how to read line by line in android? - java

i am using this code.
try{
// Open the file that is the first
// command line parameter
FileInputStream fstream = new FileInputStream("config.txt");
// Get the object of DataInputStream
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
while ((br.readLine()) != null) {
temp1 = br.readLine();
temp2 = br.readLine();
}
in.close();
}catch (Exception e){//Catch exception if any
Toast.makeText(getBaseContext(), "Exception", Toast.LENGTH_LONG).show();
}
Toast.makeText(getBaseContext(), temp1+temp2, Toast.LENGTH_LONG).show();
but this is showing exception and is not updating temp1 and temp2.

The exception you see - that I would strongly recommend a) to catch as a specific type, e.g. IOException, and b) to log or show with a message or a stack trace, and c) at least to check for in LogCat, from the DDMS perspective if you are programming with Eclipse - is probably due to Android not finding the config.txt file you are trying to open. Usually, for the simplest cases such as yours, files that are private to an application are opened using openFileInput - see the documentation for details.
Apart from the exception, your reading loop is defective: you need to initialize an empty string before entering, and fill it in the while condition.
String line = "";
while ((line = br.readLine()) != null) {
// do something with the line you just read, e.g.
temp1 = line;
temp2 = line;
}
However, you don't need a loop if you just want to save the first two lines in different variables.
String line = "";
if ((line = br.readLine()) != null)
temp1 = line;
if ((line = br.readLine()) != null)
temp2 = line;
As others have already pointed out, calling readLine consumes a line, so if your config.txt file contains only one line your code consumes it on the while condition, then temp1 and temp2 get null assigned because there's no more text to read.

try{
// Open the file that is the first
// command line parameter
FileInputStream fstream = new FileInputStream("config.txt");
// Get the object of DataInputStream
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String line = "";
while ((line = br.readLine()) != null) {
temp1 = line;
temp2 = line;
}
in.close();
}catch (Exception e){//Catch exception if any
Toast.makeText(getBaseContext(), "Exception", Toast.LENGTH_LONG).show();
}
Toast.makeText(getBaseContext(), temp1+temp2, Toast.LENGTH_LONG).show();

br.readLine() in while already consumes a line.
Try this
LineNumberReader reader = new LineNumberReader(new FileReader("config.txt")));
String line;
while ((line = reader.readLine()) != null) {
//doProcessLine
}

if you want to save the first two lines you have to do:
try
{
// Open the file that is the first
// command line parameter
FileInputStream fstream = new FileInputStream("config.txt");
// Get the object of DataInputStream
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String line = "";
if((line = br.readLine()) != null)
temp1 = line;
if((line = br.readLine()) != null)
temp2 = line;
}
catch(Exception e)
{
e.printStackTrace();
}

Related

How to append multiple text in text file

I want the results from 'name' and 'code' to be inserted into log.txt file, but if I run this program only the name results gets inserted into .txt file, I cannot see code results appending under name. If I do System.outprintln(name) & System.outprintln(code) I get results printed in console but its not being inserted in a file.Can someone tell me what am I doing wrong?
Scanner sc = new Scanner(file, "UTF-8");
BufferedReader br = new BufferedReader(new FileReader(file));
PrintWriter out = new PrintWriter(new FileWriter("log.txt", true));
while ((line = br.readLine()) != null) {
if (line.contains("text1")) {
String[] splits = line.split("=");
String name = splits[2];
for (int i = 0; i < name.length(); i++) {
out.println(name);
}
}
if (line.contains("text2")) {
String[] splits = line.split("=");
String code = splits[2];
for (int i = 0; i < code.length(); i++) {
out.println(code);
}
}
out.close()
}
File looks like:
Name=111111111
Code=333,5555
Category-Warranty
Name=2222222
Code=111,22
Category-Warranty
Have a look at this code. Does that work for you?
final String NAME = "name";
final String CODE = "code";
BufferedReader br = new BufferedReader(new FileReader(file));
PrintWriter out = new PrintWriter(new FileWriter("log.txt", true));
while ((line = br.readLine()) != null) {
String[] splits = line.split("=");
String key = splits[0];
String value = splits[1];
if (key.equals(NAME) || key.equals(CODE)) {
out.println(value);
}
}
out.close();
You have a couple of problems in your code:
you never actually assign the variables name and code.
you close() your PrintWriter inside the while-loop, that means you will have a problem if you read more than one line.
I don't see why this wouldn't work, without seeing more of what you are doing:
BufferedReader br = new BufferedReader(new FileReader(file));
PrintWriter out = new PrintWriter(new FileWriter("log.txt", true));
while ((line = br.readLine()) != null) {
if (line.contains("=")) {
if (line.contains("text1")) {
String[] splits = line.split("=");
if (splits.length >= 2) {
out.println(splits[1]);
}
}
if (line.contains("text2")) {
String[] splits = line.split("=");
if (splits.length >= 2) {
out.println(splits[1]);
}
}
}
}
out.flush();
out.close();
Make sure the second if condition is satisfied i.e. the line String contains "text2".

