Find whole words without regex - java

I need to find whole words in a sentence, but without using regular expressions. So if I wanted to find the word "the" in this sentence: "The quick brown fox jumps over the lazy dog", I'm currently using:
String text = "the, quick brown fox jumps over the lazy dog";
String keyword = "the";
Matcher matcher = Pattern.compile("\\b"+keyword+"\\b").matcher(text);
Boolean contains = matcher.find();
but if I used:
Boolean contains = text.contains(keyword);
and pad the keyword with a space, it won't find the first "the" in the sentence, both because it doesn't have surround whitespaces and the punctuations.
To be clear, I'm building an Android app, and I'm getting memory leaks and it might be because I'm using a regular-expression in a ListView, so it's performing a regular-expression match X number of times, depending on the items in the Listview.

If you needed to check for multiple words and do it without regular expressions you could use StringTokenizer with a space as the delimiter.
You could then build a custom search method. Otherwise, the other solutions using String.contains() or String.indexOf() qualify.

What you do is search for "the". Then for each match you test to see if the surrounding characters are white space (or punctuation), or if the match is at the beginning / end of the string respectively.

public int findWholeWorld(final String text, final String searchString) {
return (" " + text + " ").indexOf(" " + searchString + " ");
}
This will give you the index of the first occurrence of the word "the" or -1 if the word "the" doesn't exist.

Split the string on space, and then see if the resulting array contains your word.

Simply iterate over the characters and keep storing them in a char buffer. Every time you see a whitespace, empty the buffer into a list of words and go on till you reach the end.

In the comments of the StringTokenizer.class:
StringTokenizer is a legacy class that is retained for
compatibility reasons although its use is discouraged in new code. It is
recommended that anyone seeking this functionality use the split
method of String or the java.util.regex package instead.
The following example illustrates how the String.split
method can be used to break up a string into its basic tokens:
String[] result = "this is a test".split("\\s");
for (int x=0; x<result.length; x++)
System.out.println(result[x]);
prints the following output:
this
is
a
test
Iterate through your resulting string array and test for equality and keep a count.
for (String s : result)
{
count++;
}
If this is a homework assignment, tell your lecturer to read up on Java, times have changed. I remember having the exact same stupid questions during school and it does nothing to prepare you for the real world.

I have a project that requires whole word matching, but I can't use regular expressions(because regular expressions escape some keywords), I tried to write my own code to simulate it with non-regular expressions (\bxxx\b), I only know C# and it worked fine.
public static class Finder
{
public static bool Find(string? input, string? pattern, bool isMatchCase = false, bool isMatchWholeWord = false, bool isMatchRegex = false)
{
if (String.IsNullOrWhiteSpace(input) || String.IsNullOrWhiteSpace(pattern))
{
return false;
}
if (!isMatchCase && !isMatchRegex)
{
input = input.ToLower();
pattern = pattern.ToLower();
}
if (isMatchWholeWord && !isMatchRegex)
{
int len = pattern.Length;
int suffix = 0;
while (true)
{
int start = input.IndexOf(pattern, suffix);
if (start == -1)
{
return false;
}
int end = start + len - 1;
int prefix = start - 1;
suffix = end + 1;
bool isPrefixMatched, isSuffixMatched;
if (start == 0)
{
isPrefixMatched = true;
}
else
{
isPrefixMatched = IsWord(input[prefix]) != IsWord(input[start]);
}
if (end == input.Length - 1)
{
isSuffixMatched = true;
}
else
{
isSuffixMatched = IsWord(input[suffix]) != IsWord(input[end]);
}
if (isPrefixMatched && isSuffixMatched)
{
return true;
}
}
}
if (isMatchRegex)
{
if (isMatchWholeWord)
{
if (!pattern.StartsWith(#"\b"))
{
pattern = $#"\b{pattern}";
}
if (!pattern.EndsWith(#"\b"))
{
pattern = $#"{pattern}\b";
}
}
return Regex.IsMatch(input, pattern, isMatchCase ? RegexOptions.None : RegexOptions.IgnoreCase);
}
return input.Contains(pattern);
}
private static bool IsWord(char ch)
{
return Char.IsLetterOrDigit(ch) || ch == '_';
}
}

Related

Split with delimiter and ignore delimiter and quote character which is part of data [duplicate]

