Related
Question ahead:
why does in Java the call coll.contains(null) fail for ImmutableCollections?
I know, that immutable collections cannot contain null-elements, and I do not want to discuss whether that's good or bad.
But when I write a Function, that takes a (general, not explicit immutable) Collection, it fails upon checking for nulls. Why does the implementation not return false (which is actually the 'correct' answer)?
And how can I properly check for nulls in a Collection in general?
Edit:
with some discussions (thanks to the commenters!) I realized, that I mixed up two things: ImmutableCollection from the guava library, and the List returned by java.util.List.of, being some class from ImmutableCollections. However, both classes throw an NPE on .contains(null).
My problem was with the List.of result, but technically the same would happen with guaves implementation. [edit: It does not]
I am distressed by this discussion!
Collections that do this have been a pet peeve of mine since before I wrote the first collections that eventually became Guava. If you find any Guava collection that throws NPE just because you asked it a perfectly innocent question like .contains(null), please file a bug! We hate that crap.
EDIT: I was so distressed that I had to go back to look at my 2007 changelist that first created ImmutableSet and saw literally this:
#Override public boolean contains(#Nullable Object target) {
if (target == null) {
return false;
}
ahhhhh.
why does in Java the call coll.contains(null) fail for ImmutableCollections?
Because the design team (the ones who have created guava) decided that, for their collections, null is unwanted, and therefore any interaction between their collections and a null check, even in this case, should just throw to highlight to the programmer, at the earliest possible opportunity, that there is a mismatch. Even where the established behaviour (as per the existing implementations in the core runtime itself, such as ArrayList and friends, as well as the javadoc), rather explicitly go the other way and say that a non-sequitur check (is this pear part of this list of apples?) strongly suggests that the right move is to just return false and not throw.
In other words, guava messed up. But now that they have done so, going back is potentially backwards compatibility breaking. It really isn't very - you are replacing an exception thrown with a false return value; presumably code could be out there that relies on the NPE (catching it and doing something different from what the code would do had contains(null) returned false instead of throwing) - but that's a rare case, and guava breaks backwards compatibility all the time.
And how can I properly check for nulls in a Collection in general?
By calling .contains(null), just as you are. The fact that guava doesn't do it right doesn't change the answer. You might as well ask 'how do I add elements to a list', and counter the answer of "well, you call list.add(item) to do that" with: Well, I have this implementation of the List interface that plays Rick Astley over the speaker instead of adding to the list, so, I reject your answer.
That's.. how java and interfaces work: You can have implementations of them, and the only guardianship that they do what the interface dictates they must, is that the author understands there is a contract that needs to be followed.
Now, normally a library so badly written they break contract for no good reason*, isn't popular. But guava IS popular. Very popular. That gets at a simple truth: No library is perfect. Guava's API design is generally quite good (in my opinion, vastly superior to e.g. Apache commons libraries), and the team actively spends a lot of time debating proper API design, in the sense that the code that one would write using guava is nice (as defined by: Easy to understand, has few surprises, easy to maintain, easy to test, and probably easy to mutate to deal with changing requirements - the only useful definition for nebulous terms like 'nice' or 'elegant' code - it's code that does those things, anything else is pointless aesthetic drivel). In other words, they are actively trying, and they usually get it right.
Just, not in this case. Work around it: return item != null && coll.contains(item); will get the job done.
There is one major argument in favour of guava's choice: They 'contract break' is an implicit break - one would expect that .contains(null) works, and always returns false, but it's not explicitly stated in the javadoc that one must do this. Contrast to e.g. IdentityHashMap, which uses identity equivalence (a==b) and not value equality (a.equals(b)) in its .containsKey etc implementations, which explicitly goes against the javadoc contract as stated in the j.u.Map interface. IHM has an excellent reason for it, and highlights the discrepancy, plus explains the reason, in the javadoc. Guava isn't nearly as clear about their bizarre null behaviour, but, here's a crucial thing about null in java:
Its meaning is nebulous. Sometimes it means 'empty', which is bad design: You should never write if (x == null || x.isEmpty()) - that implies some API is badly coded. If null is semantically equivalent to some value (such as "" or List.of()), then you should just return "" or List.of(), and not null. However, in such a design, list.contains(null) == false) would make sense.
