Develop Reference

Get double value from currency frormatted string

I'm using NumberFormat in my app to get the currency formatted Strings. Like if a user inputs 12.25 in the field then it will be changed to $12.25 based on locale. Here the Locale is en-US.
Now I want to get the 12.25 value as double form the formatted string.
To do that I have used:
NumberFormat.getCurrencyInstance().parse("$12.25").doubleValue();
Above line giving me the result of 12.25 which is my requirement. But suppose a user changed his locale to something else en-UK. Now for that locale above statement is giving me parseException. Because for the locale en-UK, currency string $12.25 is not parsable.
So is there any way to get the double value from currency formatted string irrespective of what the locale is?

I don't know either the below solution is perfect or not but it is working according to my requirement.
try {
return NumberFormat.getCurrencyInstance().parse(currency).doubleValue();
} catch (ParseException e) {
e.printStackTrace();
// Currency string is not parsable
// might be different locale
String cleanString = currency.replaceAll("\\D", "");
try {
double money = Double.parseDouble(cleanString);
return money / 100;
} catch (Exception ex) {
ex.printStackTrace();
}
}
return 0;

What about
new Double(NumberFormat.getCurrencyInstance().parse("$12.25").doubleValue());
and also you could use
Double.valueOf() creates a Double object so .doubleValue() should not be necessary.
also Double.parseDouble(NumberFormat.getCurrencyInstance().parse("$12.25"));
could work

Here's a little algorithm that may help you :
public static void main(String[] args) {
String cash = "R$1,000.75"; //The loop below will work for ANY currency as long as it does not start with a digit
boolean continueLoop = true;
char[] cashArray = cash.toCharArray();
int cpt = 0;
while(continueLoop){
try
{
double d = Double.parseDouble(cashArray[cpt]+"");
continueLoop = false;
}catch(NumberFormatException nfe){
cpt += 1;
}
}
System.out.println(cpt);
//From here you can do whatever you want....
String extracted = cash.substring(cpt);
NumberFormat format = NumberFormat.getInstance(Locale.US); //YOUR REQUIREMENTS !!!! lol
try {
Number youValue = format.parse(extracted);
System.out.println(youValue.doubleValue());
} catch (ParseException ex) {
//handle your parse error here
}
}
You should get as result here in the output:
2
1000.75

Why am I getting a IllegalArgumentException in my Android App?

I am working on an Android app, and I am getting the most annoying NFE for, what seems like, no reason.
So, here is what I have in my app:
int amount = 7;
NumberFormat myNumberFormat = NumberFormat.getCurrencyInstance(Locale.US);
TextView money = (TextView)findViewById(R.id.money_view);
money.setText(myNumberFormat.format(amount));
And for some reason, I am getting a NFE when I try to get the NumberFormat currency instance. As a test, to make sure I wasn't going crazy, I also wrote this stand-alone:
import java.util.Locale;
import java.text.NumberFormat;
public class NFETest {
public static void main(String[] args){
int amount = 7;
NumberFormat myNumberFormat = NumberFormat.getCurrencyInstance(Locale.US);
System.out.println(myNumberFormat.format(amount));
}
}
The stand-alone works with no problems. So, what gives ... why am I getting this error?
EDIT:
Looking further down LogCat, it looks like it is an IllegalArgumentException instead of a NFE. However, this doesn't make it any less strange. I have "Locale.US" set, so that shouldn't make any difference. However, some quick googling says it may be my tablet thinking it is not in the US. It may be a hardware issue, and not software after all.

Use this code
int amount = 7;
NumberFormat myNumberFormat = NumberFormat.getCurrencyInstance(Locale.US);
TextView money = (TextView)findViewById(R.id.money_view);
money.setText(String.valueOf(myNumberFormat.format(amount)));

Just use wrappers(Integer, Float, Double, BigDecimal or others):
public static void main(String[] args){
Integer amount = 7;
NumberFormat myNumberFormat = NumberFormat.getCurrencyInstance(Locale.US);
System.out.println(myNumberFormat.format(amount));
int amount2 = 11;
System.out.println(myNumberFormat.format(Integer.valueOf(amount2)));
}
In other solution, you may use Integer.valueOf(..) Look like here: http://ideone.com/0ZKsS3
But your example works too. Look at online compiler: http://ideone.com/0ZKsS3

try {
int amount = 7;
NumberFormat myNumberFormat = NumberFormat.getCurrencyInstance(Locale.US);
TextView money = (TextView)findViewById(R.id.money_view);
money.setText(String.valueOf(myNumberFormat.format(amount)));// your error is here.
//go on as normal
} catch (NumberFormatException e) {
//handle error
}
you should catch the exception and handle the parse error accordingly.
Or you should try for different values :
double num = 1323.526;
NumberFormat defaultFormat = NumberFormat.getCurrencyInstance();
System.out.println("US: " + defaultFormat.format(num));
Locale swedish = new Locale("sv", "SE");
NumberFormat swedishFormat = NumberFormat.getCurrencyInstance(swedish);
System.out.println("Swedish: " + swedishFormat.format(num));
OUTPUT :
US: $1,323.53
Swedish: 1 323,53 kr
Hope this time it will help you to catch your problem.

