I have a Java/GWT application. In that there is a list of items. If I click on any item title then that item is opened with full description.
I am using Anchor for the item title, so what I want is when user clicks on item title then in the URL the id of that item is appended to the current URL.
For example, this is my URL:
"http://127.0.0.1:8888/MyApp.html?gwt.codesvr=127.0.0.1:9997#listItem?list"
and I have to append id to the end of the URL like:
"http://127.0.0.1:8888/MyApp.html?gwt.codesvr=127.0.0.1:9997#listItem?list&itemId=55"
Using Window.Location should do your trick : see the doc here
Something like this :
String url = Window.Location.getHref();
url = url + "&itemId=" + itemId;
Window.Location.replace(url);
Although of course, as Crollster pointed out, you should insert your url parameter before the # sign. Give more details on what you're looking for exactly (why do you have to add the parameter manually, does the page have to reload ...)
you can use redirect command in order to add this parameter
response.sendRedirect(your url + itemId=55);
Then you can extract this variable.
I hope this will help.
You can try with javascript coding.When the user clicks on link, get this URL and appends your id to it and reconstruct the URL.
You see that # in the URL? Thats an anchor - you will need your parameter to be added before that, so it looks like this:
http://127.0.0.1:8888/MyApp.html?gwt.codesvr=127.0.0.1:9997&itemId=55#listItem?list
HTH
URIBuilder of Apache HttpComponents offers a convenient method to add parameters and will deal with existing query parameters and anchors.
Related
I would like to use URL http://localhost:8080/blog#section & obtain #section as a variable in getBlog() method.
// localhost:8080/blog#section
#GetMapping("/blog/{section}")
public String getBlog(Model model, #PathVariable("section") String section){
return "blog" + section; // localhost:8080/blog#section
}
The #section part is never sent to server (see this answer),so what you are demanding is impossible.
In fact #section is used for browser to locate the content of a web page, it's not used for server to decide which content to return.
What you are demanding can be easyily achieved with a query like localhost:8080/blog?section=? or a url path like localhost:8080/blog/section
I have a URL and I want to print in my graphical user interface the ID value after the hashtag.
For example, we have www.site.com/index.php#hello and I want to print hello value on a label in my GUI.
How can I do this using Java in Netbeans?
Simple solution is getRef() in URL class:
URL url = new URL("http://www.anyhost.com/index.php#hello");
jLabel.setText(url.getRef());
EDIT: According to #Henry comment:
I would recommend to use the java.net.URI as it also deals with encoding. The Javadocs say: "Note, the URI class does perform escaping of its component fields in certain circumstances. The recommended way to manage the encoding and decoding of URLs is to use URI, and to convert between these two classes using toURI() and URI.toURL()."
and this comment:
Why not just doing uri.getFragment()
URI uri = new URI("http://www.anyhost.com/index.php#hello");
jLabel.setText(uri.getFragment());
Use the String.split() Method.
public static String getId(string url) {
return url.split("#")[1];
}
String.split() returns an array of Strings that are delimited, or "Split," by the value you pass to it, or in this case #.
Because you want only the string after the #, you can just use the second item in the array that it returns by adding [1] to the end of it.
For more on String.split() go to Tutorials Point.
By the way, the part of the URL you are referencing is the Element ID. It is used to jump to an Element on a webpage.
This is a link generated from Google Alerts, and I would like to get where you get redirected. So I need the URL and I would have to retrieve it with Java. I have checked for the response, but no location header redirect.
https://www.google.com/url?rct=j&sa=t&url=http://naija247news.com/2016/03/nigerian-bond-yields-rise-after-cbns-interest-rate-hike-aimed-at-luring-investors/&ct=ga&cd=CAIyGjA3ZmJiYzk0ZDM0N2U2MjU6Y29tOmVuOlVT&usg=AFQjCNGs7HsYSodEUnECfdAatG6KgY18DA
Maybe something like this:
String URL = "https://www.google.com/url?rct=j&sa=t&url=http://naija247news.com/2016/03/nigerian-bond-yields-rise-after-cbns-interest-rate-hike-aimed-at-luring-investors/&ct=ga&cd=CAIyGjA3ZmJiYzk0ZDM0N2U2MjU6Y29tOmVuOlVT&usg=AFQjCNGs7HsYSodEUnECfdAatG6KgY18DA";
String subStr = URL.substring(URL.indexOf("url=") + 1, URL.indexOf("&ct"));
I forgot what the starting and ending position has to be exactly, which indexes. So you would have to verify that and check it creates a substring at the right position. But the basic idea is to cut out the URL you need and nothing more. This is an example for what you forwarded. It could be that you would have to search for something else to know the end of the substring, when you have a different URL (in the provided example I look for &ct, which maybe be not be the case in another URL). You will have to look up several URLs you have to know how to cut out the URL.
At first I had this link to a twitter icon:
#{'/public/images/twitter-icon.png'/}
But now I want to show a Twitter-, Facebook- or LinkedIn icon depending on type. So, I created a FastTag that takes the type as a parameter and the code looks like this:
In the view:
#{myApp.icon contact.type/}
FastTag Java Code:
String type = (String) args.get("arg");
out.print("/public/images/" + type + "-icon.png");
It works fine. But, on our build server we run the app with a prefix on the uri like this
http://ourdomain.com/appname/...
Obviously /public/images... won't work here. So I figured I have to ask the Router for the proper address. I've tried the following with no success:
Router.reverse("/public/images/" + type + "-icon.png");
Router.reverse("/public/");
Router.reverse("staticDir:public");
All three result in a NoRouteFoundException. How can I get the correct route for my icons?
In the routes file I have the default route for static files
GET /public/ staticDir:public
I believe this is what you want:
String imageUrl = Router.reverse(VirtualFile.fromRelativePath("public/images/" + type + "-icon.png"));
Router.reverse be used generate URL form one action!
maybe you can define a route which include your app name and route one action eg:
GET /appname/public/ TestController.test
now,you can use
Router.reverse("TestController.test")
get the URL.
I think it's better to do something like:
GET /img/ staticDir:public/images
And in the template just:
out.print("/img/" + type + "-icon.png");
What is the smartest way to get current page name where request came from? By page I mean the real page name that contains current portlet.
By using something like that you should be ok
ThemeDisplay themeDisplay = (ThemeDisplay) request.getAttribute(WebKeys.THEME_DISPLAY);
String title = themeDisplay.getLayout().getName(themeDisplay.getLocale());
just be aware,themeDisplay.getLocale() could result different char encoding format, use with caution, may cause certain string functions to fail