChronoUnit.MINUTES.between(dateTimeMin, dateTimeMax);
System.out.println(days);
System.out.println(minutes);
use SimpleDateFormat to parse the date string, and do operation on Date result, you will get right value. This works well for date between '2017-02-28 23:59:59' and '2017-03-01 00:00:01'
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date1 = format.parse("2017-02-28 23:59:59");
Date date2 = format.parse("2017-03-01 00:00:01");
long time1 = date1.getTime();
long time2 = date2.getTime();
long diff = time2 - time2; // should be 2000
I'm trying to get a time string in the format of YYYYMMDD-HHMMSSMilliseconds in Android
Ex: 20130312-1723437520 (2013 March 12th, 17 Hour 23 Minutes 43 Seconds 7520 Milliseconds)
Time now = new Time();
now.setToNow();
String snapshotTime = now.format("yyyyMMdd-HHmmss");
First of all, above code doesn't even work properly. snapshotTime is always set to the format string itself.
Second of all, according to the Android documentation, there's no way to record milliseconds.
How can I accomplish this?
See the SimpleDateFormat class, you can format a Date object into the required format (upper-case S will give millis)
SimpleDateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
Date now = new Date();
String str = fmt.format(now);
That said, using Joda Time is usually a good idea (Proguard will strip code you don't use).
You'll have to use the strftime formatting, as noted in the Android docs.
Time now = new Time();
now.setToNow();
String snapshotTime = now.format("%Y%m%d-%H%M%S");
If you really want to use milliseconds than I would recommend SimpleDateFormat.
Try getting the time as unix timestamp with milliseconds from
long currentTime = System.currentTimeMillis();
or convert your time to milliseconds:
long currentTime = now.toMillis(true);
Then you can convert this to your desired date:
Time now = new Time();
now.set(currentTime);
String snapshotTime = now.format("%Y%m%d-%H%M%S")+""+(currentTime%1000);
Didn't test it but hope it works :)
I would recommend to use this little library, it's very helpful when working with dates. Have a look at the DateTimeFormatter class.
As an alternative use Calendar and SimpleDateFormater (you'll have to adjust the format string of course, see this for explanation of the symbols)
Calendar c = new GregorianCalendar();
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy-SSSS");
String date = sdf.format(c.getTime());
You can try this:
public static String format() {
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyyMMdd-HHmmssSSS");
Date now = new Date();
return simpleDateFormat.format(now);
}
I have a date inside a string, something like "12-December-2012".
How can I convert this into milliseconds (long)?
Using SimpleDateFormat
String string_date = "12-December-2012";
SimpleDateFormat f = new SimpleDateFormat("dd-MMM-yyyy");
try {
Date d = f.parse(string_date);
long milliseconds = d.getTime();
} catch (ParseException e) {
e.printStackTrace();
}
It’s about time someone provides the modern answer to this question. In 2012 when the question was asked, the answers also posted back then were good answers. Why the answers posted in 2016 also use the then long outdated classes SimpleDateFormat and Date is a bit more of a mystery to me. java.time, the modern Java date and time API also known as JSR-310, is so much nicer to work with. You can use it on Android through the ThreeTenABP, see this question: How to use ThreeTenABP in Android Project.
For most purposes I recommend using the milliseconds since the epoch at the start of the day in UTC. To obtain these:
DateTimeFormatter dateFormatter
= DateTimeFormatter.ofPattern("d-MMMM-uuuu", Locale.ENGLISH);
String stringDate = "12-December-2012";
long millisecondsSinceEpoch = LocalDate.parse(stringDate, dateFormatter)
.atStartOfDay(ZoneOffset.UTC)
.toInstant()
.toEpochMilli();
System.out.println(millisecondsSinceEpoch);
This prints:
1355270400000
If you require the time at start of day in some specific time zone, specify that time zone instead of UTC, for example:
.atStartOfDay(ZoneId.of("Asia/Karachi"))
As expected this gives a slightly different result:
1355252400000
Another point to note, remember to supply a locale to your DateTimeFormatter. I took December to be English, there are other languages where that month is called the same, so please choose the proper locale yourself. If you didn’t provide a locale, the formatter would use the JVM’s locale setting, which may work in many cases, and then unexpectedly fail one day when you run your app on a device with a different locale setting.
SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yyyy");
Date date = (Date)formatter.parse("12-December-2012");
long mills = date.getTime();
Take a look to SimpleDateFormat class that can parse a String and return a Date and the getTime method of Date class.
First convert string to java.util.Date using date formatter
Use getTime() to obtain count of millisecs from date
you can use the simpleDateFormat to parse the string date.
Easiest way is used the Date Using Date() and getTime()
Date dte=new Date();
long milliSeconds = dte.getTime();
String strLong = Long.toString(milliSeconds);
System.out.println(milliSeconds)
using simpledateformat you can easily achieve it.
1) First convert string to java.Date using simpledateformatter.
2) Use getTime method to obtain count of millisecs from date
public class test {
public static void main(String[] args) {
String currentDate = "01-March-2016";
SimpleDateFormat f = new SimpleDateFormat("dd-MMM-yyyy");
Date parseDate = f.parse(currentDate);
long milliseconds = parseDate.getTime();
}
}
more Example click here
Try below code
SimpleDateFormat f = new SimpleDateFormat("your_string_format", Locale.getDefault());
Date d = null;
try {
d = f.parse(date);
} catch (ParseException e) {
e.printStackTrace();
}
long timeInMillis = d.getTime();
I want to remove time from Date object.
DateFormat df;
String date;
df = new SimpleDateFormat("dd/MM/yyyy");
d = eventList.get(0).getStartDate(); // I'm getting the date using this method
date = df.format(d); // Converting date in "dd/MM/yyyy" format
But when I'm converting this date (which is in String format) it is appending time also.
I don't want time at all. What I want is simply "21/03/2012".
You can remove the time part from java.util.Date by setting the hour, minute, second and millisecond values to zero.
import java.util.Calendar;
import java.util.Date;
public class DateUtil {
public static Date removeTime(Date date) {
Calendar cal = Calendar.getInstance();
cal.setTime(date);
cal.set(Calendar.HOUR_OF_DAY, 0);
cal.set(Calendar.MINUTE, 0);
cal.set(Calendar.SECOND, 0);
cal.set(Calendar.MILLISECOND, 0);
return cal.getTime();
}
}
The quick answer is :
No, you are not allowed to do that. Because that is what Date use for.
From javadoc of Date :
The class Date represents a specific instant in time, with millisecond precision.
However, since this class is simply a data object. It dose not care about how we describe it.
When we see a date 2012/01/01 12:05:10.321, we can say it is 2012/01/01, this is what you need.
There are many ways to do this.
Example 1 : by manipulating string
Input string : 2012/01/20 12:05:10.321
Desired output string : 2012/01/20
Since the yyyy/MM/dd are exactly what we need, we can simply manipulate the string to get the result.
String input = "2012/01/20 12:05:10.321";
String output = input.substring(0, 10); // Output : 2012/01/20
Example 2 : by SimpleDateFormat
Input string : 2012/01/20 12:05:10.321
Desired output string : 01/20/2012
In this case we want a different format.
String input = "2012/01/20 12:05:10.321";
DateFormat inputFormatter = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss.SSS");
Date date = inputFormatter.parse(input);
DateFormat outputFormatter = new SimpleDateFormat("MM/dd/yyyy");
String output = outputFormatter.format(date); // Output : 01/20/2012
For usage of SimpleDateFormat, check SimpleDateFormat JavaDoc.
Apache Commons DateUtils has a "truncate" method that I just used to do this and I think it will meet your needs. It's really easy to use:
DateUtils.truncate(dateYouWantToTruncate, Calendar.DAY_OF_MONTH);
DateUtils also has a host of other cool utilities like "isSameDay()" and the like. Check it out it! It might make things easier for you.
