Replace xmlns attribute of root node using xslt - java

I have xml like below
<rnp xmsns="v1">
<ele1 line="1">
<ele2></ele2>
</ele1>
</rnp>
I want to change it to
<rnp xmsns="v2">
<ele1 line="1">
<ele2></ele2>
</ele1>
</rnp>
using xslt 1.0.
I am using below xsl.
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="v2">
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="rnp">
<rnp>
<xsl:apply-templates select="*"/>
</rnp>
</xsl:template>
</xsl:stylesheet>
But this xsl does not copy the attributes so line attribute is not generated in output.
sample output
<?xml version="1.0" encoding="UTF-8"?><rnp xmlns="v2"><ele1>1
<ele2/>
</ele1></rnp>
How to change only the text of xmlns attrbiute using xslt? Is there any other way to change xmlns using xslt? I have only option of xslt 1.0.
Thanks.

This transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pNS" select="'v2'"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[true()]">
<xsl:element name="{local-name()}" namespace="{$pNS}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
when applied on the provided XML document (corrected to make it in the namespace "v1":
<rnp xmlns="v1">
<ele1 line="1">
<ele2></ele2>
</ele1>
</rnp>
produces the wanted, correct result:
<rnp xmlns="v2">
<ele1 line="1">
<ele2/>
</ele1>
</rnp>
Do note:
The desired new default namespace is passed to the transformation as an external parameter -- thus the smae transformation without any modification can be used in every case when the default namespace must be modified.
This unusual looking template match: <xsl:template match="*[true()]"> makes it possible to avoid the XSLT processors "recoverable ambiguity error" messages if we had coded it just as <xsl:template match="*"> and is shorter and more elegant than specifying a priority.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="v2">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#* | node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Output:
<rnp xmlns="v2">
<ele1 line="1">
<ele2 />
</ele1>
</rnp>

Related

when replace the xml elements with the help of xsl stylesheet using java,not getting replaced

how to replace the child tag name with xsl.
here the below is my structure of xml.
<Checkpax xmlns="http://xml.api.com/test">
<customerLevel>
<customerDetails>
<paxDetails>
<surname>MUKHERJEE</surname>
<type>A</type>
<gender>M</gender>
</paxDetails>
<otherPaxDetails>
<givenName>JOY</givenName>
<title>MR</title>
<age>11</age>
</otherPaxDetails>
<otherPaxDetails>
<title>MR</title>
</otherPaxDetails>
</customerDetails>
<staffDetails>
<staffInfo/>
<staffCategoryInfo>
<attributeDetails>
<attributeType>NA</attributeType>
</attributeDetails>
</staffCategoryInfo>
</staffDetails>
<productLevel>
<legLevel>
<legLevelIndicator>
<statusDetails>
<indicator>abc</indicator>
<action>1</action>
</statusDetails>
</legLevelIndicator>
</legLevel>
</productLevel>
<CustomerLevel>
<legLevel>
<legLevelIndicator>
<statusDetails>
<indicator>cde</indicator>
<action>1</action>
</statusDetails>
</legLevelIndicator>
</legLevel>
</CustomerLevel>
</customerLevel>
</Checkpax>
The below is my XSL file
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="customerLevel/productLevel/legLevel/legLevelIndicator/statusDetails">
<statusInformation>
<xsl:apply-templates select="#*|node()" />
</statusInformation>
</xsl:template>
</xsl:stylesheet>
here the statusDetails name should be changed as staffInformation inside the ProductLevel/LeglevelIndicator . Kindly give me the suggestion for doing this.
The below is expected result
<Checkpax xmlns="http://xml.api.com/test">
<customerLevel>
<customerDetails>
<paxDetails>
<surname>MUKHERJEE</surname>
<type>A</type>
<gender>M</gender>
</paxDetails>
<otherPaxDetails>
<givenName>JOY</givenName>
<title>MR</title>
<age>11</age>
</otherPaxDetails>
<otherPaxDetails>
<title>MR</title>
</otherPaxDetails>
</customerDetails>
<staffDetails>
<staffInfo/>
<staffCategoryInfo>
<attributeDetails>
<attributeType>NA</attributeType>
</attributeDetails>
</staffCategoryInfo>
</staffDetails>
<productLevel>
<legLevel>
<legLevelIndicator>
<statusInformation>
<indicator>abc</indicator>
<action>1</action>
</statusInformation>
</legLevelIndicator>
</legLevel>
</productLevel>
<CustomerLevel>
<legLevel>
<legLevelIndicator>
<statusDetails>
<indicator>cde</indicator>
<action>1</action>
</statusDetails>
</legLevelIndicator>
</legLevel>
</CustomerLevel>
</customerLevel>
</Checkpax>
the statusDetails name should be changed as staffInformation inside
the ProductLevel/LeglevelIndicator
Try it this way:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://xml.api.com/test"
exclude-result-prefixes="ns0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ns0:productLevel/ns0:legLevel/ns0:legLevelIndicator/ns0:statusDetails">
<staffInformation xmlns="http://xml.api.com/test">
<xsl:apply-templates/>
</staffInformation>
</xsl:template>
</xsl:stylesheet>

XSLT 1.0: how to wrap XML element around other templates?

