I am reciving a input in this format 2012-01-13T00:00:00.000-05:00 and which i need to convert this into yyyyMMdd Format .
I have also set the SimpleDateFormat.setLenient(false);
This is my coding for parsing the Date
public static String getparsedDate(String date) throws Exception {
DateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS", Locale.US);
sdf.setLenient(false);
String s1 = date;
String s2 = null;
Date d;
try {
d = sdf.parse(s1);
s2 = (new SimpleDateFormat("yyyyMMdd")).format(d);
} catch (ParseException e) {
e.printStackTrace();
}
return s2;
}
But i am getting a Exception at
java.text.ParseException: Unparseable date: "201201"
at java.text.DateFormat.parse(Unknown Source)
Could anybody please let me know , what might be the issue ?
You are missing the timezone in your format string. If you check the argument, it is finishing with -05:00 and you are also using Lenient==false.
Unfortunately, the time zone formats available to SimpleDateFormat are not ISO8601 compliant. SimpleDateFormat understands time zone strings like "GMT+01:00" or "+0100", the latter according to RFC822. Therefore using SimpleDateFormat does not seem as an option in your case (since you use UTC−05:00 as timezone).
Instead of SimpleDateFormat you need to use JodaTime for that type of date format.
Related
I am using jQuery Datepicker that is giving the date like 07/05/2015 this format.I am using simpledateformat to format this date.But always the SDF is converting it to the todays date.How to solve this ??
System.out.println("Activity IS : IS With Date");
SimpleDateFormat sdfOverTimeWithDate = new SimpleDateFormat("yyyy-MM-dd ");
Date startDate = ParamUtil.getDate(resourceRequest, "startDate", sdfOverTimeWithDate);
Date endDate = ParamUtil.getDate(resourceRequest, "endDate", sdfOverTimeWithDate);
int jobId= ParamUtil.getInteger(resourceRequest, "jobId");
System.out.println("jobId :"+jobId);
System.out.println("startDate :"+startDate);
System.out.println("endDate :"+endDate);
This statDate and endDate is giving todays's date only ,while the date i am pssing is in the format 07/05/2015.How to solve this ??somebody plaese help
You are passing wrong date format to SimpleDateFormat constructor. Try "dd/MM/yyyy" instead of "yyyy-MM-dd "
Is "07/05/2015" in July (US-Format) or May? Please clarify. If it is US-format (date expression starting with month number) then your solution is to use the pattern "MM/dd/yyyy" otherwise you should use the pattern "dd/MM/yyyy".
The pattern "yyyy-MM-dd " cannot be right due to two reasons:
a) It starts with a four-digit-year but your input begins with a two-digit-number.
b) It contains a trailing space.
Try to do it.
SimpleDateFormat sdfOverTimeWithDate = new SimpleDateFormat("yyyy-MM-dd");
try {
Date d = sdfOverTimeWithDate.parse("07/05/2015");
} catch (ParseException e) {
e.printStackTrace();
}
Please help me with the following code. I got unparseable date exception.
public static Date getUtilDateFromString(String date) throws ParseException {
return getUtilDateFromString(date, null);
}
public static Date getUtilDateFromString(String date, String format)
throws ParseException {
if (format == null || "".equals(format)) {
format = "yyyy/MM/dd HH:mm:ss";
}
DateFormat dateFormat = new SimpleDateFormat(format);
return dateFormat.parse(date);
}
The Date format should be yyyy-MM-dd HH:mm:ss.S since you're dealing with milliseconds. Your date pattern has mistakes too.
This works:
System.out.println(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.S").parse("2014-11-26 12:22:44.0"));
Output:
Wed Nov 26 12:22:44 CAT 2014
I would check the String date variable you are using, it seems that it does not fit the format you are trying to implement.
For example if you call getUtilDateFromString("2014-12-06 12:26:11") it will not work because the SimpleDateFormat will be expecting a String date with the format "yyyy/MM/dd HH:mm:ss".
If you call getUtilDateFromString("2014/12/06 12:26:11") will work perfectly fine because the
String date fits the format "yyyy/MM/dd HH:mm:ss".
Hope it helps.
I am trying to format dates entered by my application user using SimpleDateFormat but I always get an error:
01/28/2014java.text.ParseException: Unparseable date: "01/28/2014"
The code I am using to format the date is as follows:
Date rDate, dDate;
String Date1 = request.getParameter("Date1");
String Date2 = request.getParameter("Date2");
//Here the date get display for example as 01/29/2014 (i.e. MM/DD/YYYY)
System.out.println("Date1:: "+ Date1);
System.out.println("Date2:: "+ Date2);
SimpleDateFormat parseRDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
SimpleDateFormat parseDDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
try {
//#########Crashes in the next two lines#########...
rDate = (Date)parseRDate.parse(Date1);
dDate = (Date)parseDDate.parse(Date2);
} catch (ParseException e) {
e.printStackTrace();
}
Can someone please help me by telling me what I am doing wrong here?