I have a string vaguely like this:
foo,bar,c;qual="baz,blurb",d;junk="quux,syzygy"
that I want to split by commas -- but I need to ignore commas in quotes. How can I do this? Seems like a regexp approach fails; I suppose I can manually scan and enter a different mode when I see a quote, but it would be nice to use preexisting libraries. (edit: I guess I meant libraries that are already part of the JDK or already part of a commonly-used libraries like Apache Commons.)
the above string should split into:
foo
bar
c;qual="baz,blurb"
d;junk="quux,syzygy"
note: this is NOT a CSV file, it's a single string contained in a file with a larger overall structure
Try:
public class Main {
public static void main(String[] args) {
String line = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String[] tokens = line.split(",(?=(?:[^\"]*\"[^\"]*\")*[^\"]*$)", -1);
for(String t : tokens) {
System.out.println("> "+t);
}
}
}
Output:
> foo
> bar
> c;qual="baz,blurb"
> d;junk="quux,syzygy"
In other words: split on the comma only if that comma has zero, or an even number of quotes ahead of it.
Or, a bit friendlier for the eyes:
public class Main {
public static void main(String[] args) {
String line = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String otherThanQuote = " [^\"] ";
String quotedString = String.format(" \" %s* \" ", otherThanQuote);
String regex = String.format("(?x) "+ // enable comments, ignore white spaces
", "+ // match a comma
"(?= "+ // start positive look ahead
" (?: "+ // start non-capturing group 1
" %s* "+ // match 'otherThanQuote' zero or more times
" %s "+ // match 'quotedString'
" )* "+ // end group 1 and repeat it zero or more times
" %s* "+ // match 'otherThanQuote'
" $ "+ // match the end of the string
") ", // stop positive look ahead
otherThanQuote, quotedString, otherThanQuote);
String[] tokens = line.split(regex, -1);
for(String t : tokens) {
System.out.println("> "+t);
}
}
}
which produces the same as the first example.
EDIT
As mentioned by #MikeFHay in the comments:
I prefer using Guava's Splitter, as it has saner defaults (see discussion above about empty matches being trimmed by String#split(), so I did:
Splitter.on(Pattern.compile(",(?=(?:[^\"]*\"[^\"]*\")*[^\"]*$)"))
While I do like regular expressions in general, for this kind of state-dependent tokenization I believe a simple parser (which in this case is much simpler than that word might make it sound) is probably a cleaner solution, in particular with regards to maintainability, e.g.:
String input = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
List<String> result = new ArrayList<String>();
int start = 0;
boolean inQuotes = false;
for (int current = 0; current < input.length(); current++) {
if (input.charAt(current) == '\"') inQuotes = !inQuotes; // toggle state
else if (input.charAt(current) == ',' && !inQuotes) {
result.add(input.substring(start, current));
start = current + 1;
}
}
result.add(input.substring(start));
If you don't care about preserving the commas inside the quotes you could simplify this approach (no handling of start index, no last character special case) by replacing your commas in quotes by something else and then split at commas:
String input = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
StringBuilder builder = new StringBuilder(input);
boolean inQuotes = false;
for (int currentIndex = 0; currentIndex < builder.length(); currentIndex++) {
char currentChar = builder.charAt(currentIndex);
if (currentChar == '\"') inQuotes = !inQuotes; // toggle state
if (currentChar == ',' && inQuotes) {
builder.setCharAt(currentIndex, ';'); // or '♡', and replace later
}
}
List<String> result = Arrays.asList(builder.toString().split(","));
http://sourceforge.net/projects/javacsv/
https://github.com/pupi1985/JavaCSV-Reloaded
(fork of the previous library that will allow the generated output to have Windows line terminators \r\n when not running Windows)
http://opencsv.sourceforge.net/
CSV API for Java
Can you recommend a Java library for reading (and possibly writing) CSV files?
Java lib or app to convert CSV to XML file?
I would not advise a regex answer from Bart, I find parsing solution better in this particular case (as Fabian proposed). I've tried regex solution and own parsing implementation I have found that:
Parsing is much faster than splitting with regex with backreferences - ~20 times faster for short strings, ~40 times faster for long strings.
Regex fails to find empty string after last comma. That was not in original question though, it was mine requirement.
My solution and test below.
String tested = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\",";
long start = System.nanoTime();
String[] tokens = tested.split(",(?=([^\"]*\"[^\"]*\")*[^\"]*$)");
long timeWithSplitting = System.nanoTime() - start;
start = System.nanoTime();
List<String> tokensList = new ArrayList<String>();
boolean inQuotes = false;
StringBuilder b = new StringBuilder();
for (char c : tested.toCharArray()) {
switch (c) {
case ',':
if (inQuotes) {
b.append(c);
} else {
tokensList.add(b.toString());
b = new StringBuilder();
}
break;
case '\"':
inQuotes = !inQuotes;
default:
b.append(c);
break;
}
}
tokensList.add(b.toString());
long timeWithParsing = System.nanoTime() - start;
System.out.println(Arrays.toString(tokens));
System.out.println(tokensList.toString());
System.out.printf("Time with splitting:\t%10d\n",timeWithSplitting);
System.out.printf("Time with parsing:\t%10d\n",timeWithParsing);
Of course you are free to change switch to else-ifs in this snippet if you feel uncomfortable with its ugliness. Note then lack of break after switch with separator. StringBuilder was chosen instead to StringBuffer by design to increase speed, where thread safety is irrelevant.
You're in that annoying boundary area where regexps almost won't do (as has been pointed out by Bart, escaping the quotes would make life hard) , and yet a full-blown parser seems like overkill.
If you are likely to need greater complexity any time soon I would go looking for a parser library. For example this one
I was impatient and chose not to wait for answers... for reference it doesn't look that hard to do something like this (which works for my application, I don't need to worry about escaped quotes, as the stuff in quotes is limited to a few constrained forms):
final static private Pattern splitSearchPattern = Pattern.compile("[\",]");
private List<String> splitByCommasNotInQuotes(String s) {
if (s == null)
return Collections.emptyList();
List<String> list = new ArrayList<String>();
Matcher m = splitSearchPattern.matcher(s);
int pos = 0;
boolean quoteMode = false;
while (m.find())
{
String sep = m.group();
if ("\"".equals(sep))
{
quoteMode = !quoteMode;
}
else if (!quoteMode && ",".equals(sep))
{
int toPos = m.start();
list.add(s.substring(pos, toPos));
pos = m.end();
}
}
if (pos < s.length())
list.add(s.substring(pos));
return list;
}
(exercise for the reader: extend to handling escaped quotes by looking for backslashes also.)
Try a lookaround like (?!\"),(?!\"). This should match , that are not surrounded by ".
The simplest approach is not to match delimiters, i.e. commas, with a complex additional logic to match what is actually intended (the data which might be quoted strings), just to exclude false delimiters, but rather match the intended data in the first place.
The pattern consists of two alternatives, a quoted string ("[^"]*" or ".*?") or everything up to the next comma ([^,]+). To support empty cells, we have to allow the unquoted item to be empty and to consume the next comma, if any, and use the \\G anchor:
Pattern p = Pattern.compile("\\G\"(.*?)\",?|([^,]*),?");
The pattern also contains two capturing groups to get either, the quoted string’s content or the plain content.
Then, with Java 9, we can get an array as
String[] a = p.matcher(input).results()
.map(m -> m.group(m.start(1)<0? 2: 1))
.toArray(String[]::new);
whereas older Java versions need a loop like
for(Matcher m = p.matcher(input); m.find(); ) {
String token = m.group(m.start(1)<0? 2: 1);
System.out.println("found: "+token);
}
Adding the items to a List or an array is left as an excise to the reader.
For Java 8, you can use the results() implementation of this answer, to do it like the Java 9 solution.
For mixed content with embedded strings, like in the question, you can simply use
Pattern p = Pattern.compile("\\G((\"(.*?)\"|[^,])*),?");
But then, the strings are kept in their quoted form.
what about a one-liner using String.split()?
String s = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String[] split = s.split( "(?<!\".{0,255}[^\"]),|,(?![^\"].*\")" );
A regular expression is not capable of handling escaped characters. For my application, I needed the ability to escape quotes and spaces (my separator is spaces, but the code is the same).
Here is my solution in Kotlin (the language from this particular application), based on the one from Fabian Steeg:
fun parseString(input: String): List<String> {
val result = mutableListOf<String>()
var inQuotes = false
var inEscape = false
val current = StringBuilder()
for (i in input.indices) {
// If this character is escaped, add it without looking
if (inEscape) {
inEscape = false
current.append(input[i])
continue
}
when (val c = input[i]) {
'\\' -> inEscape = true // escape the next character, \ isn't added to result
',' -> if (inQuotes) {
current.append(c)
} else {
result += current.toString()
current.clear()
}
'"' -> inQuotes = !inQuotes
else -> current.append(c)
}
}
if (current.isNotEmpty()) {
result += current.toString()
}
return result
}
I think this is not a place to use regular expressions. Contrary to other opinions, I don't think a parser is overkill. It's about 20 lines and fairly easy to test.
Rather than use lookahead and other crazy regex, just pull out the quotes first. That is, for every quote grouping, replace that grouping with __IDENTIFIER_1 or some other indicator, and map that grouping to a map of string,string.
After you split on comma, replace all mapped identifiers with the original string values.
I would do something like this:
boolean foundQuote = false;
if(charAtIndex(currentStringIndex) == '"')
{
foundQuote = true;
}
if(foundQuote == true)
{
//do nothing
}
else
{
string[] split = currentString.split(',');
}