What about this:
Date today = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
today = sdf.parse(sdf.format(today));
What you want is impossible.
A Date object represents an "absolute" moment in time. You cannot "remove the time part" from it. When you print a Date object directly with System.out.println(date), it will always be formatted in a default format that includes the time. There is nothing you can do to change that.
Instead of somehow trying to use class Date for something that it was not designed for, you should look for another solution. For example, use SimpleDateFormat to format the date in whatever format you want.
The Java date and calendar APIs are unfortunately not the most well-designed classes of the standard Java API. There's a library called Joda-Time which has a much better and more powerful API.
Joda-Time has a number of special classes to support dates, times, periods, durations, etc. If you want to work with just a date without a time, then Joda-Time's LocalDate class would be what you'd use.
edit - note that my answer above is now more than 10 years old. If you are using a current version of Java (Java 8 or newer), then prefer to use the new standard date and time classes in package java.time. There are many classes available that represent just a date (day, month, year); a date and time; just a time; etc.
Date dateWithoutTime =
new Date(myDate.getYear(),myDate.getMonth(),myDate.getDate())
This is deprecated, but the fastest way to do it.
May be the below code may help people who are looking for zeroHour of the day :
Date todayDate = new Date();
GregorianCalendar todayDate_G = new GregorianCalendar();
gcd.setTime(currentDate);
int _Day = todayDate_GC.get(GregorianCalendar.DAY_OF_MONTH);
int _Month = todayDate_GC.get(GregorianCalendar.MONTH);
int _Year = todayDate_GC.get(GregorianCalendar.YEAR);
GregorianCalendar newDate = new GregorianCalendar(_Year,_Month,_Day,0,0,0);
zeroHourDate = newDate.getTime();
long zeroHourDateTime = newDate.getTimeInMillis();
Hope this will be helpful.
you could try something like this:
import java.text.*;
import java.util.*;
public class DtTime {
public static void main(String args[]) {
String s;
Format formatter;
Date date = new Date();
formatter = new SimpleDateFormat("dd/MM/yyyy");
s = formatter.format(date);
System.out.println(s);
}
}
This will give you output as21/03/2012
Or you could try this if you want the output as 21 Mar, 2012
import java.text.*;
import java.util.*;
public class DtTime {
public static void main(String args[]) {
Date date=new Date();
String df=DateFormat.getDateInstance().format(date);
System.out.println(df);
}
}
You can write that for example:
private Date TruncarFecha(Date fechaParametro) throws ParseException {
String fecha="";
DateFormat outputFormatter = new SimpleDateFormat("MM/dd/yyyy");
fecha =outputFormatter.format(fechaParametro);
return outputFormatter.parse(fecha);
}
The correct class to use for a date without time of day is LocalDate. LocalDate is a part of java.time, the modern Java date and time API.
So the best thing you can do is if you can modify the getStartDate method you are using to return a LocalDate:
DateTimeFormatter dateFormatter = DateTimeFormatter
.ofLocalizedDate(FormatStyle.SHORT)
.withLocale(Locale.forLanguageTag("en-IE"));
LocalDate d = eventList.get(0).getStartDate(); // We’re now getting a LocalDate using this method
String dateString = d.format(dateFormatter);
System.out.println(dateString);
Example output:
21/03/2012
If you cannot change the getStartDate, you may still be able to add a new method returning the type that we want. However, if you cannot afford to do that just now, convert the old-fashioned Date that you get (I assume java.util.Date):
d = eventList.get(0).getStartDate(); // I'm getting the old-fashioned Date using this method
LocalDate dateWithoutTime = d.toInstant()
.atZone(ZoneId.of("Asia/Kolkata"))
.toLocalDate();
Please insert the time zone that was assumed for the Date. You may use ZoneId.systemDefault() for the JVM’s time zone setting, only this setting can be changed at any time from other parts of your program or other programs running in the same JVM.