I am using xsltproc to process XSLT 1.0 transform on OS X Yosemite; input is HTML, and output is XML.
The idea is that the templates below matching h1[#class='page-header'] and div[#class='mixins'] actually work, but the problem is wrapping them in a custom parent XML element (here called dye).
I realize my template matching * is broken; it's there simply to illustrate the kind of structure I would like to output.
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" method="xml"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|style|script"/>
<xsl:template match="*">
<xsl:element name="dye">
<xsl:apply-templates select="h1[#class='page-header']"/>
<xsl:apply-templates select="div[#class='mixins']"/>
</xsl:element>
</xsl:template>
<xsl:template match="h1[#class='page-header']">
<xsl:element name="color">
<xsl:value-of select="text()"/>
</xsl:element>
<xsl:text>
</xsl:text>
</xsl:template>
<xsl:template match="div[#class='mixins']">
<xsl:element name="tone">
<xsl:value-of select="p/a[#class='tone']/#href"/>
</xsl:element>
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
Thanks for your interest!
I believe this should work:
<xsl:template match="*">
<dye>
<xsl:apply-templates select="h1[#class='page-header']"/>
<xsl:apply-templates select="div[#class='mixins']"/>
</dye>
</xsl:template>

Generate xpath of XML using XSLT for all Nodes

I was trying to find a way to convert the XML tags to their respective unique address like xPath. Nd I found an XSLT, where XML is processed and the unique address is created only for the nodes which doesnt have child elements and with attributes. [link]:Generate/get xpath from XML node java
XSLT :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:variable name="vApos">'</xsl:variable>
<xsl:template match="*[#* or not(*)] ">
<xsl:if test="not(*)">
<xsl:apply-templates select="ancestor-or-self::*" mode="path"/>
<xsl:value-of select="concat('=',$vApos,.,$vApos)"/>
<xsl:text>
</xsl:text>
</xsl:if>
<xsl:apply-templates select="#*|*"/>
</xsl:template>
<xsl:template match="*" mode="path">
<xsl:value-of select="concat('/',name())"/>
<xsl:variable name="vnumPrecSiblings" select=
"count(preceding-sibling::*[name()=name(current())])"/>
<xsl:if test="$vnumPrecSiblings">
<xsl:value-of select="concat('[', $vnumPrecSiblings +1, ']')"/>
</xsl:if>
</xsl:template>
<xsl:template match="#*">
<xsl:apply-templates select="../ancestor-or-self::*" mode="path"/>
<xsl:value-of select="concat('[#',name(), '=',$vApos,.,$vApos,']')"/>
<xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
when passed to this
<?xml version="1.0" encoding="UTF-8"?>
<root>
<main>
<tag1>001</tag1>
<tag2>002</tag2>
<tag3>
<tag4>004</tag4>
</tag3>
<tag2>002</tag2>
<tag5>005</tag5>
</main>
</root>
produces
/root/main/tag1='001' /root/main/tag2='002' /root/main/tag3/tag4='004' /root/main/tag2[2]='002' /root/main/tag5='005'
So I need the xslt to generate in the following way
/root
/root/main
/root/main/tag1
/root/main/tag2
/root/main/tag3
/root/main/tag3/tag4
/root/main/tag2[2]
/root/main/tag5
Also I dont need values. So please help me with this
Your result could be produced rather simply by:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="UTF-8"/>
<xsl:template match="*">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="name()" />
<xsl:variable name="i" select="count(preceding-sibling::*[name()=name(current())])"/>
<xsl:if test="$i">
<xsl:value-of select="concat('[', $i + 1, ']')"/>
</xsl:if>
<xsl:if test="position()!=last()">
<xsl:text>/</xsl:text>
</xsl:if>
</xsl:for-each>
<xsl:text>
</xsl:text>
<xsl:apply-templates select="*"/>
</xsl:template>
</xsl:stylesheet>
Note that this does not process attributes (or any other type of nodes other than elements).

