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Splitting a string starts with $

I am trying to split a string like "$ 12,9608,03" and just want the numbers and convert to an integer.
For splitting how should I use split() in java as there is a space after the $ sign.
Tried with following:
String[] arr_1=mystring.Split(“[\$, ] “);
String array1=arr_1[0];
Sopln(array1);

You can do what you want, I believe, using this:
String splited = "$ 12,9608,03".replaceAll("[^0-9]", "");
Then you will have splitted only the numbers by commas, but as String. Then you can use, for each String you got, Integer.valueOf() method.

String[] splitted = mystring.split(" ");
String numb = splitted[1];
Just split on the whitespace.

Just like that:
String[] arr_1=mystring.Split("$");
String array1=arr_1[0].trim();
Sopln(array1);

use space in regular experssion to split the string.
String[] split = str.split("( )");
System.out.println(split[1]);

Some fine answers here, to finish off the whole question
and convert to an integer
Here you are:
String myString = "$ 12,9608,03";
String[] splitted = myString.split(" ");
int numb = Integer.parseInt(splitted[1].replaceAll(",", ""));
System.out.println(numb);

To take just the digits, you'd do better with replace:
mystring.replaceAll("[^0-9]", "")
The first parameter is a regex that matches anything but a digit. So this will return you just the number

Stop being insane. Almost everything you will ever do (applies to all readers) has already been done (often better) by the Apache Commons project.
Read the Apache Commons StringUtils API page, pay attention to the RemoveAll method.
Use the StringUtils.RemoveAll method.
Convert the output from the StringUtils.RemoveAll method to an int;
catch any exceptions and handle them appropriately.

Difficulty splitting string at delimiter and keeping it

I have a string that is read in pairs, separated by comma. However, I do not always want to split at the comma because there is not always 1 comma in the input. For example, the string,
(http://www.wolframalpha.com/input/?i=103%2F30+%3D+4a-3b,+71%2F60+%3D+a+%2B+b
,http://www.wolframalpha.com/input/?i=x%5E2%2B5x%2B6,file:///tmp/foo/bar/p,d,f.pdf)
Is read in all one line. For this case, I only want to split at the ,h, and no where else in the string. Essentially, after the split, the strings should be:
http://www.wolframalpha.com/input/?i=103%2F30+%3D+4a-3b,+71%2F60+%3D+a+%2B+b
http://www.wolframalpha.com/input/?i=x%5E2%2B5x%2B6
file:///tmp/foo/bar/p,d,f.pdf
Maintaining the order of the comma in the first string. (I will get rid of parenthesis). I have looked at this stack overflow question, and while helpful, does not correctly split this string. This is in Java. Any help is appreciated.

You can use regex to do the split. Please see below code snippet.
String str = "(http://www.wolframalpha.com/input/?i=103%2F30+%3D+4a-3b,+71%2F60+%3D+a+%2B+b,http://www.wolframalpha.com/input/?i=x%5E2%2B5x%2B6)";
String[] strArr = str.split("(,(?=http))");
You will have Array of all the value which would be possible according to your requirement.

Split on 'http' then re-add it.
Psuedo-code
String input = "http://www.wolframalpha.com/input/?i=103%2F30+%3D+4a-3b,+71%2F60+%3D+a+%2B+b
,http://www.wolframalpha.com/input/?i=x%5E2%2B5x%2B6"
List<String> split = input.split('http');
List<String> finalList = new ArrayList<String>();
for(String fixup in split)
{
finalList.put( "http" + fixup );
}
Final should contain the two URLs.

why split() produces extra , after sets limit -1

I want to split Area Code and preceding number from Telephone number without brackets so i did this.
String pattern = "[\\(?=\\)]";
String b = "(079)25894029".trim();
String c[] = b.split(pattern,-1);
for (int a = 0; a < c.length; a++)
System.out.println("c[" + a + "]::->" + c[a] + "\nLength::->"+ c[a].length());
Output:
c[0]::-> Length::->0
c[1]::->079 Length::->3
c[2]::->25894029 Length::->8
Expected Output:
c[0]::->079 Length::->3
c[1]::->25894029 Length::->8
So my question is why split() produces and extra blank at the start, e.g
[, 079, 25894029]. Is this its behavior, or I did something go wrong here?
How can I get my expected outcome?

