Develop Reference

Java: Replace only exactly matching URL

I want to replace only exactly matching link given in String.
My code is as follows:
String originalString = "<a target=\"_blank\" href=\"http://example.com/\"><span style=\"font-size: 12px;\">ABC</span></a>"
+ "<a target=\"_blank\" href=\"http://example.com/contact/\"><span style=\"font-size: 12px;\">Contact</span></a>";
String replacedString = originalString.replace("http://example.com/", "link1");
System.out.println("Replaced String:" + replacedString);
replacedString = "<a target="_blank" href="link1"><span style="font-size: 12px;">ABC</span></a><a target="_blank" href="link1contact/"><span style="font-size: 12px;">Contact</span></a>"
requiredString = "<a target="_blank" href="link1"><span style="font-size: 12px;">ABC</span></a><a target="_blank" href="link2"><span style="font-size: 12px;">Contact</span></a>"
I get Output as replacedString but required Output should be as requiredString.
Thanks in advance.

Replace the URL with the quotes:
String replacedString = originalString.replace("\"http://example.com/\"", "\"link1\"");
replacedString = replacedString.replace("\"http://example.com/contact/\"", "\"link2\"");

The problem is that http://example.com/contact/ contains http://example.com/.
Use this instead:
String replacedString = originalString.replace("http://example.com/contact/", "link2");
String replacedString2 = replacedString.replace("http://example.com/", "link1");
replacedString2 is the required output

working regex ishttp:\\/\\/example.com.*?(?=\\\\) in java. it matches all occurences of http://example.com and until the next backslash

Java regex , jsoup

How to extract these messages by regex or jsoup ? 19040172b-1、 SQL Server Develop 、zheng 、3-5,7-14 、D-101 ，
<div id="AE9D7F630640426F8457A661607D2B8E-5-2" style="display: none;" class="kbcontent">
19040172b-1
<br>SQL Server Develop
<br>
<font title="teacher">zheng</font>
<br>
<font title="week">3-5,7-14</font>
<br>
<font title="classroom">D-101</font>
<br>
</div>
I have tried the following ways but failed.
1. Pattern pattern = Pattern.compile(">(.*?)<br>");
2. Elements msg = doc.select(":matchesOwn([>.*?<br>])");

1) First, it's never a good idea to parse HTMl with a regex. You can read more about that here.
2)You can just take all text between tags.
Document doc = Jsoup.parse(file, charsetName);
String text= doc.text();
System.out.println(text);

String html = "<div id=\"AE9D7F630640426F8457A661607D2B8E-5-2\" style=\"display: none;\" class=\"kbcontent\"> 19040172b-1 <br>SQL Server Develop <br> <font title=\"teacher\">zheng</font> <br> <font title=\"week\">3-5,7-14</font> <br> <font title=\"classroom\">D-101</font> <br> </div> ";
html = html.replaceAll("<br>", "#~#");
Document doc = Jsoup.parse(html.toString());
String newHtml = doc.text();
String[] ary = newHtml.split("#~#");
This will do the job, yet there may be other clean ways to replace the br tag.

java regular expressions regex

I have problem with extracting data from website.
Im trying to get name of company and price its: SYGNITY and 8,40
<a class="link" href="http://www.money.pl/gielda/spolki-gpw/PLCMPLD00016.html">SYGNITY</a>
</td>
<td class="ac"><img width="12" height="11" src="http://static1.money.pl/i/gielda/chart.gif" title="Pokaż wykres" alt="Pokaż wykres" /></td>
<td class="al">SGN</td>
<td class="ar">8,40</td>
I tried to use this pattern but it doesnt work:
String expr = "<a class=\"link\" href=\"(.+?)\">(.+?)</a>(.+?)<td class=\"ar\">(.+?)</td> ";
any advices?

Using JSoup parser
You should use a html parser like JSoup since regex is not a good idea to parse html.
You can do something like this:
String htmlString = "YOUR HTML HERE";
Document document=Jsoup.parse(htmlString);
Element element=document.select("a[href=http://www.money.pl/gielda/spolki-gpw/PLCMPLD00016.html]").first();
System.out.println(element.text()); //SYGNITY
element=document.select("td[class=ar]").first();
System.out.println(element.text()); //8,40
Using regex
If you still want to use a regex, then you could use a regex like below and grab the content from capturing groups:
PLCMPLD00016.html">(.*?)<\/a>|"ar">(.*?)<\/td>
Working demo
String htmlString = "YOUR HTML HERE"
Pattern pattern = Pattern.compile("PLCMPLD00016.html">(.*?)<\\/a>|"ar">(.*?)<\\/td>");
Matcher matcher = pattern.matcher(htmlString );
while (matcher.find()) {
System.out.println(matcher.group(1));
System.out.println(matcher.group(2));
}