How to split emails which are seperated by comma(,) containing special characters in sender name? [duplicate]

I have a string vaguely like this:
foo,bar,c;qual="baz,blurb",d;junk="quux,syzygy"
that I want to split by commas -- but I need to ignore commas in quotes. How can I do this? Seems like a regexp approach fails; I suppose I can manually scan and enter a different mode when I see a quote, but it would be nice to use preexisting libraries. (edit: I guess I meant libraries that are already part of the JDK or already part of a commonly-used libraries like Apache Commons.)
the above string should split into:
foo
bar
c;qual="baz,blurb"
d;junk="quux,syzygy"
note: this is NOT a CSV file, it's a single string contained in a file with a larger overall structure
Try:
public class Main {
public static void main(String[] args) {
String line = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String[] tokens = line.split(",(?=(?:[^\"]*\"[^\"]*\")*[^\"]*$)", -1);
for(String t : tokens) {
System.out.println("> "+t);
}
}
}
Output:
> foo
> bar
> c;qual="baz,blurb"
> d;junk="quux,syzygy"
In other words: split on the comma only if that comma has zero, or an even number of quotes ahead of it.
Or, a bit friendlier for the eyes:
public class Main {
public static void main(String[] args) {
String line = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String otherThanQuote = " [^\"] ";
String quotedString = String.format(" \" %s* \" ", otherThanQuote);
String regex = String.format("(?x) "+ // enable comments, ignore white spaces
", "+ // match a comma
"(?= "+ // start positive look ahead
" (?: "+ // start non-capturing group 1
" %s* "+ // match 'otherThanQuote' zero or more times
" %s "+ // match 'quotedString'
" )* "+ // end group 1 and repeat it zero or more times
" %s* "+ // match 'otherThanQuote'
" $ "+ // match the end of the string
") ", // stop positive look ahead
otherThanQuote, quotedString, otherThanQuote);
String[] tokens = line.split(regex, -1);
for(String t : tokens) {
System.out.println("> "+t);
}
}
}
which produces the same as the first example.
EDIT
As mentioned by #MikeFHay in the comments:
I prefer using Guava's Splitter, as it has saner defaults (see discussion above about empty matches being trimmed by String#split(), so I did:
Splitter.on(Pattern.compile(",(?=(?:[^\"]*\"[^\"]*\")*[^\"]*$)"))
While I do like regular expressions in general, for this kind of state-dependent tokenization I believe a simple parser (which in this case is much simpler than that word might make it sound) is probably a cleaner solution, in particular with regards to maintainability, e.g.:
String input = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
List<String> result = new ArrayList<String>();
int start = 0;
boolean inQuotes = false;
for (int current = 0; current < input.length(); current++) {
if (input.charAt(current) == '\"') inQuotes = !inQuotes; // toggle state
else if (input.charAt(current) == ',' && !inQuotes) {
result.add(input.substring(start, current));
start = current + 1;
}
}
result.add(input.substring(start));
If you don't care about preserving the commas inside the quotes you could simplify this approach (no handling of start index, no last character special case) by replacing your commas in quotes by something else and then split at commas:
String input = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
StringBuilder builder = new StringBuilder(input);
boolean inQuotes = false;
for (int currentIndex = 0; currentIndex < builder.length(); currentIndex++) {
char currentChar = builder.charAt(currentIndex);
if (currentChar == '\"') inQuotes = !inQuotes; // toggle state
if (currentChar == ',' && inQuotes) {
builder.setCharAt(currentIndex, ';'); // or '♡', and replace later
}
}
List<String> result = Arrays.asList(builder.toString().split(","));
http://sourceforge.net/projects/javacsv/
https://github.com/pupi1985/JavaCSV-Reloaded
(fork of the previous library that will allow the generated output to have Windows line terminators \r\n when not running Windows)
http://opencsv.sourceforge.net/
CSV API for Java
Can you recommend a Java library for reading (and possibly writing) CSV files?
Java lib or app to convert CSV to XML file?
I would not advise a regex answer from Bart, I find parsing solution better in this particular case (as Fabian proposed). I've tried regex solution and own parsing implementation I have found that:
Parsing is much faster than splitting with regex with backreferences - ~20 times faster for short strings, ~40 times faster for long strings.
Regex fails to find empty string after last comma. That was not in original question though, it was mine requirement.
My solution and test below.
String tested = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\",";
long start = System.nanoTime();
String[] tokens = tested.split(",(?=([^\"]*\"[^\"]*\")*[^\"]*$)");
long timeWithSplitting = System.nanoTime() - start;
start = System.nanoTime();
List<String> tokensList = new ArrayList<String>();
boolean inQuotes = false;
StringBuilder b = new StringBuilder();
for (char c : tested.toCharArray()) {
switch (c) {
case ',':
if (inQuotes) {
b.append(c);
} else {
tokensList.add(b.toString());
b = new StringBuilder();