First you have unnecessary escaping inside your character class. Your regex is same as:
String pattern = "[(?=)]";
Now, you are getting an empty result because ( is the very first character in the string and split at 0th position will indeed cause an empty string.
To avoid that result use this code:
String str = "(079)25894029";
toks = (Character.isDigit(str.charAt(0))? str:str.substring(1)).split( "[(?=)]" );
for (String tok: toks)
System.out.printf("<<%s>>%n", tok);
Output:
<<079>>
<<25894029>>

From the Java8 Oracle docs:
When there is a positive-width match at the beginning of this string
then an empty leading substring is included at the beginning of the
resulting array. A zero-width match at the beginning however never
produces such empty leading substring.
You can check that the first character is an empty string, if yes then trim that empty string character.

Your regex has problems, as does your approach - you can't solve it using your approach with any regex. The magic one-liner you seek is:
String[] c = b.replaceAll("^\\D+|\\D+$", "").split("\\D+");
This removes all leading/trailing non-digits, then splits on non-digits. This will handle many different formats and separators (try a few yourself).
See live demo of this:
String b = "(079)25894029".trim();
String[] c = b.replaceAll("^\\D+|\\D+$", "").split("\\D+");
System.out.println(Arrays.toString(c));
Producing this:
[079, 25894029]

java string split based on new line

I have following string
String str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n \n";
I want to break it on \n so at the end i should two string aaaaaaaa and bbbbbbbb. I dont want last one as it only contain white space. so if i split it based on new line character using str.split() final array should have two entry only.
I tried below:
String str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n \n".replaceAll("\\s+", " ");
String[] split = str.split("\n+");
it ignore all \n and give single string aaaaaaaaaa bbbbbbbb.

Delete the call to replaceAll(), which is removing the newlines too. Just this will do:
String[] split = str.split("\n\\s*");
This will not split on just spaces - the split must start at a newline (followed by optional further whitespace).
Here's some test code using your sample input with edge case enhancement:
String str = "aaaaaaaaa\nbbbbbb bbbbb\n \n";
String[] split = str.split("\n\\s*");
System.out.println(Arrays.toString(split));
Output:
[aaaaaaaaa, bbbbbb bbbbb]

This should do the trick:
String str="aaaaaaaaa\n\n\nbbbbbbbbbbb\n \n";
String[] lines = str.split("\\s*\n\\s*");
It will also remove all trailing and leading whitespace from all lines.

The \ns are removed by your first statement: \s matches \n

Parsing string from the name

I am trying to parse the certain name from the filename.
The examples of File names are
xs_1234323_00_32
sf_12345233_99_12
fs_01923122_12_12
I used String parsedname= child.getName().substring(4.9) to get the 1234323 out of the first line. Instead, how do I format it for the above 3 to output only the middle numbers(between the two _)? Something using split?

one line solution
String n = str.replaceAll("\\D+(\\d+).+", "$1");
most efficent solution
int i = str.indexOf('_');
int j = str.indexOf('_', i + 1);
String n = str.substring(i + 1, j);

String [] tokens = filename.split("_");
/* xs_1234323_00_32 would be
[0]=>xs [1]=> 1234323 [2]=> 00 [3] => 32
*/
String middleNumber = tokens[2];

You can try using split using the '_' delimiter.

The String.split methods splits this string around matches of the given ;parameter. So use like this
String[] output = input.split("_");
here output[1] will be your desired result
ANd input will be like
String input = "xs_1234323_00_32"

I would do this:
filename.split("_", 3)[1]
The second argument of split indicates the maximum number of pieces the string should be split into, in your case you only need 3. This will be faster than using the single-argument version of split, which will continue splitting on the delimiter unnecessarily.