Transforming XSL with XSL

A question about Martin's answer:
Martin Honnen's answer works great, but not with the root element. Let's say I have "cars" as a root element:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="foo">
<cars>
<car1 />
<car2 />
</cars>
</xsl:template>
</xsl:stylesheet>
And I want to obtain:
<xsl:template match="foo">
<cars>
<car1 />
<car2 />
<TANK />
</cars>
</xsl:template>
For this, I'd use:
<xsl:template match="cars" >
<xsl:copy>
<xsl:apply-templates/>
<TANK />
</xsl:copy>
</xsl:template>
Which outputs the exact input, without changing anything. I can try:
<xsl:template match="/" >
<xsl:copy>
<xsl:apply-templates/>
<TANK />
</xsl:copy>
</xsl:template>
But it will place the TANK node outside the stylesheet, like this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="order">
<cars>
<car1/>
<car2/>
</cars>
</xsl:template>
</xsl:stylesheet><TANK/>
How to get the TANK element inside cars?
Original question:
I have a XSL that I use to transform an XML:
XML_format1 -> XSL1 -> XML_format2
I need to transform this first XSL file (using a second XSL) to obtain a third XSL file, which will output an XML with a third format. In short:
XSL1 -> XSL2 -> XSL3
XML_format1 -> XSL3 -> XML_format3
Using the following stylesheet, I am able to copy the first XSL's contents and also skip certain nodes:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//skipThisNode"/>
</xsl:stylesheet>
My problem: in addition to this, I also need to change some nodes' structure (add something), from this:
<car>
<color>green</color>
<fuel>petrol</fuel>
</car>
To this:
<car>
<color>green</color>
<fuel>petrol</fuel>
<topSpeed>99</topSpeed>
</car>
LE: I could create a template to match the specific nodes that I need to add children to, like so:
<xsl:template match="car">
<color>
<!-- existing value-of -->
</color>
<fuel>
<!-- existing value-of -->
</fuel>
<topSpeed>
<!-- * new value-of * -->
</topSpeed>
</xsl:template>
But this seems like going over the top. Is there a simpler way of achieving what I want?
I would rather use
<xsl:param name="newSpeed" select="99"/>
<xsl:template match="car">
<xsl:copy>
<xsl:apply-templates/>
<topSpeed>
<xsl:value-of select="$newSpeed"/>
</topSpeed>
</xsl:copy>
</xsl:template>
that keeps the processing chain up, allowing you to add templates to transform or delete child and descendants of car elements when needed.
[edit]
I am not sure I understand your latest requirement as the input seems to be a complete stylesheet but then as the wanted output you have only shown a single template. So assuming you have the input as
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="order">
<cars>
<car1 />
<car2 />
</cars>
</xsl:template>
</xsl:stylesheet>
and you want to both transform the xsl:template's match attribute as well as the literal result elements in the template body I would use
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xsl:template[#match = 'order']/#match">
<xsl:attribute name="{name()}">
<xsl:text>foo</xsl:text>
</xsl:attribute>
</xsl:template>
<xsl:template match="xsl:template[#match = 'order']/cars">
<xsl:copy>
<xsl:apply-templates/>
<TANK/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
that way I get (tested with Saxon 6.5.5) the result
<?xml version="1.0" encoding="utf-8"?><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="foo">
<cars>
<car1/>
<car2/>
<TANK/></cars>
</xsl:template>
</xsl:stylesheet>
which is hopefully what you want (lacking proper indentation perhaps).

XSLT for XML containing multiple namespaces

I'm working on an XSLT that is giving me a little headache, and was looking for some tips. I'm working on converting an XML where some of the tags have namespaces prefixes, and others do not. I am working to convert all of the tags to one common namespace prefix.
Example of XML:
<yes:Books>
<no:Book>
<Title>Yes</Title>
<maybe:Version>1</maybe:Version>
</no:Book>
</yes:Books>
What I'm trying to get:
<yes:Books>
<yes:Book>
<yes:Title>Yes</yes:Title>
<yes:Version>1</yes:Version>
</yes:Book>
</yes:Books>
The XML input is the aggregate of several webservices, that are returning various namespaces. I have no issue aggregating it together appropriately, it's creating one common prefix namespace that I am having an issue with.
Worst case, I could regex them away, but I'm sure that isn't recomended.
Thanks.
This transformation allows the wanted final prefix and its namespace to be specified as external/global parameters. It shows how to process in the same way attribute names:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:param name="pPrefix" select="'yes'"/>
<xsl:param name="pNamespace" select="'yes'"/>
<xsl:template match="*">
<xsl:element name="{$pPrefix}:{local-name()}" namespace="{$pNamespace}">
<xsl:apply-templates select="node()|#*"/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{$pPrefix}:{local-name()}" namespace="{$pNamespace}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
</xsl:stylesheet>
when applied on the following document (the provided one with one added attribute to make the problem more challenging):
<yes:Books xmlns:yes="yes">
<no:Book xmlns:no="no">
<Title no:Major="true">Yes</Title>
<maybe:Version xmlns:maybe="maybe">1</maybe:Version>
</no:Book>
</yes:Books>
produces the wanted, correct result:
<yes:Books xmlns:yes="yes">
<yes:Book>
<yes:Title yes:Major="true">Yes</yes:Title>
<yes:Version>1</yes:Version>
</yes:Book>
</yes:Books>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:custom="c">
<xsl:template match="/">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:element name="custom:{local-name()}" namespace-uri="c">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

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