}
break;
case '\"':
inQuotes = !inQuotes;
default:
b.append(c);
break;
}
}
tokensList.add(b.toString());
long timeWithParsing = System.nanoTime() - start;
System.out.println(Arrays.toString(tokens));
System.out.println(tokensList.toString());
System.out.printf("Time with splitting:\t%10d\n",timeWithSplitting);
System.out.printf("Time with parsing:\t%10d\n",timeWithParsing);
Of course you are free to change switch to else-ifs in this snippet if you feel uncomfortable with its ugliness. Note then lack of break after switch with separator. StringBuilder was chosen instead to StringBuffer by design to increase speed, where thread safety is irrelevant.
You're in that annoying boundary area where regexps almost won't do (as has been pointed out by Bart, escaping the quotes would make life hard) , and yet a full-blown parser seems like overkill.
If you are likely to need greater complexity any time soon I would go looking for a parser library. For example this one
I was impatient and chose not to wait for answers... for reference it doesn't look that hard to do something like this (which works for my application, I don't need to worry about escaped quotes, as the stuff in quotes is limited to a few constrained forms):
final static private Pattern splitSearchPattern = Pattern.compile("[\",]");
private List<String> splitByCommasNotInQuotes(String s) {
if (s == null)
return Collections.emptyList();
List<String> list = new ArrayList<String>();
Matcher m = splitSearchPattern.matcher(s);
int pos = 0;
boolean quoteMode = false;
while (m.find())
{
String sep = m.group();
if ("\"".equals(sep))
{
quoteMode = !quoteMode;
}
else if (!quoteMode && ",".equals(sep))
{
int toPos = m.start();
list.add(s.substring(pos, toPos));
pos = m.end();
}
}
if (pos < s.length())
list.add(s.substring(pos));
return list;
}
(exercise for the reader: extend to handling escaped quotes by looking for backslashes also.)
Try a lookaround like (?!\"),(?!\"). This should match , that are not surrounded by ".
The simplest approach is not to match delimiters, i.e. commas, with a complex additional logic to match what is actually intended (the data which might be quoted strings), just to exclude false delimiters, but rather match the intended data in the first place.
The pattern consists of two alternatives, a quoted string ("[^"]*" or ".*?") or everything up to the next comma ([^,]+). To support empty cells, we have to allow the unquoted item to be empty and to consume the next comma, if any, and use the \\G anchor:
Pattern p = Pattern.compile("\\G\"(.*?)\",?|([^,]*),?");
The pattern also contains two capturing groups to get either, the quoted string’s content or the plain content.
Then, with Java 9, we can get an array as
String[] a = p.matcher(input).results()
.map(m -> m.group(m.start(1)<0? 2: 1))
.toArray(String[]::new);
whereas older Java versions need a loop like
for(Matcher m = p.matcher(input); m.find(); ) {
String token = m.group(m.start(1)<0? 2: 1);
System.out.println("found: "+token);
}
Adding the items to a List or an array is left as an excise to the reader.
For Java 8, you can use the results() implementation of this answer, to do it like the Java 9 solution.
For mixed content with embedded strings, like in the question, you can simply use
Pattern p = Pattern.compile("\\G((\"(.*?)\"|[^,])*),?");
But then, the strings are kept in their quoted form.
what about a one-liner using String.split()?
String s = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String[] split = s.split( "(?<!\".{0,255}[^\"]),|,(?![^\"].*\")" );
A regular expression is not capable of handling escaped characters. For my application, I needed the ability to escape quotes and spaces (my separator is spaces, but the code is the same).
Here is my solution in Kotlin (the language from this particular application), based on the one from Fabian Steeg:
fun parseString(input: String): List<String> {
val result = mutableListOf<String>()
var inQuotes = false
var inEscape = false
val current = StringBuilder()
for (i in input.indices) {
// If this character is escaped, add it without looking
if (inEscape) {
inEscape = false
current.append(input[i])
continue
}
when (val c = input[i]) {
'\\' -> inEscape = true // escape the next character, \ isn't added to result
',' -> if (inQuotes) {
current.append(c)
} else {
result += current.toString()
current.clear()
}
'"' -> inQuotes = !inQuotes
else -> current.append(c)
}
}
if (current.isNotEmpty()) {
result += current.toString()
}
return result
}
I think this is not a place to use regular expressions. Contrary to other opinions, I don't think a parser is overkill. It's about 20 lines and fairly easy to test.
Rather than use lookahead and other crazy regex, just pull out the quotes first. That is, for every quote grouping, replace that grouping with __IDENTIFIER_1 or some other indicator, and map that grouping to a map of string,string.
After you split on comma, replace all mapped identifiers with the original string values.
I would do something like this:
boolean foundQuote = false;
if(charAtIndex(currentStringIndex) == '"')
{
foundQuote = true;
}
if(foundQuote == true)
{
//do nothing
}
else
{
string[] split = currentString.split(',');
}