But sometimes null means not found, irrelevant, not applicable, or unknown (for example, if map.get(k) returns null, that's what it means: Not found. Not 'I found an empty value for you'). This matches with what NULL means in e.g. SQL. In all those cases, .contains(null) should be returning neither true nor false. If I hand you a bag of marbles and ask you if there is a marble in there that is grue, and you have no idea what grue means, you shouldn't answer either yes or no to my query: Either answer is a meaningless guess. You should tell me that the question cannot be answered. Which is best represented in java by throwing, which is precisely what guava does. This also matches with what NULL does in SQL. In SQL, v IN (x) returns one of 3 values, not 2 values: It can resolve to true, false, or null. v IN (NULL) would resolve to NULL and not false. It is answering a question that can't be answered with the NULL value, which is to be read as: Don't know.
In other words, guava made a call on what null implies which evidently does not match with your definitions, as you expect .contains(null) to return false. I think your viewpoint is more idiomatic, but the point is, guava's viewpoint is different but also consistent, and the javadoc merely insinuates, but does not explicitly demand, that .contains(null) returns false.
That's not useful whatsoever in fixing your code, but hopefully it gives you a mental model, and answers your question of "why does it work like this?".
This question already has answers here:
object==null or null==object?
(11 answers)
Closed 7 years ago.
I have seen various codes of my seniors and they have used this at many places.What effect does it have? why cant they include anything != null. This is true for below thing too
"true".equals(x).
Why is this so?
anything != null is exactly equivalent to null != anything.
On the other hand, "true".equals(x) avoids the need to check if x is null when doing x.equals("true").
The reason for including constants on the left hand side of an equals expression is to avoid NullPointerException even when the variable is null. This also improves the readability of the expression.
That being said, null!=something is a personal choice and I would prefer using something!=null.
These are two separate practices.
Using null on the left side when comparing to null ensures that you won't, by mistake, use = instead of ==. However, this is a practice taken from languages other than Java, as in Java the expression
if ( something = null )
is going to fail as it does not resolve to a boolean value. In other languages it may be permissible to use a condition whose value is actually a pointer.
Thus this practice has no meaning in Java.
The second practice, as you were told, has to do with preventing a NullPointerException. It should be noted that this practice is controversial, because it allows a null to propagate to a later point in the program, and that usually means that it will be harder to find when it causes a bug.
This is called a Yoda condition. Among other things, it helps prevent an accidental assignment due to a missing = or !, as in foo = null. The reverse, null = foo, would not even compile.
That said, it is purely a stylistic preference. foo != null is logically equivalent to null != foo.
That check is so the program ensures the variable in question has been initialized before reading it. If a program tries to access a null variable, it will crash (specifically in Java it will throw a NullPointerException). It is a critical aspect of defensive programming.
As far as ordering, the evaluation of whether something is null or not is commutative. Meaning:
something != null
Is the same as
null != something
It is all a matter of personal preference. And as #manouti explains above, "true".equals(x) avoids the need to check if x is null when doing x.equals("true"), so you save a line of code.
Seems that some people prefer null != anything, because anything might be quite long expression, so writing null first makes it visible in the narrow window and simplifies code reading ("ok, we just check if something is not null"). But it's totally a matter of style.
As for "true".equals(x), it's well explained by #manouti.
This question already has answers here:
Is the ternary operator faster than an "if" condition in Java [duplicate]
(9 answers)
Closed 9 years ago.
This is something I was thinking, when I searched at Google I couldn't find the answer (maybe I don't know the keywords). Just at a curiosity level, no implementation in any project.
Which is faster:
if (bool)
return true;
else
return false;
or
bool ? true : false;
Are they equal?
Why?
One is faster than another in every language, in every system?
(If someone knows the answer for microcontrollers, Obj-C for iOS or Java, I would really appreciate your answer to my question)
EDIT:
I didn't know that bool ? true : false is called ternary, as I said "I don't know the keywords".
This Question has a number of problems.
First, languages don't have performance characteristics. You cannot measure the performance of a language. You can only measure an implementation of a language. And any given language can have lots of different implementations.
The idea that all languages will support constructs equivalent to those two is naive ... and incorrect.
The idea that something might perform the same way across all languages and all implementations and all systems, is fanciful.