Thanks for your time
You need to match the DateFormat pattern to your input String
SimpleDateFormat parseRDate = new SimpleDateFormat("MM/dd/yyyy");
Any idea how I can convert the format from MM/dd/YYYY to yyyy-MM-dd HH:mm:ss?
All you need to do is use a separate SimpleDateFormat instance for formatting
SimpleDateFormat output = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
System.out.println(output.format(date1));
As you say, Date1 is of the form MM/dd/yyyy... but you're trying to parse it with a format of yyyy-MM-dd HH:mm:ss.
The pattern you parse to the SimpleDateFormat constructor has to match the format of the data itself. (What did you think you were specifying in the constructor?)
Note that the code you've provided isn't doing and formatting at all - just parsing.
You should also work out which time zone you're interested in, and which Locale. Personally I think it's clearer to specify both of those explicitly - even if you want the system default ones.
(If you're doing any significant amount of date/time work, you should also consider using Joda Time, which is a much more pleasant date/time API. I'd also consider more useful exception handling, and following Java naming conventions...)
You specify the format yyyy-MM-dd HH:mm:ss in the constructor and then accept a completely different format (MM/dd/yyyy) as input. You need to make the actual format match the expected format.
Examine the following (for comparison):
Date rDate, dDate;
SimpleDateFormat parseRDate = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
SimpleDateFormat parseDDate = new SimpleDateFormat("MM/dd/yyyy");
try {
rDate = (Date)parseRDate.parse("2014-01-28 12:22:22");
dDate = (Date)parseDDate.parse("01/28/2014");
} catch (ParseException e) {
e.printStackTrace();
}
The string passed to the constructor is what tells SimpleDateFormat how to read the input you give it later.
I have a string that contains a date, in the following format:
dd-mm-yyyy
with the month that is all lowercased. For example:
25-aug-2019
Now i tried to use SimpleDateFormat to convert my string to a Date, but i have the following exception:
java.text.ParseException: Unparseable date: "25-aug-2019"
at java.text.DateFormat.parse(Unknown Source)
at org.whoislibrary.servers.WhoisCom.parseResponse(WhoisCom.java:37)
at org.whoislibrary.WhoisAbstract.executeQuery(WhoisAbstract.java:44)
at org.whoislibrary.WhoisCommand.executeQuery(WhoisCommand.java:69)
at org.whoislibrary.WhoisMain.main(WhoisMain.java:10)
This is the code that i used:
DateFormat df = new SimpleDateFormat("dd-MM-yyyy");
try {
Date expDate = df.parse(dateString).trim());
System.out.println(expDate.toString());
} catch (ParseException e) {
e.printStackTrace();
}
I think the problem is that MM refers to month name that start with a capital letter (Aug, Jul etc). There is an option, or a class like SimpleDateFormat that help me to convert that string into a Date. or it must be done Manually?
Well in your code you have:
new SimpleDateFormat("dd-MM-yyyy")
Which should be:
new SimpleDateFormat("dd-MMM-yyyy")
Since the month part in your string has 3 letters (MMM) and not 2 (MM)
use dd-MMM-yyyy
Your date "25-aug-2019" is in "dd-MMM-yyyy" format not "dd-MM-yyyy". So you get parse error. You should use "dd-MMM-yyyy" while creating SimpleDateFormat object.
DateFormat df = new SimpleDateFormat("dd-MMM-yyyy");
try {
Date expDate = df.parse("25-aug-2019");
System.out.println(expDate.toString());
} catch (ParseException e) {
e.printStackTrace();
}
Refer javaDocs java.text.SimpleDateFormat
I'm parsing this date format from XML:=> "2011-12-06T07:41:14.016+00:00", and I'm getting this error:
W/System.err(574): java.text.ParseException: Unparseable date:
"2011-12-06T07:41:14.016+00:00"
I'm certain it's the formatting statement I'm using, but I can't figure out what it SHOULD be...
Here's the statement I'm using:
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSZ:ss");
I get how to create a format for this part: "2011-12-06T07:41:14....", it's this other part :=> ".016+00:00" that's throwing me for a loop.
I've looked for answers here already: Android SimpleDateFormat Page, and here Oracle SimpleDateFormat Page, but I fear I'm missing something fundamental....
Do you have any suggestions on a proper format statement for that particular date format, or pertinent resources to peruse?
Big Thanks in advance!
The "Z" pattern matches +0000 and not +00:00 so if you remove the last ":" before you parse then it will work.
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSZ");
try {
Date myDate = sdf.parse( "2011-12-06T07:41:14.016+00:00".replaceAll( "([0-9\\-T]+:[0-9]{2}:[0-9.+]+):([0-9]{2})", "$1$2" ) );
System.out.println( myDate );
} catch (ParseException e) {
e.printStackTrace();
}
"yyyy-MM-dd'T'HH:mm:ss.SSSZ" 2001-07-04T12:08:56.235-0700
The :ss at the end looks incorrect
As one of the answers in the question I linked shows, you can use
String string = "2011-12-06T07:41:14.016+00:00";
Calendar cal = DatatypeConverter.parseDateTime(string);
What's the best way to parse an XML dateTime in Java?