Split a string by commas except when the comma is part of the sentence [duplicate]

I have a string vaguely like this:
foo,bar,c;qual="baz,blurb",d;junk="quux,syzygy"
that I want to split by commas -- but I need to ignore commas in quotes. How can I do this? Seems like a regexp approach fails; I suppose I can manually scan and enter a different mode when I see a quote, but it would be nice to use preexisting libraries. (edit: I guess I meant libraries that are already part of the JDK or already part of a commonly-used libraries like Apache Commons.)
the above string should split into:
foo
bar
c;qual="baz,blurb"
d;junk="quux,syzygy"
note: this is NOT a CSV file, it's a single string contained in a file with a larger overall structure
Try:
public class Main {
public static void main(String[] args) {
String line = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String[] tokens = line.split(",(?=(?:[^\"]*\"[^\"]*\")*[^\"]*$)", -1);
for(String t : tokens) {
System.out.println("> "+t);
}
}
}
Output:
> foo
> bar
> c;qual="baz,blurb"
> d;junk="quux,syzygy"
In other words: split on the comma only if that comma has zero, or an even number of quotes ahead of it.
Or, a bit friendlier for the eyes:
public class Main {
public static void main(String[] args) {
String line = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String otherThanQuote = " [^\"] ";
String quotedString = String.format(" \" %s* \" ", otherThanQuote);
String regex = String.format("(?x) "+ // enable comments, ignore white spaces
", "+ // match a comma
"(?= "+ // start positive look ahead
" (?: "+ // start non-capturing group 1
" %s* "+ // match 'otherThanQuote' zero or more times
" %s "+ // match 'quotedString'
" )* "+ // end group 1 and repeat it zero or more times
" %s* "+ // match 'otherThanQuote'
" $ "+ // match the end of the string
") ", // stop positive look ahead
otherThanQuote, quotedString, otherThanQuote);
String[] tokens = line.split(regex, -1);
for(String t : tokens) {
System.out.println("> "+t);
}
}
}
which produces the same as the first example.
EDIT
As mentioned by #MikeFHay in the comments:
I prefer using Guava's Splitter, as it has saner defaults (see discussion above about empty matches being trimmed by String#split(), so I did:
Splitter.on(Pattern.compile(",(?=(?:[^\"]*\"[^\"]*\")*[^\"]*$)"))
While I do like regular expressions in general, for this kind of state-dependent tokenization I believe a simple parser (which in this case is much simpler than that word might make it sound) is probably a cleaner solution, in particular with regards to maintainability, e.g.:
String input = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
List<String> result = new ArrayList<String>();
int start = 0;
boolean inQuotes = false;
for (int current = 0; current < input.length(); current++) {
if (input.charAt(current) == '\"') inQuotes = !inQuotes; // toggle state
else if (input.charAt(current) == ',' && !inQuotes) {
result.add(input.substring(start, current));
start = current + 1;
}
}
result.add(input.substring(start));
If you don't care about preserving the commas inside the quotes you could simplify this approach (no handling of start index, no last character special case) by replacing your commas in quotes by something else and then split at commas:
String input = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
StringBuilder builder = new StringBuilder(input);
boolean inQuotes = false;
for (int currentIndex = 0; currentIndex < builder.length(); currentIndex++) {
char currentChar = builder.charAt(currentIndex);
if (currentChar == '\"') inQuotes = !inQuotes; // toggle state
if (currentChar == ',' && inQuotes) {
builder.setCharAt(currentIndex, ';'); // or '♡', and replace later
}
}
List<String> result = Arrays.asList(builder.toString().split(","));
http://sourceforge.net/projects/javacsv/
https://github.com/pupi1985/JavaCSV-Reloaded
(fork of the previous library that will allow the generated output to have Windows line terminators \r\n when not running Windows)
http://opencsv.sourceforge.net/
CSV API for Java
Can you recommend a Java library for reading (and possibly writing) CSV files?
Java lib or app to convert CSV to XML file?
I would not advise a regex answer from Bart, I find parsing solution better in this particular case (as Fabian proposed). I've tried regex solution and own parsing implementation I have found that:
Parsing is much faster than splitting with regex with backreferences - ~20 times faster for short strings, ~40 times faster for long strings.
Regex fails to find empty string after last comma. That was not in original question though, it was mine requirement.
My solution and test below.
String tested = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\",";
long start = System.nanoTime();
String[] tokens = tested.split(",(?=([^\"]*\"[^\"]*\")*[^\"]*$)");
long timeWithSplitting = System.nanoTime() - start;
start = System.nanoTime();
List<String> tokensList = new ArrayList<String>();
boolean inQuotes = false;
StringBuilder b = new StringBuilder();
for (char c : tested.toCharArray()) {
switch (c) {
case ',':
if (inQuotes) {
b.append(c);
} else {
tokensList.add(b.toString());
b = new StringBuilder();
}
break;