The idea that anyone would know ... for all languages, platforms, hardware, etcetera is fanciful.
It is unclear what those two utterances mean. In Java (for example) they don't mean the same thing ... the second one is not a valid statement ... even if you add a ; ... and even if it was, it doesn't return anything.
Having said that ... in Java (assuming you add a return in the 2nd case):
they mean the same thing, and
a modern Hotspot JIT compiler is likely to compile those to equivalent native code; i.e. there is likely to be no performance difference.
In Java, at least, there's no difference between them other than the ability to debug line-by-line in the first case. The compiled bytecode is most likely exactly the same for both cases. I suspect the same is true in every environment you are asking about.
The speed difference occurs at the machine code level, and at that level it can't even be guessed which of your idioms compiled into it. Therefore your answer is: there is no correlation between the choice of your idioms and performance. Mostly it should be exactly the same, but if it isn't, there will be no generally applicable explanation.
What is usually faster is
return bool;
This avoids any possible branching produced by the conditional, being faster on a CPU with expensive branch misses. An optimizing compiler might remove the branch anyway, but since this is language agnostic it can't be guaranteed.
The conditional expression versus the ternary is debatable. This is one of those ones where you shouldn't be able to notice a difference in either case.
If you have a single if/else (which that should be, there is no need for an else if in there), the Ternary will be faster.
However, it is more difficult to add additional checks, since you need to chain the ternary:
(conditional) ? ((conditional) ? true : false) : ((conditional) ? true : false) so it becomes difficult to read.
The best choice if expansion is possible is to use a switch which is faster than an if/else check. This is especially true if you want to allow multiple if's to result in the same result, but is not useful if you're using datatype checking since it uses loose comparisons (== and never === checks). Unlike an if/elseif/else pair, the switch can potentially use more memory and time if you never break.
Performance wise both Ternary and if-else are same.
Ternary operators are just shorthand. They compile into the equivalent if-else statement.
Are they equal?
Logically yes. The do the same thing here. The second one is called ternary operator.
One is faster than another in every language, in every system?
In java there is no difference. I doubt if there is any performance in other language also. Even if so, then I guess the difference will be very negligible. You better concentrate on more readable codes. The first one is definitely more readable.
They are pretty much equal in performance, or if not there is a very, VERY trivial difference.
For something simple like what you asked for I would use the ternary operator ?: because it is much shorter and still very readable.
When you need to do multiple statements, use if-else.
Remember that you can also use ?: in return statements:
return bool ? yes : no;
EDIT: It looks like you just want to return the value of the boolean. If you do then all you have to type is: return bool;
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
What is the difference between these (bCondition == NULL) and (NULL==bCondition)?
please see the below code:-
if(myVariable==5)
{
//some logic
}
one of my friends says that this is not a good way to write the code as its not per guidelines, however he dont have any reason to it. Is there is a chance of exception with above code or accidental modification?? According to him the better way would have been
if(5==myVariable)
{
//some logic
}
please let me know which is a better way and why??? Do provide links if u have any.
The only reason to write:
5 == variable
instead of
variable == 5
is that in the former case if you incorrectly put an assignment (single =) in place you will get a compile time error because you are trying to overwrite a constant.
However any decent compiler will give you a warning if you do:
if (variable = 5)
so IMHO it's not worth worrying about. I always use the latter if (var == num) form.
However in Java there is a common pattern that is worth using. When testing a string for equality, one should use:
if ("constant".equals(variable)) { ... }
instead of:
if (variable.equals("constant")) { ... }
since the latter can trigger a null pointer exception, and the former cannot.
The reversal is preferable in some languages like C, where
if (x = 5) {
...
}
would accidentally assign x to the value 5 if you mistype = instead of ==. By reversing the two arguments the compiler would rightfully object to you reassigning the value 5.
Unlike C/C++, for languages such as Java it's not such an issue since
if (x = 5) {
...
}
isn't a valid statement. I still follow the above practise however. I don't have to rethink when swapping between Java and C/C++.
Both are same. select which ever you find more readable.. I would go with first
For that specific case, it's technically safer to do 5 == variable because then if you accidentally say 5 = variable the compiler will complain. On the other hand, variable = 5 is perfectly legal.
