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Getting an error while using "Generics" in Hibernate Query

I'm using Hibernate in my project and using "Query" Like below.
Query query = em.createQuery("delete from User where name=:name");
query.setParameter("name", "Zigi");
int deleted = query.executeUpdate();
I'm getting the result. When i'm using generics Like below
Query<?> query = em.createQuery("delete from User where name=:name");
query.setParameter("name", "Zigi");
int deleted = query.executeUpdate();
getting the result because "?" is something as wildcard (or) it will accept any datatype
when i'm using the code as below getting some error( java.lang.IllegalArgumentException: Update/delete queries cannot be typed ). i'm using Integer datatype because createQuery return number when it's executed
Query<Integer> query = em.createQuery("delete from User where name=:name", Integer.class);
query.setParameter("name", "Zigi");
int deleted = query.executeUpdate();
Any suggestions. I have to use Generics with specific datatype in it like above code.
thanks in advance

Unfortunately executeUpdate does not allow you to use a typed query.
Instead you can use uniqueResult, and cast to the type that you want:
Query query = em.createQuery("delete from User where name=:name");
query.setParameter("name", "Zigi");
int deleted = (Integer) query.uniqueResult();
Referencing this answer

Query not giving solution in DAO class

when i run my query in database visualizer its working perfectly, but i think there are some issues in syntax when i convert it in my DAO class method.
I want to get whole data against the name provided
In Visualizer:
SELECT first_name,last_name,nic,phone,email FROM x_hr_user where (first_name = 'Irum');
Now in Dao
public List<XHrUser> findXHrUserByNameInTable()
{
String name ="Irum";
Query query = em.createQuery("SELECT xHrNewUserObj.firstName,xHrNewUserObj.lastName, xHrNewUserObj.nic, xHrNewUserObj.phone, xHrNewUserObj.emil FROM XHrUser xHrNewUserObj where (xHrNewUserObj.firstName) = (name)");
List<XHrUser> list = query.getResultList();
return list;
}
Instead of showing single row, it displays whole data Table
Thank you

Your current query is not valid JPQL. It appears that you intended to insert the raw name string into your query, which could be done via a native query, but certainly is not desirable. Instead, use a named parameter in your JPQL query and then bind name to it.
String name = "Irum";
Query query = em.createQuery("SELECT x FROM XHrUser WHERE x.firstName = :name")
.setParameter("name", name);
List<XhrUser> list = query.getResultList();

You have to write query as below. where : is used for variable
Query query = em.createQuery("SELECT xHrNewUserObj.firstName,xHrNewUserObj.lastName, xHrNewUserObj.nic, xHrNewUserObj.phone, xHrNewUserObj.emil FROM XHrUser xHrNewUserObj where (xHrNewUserObj.firstName) = :name");

Hibernate Subqueries

I have a situation where I need to convert a query like :-
select hostname, avg(cpu_utilization_percentage) from cpu_utilization where timestamp In (select distinct(timestamp) from report.cpu_utilization order by timestamp desc limit 6) group by hostname
Now, this data I want to fetch using hibernate so I have used Subqueries:-
// For inner Query
DetachedCriteria subquery = DetachedCriteria.forClass(CpuUtilizationDTO.class);
subquery.setProjection(Projections.distinct(Projections.property("timeStamp"))).addOrder(Order.desc("timeStamp"));
subquery.getExecutableCriteria(session).setMaxResults(6);
// For Outer Query
Criteria query = session.createCriteria(CpuUtilizationDTO.class);
ProjectionList list = Projections.projectionList();
list.add(Projections.groupProperty("hostName"));
list.add(Projections.avg("cpuUtilizationpercentage"));
query.setProjection(list);
List<Object[]> obj= (List<Object[]>)hibernateTemplate.findByCriteria(query);ction(list);
//Now to add subquery into main query I am using
query.add(Subqueries.propertyIn("timeStamp", subquery));
But everytime I am getting the average of entire data. Can anyone please help that where did I miss?

How to pass parameter on jpa query?

I have two entities Like SmsOut and SmsIn. The relation between two entities contains OneToMany where smsIn.id is primary key and smsOut.sms_in_id is foreign key.
Now I want to pass parameter like smsIn.mobileNumber, smsIn.smsText and so on, on the query
SELECT so FROM SmsOut so order by id desc
Following is my database diagram:
Edited
Following is my code :
String sql = "SELECT so FROM SmsOut so WHERE so.smsInId.mobileNumber =:mobileNumber AND so.smsInId.smsText =:smsText AND so.smsInId.shortCode =:shortCode between so.smsOutDate =:startDate and so.smsOutDate =:endDate order by id desc";
Query query = em.createQuery(sql);
query.setParameter("mobileNumber", mobileNumber);
query.setParameter("smsText", smsText);
query.setParameter("shortCode", shortCode);
query.setParameter("smsOutDate", startDate);
query.setParameter("smsOutDate", endDate);
smsOutList = query.getResultList();
and exception is :
SEVERE: line 1:188: expecting "and", found '='
java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: expecting "and", found '=' near line 1, column 188 [SELECT so FROM com.f1soft.SMSC.entities.SmsOut so WHERE so.smsInId.mobileNumber =:mobileNumber AND so.smsInId.smsText =:smsText AND so.smsInId.shortCode =:shortCode between so.smsOutDate =:startDate and so.smsOutDate =:endDate order by id desc]
at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:624)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:96)
Please Help me.
Thanks

You haven't explained the JPA relationship between SmsIn and SmsOut, so I'll assume SmsOut has a getSmsIn() with a relation on the id field.
When you have an EntityManager em, you can call em.createQuery, which is like SQL prepare, and then setParameter:
TypedQuery<SmsOut> q = em.createQuery("SELECT so FROM SmsOut so WHERE so.smsIn.mobileNumber = :number ORDER BY id DESC");
q.setParameter("number", "12345678");
List<SmsOut> results = q.getResultList();
See the Javadoc for Query for the different ways you can specify the parameters.

SELECT so FROM SmsOut so WHERE smsIn.mobileNumber = ? AND smsIn.smsText =? order by id desc
Replace the ? sign with the apropiate values.

between is the problem:
between so.smsOutDate =:startDate and so.smsOutDate =:endDate
try
so.smsOutDate between =:startDate and =:endDate

How to use :value for list values in hibernate?

I know that I can write so:
Query query = session.createSQLQuery(
"select s.stock_code from stock s where s.stock_code = :stockCode")
.setParameter("stockCode", "7277");
List result = query.list();
How I must do if I use list values
select count(*) from skill where skill.id in (1,2,4)
I want replace hardcode values.

Maybe:
Query query = session.createSQLQuery("select count(*) from skill where skill.id in :ids")
.setParameter("ids", Arrays.asList(1,2,4));

Query interface have setParameterList(List<any>) function to set the value in IN Clause in HQL. But in HQL IN Clause have a limit to set the element. If the limit is exceed, memory overflow exception occur.

Have you tried something like this?
Query query = session.createSQLQuery(
"select s.stock_code from stock s where s.stock_code in (:stockCodes)")
.setParameter("stockCodes", "1,2,4");
Does it work for you?