Detect overlapping between two squares/rectangles JAVA - java

I don't know how to complete this. I'm learning by myself and I found this exercise where you have a class for a rectangle like this:
public class Rectangulo {
private int x, y, width, heigth;
public Rectangulo(int x, int y, int width, int heigth){
this.x = x;
this.y = y;
this.width = width;
this.heigth = heigth;
}
public boolean isOverlaping(Rectangulo r1, Rectangulo r2){
}
And I have to complete the method so it returns true if the 2 rectangles are overlapping / colliding or false if they aren't. Can you give me any guide to help me think this problem, or tips?
I don't have to use the intersects method.
Thanks!

If you look at the method, you're provided with two rectangle objects as arguments, r1 & r2. Each instance has its specific value for x,y, width and height. You can use these values to determine whether the two rectangles collide or overlap
For your specific doubt, you might want to read the javadoc for Rectangle.. This will help you understand how a rectangle is created in Java

Related

finding the other two points of a Perfect Right Triangle

I am writing code that is meant to use one given point of a perfect right triangle to find the remaining two. We assume for this exercise that it is a triangle like so: righttriangle
The first bit of code uses the Point2D class to establish the bottom left point like so:
public Triangle(Point2D.Double bottomLeftPoint, double height, double base){
this.base = base;
this.height = height;
this.bottomLeftPoint = bottomLeftPoint;
}
public Point2D.Double getBottomLeftTrianglePoint() {
return this.bottomLeftPoint;
}
I know that mathematically, the top point of the triangle would have the same x value, but would have the y value added by the height. Also the bottom right point would have the same y value but the x value added by the base.
My question is for method purposes, how would I structure that?
Would it be something like:
public Point2D.Double getTopTrianglePoint() {
return this.bottomLeftPoint(x, y + this.height);
}
public Point2D.Double getBottomRightTrianglePoint() {
return this.bottomLeftPoint(x + this.base, y);
}
For further info, I have a separate class that is meant to test the methods with with a test triangle:
public class TriangleTest {
private Triangle triangle01;
public TriangleTest() {
this.triangle01 = new Triangle(new Point2D.Double(1, 2), 5, 3);
}
}
Any help is appreciated. Thanks!
return this.bottomLeftPoint(x, y + this.height);
Break this down, then you'll notice this doesn't make sense. this.bottomLeftPoint is a variable of type Point2D.Double. You then.. try to treat this as a method somehow. It's not. This doesn't work.
You want to create an entirely new Point2D.Double. new Point2.Double(x, y) as per usual; Thus:
return new Point2D.Double(x, y + this.height);
Except, of course, if you try this, the compiler will tell you this doesn't work either; the compiler has no idea what x means. So, what do you intend to use there? Clearly it's the x coordinate of the Point2D.Double object referenced by your this.bottomLeftPoint field. Which has a .getX() method. So:
return new Point2D.Double(bottomLeftPoint.getX(), bottomLeftPoint.getY() + height);

Object in Constructor Parameters: Create New Instance, or Assign Pointer?

If a class contains an object as an instance variable, and one of the constructors includes an object of the same type as a parameter, is it best practice to assign the argument to the instance variable, or to create a new object from the argument, and assign THE NEW OBJECT to the instance variable.
Here's an example from an exercise I'm working through:
public class MyCircle {
private MyPoint center; //contains variables int x and int y
private int radius;
//Non-controversial Constructor:
public MyCircle(int x, int y, int radius ) {
//creates new center using a valid MyPoint constructor
this.center = new MyPoint(x, y);
this.radius = radius;
}
//OPTION A
public MyCircle( MyPoint center, int radius ) {
this.center = center;
this.radius = radius;
}
//OPTION B
public MyCircle( MyPoint center, int radius ){
this.center = new MyPoint( center.getX(), center.getY() );
this.radius = radius;
}
}
Initially, I typed option A, but I thought that this could create buggy behavior if this.center referenced an existing object that could be modified indirectly unintentionally. The alternative way of thinking about it, I guess, is that this creates an avenue for creating multiple objects that share a center, and moving a single center would intentionally move all circles that share that center.
Since Java has no pointers (at least not for developers) that option will be discarded and is not the way to go..
Now this:
public MyCircle( MyPoint center, int radius ) {
this.center = center;
this.radius = radius; }
Is in my opinion better, you can just assign the center and don't need to make a risky copy of the class MyPoint... And I say risky because if you want to do that you should at least check the non-null condition of that parameter....
You can for sure think... what if center is null in option A, you are right, that can happen, then you can take care of it by either throwing an illegalparameterexception, or just assigning that object to a default value. ..
But as I said before is my opinion..
I think it depends on your program. If you want the circle to have a reference to the MyPoint object, then you must pass it. Otherwise, why not pass in the actually x and y values themselves.
For example, option B can be written as:
public MyCircle(int x, int y, int radius) {
// rest
}
both options are fine, but as you told, an object may change in the time, the option A is ok when you want to modify the center in more than one object at the same time, for example in an List of Circles, but if you want to have unique and independient center points, option B is correct. So you why don't you have both constructors and use one or another depending many cases in your app, use whatever you want you consider better, keep both, it is my advice.
Hope it helps to you.

