Develop Reference

include external library inside programmatically created jar

I have a java program that is created using jaroutput stream. and the output jar uses an external library.
At first I thought that I could use classpath in the manifest to get the external library inside the jar.
Then I found out that that doesnt work.
Then I thought about custom class loaders such as one-jar.
but I got stuck trying to get it to work in a generated jar.
External library is jsonsimple 1.1.1 if you are wondering.
and here is the code for the generated custom jar.
public void run(String output) throws IOException {
Manifest manifest = new Manifest();
manifest.getMainAttributes().put(Attributes.Name.MANIFEST_VERSION, "1.0");
manifest.getMainAttributes().put(Attributes.Name.MAIN_CLASS, "Install");
manifest.getMainAttributes().put(Attributes.Name.CLASS_PATH, "json-simple-1.1.1.jar");
JarOutputStream target = new JarOutputStream(new FileOutputStream(output), manifest);
add(tempclass, target,"Install.class");
add(tempjar, target,"lib/json-simple-1.1.1.jar");
if (resourcepackzip != null) {
add(resourcepackzip, target,resourcepackzip.getName().toString());
}
if (optionstxt != null){
add(optionstxt, target,optionstxt.getName().toString());
}
add(worldzip, target,worldzip.getName().toString());
add(temptxt, target,temptxt.getName().toString());
target.close();
}
#SuppressWarnings("resource")
private void add(File source, JarOutputStream target,String source2) throws IOException
{
BufferedInputStream in = null;
try
{
if (source.isDirectory())
{
String name = source.getPath().replace("\\", "/");
if (!name.isEmpty())
{
if (!name.endsWith("/"))
name += "/";
JarEntry entry = new JarEntry(name);
entry.setTime(source.lastModified());
target.putNextEntry(entry);
target.closeEntry();
}
for (File nestedFile: source.listFiles())
add(nestedFile, target, nestedFile.getName().toString());
return;
}
JarEntry entry = new JarEntry(source2);
entry.setTime(source.lastModified());
target.putNextEntry(entry);
in = new BufferedInputStream(new FileInputStream(source));
byte[] buffer = new byte[1024];
while (true)
{
int count = in.read(buffer);
if (count == -1)
break;
target.write(buffer, 0, count);
}
}finally {
}
}
So is there anyway I can include json in a jar made with jaroutputstream?

How to zip files and folders in Java?

Please have a look at the below code.
public void startCompress(String path,String fileName,String outputLocation,int compressType,int filSize) throws Exception
{
System.out.println("Input Location: "+path);
System.out.println("Output Location: "+outputLocation);
System.out.println(compressType);
byte[] bs=new byte[filSize];
System.out.println(filSize);
FileOutputStream fos=new FileOutputStream(outputLocation+"/test.zip");
System.out.println(fos.toString());
ZipOutputStream zos=new ZipOutputStream(fos);
ZipEntry ze = new ZipEntry(fileName);
zos.putNextEntry(ze);
FileInputStream inputStream=new FileInputStream(path);
int len;
while((len=inputStream.read(bs))>0){
zos.write(bs, 0, len);
}
inputStream.close();
zos.closeEntry();
zos.close();
}
In above code, we compress a file using java.util.zip package. But we have an issue. That is, if we select multiple files then only one file is being compressed. If we select a folder, the compression simply won't work.
How can I fix this to compress either a file, files, folder, folders, or even nested folders? Java zip package does support .zip, .tar, .tarGz and tarZ. So the solution should not be something which is limited to .zip extension as well.

Here is my solution that uses the new java.nio package. Just call zipDir giving it the path to the directory. It will create a zip file in the same location but called <directory>.zip.
private static Path buildPath(final Path root, final Path child) {
if (root == null) {
return child;
} else {
return Paths.get(root.toString(), child.toString());
}
}
private static void addZipDir(final ZipOutputStream out, final Path root, final Path dir) throws IOException {
try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir)) {
for (Path child : stream) {
Path entry = buildPath(root, child.getFileName());
if (Files.isDirectory(child)) {
addZipDir(out, entry, child);
} else {
out.putNextEntry(new ZipEntry(entry.toString()));
Files.copy(child, out);
out.closeEntry();
}
}
}
}
public static void zipDir(final Path path) throws IOException {
if (!Files.isDirectory(path)) {
throw new IllegalArgumentException("Path must be a directory.");
}
BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(path.toString() + ".zip"));
try (ZipOutputStream out = new ZipOutputStream(bos)) {
addZipDir(out, path.getFileName(), path);
}
}