The java.util.Date class was what we were all using when this question was asked 6 years ago (no, not all; I was, and we were many). java.time came out a couple of years later and has replaced the old Date, Calendar, SimpleDateFormat and DateFormat. Recognizing that they were poorly designed. Furthermore, a Date despite its name cannot represent a date. It’s a point in time. What the other answers do is they round down the time to the start of the day (“midnight”) in the JVM’s default time zone. It doesn’t remove the time of day, only sets it, typically to 00:00. Change your default time zone — as I said, even another program running in the same JVM may do that at any time without notice — and everything will break (often).
Link: Oracle tutorial: Date Time explaining how to use java.time.
A bit of a fudge but you could use java.sql.Date. This only stored the date part and zero based time (midnight)
Calendar c = Calendar.getInstance();
c.set(Calendar.YEAR, 2011);
c.set(Calendar.MONTH, 11);
c.set(Calendar.DATE, 5);
java.sql.Date d = new java.sql.Date(c.getTimeInMillis());
System.out.println("date is " + d);
DateFormat df = new SimpleDateFormat("dd/MM/yyyy");
System.out.println("formatted date is " + df.format(d));
gives
date is 2011-12-05
formatted date is 05/12/2011
Or it might be worth creating your own date object which just contains dates and not times. This could wrap java.util.Date and ignore the time parts of it.
java.util.Date represents a date/time down to milliseconds. You don't have an option but to include a time with it. You could try zeroing out the time, but then timezones and daylight savings will come into play--and that can screw things up down the line (e.g. 21/03/2012 0:00 GMT is 20/03/2012 PDT).
What you might want is a java.sql.Date to represent only the date portion (though internally it still uses ms).
String substring(int startIndex, int endIndex)
In other words you know your string will be 10 characers long so you would do:
FinalDate = date.substring(0,9);
Another way to work out here is to use java.sql.Date as sql Date doesn't have time associated with it, whereas java.util.Date always have a timestamp.
Whats catching point here is java.sql.Date extends java.util.Date, therefore java.util.Date variable can be a reference to java.sql.Date(without time) and to java.util.Date of course(with timestamp).
In addtition to what #jseals has already said. I think the org.apache.commons.lang.time.DateUtils class is probably what you should be looking at.
It's method : truncate(Date date,int field) worked very well for me.
JavaDocs : https://commons.apache.org/proper/commons-lang/javadocs/api-2.6/org/apache/commons/lang/time/DateUtils.html#truncate(java.util.Date, int)
Since you needed to truncate all the time fields you can use :
DateUtils.truncate(new Date(),Calendar.DAY_OF_MONTH)
If you are using Java 8+, use java.time.LocalDate type instead.
LocalDate now = LocalDate.now();
System.out.println(now.toString());
The output:
2019-05-30
https://docs.oracle.com/javase/8/docs/api/java/time/LocalDate.html
You can also manually change the time part of date and format in "dd/mm/yyyy" pattern according to your requirement.
public static Date getZeroTimeDate(Date changeDate){
Date returnDate=new Date(changeDate.getTime()-(24*60*60*1000));
return returnDate;
}
If the return value is not working then check for the context parameter in web.xml.
eg.
<context-param>
<param-name>javax.faces.DATETIMECONVERTER_DEFAULT_TIMEZONE_IS_SYSTEM_TIMEZONE</param-name>
<param-value>true</param-value>
</context-param>
Don't try to make it hard just follow a simple way
date is a string where your date is saved
String s2=date.substring(0,date.length()-11);
now print the value of s2.
it will reduce your string length and you will get only date part.
Can't believe no one offered this shitty answer with all the rest of them. It's been deprecated for decades.
#SuppressWarnings("deprecation")
...
Date hitDate = new Date();
hitDate.setHours(0);
hitDate.setMinutes(0);
hitDate.setSeconds(0);