case '\"':
inQuotes = !inQuotes;
default:
b.append(c);
break;
}
}
tokensList.add(b.toString());
long timeWithParsing = System.nanoTime() - start;
System.out.println(Arrays.toString(tokens));
System.out.println(tokensList.toString());
System.out.printf("Time with splitting:\t%10d\n",timeWithSplitting);
System.out.printf("Time with parsing:\t%10d\n",timeWithParsing);
Of course you are free to change switch to else-ifs in this snippet if you feel uncomfortable with its ugliness. Note then lack of break after switch with separator. StringBuilder was chosen instead to StringBuffer by design to increase speed, where thread safety is irrelevant.
You're in that annoying boundary area where regexps almost won't do (as has been pointed out by Bart, escaping the quotes would make life hard) , and yet a full-blown parser seems like overkill.
If you are likely to need greater complexity any time soon I would go looking for a parser library. For example this one
I was impatient and chose not to wait for answers... for reference it doesn't look that hard to do something like this (which works for my application, I don't need to worry about escaped quotes, as the stuff in quotes is limited to a few constrained forms):
final static private Pattern splitSearchPattern = Pattern.compile("[\",]");
private List<String> splitByCommasNotInQuotes(String s) {
if (s == null)
return Collections.emptyList();
List<String> list = new ArrayList<String>();
Matcher m = splitSearchPattern.matcher(s);
int pos = 0;
boolean quoteMode = false;
while (m.find())
{
String sep = m.group();
if ("\"".equals(sep))
{
quoteMode = !quoteMode;
}
else if (!quoteMode && ",".equals(sep))
{
int toPos = m.start();
list.add(s.substring(pos, toPos));
pos = m.end();
}
}
if (pos < s.length())
list.add(s.substring(pos));
return list;
}
(exercise for the reader: extend to handling escaped quotes by looking for backslashes also.)
Try a lookaround like (?!\"),(?!\"). This should match , that are not surrounded by ".
The simplest approach is not to match delimiters, i.e. commas, with a complex additional logic to match what is actually intended (the data which might be quoted strings), just to exclude false delimiters, but rather match the intended data in the first place.
The pattern consists of two alternatives, a quoted string ("[^"]*" or ".*?") or everything up to the next comma ([^,]+). To support empty cells, we have to allow the unquoted item to be empty and to consume the next comma, if any, and use the \\G anchor:
Pattern p = Pattern.compile("\\G\"(.*?)\",?|([^,]*),?");
The pattern also contains two capturing groups to get either, the quoted string’s content or the plain content.
Then, with Java 9, we can get an array as
String[] a = p.matcher(input).results()
.map(m -> m.group(m.start(1)<0? 2: 1))
.toArray(String[]::new);
whereas older Java versions need a loop like
for(Matcher m = p.matcher(input); m.find(); ) {
String token = m.group(m.start(1)<0? 2: 1);
System.out.println("found: "+token);
}
Adding the items to a List or an array is left as an excise to the reader.
For Java 8, you can use the results() implementation of this answer, to do it like the Java 9 solution.
For mixed content with embedded strings, like in the question, you can simply use
Pattern p = Pattern.compile("\\G((\"(.*?)\"|[^,])*),?");
But then, the strings are kept in their quoted form.
what about a one-liner using String.split()?
String s = "foo,bar,c;qual=\"baz,blurb\",d;junk=\"quux,syzygy\"";
String[] split = s.split( "(?<!\".{0,255}[^\"]),|,(?![^\"].*\")" );
A regular expression is not capable of handling escaped characters. For my application, I needed the ability to escape quotes and spaces (my separator is spaces, but the code is the same).
Here is my solution in Kotlin (the language from this particular application), based on the one from Fabian Steeg:
fun parseString(input: String): List<String> {
val result = mutableListOf<String>()
var inQuotes = false
var inEscape = false
val current = StringBuilder()
for (i in input.indices) {
// If this character is escaped, add it without looking
if (inEscape) {
inEscape = false
current.append(input[i])
continue
}
when (val c = input[i]) {
'\\' -> inEscape = true // escape the next character, \ isn't added to result
',' -> if (inQuotes) {
current.append(c)
} else {
result += current.toString()
current.clear()
}
'"' -> inQuotes = !inQuotes
else -> current.append(c)
}
}
if (current.isNotEmpty()) {
result += current.toString()
}
return result
}
I think this is not a place to use regular expressions. Contrary to other opinions, I don't think a parser is overkill. It's about 20 lines and fairly easy to test.
Rather than use lookahead and other crazy regex, just pull out the quotes first. That is, for every quote grouping, replace that grouping with __IDENTIFIER_1 or some other indicator, and map that grouping to a map of string,string.
After you split on comma, replace all mapped identifiers with the original string values.
I would do something like this:
boolean foundQuote = false;
if(charAtIndex(currentStringIndex) == '"')
{
foundQuote = true;
}
if(foundQuote == true)
{
//do nothing
}
else
{
string[] split = currentString.split(',');
}