This convention is to prevent you from accidentally writing if (myVariable=5) when you mean if (myVariable==5).
For ==, it doesn't matter a bit what order you do it in.
Your friend mentioned "guidelines"-- perhaps it's a business rule? Albeit an arbitrary and semi-pointless one...
It's immaterial. I prefer the first one, because it's more readable.
I hope you're aware that using == is not always correct for reference types. In those cases you should prefer equals. THEN it matters, because you want to avoid null pointer exceptions. It's best to dereference the instance that cannot be null in that case.
There is no such guildline I found.
First approach should be followed because it is more readable.
i think if you what to know if they are equals it's fine then.
but if you want to know about string, then i more appropriated use '.equals'.
e.g:
object.equals("something");
The only thing I can think of is to avoid possible syntax errors of the kind constant = expression, or to avoid mangled operator overload in C++. In Java both expressions are syntatically valid and picking one over the other is a matter of choice.
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Closed 11 years ago.
In the same spirit of other platforms, it seemed logical to follow up with this question: What are common non-obvious mistakes in Java? Things that seem like they ought to work, but don't.
I won't give guidelines as to how to structure answers, or what's "too easy" to be considered a gotcha, since that's what the voting is for.
See also:
Perl - Common gotchas
.NET - Common gotchas
"a,b,c,d,,,".split(",").length
returns 4, not 7 as you might (and I certainly did) expect. split ignores all trailing empty Strings returned. That means:
",,,a,b,c,d".split(",").length
returns 7! To get what I would think of as the "least astonishing" behaviour, you need to do something quite astonishing:
"a,b,c,d,,,".split(",",-1).length
to get 7.
Comparing equality of objects using == instead of .equals() -- which behaves completely differently for primitives.
This gotcha ensures newcomers are befuddled when "foo" == "foo" but new String("foo") != new String("foo").
I think a very sneaky one is the String.substring method. This re-uses the same underlying char[] array as the original string with a different offset and length.
This can lead to very hard-to-see memory problems. For example, you may be parsing extremely large files (XML perhaps) for a few small bits. If you have converted the whole file to a String (rather than used a Reader to "walk" over the file) and use substring to grab the bits you want, you are still carrying around the full file-sized char[] array behind the scenes. I have seen this happen a number of times and it can be very difficult to spot.
In fact this is a perfect example of why interface can never be fully separated from implementation. And it was a perfect introduction (for me) a number of years ago as to why you should be suspicious of the quality of 3rd party code.
Overriding equals() but not hashCode()
It can have really unexpected results when using maps, sets or lists.
SimpleDateFormat is not thread safe.
There are two that annoy me quite a bit.
Date/Calendar
First, the Java Date and Calendar classes are seriously messed up. I know there are proposals to fix them, I just hope they succeed.
Calendar.get(Calendar.DAY_OF_MONTH) is 1-based
Calendar.get(Calendar.MONTH) is 0-based
Auto-boxing preventing thinking
The other one is Integer vs int (this goes for any primitive version of an object). This is specifically an annoyance caused by not thinking of Integer as different from int (since you can treat them the same much of the time due to auto-boxing).
int x = 5;
int y = 5;
Integer z = new Integer(5);
Integer t = new Integer(5);
System.out.println(5 == x); // Prints true
System.out.println(x == y); // Prints true
System.out.println(x == z); // Prints true (auto-boxing can be so nice)
System.out.println(5 == z); // Prints true
System.out.println(z == t); // Prints SOMETHING
Since z and t are objects, even they though hold the same value, they are (most likely) different objects. What you really meant is:
System.out.println(z.equals(t)); // Prints true
This one can be a pain to track down. You go debugging something, everything looks fine, and you finally end up finding that your problem is that 5 != 5 when both are objects.
Being able to say
List<Integer> stuff = new ArrayList<Integer>();
stuff.add(5);
is so nice. It made Java so much more usable to not have to put all those "new Integer(5)"s and "((Integer) list.get(3)).intValue()" lines all over the place. But those benefits come with this gotcha.
Try reading Java Puzzlers which is full of scary stuff, even if much of it is not stuff you bump into every day. But it will destroy much of your confidence in the language.
List<Integer> list = new java.util.ArrayList<Integer>();
list.add(1);
list.remove(1); // throws...