NumberFormat : setMaximumFractionDigits - not giving expected results

Trying to figure out why the following code is not outputting expecting results. Please advise. Thank you.
import java.text.*;
public class Test {
public static void main(String[] args) {
String s = "987.123456";
double d = 987.123456d;
NumberFormat nf = NumberFormat.getInstance();
nf.setMaximumFractionDigits(5);
System.out.println(nf.format(d) + " ");
try {
System.out.println(nf.parse(s));
} catch (Exception e) {
System.out.println("got exc");
}
}
}
Output:
987.12346 // Expected 987.12345 not 987.12346
987.123456

Your second print doesn't format the double you've parsed.
// System.out.println(nf.parse(s));
System.out.println(nf.format(nf.parse(s))); // <-- 987.12346
To get the output you asked for, you can add a call to NumberFormat#setRoundingMode(RoundingMode) - something like
nf.setMaximumFractionDigits(5);
nf.setRoundingMode(RoundingMode.DOWN);

Is java.text.DecimalFormat.setMaximumIntegerDigits() being ignored?

I've been trying to use java.text.DecimalFormat to validate user input of decimal numbers. I know the maximum number of digits both before and after the decimal place that are to be allowed - if there are more of either, that's an input error by the user. It seems like setMaximumIntegerDigits() is not being enforced though. (Or if I use a pattern, rather than the min/max setters, the maximum digits implied by the pattern seem again to be ignored.)
What am I missing?
(Apologies if this is a duplicate. I can find a lot of questions about DecimalFormat on SO - but none that seem to be quite this problem.)
Here's the sample code and a unit test (distilled from real code):
---- Numbers.java
/** Utility for creating and using a standard DecimalFormat. */
package com.myco.util;
import java.math.BigDecimal;
import java.text.DecimalFormat;
import java.text.ParsePosition;
public final class Numbers {
private Numbers() { ; }
public static DecimalFormat standardFormat() {
DecimalFormat df = new DecimalFormat();
df.setParseBigDecimal(true);
df.setMaximumIntegerDigits(3);
df.setMinimumIntegerDigits(1);
df.setMaximumFractionDigits(2);
df.setMinimumFractionDigits(0);
return df;
}
// Alternatively, approach, also doesn't work.
/*public static DecimalFormat standardFormat() {
DecimalFormat df = new DecimalFormat("##0.##");
df.setParseBigDecimal(true);
return df;
}*/
public static BigDecimal match(DecimalFormat df, String s)
throws NumberFormatException {
if(s == null || (s = s.trim()).length() == 0)
return null;
ParsePosition pp = new ParsePosition(0);
Number n = df.parse(s, pp);
if(n == null || pp.getIndex() != s.length())
throw new NumberFormatException(
"Invalid BigDecimal for format '"+df+"'!");
return BigDecimal.class.cast(n);
}
}
By my reading of the Javadoc for DecimalFormat the test for 1000 (below) should pass
(that is, it should throw an exception) but it doesn't.
http://docs.oracle.com/javase/7/docs/api/java/text/DecimalFormat.html
---- Numbers_Test.java
package com.myco.util;
import java.text.DecimalFormat;
import junit.framework.TestCase;
public final class Numbers_Test extends TestCase {
public void testOkay() {
DecimalFormat df = Numbers.standardFormat();
assertEquals("0.1", Numbers.match(df, "0.1").toString());
assertEquals("4.2", Numbers.match(df, "4.2").toString());
assertEquals("999.99", Numbers.match(df, "999.99").toString());
}
public void testFail() {
DecimalFormat df = Numbers.standardFormat();
try {
// Returns 1000 (as BigDecimal) but should fail (?).
Numbers.match(df, "1000");
fail();
}
catch(NumberFormatException e) { ; }
}
}

Convert Double to String Android

i try to save my String value (50000000) into Double format, while I'm trying to show it again in my Edittext, I can't to show it in normal format, and it show as (5E+07), is there any way to convert from double format into String format?
I have try this way :
Double value_doble = 5E+07;
EditText.setText(String.valueOf(value_doble);
but its Still show as 5E+07, so my question how to convert from Double to String?

You can try this:
System.out.println(new BigDecimal(value_doble).toString());

Is this what you are looking for?
public static void main(String[] args) {
Double value_doble = 5E+07;
NumberFormat formatter = new DecimalFormat("###.#####");
String f = formatter.format(value_doble);
System.out.println(f);
}

I agree that you need use Formater
http://docs.oracle.com/javase/tutorial/i18n/format/decimalFormat.html
but the pattern should be look like this:
import java.text.DecimalFormat;
import java.text.NumberFormat;
public class DoubleFormat {
public static void main(String[] args) {
double valueD = 5E+07;
NumberFormat format = new DecimalFormat("#");
System.out.println(format.format(valueD));
}
}