I am new in hibernate. I am using hibernate 3 in my application using hibernate annotations , I am developing application in struts 1.3.
My question is :
I have googled a lot but could not understand how to call a stored procedure in hibernate using annotations , I have a simple scenario : suppose I have 2 fields in my jsp say 1) code 2) name , I have created a stored procedure in database for inserting those records into table. Now my problem is that how to execute it
List<MyBean> list = sessionFactory.getCurrentSession()
.getNamedQuery("mySp")
.setParameter("code", code)
.setParameter("name", name)
I don't know the exact code how to do this. But I guess something like that actually I come from jdbc background therefore have no idea how to do this and same thing I want when selecting the data from database using stored procedure.
Hibernate provides many simple ways to call a SP like
Native SQL
Named Query in native SQL as Annotation/XML mapping file
Following link shows how each of above can be implemented
http://www.mkyong.com/hibernate/how-to-call-store-procedure-in-hibernate/
http://docs.jboss.org/hibernate/orm/3.3/reference/en/html/querysql.html#sp_query
Sample to run native SQL query using hibernate:
Session session = getSession();
SQLQuery sqlQuery = session.createSQLQuery("SELECT COUNT(id) FROM tableName WHERE external_id = :external_id");
sqlQuery.setParameter("external_id", idValue);
int count = ((BigInteger) sqlQuery.uniqueResult()).intValue();
releaseSession(session);
You can execute your stored procedure using Hibernate's SQLQuery with the same SQL as when you call it against the database. For example, in postgreSQL:
String query = "select schema.procedure_name(:param1)";
SQLQuery sqlquery = sessionFactory.getCurrentSession().createSQLQuery(query);
sqlquery.setInteger("param1", "this is first parameter");
sqlQuery.list();
Hope it helps.
Related
I use spring boot, and I want to add 1 year to a specific column in mysql database
String queryRecherche = "UPDATE myTable t SET t.dateDebut = DATE_ADD(t.dateDebut, INTERVAL 1 YEAR) WHERE.id = 3 ";
Query query = em.createQuery(queryRecherche);;
query.executeUpdate();
But I get the folowing error :
org.hibernate.query.sqm.ParsingException: line 1:66 no viable alternative at input 'DATE_ADD(t.dateDebut,INTERVAL1'
Have you please any suggestions to do this.
You're using Hibernate 6 (I can tell by the error message), so the correct HQL syntax to use is:
UPDATE MyEntity t SET t.dateDebut = t.dateDebut + 1 year WHERE t.id = 3
You had three errors in your query:
You referred to the name of a table instead of the name of an entity class in the UPDATE clause.
You used the unportable MySQL DATE_ADD function instead of the portable HQL date/time arithmetic described here.
The syntax of your WHERE clause was garbled.
Perhaps you meant for this to be a native SQL query, in which case you called the wrong method of Session. But there's no need to use native SQL for the above query. As you can see, HQL is perfectly capable of expressing that query.
You can use SQL directly, via createNativeQuery, or register a new function as shown in this example to call it from HQL
Is it possible to create native SQL-queries for saving, updating or removing certain entities from the database via hibernate ?
What i am searching for is pretty much this...
String sqlQuery = session.save(listOfEntities);
session.execute(sqlQuery);
sqlQuery : "insert into players(id,...) values((10,...),(11,...))"
Why would you need the statements? Just doing session.persist(entity) will execute the statement for you already.
I am absolutly new in Hibernate and I have the following problem.
I have this standard SQL query:
SELECT count(*)
FROM TID003_ANAGEDIFICIO anagraficaEdificio
INNER JOIN TID002_CANDIDATURA candidatura
ON (candidatura.PRG_PAR = anagraficaEdificio.PRG_PAR AND candidatura.PRG_CAN = anagraficaEdificio.PRG_CAN)
INNER JOIN TID001_ANAGPARTECIPA anagPartecipa ON(anagPartecipa.PRG_PAR = candidatura.PRG_PAR)
INNER JOIN anagrafiche.TPG1029_PROVNUOIST provNuovIst ON (provNuovIst.COD_PRV_NIS = anagPartecipa.COD_PRV_NIS)
WHERE anagraficaEdificio.FLG_GRA = 1 AND provNuovIst.COD_REG = "SI";
This works fine and return an integer number.
The important thing to know is that in this query the only
parameter that can change (inserted by the user in the frontend of a webappplication) is the last one (this one: provNuovIst.COD_REG = "SI").
So, the application on which I am working use Hibernate and the requirement say that I have to implement this query using Hibernate Native SQL, I have found this tutorial:
http://www.tutorialspoint.com/hibernate/hibernate_native_sql.htm
that show this example:
String sql = "SELECT * FROM EMPLOYEE WHERE id = :employee_id";
SQLQuery query = session.createSQLQuery(sql);
query.addEntity(Employee.class);
query.setParameter("employee_id", 10);
List results = query.list();
that, from what I have understand (correct me if I am doing wrong assertion), involves the use of an Employee model class. So th prvious query first define the query (using the :param_name syntax for the parameter), then create an SQLQuery Hibernate object, add the class used for the result, set the previous parameter neam and finally obtain a List (that I think Hibernate create as something like an ArrayList) with the retrieved object.