The old APIs were not designed with boxing in mind, so overload with primitives and objects.
This one I just came across:
double[] aList = new double[400];
List l = Arrays.asList(aList);
//do intense stuff with l
Anyone see the problem?
What happens is, Arrays.asList() expects an array of object types (Double[], for example). It'd be nice if it just threw an error for the previous ocde. However, asList() can also take arguments like so:
Arrays.asList(1, 9, 4, 4, 20);
So what the code does is create a List with one element - a double[].
I should've figured when it took 0ms to sort a 750000 element array...
this one has trumped me a few times and I've heard quite a few experienced java devs wasting a lot of time.
ClassNotFoundException --- you know that the class is in the classpath BUT you are NOT sure why the class is NOT getting loaded.
Actually, this class has a static block. There was an exception in the static block and someone ate the exception. they should NOT. They should be throwing ExceptionInInitializerError. So, always look for static blocks to trip you. It also helps to move any code in static blocks to go into static methods so that debugging the method is much more easier with a debugger.
Floats
I don't know many times I've seen
floata == floatb
where the "correct" test should be
Math.abs(floata - floatb) < 0.001
I really wish BigDecimal with a literal syntax was the default decimal type...
Not really specific to Java, since many (but not all) languages implement it this way, but the % operator isn't a true modulo operator, as it works with negative numbers. This makes it a remainder operator, and can lead to some surprises if you aren't aware of it.
The following code would appear to print either "even" or "odd" but it doesn't.
public static void main(String[] args)
{
String a = null;
int n = "number".hashCode();
switch( n % 2 ) {
case 0:
a = "even";
break;
case 1:
a = "odd";
break;
}
System.out.println( a );
}
The problem is that the hash code for "number" is negative, so the n % 2 operation in the switch is also negative. Since there's no case in the switch to deal with the negative result, the variable a never gets set. The program prints out null.
Make sure you know how the % operator works with negative numbers, no matter what language you're working in.
Manipulating Swing components from outside the event dispatch thread can lead to bugs that are extremely hard to find. This is a thing even we (as seasoned programmers with 3 respective 6 years of java experience) forget frequently! Sometimes these bugs sneak in after having written code right and refactoring carelessly afterwards...
See this tutorial why you must.
Immutable strings, which means that certain methods don't change the original object but instead return a modified object copy. When starting with Java I used to forget this all the time and wondered why the replace method didn't seem to work on my string object.
String text = "foobar";
text.replace("foo", "super");
System.out.print(text); // still prints "foobar" instead of "superbar"
I think i big gotcha that would always stump me when i was a young programmer, was the concurrent modification exception when removing from an array that you were iterating:
List list = new ArrayList();
Iterator it = list.iterator();
while(it.hasNext()){
//some code that does some stuff
list.remove(0); //BOOM!
}
if you have a method that has the same name as the constructor BUT has a return type. Although this method looks like a constructor(to a noob), it is NOT.
passing arguments to the main method -- it takes some time for noobs to get used to.
passing . as the argument to classpath for executing a program in the current directory.
Realizing that the name of an Array of Strings is not obvious
hashCode and equals : a lot of java developers with more than 5 years experience don't quite get it.
Set vs List
Till JDK 6, Java did not have NavigableSets to let you easily iterate through a Set and Map.
Integer division
1/2 == 0 not 0.5
Using the ? generics wildcard.
People see it and think they have to, e.g. use a List<?> when they want a List they can add anything to, without stopping to think that a List<Object> already does that. Then they wonder why the compiler won't let them use add(), because a List<?> really means "a list of some specific type I don't know", so the only thing you can do with that List is get Object instances from it.
(un)Boxing and Long/long confusion. Contrary to pre-Java 5 experience, you can get a NullPointerException on the 2nd line below.
Long msec = getSleepMsec();
Thread.sleep(msec);
If getSleepTime() returns a null, unboxing throws.
The default hash is non-deterministic, so if used for objects in a HashMap, the ordering of entries in that map can change from run to run.
As a simple demonstration, the following program can give different results depending on how it is run:
public static void main(String[] args) {
System.out.println(new Object().hashCode());
}
How much memory is allocated to the heap, or whether you're running it within a debugger, can both alter the result.