BufferedReader to skip first line

I am using the following bufferedreader to read the lines of a file,
BufferedReader reader = new BufferedReader(new FileReader(somepath));
while ((line1 = reader.readLine()) != null)
{
//some code
}
Now, I want to skip reading the first line of the file and I don't want to use a counter line int lineno to keep a count of the lines.
How to do this?
You can try this
BufferedReader reader = new BufferedReader(new FileReader(somepath));
reader.readLine(); // this will read the first line
String line1=null;
while ((line1 = reader.readLine()) != null){ //loop will run from 2nd line
//some code
}
You can use the Stream skip() function, like this:
BufferedReader reader = new BufferedReader(new FileReader(somepath));
Stream<String> lines = reader.lines().skip(1);
lines.forEachOrdered(line -> {
...
});
File file = new File("path to file");
FileInputStream fis = new FileInputStream(file);
BufferedReader br = new BufferedReader(new InputStreamReader(fis));
String line = null;
int count = 0;
while((line = br.readLine()) != null) { // read through file line by line
if(count != 0) { // count == 0 means the first line
System.out.println("That's not the first line");
}
count++; // count increments as you read lines
}
br.close(); // do not forget to close the resources
Use a linenumberreader instead.
LineNumberReader reader = new LineNumberReader(new InputStreamReader(file.getInputStream()));
String line1;
while ((line1 = reader.readLine()) != null)
{
if(reader.getLineNumber()==1){
continue;
}
System.out.println(line1);
}
You can create a counter that contains the value of the starting line:
private final static START_LINE = 1;
BufferedReader reader = new BufferedReader(new FileReader(somepath));
int counter=START_LINE;
while ((line1 = reader.readLine()) != null) {
if(counter>START_LINE){
//your code here
}
counter++;
}
You can do it like this:
BufferedReader buf = new BufferedReader(new FileReader(fileName));
String line = null;
String[] wordsArray;
boolean skipFirstLine = true;
while(true){
line = buf.readLine();
if ( skipFirstLine){ // skip data header
skipFirstLine = false; continue;
}
if(line == null){
break;
}else{
wordsArray = line.split("\t");
}
buf.close();

PrintWriter object doesn't print all the lines in text document to out put file

public String getText()
{
ApplicationContext appContext = new ClassPathXmlApplicationContext(new String[]{"spring-config-server.xml"});
Resource resource = appContext.getResource("file:D:\\text\\test.txt");
StringBuilder builder = new StringBuilder();
try{
InputStream is = resource.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line;
PrintWriter out=null;
while ((line = br.readLine()) != null) {
//System.out.println(line);
out = new PrintWriter(new FileWriter("D:\\outputfile.txt"));
out.println(line);
//br.close();
}
out.close();
br.close();
}catch(IOException e){
e.printStackTrace();
}
return builder.toString();
}
Create PrintWriter instance out of your while loop.
Move it outside the loop.Due to which new instance is created every line
out = new PrintWriter(new FileWriter("D:\\outputfile.txt"));
You are creating new PrintWriters in the loop. Make it outside of it.
out = new PrintWriter(new FileWriter("D:\\outputfile.txt"));
while ((line = br.readLine()) != null) {
//System.out.println(line);
out.println(line);
//br.close();
}
The PrintWriter is being assigned to a new instance during each loop iteration. Declare the PrintWriter outside of the loop.
String line;
PrintWriter out= new PrintWriter(new FileWriter("D:\\outputfile.txt"));
while ((line = br.readLine()) != null) {
out.println(line);
}

Reading txt file contents and storing in array

I have been trying to read a txt file. The txt file contains lines e.g
First Line
Second Line
Third Line
.
.
.
Now I am using following code
InputStream is = null;
try {
is = getResources().getAssets().open("myFile.txt");
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
ArrayList<String> arrayOfLines = new ArrayList<String>();
Reader reader;
//char[] buffer = new char[2048];
try {
Reader = new BufferedReader(new InputStreamReader(is, "UTF-8"));
int n;
while ((n = reader.read()) != -1) {
}
}catch (Exception e) {
e.printStackTrace();
}
My question is, how can i store each line in the arrayList. Ofc We have to use a check for "/n" but how.
You could alternatively use the Scanner class.
Scanner in = new Scanner(new File("/path/to/file.txt"));
while(in.hasNextLine()) {
arrayOfLines.add(in.nextLine());
}
You don't have to worry about \n, since Scanner.nextLine() will skip the newline.
This code should work.
ArrayList<String> arrayOfLines = new ArrayList<String>();
FileInputStream fstream = new FileInputStream("myfile.txt");
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strLine;
while ((strLine = br.readLine()) != null) {
arrayOfLines.add(strLine);
}
This:
int n;
while ((n = reader.read()) != -1) {
}
Should probably look more like this:
String line = reader.readLine();
while (line!=null) {
arrayOfLines.add(line);
line = reader.readLine();
}
Since you are using a BufferedReader, you should be calling readLine() instead of reading into a char buffer. The Reader declaration also needs to be BufferedReader.

Make FileReader read every fourth line with a loop

My problems is that I have to arrange, when searching for a customer, arrange the while loop to only examine every fourth line read.
This is the code I already have on this problem:
BufferedReader br = new BufferedReader(new FileReader("Customers.txt"));
String line;
while ((line = br.readLine()) != null)
{
...
}
br.close();
Does anybody know what needs to be at the place of "..."?
Thanks!
Something along the lines of
int i = 0;
while ((line = br.readLine()) != null)
{
i++;
if (i % 4 == 0)
{
// if i is divisible by 4, then
// your actual code will get executed
...
}
}
Just call br.readLine() 3 times at the end of the loop, discarding the output:
BufferedReader br = new BufferedReader(new FileReader("Customers.txt"));
String line;
while ((line = br.readLine()) != null)
{
...
for(int i=0;i<3;i++){ br.readLine(); }
}
br.close();
BufferedReader br = new BufferedReader(new FileReader("Customers.txt"));
String line;
int count 0;
while ((line = br.readLine()) != null)
{
if (count!=3)
count++;
else {
// Do something?
count=0;
}
}
br.close();

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