The zip libraries for java cannot be used to compress folders in simpler way like - compress this folder.
You need to do the test if the input is folder or file by yourself. If it is a file - add it to the zip. If it is a folder - iterate the folder and add each file to the zip. For the subfolders to the same. To add more than one file to the Zip you need to create ZipEntry for each file.
You can try this code which works for me:
public static void zip(File directory, File zipfile) throws IOException {
URI base = directory.toURI();
Deque<File> queue = new LinkedList<File>();
queue.push(directory);
OutputStream out = new FileOutputStream(zipfile);
Closeable res = out;
try {
ZipOutputStream zout = new ZipOutputStream(out);
res = zout;
while (!queue.isEmpty()) {
directory = queue.pop();
for (File kid : directory.listFiles()) {
String name = base.relativize(kid.toURI()).getPath();
if (kid.isDirectory()) {
queue.push(kid);
name = name.endsWith("/") ? name : name + "/";
zout.putNextEntry(new ZipEntry(name));
} else {
zout.putNextEntry(new ZipEntry(name));
copy(kid, zout);
zout.closeEntry();
}
}
}
} finally {
res.close();
}
}

Updated from this answer, which fixes issue with each file been added to it's own directory. Also better supports Windows explorer.
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.ArrayList;
import java.util.List;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class Test {
public static void main(String agrs[]) {
ZipUtils appZip = new ZipUtils();
appZip.zipIt(new File(source directory), new File(dest zip));
}
public static class ZipUtils {
private final List<File> fileList;
private List<String> paths;
public ZipUtils() {
fileList = new ArrayList<>();
paths = new ArrayList<>(25);
}
public void zipIt(File sourceFile, File zipFile) {
if (sourceFile.isDirectory()) {
byte[] buffer = new byte[1024];
FileOutputStream fos = null;
ZipOutputStream zos = null;
try {
// This ensures that the zipped files are placed
// into a folder, within the zip file
// which is the same as the one been zipped
String sourcePath = sourceFile.getParentFile().getPath();
generateFileList(sourceFile);
fos = new FileOutputStream(zipFile);
zos = new ZipOutputStream(fos);
System.out.println("Output to Zip : " + zipFile);
FileInputStream in = null;
for (File file : this.fileList) {
String path = file.getParent().trim();
path = path.substring(sourcePath.length());
if (path.startsWith(File.separator)) {
path = path.substring(1);
}
if (path.length() > 0) {
if (!paths.contains(path)) {
paths.add(path);
ZipEntry ze = new ZipEntry(path + "/");
zos.putNextEntry(ze);
zos.closeEntry();
}
path += "/";
}
String entryName = path + file.getName();
System.out.println("File Added : " + entryName);
ZipEntry ze = new ZipEntry(entryName);
zos.putNextEntry(ze);
try {
in = new FileInputStream(file);
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
} finally {
in.close();
}
}
zos.closeEntry();
System.out.println("Folder successfully compressed");
} catch (IOException ex) {
ex.printStackTrace();
} finally {
try {
zos.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
protected void generateFileList(File node) {
// add file only
if (node.isFile()) {
fileList.add(node);
}
if (node.isDirectory()) {
File[] subNote = node.listFiles();
for (File filename : subNote) {
generateFileList(filename);
}
}
}
}
}

Java Exclude Base Directory from Namespace

I am trying to programmatically create a runnable jar file. I am using the following code:
The add method:
private static void add(File source, JarOutputStream target) throws IOException
{
BufferedInputStream in = null;
try
{
if (source.isDirectory())
{
String name = source.getPath().replace("\\", File.separator);
if (!name.isEmpty())
{
if (!name.endsWith(File.separator))
name += File.separator;
JarEntry entry = new JarEntry(name);
entry.setTime(source.lastModified());
target.putNextEntry(entry);
//target.closeEntry();
}
for (File nestedFile: source.listFiles())
add(nestedFile, target);
return;
}
JarEntry entry = new JarEntry(source.getPath().replace("\\", "/"));
entry.setTime(source.lastModified());
target.putNextEntry(entry);
in = new BufferedInputStream(new FileInputStream(source));
byte[] buffer = new byte[1024];
while (true)
{
int count = in.read(buffer);
if (count == -1)
break;
target.write(buffer, 0, count);
}
target.closeEntry();
}
finally
{
if (in != null)
in.close();
}
}
Its implementation:
try {
File[] files = new File("tmp").listFiles();
for (File file : files) {
System.out.println("Archiving: "+file.getName());
add(file, target);
}
} catch (IOException e) {
e.printStackTrace();
}
try {
target.close();
} catch (IOException e) {
e.printStackTrace();
}
I am trying to add all of the contents of the tmp directory to my jar, but I do not want to prefix all of the namespaces with tmp.. I tried using this code to iterate through the the files in tmp and add them but I keep getting errors saying "no such file or directory". I am pretty sure that's because it is looking outside the tmp directory. However, when I change it to add(new File("tmp"+File.separator+file.getName()), target); I end up with "tmp" in my namespaces (because I started with the tmp/ directory). Is there a way around this?
Here is an example:
I have a jar file with the Main-Class attribute com.name.proj.ProjDriver
When I decompress it into the tmp folder I end up with the file in tmp/com/name/proj/ProjDriver.class. I then recompress my jar using the manifest object from the old jar still specifying the main class as com.name.proj.ProjDriver but now it is actually tmp.com.name.proj.ProjDriver. How can I avoid having tmp. as a prefix for all the namespaces?