How to calculate syllables in text with regex and Java

I have text as a String and need to calculate number of syllables in each word. I've tried to split all text into array of words and than processed each word separately. I used regular expressions for that. But pattern for syllables doesn't work as it should. Please advice how to change it to calculate correct number of syllables. My initial code.
public int getNumSyllables()
{
String[] words = getText().toLowerCase().split("[a-zA-Z]+");
int count=0;
List <String> tokens = new ArrayList<String>();
for(String word: words){
tokens = Arrays.asList(word.split("[bcdfghjklmnpqrstvwxyz]*[aeiou]+[bcdfghjklmnpqrstvwxyz]*"));
count+= tokens.size();
}
return count;
}
This question is from a Java Course of UCSD, am I right?
I think you should provide enough information for this question, so that it won't confused people who want to offer some help. And here I have my own solution, which already been tested by the test case from the local program, also the OJ from UCSD.
You missed some important information about the definition of syllable in this question. Actually I think the key point of this problem is how should you deal with the e. For example, let's say there is a combination of te. And if you put te in the middle of a word, of course it should be counted as a syllable; However if it's at the end of a word, the e should be thought as a silent e in English, so it should not be thought as a syllable.
That's it. And I would like to write down my thought with some pseudo code:
if(last character is e) {
if(it is silent e at the end of this word) {
remove the silent e;
count the rest part as regular;
} else {
count++;
} else {
count it as regular;
}
}
You may find that I am not only using regex to deal with this problem. Actually I have thought about it: can this question really be done only using regex? My answer is: nope, I don't think so. At least now, with the knowledge UCSD gives us, it's too difficult to do that. Regex is a powerful tool, it can map the desired characters very fast. However regex is missing some functionality. Take the te as example again, regex won't be able to think twice when it is facing the word like teate (I made up this word just for example). If our regex pattern would count the first te as syllable, then why the last te not?
Meanwhile, UCSD actually have talked about it on the assignment paper:
If you find yourself doing mental gymnastics to come up with a single regex to count syllables directly, that's usually an indication that there's a simpler solution (hint: consider a loop over characters--see the next hint below). Just because a piece of code (e.g. a regex) is shorter does not mean it is always better.
The hint here is that, you should think this problem together with some loop, combining with regex.
OK, I should finally show my code now:
protected int countSyllables(String word)
{
// TODO: Implement this method so that you can call it from the
// getNumSyllables method in BasicDocument (module 1) and
// EfficientDocument (module 2).
int count = 0;
word = word.toLowerCase();
if (word.charAt(word.length()-1) == 'e') {
if (silente(word)){
String newword = word.substring(0, word.length()-1);
count = count + countit(newword);
} else {
count++;
}
} else {
count = count + countit(word);
}
return count;
}
private int countit(String word) {
int count = 0;
Pattern splitter = Pattern.compile("[^aeiouy]*[aeiouy]+");
Matcher m = splitter.matcher(word);
while (m.find()) {
count++;
}
return count;
}
private boolean silente(String word) {
word = word.substring(0, word.length()-1);
Pattern yup = Pattern.compile("[aeiouy]");
Matcher m = yup.matcher(word);
if (m.find()) {
return true;
} else
return false;
}
You may find that besides from the given method countSyllables, I also create two additional methods countit and silente. countit is for counting the syllables inside the word, silente is trying to figure it out that is this word end with a silent e. And it should also be noticed that the definition of not silent e. For example, the should be consider not silent e, while ate is considered silent e.
And here is the status my code has already passed the test, from both local test case and OJ from UCSD:
And from OJ the test result:
P.S: It should be fine to use something like [^aeiouy] directly, because the word is parsed before we call this method. Also change to lowercase is necessary, that would save a lot of work dealing with the uppercase. What we want is only the number of syllables.
Talking about number, an elegant way is to define count as static, so the private method could directly use count++ inside. But now it's fine.
Feel free to contact me if you still don't get the method of this question :)
Using the concept of user5500105, I have developed the following method to calculate the number of Syllables in a word. The rules are:
consecutive vowels are counted as 1 syllable. eg. "ae" "ou" are 1 syllable
Y is considered as a vowel
e at the end is counted as syllable if e is the only vowel: eg: "the" is one syllable, since "e" at the end is the only vowel while "there" is also 1 syllable because "e" is at the end and there is another vowel in the word.
public int countSyllables(String word) {
ArrayList<String> tokens = new ArrayList<String>();
String regexp = "[bcdfghjklmnpqrstvwxz]*[aeiouy]+[bcdfghjklmnpqrstvwxz]*";
Pattern p = Pattern.compile(regexp);
Matcher m = p.matcher(word.toLowerCase());
while (m.find()) {
tokens.add(m.group());
}
//check if e is at last and e is not the only vowel or not
if( tokens.size() > 1 && tokens.get(tokens.size()-1).equals("e") )
return tokens.size()-1; // e is at last and not the only vowel so total syllable -1
return tokens.size();
}
This gives you a number of syllables vowels in a word:
public int getNumVowels(String word) {
String regexp = "[bcdfghjklmnpqrstvwxz]*[aeiouy]+[bcdfghjklmnpqrstvwxz]*";
Pattern p = Pattern.compile(regexp);
Matcher m = p.matcher(word.toLowerCase());
int count = 0;
while (m.find()) {
count++;
}
return count;
}
You can call it on every word in your string array:
String[] words = getText().split("\\s+");
for (String word : words ) {
System.out.println("Word: " + word + ", vowels: " + getNumVowels(word));
}
Update: as freerunner noted, calculating the number of syllables is more complicated than just counting vowels. One need to take into account combinations like ou, ui, oo, the final silent e and possibly something else. As I am not a native English speaker, I am not sure what the correct algorithm would be.
This is how I do it. This is about as simple an algorithm I could come up with.
public static int syllables(String s) {
final Pattern p = Pattern.compile("([ayeiou]+)");
final String lowerCase = s.toLowerCase();
final Matcher m = p.matcher(lowerCase);
int count = 0;
while (m.find())
count++;
if (lowerCase.endsWith("e"))
count--;
return count < 0 ? 1 : count;
}
I use this in combination with a soundex function to determine if words sound alike. The syllable count improves accuracy of my soundex function.
Note: This is strictly for counting the syllables in a word. I assume you can parse your input for words using something like java.util.StringTokenizer.
Your line
String[] words = getText().toLowerCase().split("[a-zA-Z]+");
is splitting ON words, and returning only the space between words! You want to split on the space between words, as follows:
String[] words = getText().toLowerCase().split("\\s+");
you can do it as the following :
public int getNumSyllables()
{
return getSyllables(getTokens("[a-zA-Z]+"));
}
protected List<String> getWordTokens(String word,String pattern)
{
ArrayList<String> tokens = new ArrayList<String>();
Pattern tokSplitter = Pattern.compile(pattern);
Matcher m = tokSplitter.matcher(word);
while (m.find()) {
tokens.add(m.group());
}
return tokens;
}
private int getSyllables(List<String> tokens)
{
int count=0;
for(String word : tokens)
if(word.toLowerCase().endsWith("e") && getWordTokens(word.toLowerCase().substring(0, word.length()-1), "[aeiouy]+").size() > 0)
count+=getWordTokens(word.toLowerCase().substring(0, word.length()-1), "[aeiouy]+").size();
else
count+=getWordTokens(word.toLowerCase(), "[aeiouy]+").size();
return count;
}
I count the the separately, then split the text based on words which are ended with e.
Then counting the syllables, here is my implementation:
int syllables = 0;
word = word.toLowerCase();
if(word.contains("the ")){
syllables ++;
}
String[] split = word.split("e!$|e[?]$|e,|e |e[),]|e$");
ArrayList<String> tokens = new ArrayList<String>();
Pattern tokSplitter = Pattern.compile("[aeiouy]+");
for (int i = 0; i < split.length; i++) {
String s = split[i];
Matcher m = tokSplitter.matcher(s);
while (m.find()) {
tokens.add(m.group());
}
}
syllables += tokens.size();
I've testesd an all test cases are passed.
You are using method split incorrectly. This method recieve separator. Need write something like this:
String[] words = getText().toLowerCase().split(" ");
But if you want to count the number of syllables, it is enough to count the number of vowels:
String input = "text";
Set<Character> vowel = new HashSet<>();
vowel.add('a');
vowel.add('e');
vowel.add('i');
vowel.add('o');
vowel.add('u');
int count = 0;
for (char c : input.toLowerCase().toCharArray()) {
if (vowel.contains(c)){
count++;
}
}
System.out.println("count = " + count);