Object Construction

I know there is an easy solution to this problem but it's driving me crazy. Why is there an error when I want to print the new Rectangle? any help appreciated!
public class Rectangle {
public Rectangle(int x, int y, int width, int length) {
x = 5;
y = 10;
width = 20;
length = 30;
Rectangle box = new Rectangle(5, 10, 20, 30);
System.out.println(new Rectangle());
}
}
There are several problems with your code. First, you may not want to instantiate a Rectangle in the constructor of Rectangle as will lead to infinite recursion. The second problem is that you are calling a constructor that does not exist.
When you write:
new Rectangle()
the Java compiler will look for a constructor in the Rectangle class that accepts no arguments. But your code does not have such a constructor. You can add one like this:
public Rectangle(){
//Your code here to instantiate a default rectangle
}
Usually a constructor is used to set the values of the instance variables in a class rather than to execute code the way you have written it. You can move those lines that are creating rectangles into a main method to test the code.
Here is some code that does what I think you want it to:
public class Rectangle
{
int x, y, width, length; //declares the class's fields
public Rectangle(int x, int y, int width, int length)
{
this.x = x; //initializes the field x to the value of the local variable x
this.y = y; //initializes the field y to the value of the local variable y
this.width = width; //initializes the field width to the value of the local variable width
this.length = length; //initializes the field length to the value of the local variable length
System.out.println(this); //prints this object. should look similar to "Rectangle#1246889"
}
}
Please take a basic java tutorial (e.g. Providing Constructors for Your Classes), it will make your life easier.
You are calling a non-parameterized/default constructor from a parameterized constructor. The JVM in this case unable to create the default constructor. Hence in this case you need to include non-parameterized constructor explicitly into your class.
public class Rectangle {
public Rectangle(int x, int y, int width, int length) {
x = 5;
y = 10;
width = 20;
length = 30;
Rectangle box = new Rectangle(5, 10, 20, 30);
System.out.println(new Rectangle());
}
public Rectangle(){}
}
This will be error free.
First, the code (as you have provided it) can not possibly compile: you haven't declared x, y, width and height as member variables (fields) of your Rectangle. E.g.
// I'm assuming you want these private and final (I would)
private final int x, y, width, height;
Alternative, for a quick hack:
int x, y, width, height;
You are also trying to call a 0-argument constructor on your println line. Your class doesn't have a 0-argument constructor; it has a 4-argument constructor. I suspect (as noted above) you really want to print this.
But that wouldn't help much, on its own, unless you add an appropriate toString method to your class. E.g.:
public String toString() {
StringBuilder sb = new StringBuilder("Rectangle: ");
sb.append("x=").append(x);
sb.append(", y=").append(y);
sb.append(", width=").append(width);
sb.append(", height=").append(height);
return sb.toString();
}
You might want to think about implementing equals() and hashCode() too, if you choose to make this class immutable (I would). You can ixquick* or duckduckgo* this - there are plenty of explanations around.
[*] They are search engines: I don't use google.

Simplifying Java method with variable amount of arguments

Working in java, I was wanting to simplify a draw function (polygon creator) that I am working with. Typically, when you create a polygon, you do this:
Polygon mypoly = new Polygon();
mypoly.addPoint(x1, y1);
mypoly.addPoint(x2, y2);
mypoly.addPoint(x3, y3);
Draw.fillPolygon(g, mypoly, Color.blue);
I would like to use an image mapper to automatically give me the coordinates, so I could just copy paste them into my own function.
myCommand(x1, y1, x2, y2, x3, y3);
Each of these would go into the polygon command on the top. The problem that I am facing though is that when mypoly is created, how would it know how many points to add and where to put them?
I am trying to get myCommand to automatically add points as I add arguments, and each point to correspond with the x,y of the original polygon creation method.
Sounds like you need to make use of the builder pattern. In pseudocode:
PolygonBuilder pb = new PolygonBuilder();
pb.addPoint(1,1);
pb.addPoint(1,2);
// etc...
Polygon p = pb.newPolygon();
so the idea is that you provide the builder with a set of points, and it'll generate you the appropriate polygon. Builders are often designed with a fluent interface. Note that the builder can act like a factory and return you appropriate subclasses of Polygon (square, triangle, pentagle etc. if you so wish).
Note that you could instead provide a method that takes a variable number of arguments, using the Java varargs mechanism. e.g.
public void addPoints(Integer... args) {
// and iterate here
}
You may wish to create a Point object to define an x/y coordinate together. Otherwise the above will have to check for an even number of arguments, and those arguments won't be tied together.
You can use varargs and create the polygon dynamically by using the constructor that gets arrays of xs and ys
(Code not tested)
public Polygon createPolygon(int... points) {
if (0 != points.length % 2) {
throw new IllegalArgumentException("Must have even number of points");
}
int numOfPoints = points.length / 2;
int xs = new int[numOfPoints];
int ys = new int[numOfPoints];
for (int i=0; i < numOfPoints;i++) {
xs[i] = points[i*2];
yx[i] = points[i*2 + 1];
}
return new Polygon(xs, ys, numOfPOints);
}
Then you can invoke the method with any number of points
Polygon p = createPolygon(x1,y1,x2,y2,x3,y3);
To extend Brian Agnew's answer, it might also be worth adding a Point class which the addPoints method could take in. It could make it slightly easier to add/remove points from your polygon.
public final class Point<X,Y>{
private final X x;
private final Y y;
public Point(X x, Y y){
this.x=x;
this.y=y;
}
public X getX(){return x;}
public Y getY(){return y;}
}
Then you could have a:
public void addPoints(Point<Integer,Integer>... points){
for(Point<Integer,Integer> point:points)
//your logic
}
I think you could use a method that received a varargs (...)
You need a wrapper for each point:
class Point {
int x;
int y;
Point(int x, int y) {
this.x = x;
this.y = y;
}
}
The method could be:
myCommand(Point ... points)
For call
myCommand(new Point(0,0), new Point(1,1), new Point(0,1));
And for draw:
Polygon mypoly = new Polygon();
for(Point p : points)
mypoly.addPoint(p.x,p.y);
Draw.fillPolygon(g,mypoly,Color.blue);