Add a new html tag to an html string in android

I have a string obtained from an EditText. The string contains html tags.
Spannable s = mainEditText.getText();
String webText = Html.toHtml(s);
The contents of the string is :
<p dir="ltr">test</p>
<p dir="ltr"><img src="http://files.parsetfss.com/bcff7108-cbce-4ab8-b5d1-1f82827e6519/tfss-0de7a730-3fa9-4a1e-9f82-d34e4f6e2d31-file" /><br /></p>
<p dir="ltr"><img src="http://maps.google.com/maps/api/staticmap?center=22.572646,88.363895&zoom=15&size=960x540&sensor=false&markers=color:blue%7Clabel:!%7C22.572646,88.363895" /><br /> </p>
Now, what I want to do is, wherever there is an img src tag, I want to precede it with a center tag.
What should I do to get the following output?
<p dir="ltr">test</p>
<p dir="ltr"><center><img src="http://files.parsetfss.com/bcff7108-cbce-4ab8-b5d1-1f82827e6519/tfss-0de7a730-3fa9-4a1e-9f82-d34e4f6e2d31-file" /></center><br /></p>
<p dir="ltr"><center><img src="http://maps.google.com/maps/api/staticmap?center=22.572646,88.363895&zoom=15&size=960x540&sensor=false&markers=color:blue%7Clabel:!%7C22.572646,88.363895" /></center><br /> </p>
Can a regex solve the issue or should it be done in a different way?
Can JSOUP help in any way? Is there any other type of HTML parser which can do the job?

(<img\s+[^>]*>)
You can try this.Replace with <center>$1</centre>.See demo.
http://regex101.com/r/sU3fA2/38
Something like
var re = /(<img\s+[^>]*>)/g;
var str = '<p dir="ltr">test</p> \n<p dir="ltr"><img src="http://files.parsetfss.com/bcff7108-cbce-4ab8-b5d1-1f82827e6519/tfss-0de7a730-3fa9-4a1e-9f82-d34e4f6e2d31-file" /><br /></p> \n<p dir="ltr"><img src="http://maps.google.com/maps/api/staticmap?center=22.572646,88.363895&zoom=15&size=960x540&sensor=false&markers=color:blue%7Clabel:!%7C22.572646,88.363895" /><br /> </p>';
var subst = '<center>$1</centre>';
var result = str.replace(re, subst);

By using Jsoup, you can use the wrap() method of the Element class of Jsoup.
It would look like this :
public String wrapImgWithCenter(String html) {
Document doc = Jsoup.parse(html);
doc.getElementsByTag("img").wrap("<center></center>");
return doc.html();
}

I implemented the JSOUP solution suggested by mourphy. But, I had edited the method a little and it did the miracle for me. The new method is:
public String wrapImgWithCenter(String html){
Document doc = Jsoup.parse(html);
doc.select("img").wrap("<center></center>");
return doc.html();
}
Thanks mourphy and vks for your help!

Using Regex, you could also do this in java:
String formatted = str.replaceAll("(<img\\s+[^>]*>)", "<center>$1</center>");

Java-Jsoup, scrape html

I am using Jsoup with Java to Parse an HTML file. My question is how can I just extract the line that says "Hourly Rate: 23,016 orders"
I am parsing a lot of files, so the number next to the Hourly Rate will change.
<html>
<head>
<title>Testing</title>
</head>
<body>
<p class=MsoNormal align=center style='background:#DEDEDF'>
<span style='font-size:18.0pt'><b>Testing</b></span></p>
Hourly Rate: 23,016 orders<br>
<table border=0 cellpadding=0>
<tr valign=top>
<td>
Thanks

I just added this code:
String HourlyRate = doc.body().ownText();
//String text = doc.body().text();
System.out.println(HourlyRate);
This Printed out:
Hourly Rate: 23,016 orders

Grab the MsoNormal class then use a regular expression to look for a number i.e.
Document doc = Jsoup.parse(htmlString);
Element msoNormal = doc.getElementsByClass("MsoNormal").first();
if(msoNormal!=null){
Pattern p = Pattern.compile("[0-9]+,[0-9]+");
Matcher m = pattern.matcher(msoNormal.text());
if(matcher.find())
System.out.println(m.get());
}