Replace your code with this:
private static void add(File source, JarOutputStream target) throws IOException
{
BufferedInputStream in = null;
try
{
if (source.isDirectory())
{
String name = source.getPath().replace("\\", File.separator);
if (!name.isEmpty())
{
if (!name.endsWith(File.separator))
name += File.separator;
JarEntry entry = new JarEntry(name);
entry.setTime(source.lastModified());
target.putNextEntry(entry);
//target.closeEntry();
}
for (File nestedFile: source.listFiles())
try{add(nestedFile, target);}catch(IOException e){System.out.println(e);}
return;
}
JarEntry entry = new JarEntry(source.getPath().replace("tmp\\","").replace("\\", "/"));
entry.setTime(source.lastModified());
target.putNextEntry(entry);
in = new BufferedInputStream(new FileInputStream(source));
byte[] buffer = new byte[1024];
while (true)
{
int count = in.read(buffer);
if (count == -1)
break;
target.write(buffer, 0, count);
}
target.closeEntry();
}
finally
{
if (in != null)
in.close();
}
}
I have varied this row:
JarEntry entry = new JarEntry(source.getPath().replace("tmp\\","").replace("\\", "/"));

File locations as URI,can not find file

I have to do simple file operations code based,including copy/delete operations.The problem is if i declare the file location as a path
File remotefile = new File("//mypc/myfolder/myjar.JAR");
Windows finds the file in the network and does the operations.How ever Linux machines can not find the file.If i were to use:
File remotefile = new File("file://mypc/myfolder/myjar.JAR");
Both platforms find the file.Now i have a method to copy the files which is:
public static void copyFile(File sourceFile, File destFile) throws IOException {
if(!destFile.exists()) {
destFile.createNewFile();
}
FileChannel source = null;
FileChannel destination = null;
try {
source = new FileInputStream(sourceFile).getChannel();
destination = new FileOutputStream(destFile).getChannel();
destination.transferFrom(source, 0, source.size());
}
finally {
if(source != null) {
source.close();
}
if(destination != null) {
destination.close();
}
}
}
If I were to send the file URI to this method, both platforms can not find the file. But if I send it as a path, windows machines work properly but linux machines can not find the file.
What could be the problem here?

Reading properties file from JAR directory

I’m creating an executable JAR that will read in a set of properties at runtime from a file. The directory structure will be something like:
/some/dirs/executable.jar
/some/dirs/executable.properties
Is there a way of setting the property loader class in the executable.jar file to load the properties from the directory that the jar is in, rather than hard-coding the directory.
I don't want to put the properties in the jar itself as the properties file needs to be configurable.

Why not just pass the properties file as an argument to your main method? That way you can load the properties as follows:
public static void main(String[] args) throws IOException {
Properties props = new Properties();
props.load(new BufferedReader(new FileReader(args[0])));
System.setProperties(props);
}
The alternative: If you want to get the current directory of your jar file you need to do something nasty like:
CodeSource codeSource = MyClass.class.getProtectionDomain().getCodeSource();
File jarFile = new File(codeSource.getLocation().toURI().getPath());
File jarDir = jarFile.getParentFile();
if (jarDir != null && jarDir.isDirectory()) {
File propFile = new File(jarDir, "myFile.properties");
}
... where MyClass is a class from within your jar file. It's not something I'd recommend though - What if your app has multiple MyClass instances on the classpath in different jar files (each jar in a different directory)? i.e. You can never really guarantee that MyClass was loaded from the jar you think it was.

public static void loadJarCongFile(Class Utilclass )
{
try{
String path= Utilclass.getResource("").getPath();
path=path.substring(6,path.length()-1);
path=path.split("!")[0];
System.out.println(path);
JarFile jarFile = new JarFile(path);
final Enumeration<JarEntry> entries = jarFile.entries();
while (entries.hasMoreElements()) {
final JarEntry entry = entries.nextElement();
if (entry.getName().contains(".properties")) {
System.out.println("Jar File Property File: " + entry.getName());
JarEntry fileEntry = jarFile.getJarEntry(entry.getName());
InputStream input = jarFile.getInputStream(fileEntry);
setSystemvariable(input);
InputStreamReader isr = new InputStreamReader(input);
BufferedReader reader = new BufferedReader(isr);
String line;
while ((line = reader.readLine()) != null) {
System.out.println("Jar file"+line);
}
reader.close();
}
}
}
catch (Exception e)
{
System.out.println("Jar file reading Error");
}
}
public static void setSystemvariable(InputStream input)
{
Properties tmp1 = new Properties();
try {
tmp1.load(input);
for (Object element : tmp1.keySet()) {
System.setProperty(element.toString().trim(),
tmp1.getProperty(element.toString().trim()).trim());
}
} catch (IOException e) {
System.out.println("setSystemvariable method failure");
}
}