Develop Reference

Preloading a website before fetching HTML from the URL

I'm trying to get data off of a URL, but the information I need takes a few seconds to load, and only shows as LOADING in the HTML until it does load, so when I use this code I can't pull the data I need.
URL url = new URL("https://www.cardservices.uga.edu/fs_mobile/");
URLConnection con = url.openConnection();
InputStream is = con.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line = null;
while ((line = br.readLine()) != null){
System.out.println(lineNumber +": "+ line);
}
How could I go about allowing the URL to load for a set amount of time before pulling the HTML off of it?

The webpage you are calling probably call an ajax call to fetch the data, thats why you won't get it using your approach.
You have 2 options to get that data:
Use browser's inspect elements(F12 in chrome) and in "network" tab, get that ajax call, and use it instead of the URL you are using in your code.
Call your URL using a headless library(e.g ghoustjs) and after page is load crawl the data.
IMO I would choose option 1

Here is a working alternate,
URL url = new URL("https://www.cardservices.uga.edu/fs_mobile/index.php/dashboard/occupancies/"); //This is the AJAX call that goes to load the data into webpage. You can get this from inspecting the network calls.
URLConnection con = url.openConnection();
InputStream is = con.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line = null;
while ((line = br.readLine()) != null){
System.out.println(line);
}
Which basically gives you the JSON response containing the percentage.
Hope it helps.
Also, you can use Selenium for performing wait if you are so curious to get the exact HTML output.

Reading HTML from URL in Java vs. Python

I'm trying to read the HTML from a particular URL and store it into a String for parsing. I referred to a previous post to help me out. When I print out what was read, all I get are special characters.
Here is my Java code (with try/catches left out) that reads from a URL and prints:
String path = "https://html1-f.scribdassets.com/913q5pjrsw60h9i4/pages/106-6b1bd15200.jsonp";
URL url = new URL(path);
InputStream in = url.openStream();
BufferedReader bw = new BufferedReader(new InputStreamReader(in, "UTF-8");
String line;
while ((line = bw.readLine()) != null) {
System.out.println(line);
}
Program output:
�ĘY106-6b1bd15200.jsonpmP�r� �Ƨ�!�%m�vD"��Ra*��w�%����ݳ�sβ��MK�d�9+%�m��l^��މ����:���� ���8B�Vce�.A*��x$FCo���a�b�<����Xy��m�c�>t����� �Z������Gx�o� �J���oKe�0�5�kGYpb�*l����+|�U���-�N3��jBp�R�z5Cۥjh��o�;�~)����~��)~ɮhy��<c,=;tHW���'�c�=~�w���
Expected output:
window.page106_callback(["<div class=\"newpage\" id=\"page106\" style=\"width: 902px; height:1273px\">\n<div class=image_layer style=\"z-index: 1\">\n<div class=ie_fix>\n<img class=\"absimg\" style=\"left:18px;top:27px;width:860px;height:1077px;clip:rect(1px 859px 1076px 1px)\" orig=\"http://html.scribd.com/913q5pjrsw60h9i4/images/106-6b1bd15200.jpg\"/>\n</div>\n</div>\n</div>\n\n"]);
At first, I thought it was an issue with permissions or something that somehow encrypted the stream, but my friend wrote a small Python script to do the same thing and it worked, thereby ruling this out. This is what he wrote:
import requests
link = 'https://html1-f.scribdassets.com/913q5pjrsw60h9i4/pages/106-
6b1bd15200.jsonp'
f = requests.get(link)
text = (f.text)
print(text)
So the question is, why is the Java version unable to correctly read and print from this particular URL? Note that I tried testing some other URLs from various websites and those worked fine. Maybe I should learn Python.

The response is gzip-encoded. You can do:
InputStream in = new GZIPInputStream(con.getInputStream());

#Maurice Perry is right, I tried with below code
String url = "https://html1-f.scribdassets.com/913q5pjrsw60h9i4/pages/106-6b1bd15200.jsonp";
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
BufferedReader in = new BufferedReader(
new InputStreamReader(new GZIPInputStream(con.getInputStream())));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
System.out.println(response.toString());

How to get a part of an URL content

I wan't to display a part of an HTML page, but I only find how to get a source code of an HTML page when I search a solution: How to get the html-source of a page from a html link in android?
HttpClient client = new DefaultHttpClient();
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);
String html = "";
InputStream in = response.getEntity().getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder str = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null)
{
str.append(line);
}
in.close();
html = str.toString();
But if I do that, how can I get a part of the page, and the solution is too old. I've found an another solution named webview, but I don't know what is the best solution to display a part of a html page and how to do it.
EDIT:
This page: http://www.solutis.fr/groupe-solutis,mentions-legales.html
Without tag, header, footer, only the content of body without tag too.

What you need is one more line - when you become the HttpResponse it is the whole html from the response site, so you need to remove all tags from it and you could do this with a single line
String responseAsText = android.text.Html.fromHtml(html).toString();
where html is your string with the repsonse from the HttpResponse.

How do I send a cookie while trying to grab a sites source?

I am trying to grab a site's source code using this code
private static String getUrlSource(String url) throws IOException {
URL url = new URL(url);
URLConnection urlConn = url.openConnection();
BufferedReader in = new BufferedReader(new InputStreamReader(
urlConn.getInputStream(), "UTF-8"));
String inputLine;
StringBuilder a = new StringBuilder();
while ((inputLine = in.readLine()) != null)
a.append(inputLine);
in.close();
return a.toString();
}
When I do grab the site code this way I get an error about needing to allow cookies. Is there anyway to allow cookies in a java application just so I can grab some source code? I do have the cookie my browser uses to log me in if that helps.
Thanks
John

This way you would have to deal with raw request data, Go with apache http client that gives you abstraction and some methods to allow to set headers in request

Get raw text from html

Im on quite a basic level of android development.
I would like to get text from a page such as "http://www.google.com". (The page i will be using will only have text, so no pictures or something like that)
So, to be clear: I want to get the text written on a page into etc. a string in my application.
I tried this code, but im not even sure if it does what i want.
URL url = new URL(/*"http://www.google.com");
URLConnection connection = url.openConnection();
// Get the response
BufferedReader rd = new BufferedReader(new InputStreamReader(connection.getInputStream()));
String line = "";
I cant get any text from it anyhow. How should I do this?

From the sample code you gave you are not even reading the response from the request. I would get the html with the following code
URL u = new URL("http://www.google.com");
URLConnection conn = u.openConnection();
BufferedReader in = new BufferedReader(
new InputStreamReader(
conn.getInputStream()));
StringBuffer buffer = new StringBuffer();
String inputLine;
while ((inputLine = in.readLine()) != null)
buffer.append(inputLine);
in.close();
System.out.println(buffer.toString());
From there you would need to pass the string into some kind of html parser if you want only the text. From what I've heard JTidy would is a good library for this however I have never used any Java html parsing libraries.

You want to extract text from HTML file? You can make use of specialized tool such as the Jericho HTML parser library. I'm not sure if it can be used directly in Android app, it is quite big, but it is open source so you can make use of its code and take only what you need for your task.

Here is one way:
public String scrape(String urlString) throws Exception {
URL url = new URL(urlString);
URLConnection connection = url.openConnection();
BufferedReader reader = new BufferedReader(new InputStreamReader(
connection.getInputStream()));
String line = null, data = "";
while ((line = reader.readLine()) != null) {
data += line + "\n";
}
return data;
}
Here is another.