Why is the output this? (Java)

This is an instance method from a Rectangle class where we modify the x and y coordinates of the rectangle and its width and height
public void modify(int newX, int y, int width, int h) {
int x = newX;
this.y = y;
width = width;
this.height = height;
}
Rectangle r3 = new Rectangle(0, 0, 10, 10);
r3.modify(5, 5, 50, 50);
System.out.print(r3.getX() + " " + r3.getY() + " ");
System.out.println(r3.getWidth() + " " + r3.getHeight());
I have this code and I know that the output is 0 5 10 10 but i'm not entirely sure why. can anyone explain why?
public void modify(int newX, int y, int width, int h) {
int x = newX; // the value isn't saved to the class members
this.y = y; // this is saved, hence you see the change in the y value
width = width; // meaningless, the variable is overwritten with it's own value
this.height = height; // who is height? the function receives h
}
You have created a new object of type "int" for X within the modify method. This means that it only exists within that method since you're not passing it by reference. So, the newX value is only 5 within the modify method, but does not exist as '5' outside of it. this.y works fine because you've called that specific instance of the object and modified it's value. Therefore, it's retained outside the method. 'width = width' doesn't work because you're simply assigning 50=50 (since you've inputted 50 as the width). 'this.height = h' would be fine, but you've said 'this.height = height'. But, from the code you've given, 'height' doesn't exist.
y is the only instance variable that is actually modified in the modify method. The other the arguments passed in have no net effect on the state of the object.
Actually, the code shouldn't compile. height isn't defined in your method call. Unless this is another property that you didn't include in your code snippet.
int x = newX creates a new int named x that you then do nothing with. That's why r3.getX() returns 0, since you never modified it.
this.y = y changes the value of the field y within the Rectangle class. This is why this change is shown in your output as 5.
width = width changes the method parameter named width to itself. It doesn't change the value, but it also doesn't set the field width within Rectangle. No change shown, original value of 10 prints.
If height is a field elsewhere, then it makes sense that r3.getHeight() wouldn't update the field, since the parameter in the method call is for h, not height. If not, then I don't know how the code compiles since height isn't mentioned anywhere.
The "int x = newX" line creates a variable "x" on the stack that exists only for the duration of the current method call.
"this.x" would refer to the "x" created by the classes constructor. Which is probably what "getX()" returns.
This code shows the difference between the function stack variable and object variable. For function modify, the four passing variables are on the stack. The line declares a stack variable x and set its value as newX. The second line uses the object variable this.y and set to passing variable y. The third line is to assign the width to its self on stack. The fourth line uses the object variable height and assign to its self. Once the program goes out of the scope of function modify, all its stack variables' value are whacked. So the result is 0 5 10 10 because only the second line which is not stack variable this.y retains its value after calling function modify.
I would venture to say your issue is in how you are assigning the new values of x, y, width and height to your rectangle object.
Assuming that your modify method is in the rectangle class your code currently looks like this (I added comments on the mistakes:
public void modify(int newX, int y, int width, int h) {
int x = newX; //you are declaring a new x here...not assigning newX to rectangle's x
this.y = y; //this is correct
width = width; //here you're just assigning the parameter width its current value
this.height = height; //here you are assigning the rectangles height value to itself
}
I would HIGHLY advise finding a naming convention and sticking with it as it would help tremendously here.
Try something like this:
public void modify(int x, int y, int w, int h) { //changed names of parameters
this.x = x; //removed the int type declaration and used this. prefix
this.y = y; //changed nothing
this.width = w; //adjusted for renamed parameter, used this. prefix
this.height = h; // adjusted for renamed parameter, again used this. prefix
}
As you can see, sticking to a convention makes the code less confusing and easier to read. This also allows you to see your mistakes more easily as they will usually stick out from your convention like a sore thumb. Don't worry it comes with practice.

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