RegEx to find URLs in HTML takes 25 seconds in Java/Android

In Android/Java, given a website's HTML source code, I would like to extract all XML and CSV file paths.
What I am doing (with RegEx) is this:
final HashSet<String> urls = new HashSet<String>();
final Pattern urlRegex = Pattern.compile(
"[-a-zA-Z0-9+&##/%?=~_|!:,.;]*[-a-zA-Z0-9+&##/%=~_|].(xml|csv)");
final Matcher url = urlRegex.matcher(htmlString);
while (url.find()) {
urls.add(makeAbsoluteURL(url.group(0)));
}
public String makeAbsoluteURL(String url) {
if (url.startsWith("http://") || url.startsWith("http://")) {
return url;
}
else if (url.startsWith("/")) {
return mRootURL+url.substring(1);
}
else {
return mBaseURL+url;
}
}
Unfortunately, this runs for about 25 seconds for an average website with normal length. What is going wrong? Is my RegEx just bad? Or is RegEx just so slow?
Can I find the URLs faster without RegEx?
Edit:
The source for the valid characters was (roughly) this answer. However, I think the two character classes (square brackets) must be swapped so that you have a more limited character set for the first char of the URL and a broader character class for all remaining chars. This was the intention.
Your regex is written in a way that makes it slow for long inputs.
The * operator is greedy.
For instance for input:
http://stackoverflow.com/questions/19019504/regex-to-find-urls-in-html-takes-25-seconds-in-java-android.xml
The [-a-zA-Z0-9+&##/%?=~_|!:,.;]* part of the regex will consume the whole string. It will then try to match the next character group, which will fail (since whole string is consumed). It will then backtrack in match of first part of the regex by one character and try to match the second character group again. It will match. Then it will try to match the dot and fail because the whole string is consumed. Another backtrack etc...
In essence your regex is forcing a lot of backtracking to match anything. It will also waste a lot of time on matches that have no way of succeeding.
For word forest it will first consume whole word in the first part of expression and then repeatedly backtrack after failing to match the rest of expression. Huge waste of time.
Also:
the . in regex is unescaped and it will match ANY character.
url.group(0) is redundant. url.group() has same meaning
In order to speed up the regex you need to figure out a way to reduce the amount of backtracking and it would also help if you had a less general start of the match. Right now every single word will cause matching to start and generally fail. For instance typically in html all the links are inside 2 ". If that's the case you can start your matching at " which will speed it up tremendously. Try to find a better start of the expression.
I've nothing the say in the theoretical overview that U Mad did, he highlighted everything I'd noticed.
What I would like to suggest you, considering what are you look for with the RE, is to change the point of view of your RE :)
You are looking for xml and csv files, so why don't you reverse the html string, for example using:
new StringBuilder("bla bla bla foo letme/find.xml bla bla").reverse().toString()
after that you could look for the pattern:
final Pattern urlRegex = Pattern.compile(
"(vsc|lmx)\\.[-a-zA-Z0-9+&##/%=~_|][-a-zA-Z0-9+&##/%?=~_|!:,.;]*");
urlRegex pattern could be refined as U Mad has already suggested. But in this way you could reduce the number of failed matches.
I had my doubts, if there can be a String really long enough to take 25 seconds for parsing. So I tried and must admit now, that with about 27MB of text, it takes around 25 seconds to parse it with the given regular expression.
Being curious I changed the little test program with #FabioDch's approach (so, please vote for him, if you want to vote anywhere :-)
The result is quite impressing: Instead of 25 Seconds, #FabioDch's approach needed less then 1 second (100ms to 800ms) + 70ms to 85ms for reversing!
Here's the code I used. It reads text from the largest text file I've found and copies it 10 time to get 27MB of text. Then runs the regex against it and prints out the results.
#Test
public final void test() throws IOException {
final Pattern urlRegex = Pattern.compile("(lmx|vsc)\\.[-a-zA-Z0-9+&##/%=~_|][-a-zA-Z0-9+&##/%?=~_|!:,.;]*");
printTimePassed("initialized");
List<String> lines = Files.readAllLines(Paths.get("testdata", "Aster_Express_User_Guide_0500.txt"), Charset.defaultCharset());
StringBuilder sb = new StringBuilder();
for(int i=0; i<10; i++) { // Copy 10 times to get more useful data
for(String line : lines) {
sb.append(line);
sb.append('\n');
}
}
printTimePassed("loaded: " + lines.size() + " lines, in " + sb.length() + " chars");
String html = sb.reverse().toString();
printTimePassed("reversed");
int i = 0;
final Matcher url = urlRegex.matcher(html);
while (url.find()) {
System.out.println(i++ + ": FOUND: " + new StringBuilder(url.group()).reverse() + ", " + url.start() + ", " + url.end());
}
printTimePassed("ready");
}
private void printTimePassed(String msg) {
long current = System.currentTimeMillis();
System.out.printf("%s: took %d ms\n", msg, (current - ms));
ms = current;
}
Would suggest only using the regex to find file extensions (.xml or .csv). This should be a lot faster and when found, you can look backwards, examining each character before and stop when you reach one that couldn't be in a URL - see below:
final HashSet<String> urls = new HashSet<String>();
final Pattern fileExtRegex = Pattern.compile("\\.(xml|csv)");
final Matcher fileExtMatcher = fileExtRegex.matcher(htmlString);
// Find next occurrence of ".xml" or ".csv" in htmlString
while (fileExtMatcher.find()) {
// Go backwards from the character just before the file extension
int dotPos = fileExtMatcher.start() - 1;
int charPos = dotPos;
while (charPos >= 0) {
// Break if current character is not a valid URL character
char chr = htmlString.charAt(charPos);
if (!((chr >= 'a' && chr <= 'z') ||
(chr >= 'A' && chr <= 'Z') ||
(chr >= '0' && chr <= '9') ||
chr == '-' || chr == '+' || chr == '&' || chr == '#' ||
chr == '#' || chr == '/' || chr == '%' || chr == '?' ||
chr == '=' || chr == '~' || chr == '|' || chr == '!' ||
chr == ':' || chr == ',' || chr == '.' || chr == ';')) {
break;
}
charPos--;
}
// Extract/add URL if there are valid URL characters before file extension
if ((dotPos > 0) && (charPos < dotPos)) {
String url = htmlString.substring(charPos + 1, fileExtMatcher.end());
urls.add(makeAbsoluteURL(url));
}
}
Small disclaimer: I used part of your original regex for valid URL characters: [-a-zA-Z0-9+&##/%?=~_|!:,.;]. Haven't verified if this is comprehensive and there are perhaps further improvements that could be made, e.g. it would currently find local file paths (e.g. C:\TEMP\myfile.xml) as well as URLs. Wanted to keep the code above simple to demonstrate the technique so haven't tackled this.
EDIT Following the comment about effiency I've modified to no longer use a regex for checking valid URL characters. Instead, it compares the character against valid ranges manually. Uglier code but should be faster...
I know people love to use regex to parse html, but have you considered using jsoup?
For sake of clarity I created a separate answer for this regex:
Edited to escape the dot and remove reluctant quant.
(?<![-a-zA-Z0-9+&##/%=~_|])[-a-zA-Z0-9+&##/%?=~_|!:,.;]*[-a-zA-Z0-9+&##/%=~_|]‌\\​.(xml|csv)
Please try this one and tell me how it goes.
Also here's a class which will enable you to search a reversed string without actually reversing it:
public class ReversedString implements CharSequence {
public ReversedString(String input) {
this.s = input;
this.len = s.length();
}
private final String s;
private final int len;
#Override
public CharSequence subSequence(final int start, final int end) {
return new CharSequence() {
#Override
public CharSequence subSequence(int start, int end) {
throw new UnsupportedOperationException();
}
#Override
public int length() {
return end-start;
}
#Override
public char charAt(int index) {
return s.charAt(len-start-index-1);
}
#Override
public String toString() {
StringBuilder buf = new StringBuilder(end-start);
for(int i = start;i < end;i++) {
buf.append(s.charAt(len-i-1));
}
return buf.toString();
}
};
}
#Override
public int length() {
return len;
}
#Override
public char charAt(int index) {
return s.charAt(len-1-index);
}
}
You can use this class as such:
pattern.matcher(new ReversedString(inputString));

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