When you create a duplicate or slice of a ByteBuffer, it does not inherit the value of the order property from the parent buffer, so code like this will not do what you expect:
ByteBuffer buffer1 = ByteBuffer.allocate(8);
buffer1.order(ByteOrder.LITTLE_ENDIAN);
buffer1.putInt(2, 1234);
ByteBuffer buffer2 = buffer1.duplicate();
System.out.println(buffer2.getInt(2));
// Output is "-771489792", not "1234" as expected
Among the common pitfalls, well known but still biting occasionally programmers, there is the classical if (a = b) which is found in all C-like languages.
In Java, it can work only if a and b are boolean, of course. But I see too often newbies testing like if (a == true) (while if (a) is shorter, more readable and safer...) and occasionally writing by mistake if (a = true), wondering why the test doesn't work.
For those not getting it: the last statement first assign true to a, then do the test, which always succeed!
-
One that bites lot of newbies, and even some distracted more experienced programmers (found it in our code), the if (str == "foo"). Note that I always wondered why Sun overrode the + sign for strings but not the == one, at least for simple cases (case sensitive).
For newbies: == compares references, not the content of the strings. You can have two strings of same content, stored in different objects (different references), so == will be false.
Simple example:
final String F = "Foo";
String a = F;
String b = F;
assert a == b; // Works! They refer to the same object
String c = "F" + F.substring(1); // Still "Foo"
assert c.equals(a); // Works
assert c == a; // Fails
-
And I also saw if (a == b & c == d) or something like that. It works (curiously) but we lost the logical operator shortcut (don't try to write: if (r != null & r.isSomething())!).
For newbies: when evaluating a && b, Java doesn't evaluate b if a is false. In a & b, Java evaluates both parts then do the operation; but the second part can fail.
[EDIT] Good suggestion from J Coombs, I updated my answer.
The non-unified type system contradicts the object orientation idea. Even though everything doesn't have to be heap-allocated objects, the programmer should still be allowed to treat primitive types by calling methods on them.
The generic type system implementation with type-erasure is horrible, and throws most students off when they learn about generics for the first in Java: Why do we still have to typecast if the type parameter is already supplied? Yes, they ensured backward-compatibility, but at a rather silly cost.
Going first, here's one I caught today. It had to do with Long/long confusion.
public void foo(Object obj) {
if (grass.isGreen()) {
Long id = grass.getId();
foo(id);
}
}
private void foo(long id) {
Lawn lawn = bar.getLawn(id);
if (lawn == null) {
throw new IllegalStateException("grass should be associated with a lawn");
}
}
Obviously, the names have been changed to protect the innocent :)
Another one I'd like to point out is the (too prevalent) drive to make APIs generic. Using well-designed generic code is fine. Designing your own is complicated. Very complicated!
Just look at the sorting/filtering functionality in the new Swing JTable. It's a complete nightmare. It's obvious that you are likely to want to chain filters in real life but I have found it impossible to do so without just using the raw typed version of the classes provided.
System.out.println(Calendar.getInstance(TimeZone.getTimeZone("Asia/Hong_Kong")).getTime());
System.out.println(Calendar.getInstance(TimeZone.getTimeZone("America/Jamaica")).getTime());
The output is the same.
I had some fun debugging a TreeSet once, as I was not aware of this information from the API:
Note that the ordering maintained by a set (whether or not an explicit comparator is provided) must be consistent with equals if it is to correctly implement the Set interface. (See Comparable or Comparator for a precise definition of consistent with equals.) This is so because the Set interface is defined in terms of the equals operation, but a TreeSet instance performs all key comparisons using its compareTo (or compare) method, so two keys that are deemed equal by this method are, from the standpoint of the set, equal. The behavior of a set is well-defined even if its ordering is inconsistent with equals; it just fails to obey the general contract of the Set interface.
http://download.oracle.com/javase/1.4.2/docs/api/java/util/TreeSet.html
Objects with correct equals/hashcode implementations were being added and never seen again as the compareTo implementation was inconsistent with equals.
IMHO
1. Using vector.add(Collection) instead of vector.addall(Collection). The first adds the collection object to vector and second one adds the contents of collection.
2. Though not related to programming exactly, the use of xml parsers that come from multiple sources like xerces, jdom. Relying on different parsers and having their jars in the classpath is a nightmare.