My problem is that I simply I have to obtain an integer value (because I have a SELECT count(*), so I will obtain an integer value and not a set of rows).
So how can I correctly use the Hibernate Native SQL to implement my SQL query into my Hibernate repository class?
Use SQLQuery.uniqueResult to retrieve a single value from the query:
String sql = "SELECT count(*) ...";
SQLQuery query = session.createSQLQuery(sql);
// set parameters...
int count = ((Number)query.uniqueResult()).intValue();
SQL :
String hql1 = "SELECT /* PARALLEL(MVR,16) PARALLEL(MVRS,16)*/ * FROM
ICM MINUS SELECT I1.* FROM ICM I1 , C1_ICM_STATIC I2 WHERE
I1.METRIC_DIRECTION=I2.METRIC_DIRECTION AND
I1.METRIC_NAME=I2.METRIC_NAME AND I1.METRIC_UNIT=I2.METRIC_UNIT AND
I1.TERMINATION_POINT_ID=I2.TERMINATION_POINT_ID AND
I1.TERMINATION_POINT_NAME=I2.TERMINATION_POINT_NAME AND
I1.TERMINATION_POINT_TYPE=I2.TERMINATION_POINT_TYPE";
Criteria Query
icms1 = (List<ICM>) session.createCriteria(ICM.class, hql1).list();
I have executed hql1 using SQL Developer then I got only one result, but when I have integrated SQL Query with Criteria it returning me all records in ICM table.
If SQL query returning only one result in SQL Developer, Why criteria API returning all records in ICM table?
Why criteria API returning all records in ICM table?
Technically you are not using criteria api for associations.
Try something like this.
Refer.
return criteria.createCriteria(A.class)
.createCriteria("b", "join_between_a_b")
.createCriteria("c", "join_between_b_c")
.createCriteria("d", "join_between_c_d")
.add(Restrictions.eq("some_field_of_D", someValue));
You should learn to read API documentation.
The second Session.createCriteria() argument is the alias that you want to assign to the root entity. It's not a HQL query. HQL queries are not executed using Session.createCriteria(). They're executed using Session.createQuery().
BTW, your query is not a HQL query at all. It's a SQL query. SQL and HQL are 2 different languages. To execute a SQL query, you need createSQLQuery().
I've detected a performance problem with hibernate and native queries on Oracle. When I execute a complex SQL query with several parameters on TOAD I get the result in miliseconds. However, when I execute the same query using Hibernate this time is incremented hugely (up to four seconds or even more).
My SQL query is rather complex, return an unique value (so, the problem is not related with the time necessary to instation classes) and it contains several parameters with the the format ':nameParameter'. This query is stored in a String. For example,
String myNamedNativeQuery = "select count(*) from tables "+
"where column1 = :nameParameter1 "+
"and column2 = :nameParameter2";
//actually my sentence is much more complex!!
When I execute the sentence on TOAD it is resolved in few miliseconds. But using this sentence with Hibernate
SQLQuery query = session.createSQLQuery("myNamedNativeQuery");
query.setParameter(nameParameter1, value1);
query.setParameter(nameParameter2, value2);
query.uniqueResult();
are necessary several seconds to get the same result.
I realized if I replaced the parameters directly on the native query and then I execute the sentence using Hibernate the time decreases drastically. It would be something like that:
String strQuery = session.getNamedQuery("myNamedNativeQuery").getQueryString();
myNamedNativeQuery = myNamedNativeQuery.replace("nameParameter1", value1);
myNamedNativeQuery = myNamedNativeQuery.replace("nameParameter2", value2);
SQLQuery query = session.createSQLQuery("myNamedNativeQuery");
query.uniqueResult();
Anybody knows what's happening??
Thanks in advance.
PS: The Oracle version is 9i and Hibernate 3.2
I think what's happening with this code :
SQLQuery query = session.createSQLQuery("myNamedNativeQuery");
query.setParameter(nameParameter1, value1);
query.setParameter(nameParameter2, value2);
query.uniqueResult();
is this:
at line 1 : a query plan is created based on some expected values for your named parameters.
at line 4 : the query is executed with value1 and value2, but those values are not "good values" for the query plan that was elaborate at line 1 and so, the database is executing a very inappropriate plan for the actual values and it takes a lot of time.
Why ?
Looking at the source code of HibernateSessionImpl.createSQLQuery(...) I found this line of code:
SQLQueryImpl query = new SQLQueryImpl(
sql,
this,
factory.getQueryPlanCache().getSQLParameterMetadata( sql )
);
which is calling getQueryPlanCache() with some parameterMetaData. I assume that this metadata is not good enough.
My answer to you is:
Remove all bind parameters and use StatelessSession instead of Session
Use SQLQuery instead of query with full SQL including parameter values
StatelessSession session = sessionFactory.openStatelessSession();
I had similar problem and till I get better solution,this is what I managed to make it work.
See Hibernate parameterized sql query slow and active oracle sessions
<property name = "hibernate.temp.use_jdbc_metadata_defaults">false</property>
Add this to your hibernate.cfg.xml or update your application properties file.